{"common":{"save":0,"post_id":"7090","level":1,"total":10,"point":10,"point_extra":0},"segment":[{"id":"5275","post_id":"7090","mon_id":"1158924","chapter_id":"1159163","question":"<p>T&igrave;m gi&aacute; tr\u1ecb th\u1ef1c c\u1ee7a tham s\u1ed1 m \u0111\u1ec3 h&agrave;m s\u1ed1&nbsp;<span class=\"math-tex\">$f(x)=\\begin{cases}\\dfrac{x^2-x-2}{x-2}&amp;\\text{ khi }x\\ne2\\\\m&amp;\\text{ khi }x=2\\end{cases}$<\/span>&nbsp; li&ecirc;n t\u1ee5c t\u1ea1i x = 2.<\/p>","options":["<strong>A.<\/strong> 0","<strong>B.<\/strong> 1","<strong>C.<\/strong> 2","<strong>D.<\/strong> 3"],"correct":"4","level":"1","hint":"","answer":"<p>T\u1eadp x&aacute;c \u0111\u1ecbnh D = R ch\u1ee9a x = 2. Theo gi\u1ea3 thi\u1ebft, ta ph\u1ea3i c&oacute;<\/p><p>m =&nbsp;<span class=\"math-tex\">$f(2)$<\/span>&nbsp;=&nbsp;<span class=\"math-tex\">$\\displaystyle\\lim_{x\\to1} f(x)$<\/span> =&nbsp;<span class=\"math-tex\">$\\displaystyle\\lim_{x\\to2}\\dfrac{x^2-x-2}{x-2}=\\displaystyle\\lim_{x\\to2}(x+1)=3$<\/span><\/p><p>V\u1eady m = 3.<\/p><p>Ch\u1ecdn&nbsp;<span style=\"color:#16a085;\"><strong>D.<\/strong> 3.<\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2024-03-03 01:30:11","option_type":"txt","len":0},{"id":"5277","post_id":"7090","mon_id":"1158924","chapter_id":"1159163","question":"<p>T&igrave;m gi&aacute; tr\u1ecb th\u1ef1c c\u1ee7a tham s\u1ed1 m \u0111\u1ec3 h&agrave;m s\u1ed1&nbsp;<span class=\"math-tex\">$f(x)=\\begin{cases}\\dfrac{x^3-x^2+2x-2}{x-1}&amp;\\text{ khi }x\\ne1\\\\3x+m&amp;\\text{ khi }x=1\\end{cases}$<\/span>&nbsp; li&ecirc;n t\u1ee5c t\u1ea1i x = 1.<\/p>","options":["<strong>A.<\/strong> 0","<strong>B.<\/strong> 2","<strong>C.<\/strong> 4","<strong>D.<\/strong> 6"],"correct":"1","level":"1","hint":"","answer":"<p>H&agrave;m s\u1ed1 x&aacute;c \u0111\u1ecbnh v\u1edbi m\u1ecdi x&nbsp;<span class=\"math-tex\">$\\ne$<\/span>&nbsp;1. Theo gi\u1ea3 thi\u1ebft ta ph\u1ea3i c&oacute;<\/p><p>3 + m =&nbsp;<span class=\"math-tex\">$f(1)$<\/span>&nbsp;=&nbsp;<span class=\"math-tex\">$\\displaystyle\\lim_{x\\to1} f(x)$<\/span>&nbsp;=&nbsp;<span class=\"math-tex\">$\\displaystyle\\lim_{x\\to1}\\dfrac{x^3-x^2+2x-2}{x-1}$<\/span>&nbsp;<\/p><p>&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; =&nbsp;<span class=\"math-tex\">$\\displaystyle\\lim_{x\\to1}\\dfrac{(x-1)(x^2+2)}{x-1}$<\/span>&nbsp;=&nbsp;<span class=\"math-tex\">$\\displaystyle\\lim_{x\\to1}(x^2+2)$<\/span>&nbsp;= 3<\/p><p>Suy ra m = 0.<\/p><p>Ch\u1ecdn&nbsp;<span style=\"color:#16a085;\"><strong>A.<\/strong> 0.<\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2024-03-03 01:35:55","option_type":"txt","len":0},{"id":"5279","post_id":"7090","mon_id":"1158924","chapter_id":"1159163","question":"<p>T&igrave;m gi&aacute; tr\u1ecb th\u1ef1c c\u1ee7a tham s\u1ed1 k \u0111\u1ec3 h&agrave;m s\u1ed1&nbsp;<span class=\"math-tex\">$y=f(x)=\\begin{cases}\\dfrac{\\sqrt{x}-1}{x-1}&\\text{ khi }x\\ne1\\\\k+1&\\text{ khi }x=1\\end{cases}$<\/span>&nbsp; li&ecirc;n t\u1ee5c t\u1ea1i x = 1.<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$\\dfrac{1}{2}$<\/span>","<strong>B.<\/strong> 2","<strong>C.<\/strong> <span class=\"math-tex\">$-\\dfrac{1}{2}$<\/span>","<strong>D.<\/strong> 0"],"correct":"3","level":"1","hint":"","answer":"<p>H&agrave;m s\u1ed1&nbsp;<span class=\"math-tex\">$f(x)$<\/span>&nbsp;c&oacute; t\u1eadp x&aacute;c \u0111\u1ecbnh D =&nbsp;<span class=\"math-tex\">$[0;+\\infty]$<\/span>&nbsp;. \u0110i\u1ec1u ki\u1ec7n b&agrave;i to&aacute;n t\u01b0\u01a1ng \u0111\u01b0\u01a1ng v\u1edbi<\/p><p><span class=\"math-tex\">$k+1=f(1)=\\displaystyle\\lim_{x\\to1}f(x)$<\/span>&nbsp;<span class=\"math-tex\">$=\\displaystyle\\lim_{x\\to1}\\dfrac{\\sqrt{x}-1}{x-1}$<\/span>&nbsp;<span class=\"math-tex\">$=\\displaystyle\\lim_{x\\to1}\\dfrac{1}{\\sqrt{x}+1}$<\/span>&nbsp;<span class=\"math-tex\">$=\\dfrac{1}{2}$<\/span><\/p><p>Suy ra&nbsp;<span class=\"math-tex\">$k=-\\dfrac{1}{2}$<\/span>&nbsp;.<\/p><p>Ch\u1ecdn<span style=\"color:#16a085;\">&nbsp;<strong>C.<\/strong>&nbsp;<span class=\"math-tex\">$-\\dfrac{1}{2}$<\/span>.<\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2024-03-03 01:45:55","option_type":"math","len":0}]}