Chú ý: Để đảm bảo quyền lợi và bảo vệ tài khoản của mình
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{"common":{"save":0,"post_id":"7039","level":1,"total":10,"point":10,"point_extra":0},"segment":[{"id":"4735","post_id":"7039","mon_id":"1158924","chapter_id":"1159141","question":"<p>H\u1ecd nghi\u1ec7m c\u1ee7a ph\u01b0\u01a1ng trình <span class=\"math-tex\">$sin\\bigg(x+\\dfrac{\\pi}{7}\\bigg)=\\dfrac{\\sqrt{3}}{2}$<\/span> là<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$x=\\dfrac{4\\pi}{21}+k2\\pi$<\/span> ho\u1eb7c <span class=\"math-tex\">$x=\\dfrac{11\\pi}{21}+k2\\pi$<\/span> , k ∈ Z.","<strong>B.<\/strong> <span class=\"math-tex\">$x=\\dfrac{\\pi}{3}+k2\\pi$<\/span> ho\u1eb7c <span class=\"math-tex\">$x=\\dfrac{2\\pi}{3}+k2\\pi$<\/span> , k ∈ Z.","<strong>C.<\/strong> <span class=\"math-tex\">$x=\\dfrac{\\pi}{3}+k2\\pi$<\/span> ho\u1eb7c <span class=\"math-tex\">$x=-\\dfrac{\\pi}{3}+k2\\pi$<\/span> , k ∈ Z.","<strong>D.<\/strong> <span class=\"math-tex\">$x=\\dfrac{4\\pi}{21}+k2\\pi$<\/span> ho\u1eb7c <span class=\"math-tex\">$x=-\\dfrac{11\\pi}{21}+k2\\pi$<\/span> , k ∈ Z."],"correct":"1","level":"1","hint":"","answer":"<p><span class=\"math-tex\">$sin\\bigg(x+\\dfrac{\\pi}{7}\\bigg)=\\dfrac{\\sqrt{3}}{2}$<\/span><\/p><p>⇔ <span class=\"math-tex\">$x+\\dfrac{\\pi}{7}=\\dfrac{\\pi}{3}+k2\\pi$<\/span> ho\u1eb7c <span class=\"math-tex\">$x+\\dfrac{\\pi}{7}=\\dfrac{2\\pi}{3}+k2\\pi$<\/span><\/p><p>⇔ <span class=\"math-tex\">$x=\\dfrac{4\\pi}{21}+k2\\pi$<\/span> ho\u1eb7c <span class=\"math-tex\">$x=\\dfrac{11\\pi}{21}+k2\\pi$<\/span> , k ∈ Z.<\/p><p>Ch\u1ecdn <span style=\"color:#16a085;\"> <strong>A.<\/strong> <span class=\"math-tex\">$x=\\dfrac{4\\pi}{21}+k2\\pi$<\/span> ho\u1eb7c <span class=\"math-tex\">$x=\\dfrac{11\\pi}{21}+k2\\pi$<\/span> , k ∈ Z.<\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2023-11-19 08:23:42","option_type":"math","len":0},{"id":"4736","post_id":"7039","mon_id":"1158924","chapter_id":"1159141","question":"<p>H\u1ecd nghi\u1ec7m c\u1ee7a ph\u01b0\u01a1ng trình <span class=\"math-tex\">$cos\\bigg(x-\\dfrac{\\pi}{5}\\bigg)=cos\\bigg(-\\dfrac{\\pi}{3}\\bigg)$<\/span> là<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$x=\\dfrac{\\pi}{3}+k2\\pi$<\/span> ho\u1eb7c <span class=\"math-tex\">$x=-\\dfrac{\\pi}{3}+k2\\pi$<\/span> , k ∈ Z.","<strong>B.<\/strong> <span class=\"math-tex\">$x=\\dfrac{8\\pi}{15}+k2\\pi$<\/span> ho\u1eb7c <span class=\"math-tex\">$x=-\\dfrac{\\pi}{3}+k2\\pi$<\/span> , k ∈ Z.","<strong>C.<\/strong> <span class=\"math-tex\">$x=\\dfrac{\\pi}{3}+k2\\pi$<\/span> ho\u1eb7c <span class=\"math-tex\">$x=-\\dfrac{2\\pi}{15}+k2\\pi$<\/span> , k ∈ Z.","<strong>D.<\/strong> <span class=\"math-tex\">$x=\\dfrac{8\\pi}{15}+k2\\pi$<\/span> ho\u1eb7c <span class=\"math-tex\">$x=-\\dfrac{2\\pi}{15}+k2\\pi$<\/span> , k ∈ Z."],"correct":"4","level":"1","hint":"","answer":"<p>Ta có <span class=\"math-tex\">$cos\\bigg(x-\\dfrac{\\pi}{5}\\bigg)=cos\\bigg(-\\dfrac{\\pi}{3}\\bigg)$<\/span><\/p><p>⇔ <span class=\"math-tex\">$x-\\dfrac{\\pi}{5}=-\\dfrac{\\pi}{3}+k2\\pi$<\/span> ho\u1eb7c <span class=\"math-tex\">$x-\\dfrac{\\pi}{5}=\\dfrac{\\pi}{3}+k2\\pi$<\/span><\/p><p>⇔ <span class=\"math-tex\">$x=\\dfrac{8\\pi}{15}+k2\\pi$<\/span> ho\u1eb7c <span class=\"math-tex\">$x=-\\dfrac{2\\pi}{15}+k2\\pi$<\/span> , k ∈ Z.<\/p><p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>D.<\/strong> <span class=\"math-tex\">$x=\\dfrac{8\\pi}{15}+k2\\pi$<\/span> ho\u1eb7c <span class=\"math-tex\">$x=-\\dfrac{2\\pi}{15}+k2\\pi$<\/span> , k ∈ Z.<\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2023-11-19 08:29:22","option_type":"math","len":0},{"id":"4738","post_id":"7039","mon_id":"1158924","chapter_id":"1159141","question":"<p>H\u1ecd nghi\u1ec7m c\u1ee7a ph\u01b0\u01a1ng trình <span class=\"math-tex\">$tan(2x+30^0)=-1$<\/span> là<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$x=-45^0+k180^0$<\/span> , k ∈ Z.","<strong>B.<\/strong> <span class=\"math-tex\">$x=-75^0+k180^0$<\/span> , k ∈ Z.","<strong>C.<\/strong> <span class=\"math-tex\">$x=-37,5^0+k90^0$<\/span> , k ∈ Z.","<strong>A.<\/strong> <span class=\"math-tex\">$x=-37,5^0+k180^0$<\/span> , k ∈ Z."],"correct":"3","level":"1","hint":"","answer":"<p><span class=\"math-tex\">$tan(2x+30^0)=-1$<\/span> ⇔ <span class=\"math-tex\">$2x+30^0=-45^0+k180^0$<\/span><\/p><p>⇔ <span class=\"math-tex\">$2x=-75^0+k180^0$<\/span> ⇔ <span class=\"math-tex\">$x=-37,5^0+k90^0$<\/span> , k ∈ Z.<\/p><p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>C.<\/strong> <span class=\"math-tex\">$x=-37,5^0+k90^0$<\/span> , k ∈ Z. <\/span><\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2023-11-19 08:32:37","option_type":"math","len":0}]}