{"common":{"save":0,"post_id":"8210","level":2,"total":10,"point":10,"point_extra":0},"segment":[{"id":"6047","post_id":"8210","mon_id":"1159285","chapter_id":"1159382","question":"<p>Trong không gian Oxyz, ph\u01b0\u01a1ng trình m\u1eb7t ph\u1eb3ng (Oyz) là:<\/p>","options":["<strong>A.<\/strong> z = 0","<strong>B.<\/strong> x = 0","<strong>C.<\/strong> x + y + z = 0","<strong>D.<\/strong> y = 0"],"correct":"2","level":"2","hint":"<p>Khi bài toán cho bi\u1ebft m\u1eb7t ph\u1eb3ng (α) \u0111i qua \u0111i\u1ec3m <span class=\"math-tex\">$M_0(x_0;y_0;z_0)$<\/span> và có m\u1ed9t vect\u01a1 pháp tuy\u1ebfn <span class=\"math-tex\">$\\overrightarrow{n}=(A;B;C)$<\/span> ho\u1eb7c có hai vect\u01a1 ch\u1ec9 ph\u01b0\u01a1ng <span class=\"math-tex\">$\\overrightarrow{a},\\;\\overrightarrow{b}$<\/span> (v\u1edbi <span class=\"math-tex\">$\\overrightarrow{n}=\\Big[\\overrightarrow{a},\\overrightarrow{b}\\Big]$<\/span>) thì vi\u1ebft d\u01b0\u1edbi d\u1ea1ng sau: <span class=\"math-tex\">$(\\alpha):A(x-x_0)+B(y-y_0)+C(z-z_0)=0$<\/span>.<\/p><p>M\u1eb7t ph\u1eb3ng (Oyz) nh\u1eadn <span class=\"math-tex\">$\\overrightarrow{i}(1;0;0)$<\/span> làm vect\u01a1 pháp tuy\u1ebfn và \u0111i qua g\u1ed1c t\u1ecda \u0111\u1ed9 O(0; 0; 0).<\/p>","answer":"<p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>B.<\/strong> x = 0<\/span><\/p><p>M\u1eb7t ph\u1eb3ng (Oyz) nh\u1eadn <span class=\"math-tex\">$\\overrightarrow{i}(1;0;0)$<\/span> làm vect\u01a1 pháp tuy\u1ebfn và \u0111i qua g\u1ed1c t\u1ecda \u0111\u1ed9 O(0; 0; 0) nên có ph\u01b0\u01a1ng trình là:<\/p><p><span class=\"math-tex\">$1(x-0)+0(y-0)+0(z-0)=0$<\/span><\/p><p>⇒ <span class=\"math-tex\">$x = 0$<\/span>.<\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2024-12-25 09:05:56","option_type":"txt","len":2},{"id":"6049","post_id":"8210","mon_id":"1159285","chapter_id":"1159382","question":"<p>Trong không gian v\u1edbi h\u1ec7 to\u1ea1 \u0111\u1ed9 Oxyz, ph\u01b0\u01a1ng trình nào d\u01b0\u1edbi \u0111ây là ph\u01b0\u01a1ng trình c\u1ee7a m\u1eb7t ph\u1eb3ng (Oxy)?<\/p>","options":["<strong>A.<\/strong> y = 0 ","<strong>B.<\/strong> x = 0","<strong>C.<\/strong> z = 0","<strong>D.<\/strong> y – z = 0"],"correct":"3","level":"2","hint":"<p>Khi bài toán cho bi\u1ebft m\u1eb7t ph\u1eb3ng (α) \u0111i qua \u0111i\u1ec3m <span class=\"math-tex\">$M_0(x_0;y_0;z_0)$<\/span> và có m\u1ed9t vect\u01a1 pháp tuy\u1ebfn <span class=\"math-tex\">$\\overrightarrow{n}=(A;B;C)$<\/span> ho\u1eb7c có hai vect\u01a1 ch\u1ec9 ph\u01b0\u01a1ng <span class=\"math-tex\">$\\overrightarrow{a},\\;\\overrightarrow{b}$<\/span> (v\u1edbi <span class=\"math-tex\">$\\overrightarrow{n}=\\Big[\\overrightarrow{a},\\overrightarrow{b}\\Big]$<\/span>) thì vi\u1ebft d\u01b0\u1edbi d\u1ea1ng sau: <span class=\"math-tex\">$(\\alpha):A(x-x_0)+B(y-y_0)+C(z-z_0)=0$<\/span>.<\/p>","answer":"<p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>C.<\/strong> z = 0<\/span><\/p><p>M\u1eb7t ph\u1eb3ng (Oxy) nh\u1eadn <span class=\"math-tex\">$\\overrightarrow{k}(0;0;1)$<\/span> làm vect\u01a1 pháp tuy\u1ebfn và \u0111i qua g\u1ed1c t\u1ecda \u0111\u1ed9 O(0; 0; 0) nên có ph\u01b0\u01a1ng trình là:<\/p><p><span class=\"math-tex\">$0(x-0)+0(y-0)+1(z-0)=0$<\/span><\/p><p>⇒ <span class=\"math-tex\">$z = 0$<\/span>.<\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2024-12-25 09:07:52","option_type":"txt","len":2},{"id":"6050","post_id":"8210","mon_id":"1159285","chapter_id":"1159382","question":"<p>Trong không gian v\u1edbi h\u1ec7 t\u1ecda \u0111\u1ed9 ph\u01b0\u01a1ng trình Oxyz, nào sau \u0111ây là ph\u01b0\u01a1ng trình c\u1ee7a m\u1eb7t ph\u1eb3ng (Ozx)?<\/p>","options":["<strong>A.<\/strong> x = 0","<strong>B.<\/strong> y – 1 = 0","<strong>C.<\/strong> z = 0","<strong>D.<\/strong> y = 0 "],"correct":"4","level":"2","hint":"<p>Khi bài toán cho bi\u1ebft m\u1eb7t ph\u1eb3ng (α) \u0111i qua \u0111i\u1ec3m <span class=\"math-tex\">$M_0(x_0;y_0;z_0)$<\/span> và có m\u1ed9t vect\u01a1 pháp tuy\u1ebfn <span class=\"math-tex\">$\\overrightarrow{n}=(A;B;C)$<\/span> ho\u1eb7c có hai vect\u01a1 ch\u1ec9 ph\u01b0\u01a1ng <span class=\"math-tex\">$\\overrightarrow{a},\\;\\overrightarrow{b}$<\/span> (v\u1edbi <span class=\"math-tex\">$\\overrightarrow{n}=\\Big[\\overrightarrow{a},\\overrightarrow{b}\\Big]$<\/span>) thì vi\u1ebft d\u01b0\u1edbi d\u1ea1ng sau: <span class=\"math-tex\">$(\\alpha):A(x-x_0)+B(y-y_0)+C(z-z_0)=0$<\/span>.<\/p>","answer":"<p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>D.<\/strong> y = 0 <\/span><\/p><p>M\u1eb7t ph\u1eb3ng (Ozx) nh\u1eadn <span class=\"math-tex\">$\\overrightarrow{j}(0;1;0)$<\/span> làm vect\u01a1 pháp tuy\u1ebfn và \u0111i qua g\u1ed1c t\u1ecda \u0111\u1ed9 O(0; 0; 0) nên có ph\u01b0\u01a1ng trình là:<\/p><p><span class=\"math-tex\">$0(x-0)+1(y-0)+0(z-0)=0$<\/span><\/p><p>⇒ <span class=\"math-tex\">$y = 0$<\/span>.<\/p>","type":"choose","extra_type":"classic","user_id":"131","test":"0","date":"2024-12-25 09:11:01","option_type":"txt","len":2}]}