{"segment":[{"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":10,"ques":" $\\widehat{aOb}$ + $\\widehat{bOc}$ = $\\widehat{aOc}$ th\u00ec:","select":["A. Tia Oa n\u1eb1m gi\u1eefa hai tia Ob v\u00e0 Oc","B. Tia Ob n\u1eb1m gi\u1eefa hai tia Oa v\u00e0 Oc","C. Tia Oc n\u1eb1m gi\u1eefa hai tia Ob v\u00e0 Oa","D. T\u1ea5t c\u1ea3 c\u00e1c \u0111\u00e1p \u00e1n tr\u00ean \u0111\u1ec1u sai"],"hint":"","explain":" <span class='basic_left'><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/>Theo \u0111\u1eb3ng th\u1ee9c c\u1ed9ng g\u00f3c ta c\u00f3:<br\/>N\u1ebfu tia Ob n\u1eb1m gi\u1eefa hai tia Oa v\u00e0 Oc th\u00ec $\\widehat{aOb}$ + $\\widehat{bOc}$ = $\\widehat{aOc}$<br\/>V\u1eady khi $\\widehat{aOb}$ + $\\widehat{bOc}$ = $\\widehat{aOc}$ th\u00ec tia Ob n\u1eb1m gi\u1eefa hai tia Oa v\u00e0 Oc <br\/>Ta ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0: <span class='basic_pink'>B. Tia Ob n\u1eb1m gi\u1eefa hai tia Oa v\u00e0 Oc<\/span><\/span> <br\/><\/span>","column":1}],"id_ques":2261},{"title":"L\u1ef1a ch\u1ecdn \u0111\u00fang hay sai","title_trans":"","temp":"true_false","correct":[["t","t","f","t"]],"list":[{"point":10,"image":"","col_name":["","\u0110\u00fang","Sai"],"arr_ques":[" G\u00f3c b\u1eb9t l\u00e0 g\u00f3c c\u00f3 hai c\u1ea1nh l\u00e0 hai tia \u0111\u1ed1i nhau"," G\u00f3c $40^o$ v\u00e0 $50^o$ l\u00e0 hai g\u00f3c ph\u1ee5 nhau "," Hai g\u00f3c c\u00f3 t\u1ed5ng s\u1ed1 \u0111o b\u1eb1ng $180^o$ l\u00e0 hai g\u00f3c k\u1ec1 b\u00f9 ","Tia Oy n\u1eb1m gi\u1eefa hai tia Ox v\u00e0 Oz n\u1ebfu <br\/>$\\widehat{xOy}$ = $30^o$, $\\widehat{xOz}$ = $70^o$, $\\widehat{yOz}$ = $40^o$"],"hint":"","explain":["G\u00f3c b\u1eb9t l\u00e0 g\u00f3c c\u00f3 hai c\u1ea1nh l\u00e0 hai tia \u0111\u1ed1i nhau (\u0110\u00fang)","<br\/> G\u00f3c $40^o$ v\u00e0 $50^o$ l\u00e0 hai g\u00f3c ph\u1ee5 nhau (\u0110\u00fang). V\u00ec $40^o$ + $50^o$ = $90^o$, m\u00e0 hai g\u00f3c c\u00f3 t\u1ed5ng s\u1ed1 \u0111o b\u1eb1ng $90^o$ \u0111\u01b0\u1ee3c g\u1ecdi l\u00e0 hai g\u00f3c ph\u1ee5 nhau.","<br\/>Hai g\u00f3c c\u00f3 t\u1ed5ng s\u1ed1 \u0111o b\u1eb1ng $180^o$ l\u00e0 hai g\u00f3c k\u1ec1 b\u00f9 (Sai). V\u00ec hai g\u00f3c k\u1ec1 b\u00f9 l\u00e0 hai g\u00f3c v\u1eeba k\u1ec1 nhau v\u00e0 v\u1eeba b\u00f9 nhau, t\u1ee9c l\u00e0 hai g\u00f3c k\u1ec1 nhau v\u00e0 c\u00f3 t\u1ed5ng s\u1ed1 \u0111o b\u1eb1ng $180^o$ ","<br\/> Tia Oy n\u1eb1m gi\u1eefa hai tia Ox v\u00e0 Oz n\u1ebfu <br\/>$\\widehat{xOy}$ = $30^o$, $\\widehat{xOz}$ = $70^o$, $\\widehat{yOz}$ = $40^o$ (\u0110\u00fang). V\u00ec<br\/> $\\widehat{xOy}$ + $\\widehat{yOz}$ = $\\widehat{xOz}$ (v\u00ec $30^o$ + $40^o$ = $70^o$ )<br\/>Suy ra tia Oy n\u1eb1m gi\u1eefa hai tia Ox v\u00e0 Oz "]}],"id_ques":2262},{"title":"\u0110i\u1ec1n s\u1ed1 ho\u1eb7c ch\u1eef th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["2"],["C"]]],"list":[{"point":10,"width":60,"type_input":"","ques":"<span class='basic_left'>V\u1ebd tam gi\u00e1c ABC, bi\u1ebft ba c\u1ea1nh BC = 4cm, AB = 2cm, AC = 3cm.<br\/><b>C\u00e1ch v\u1ebd:<\/b><br\/>+ V\u1ebd \u0111o\u1ea1n th\u1eb3ng BC = 4cm<br\/>+ V\u1ebd cung tr\u00f2n t\u00e2m B, b\u00e1n k\u00ednh _input_ cm<br\/>+ V\u1ebd cung tr\u00f2n t\u00e2m _input_, b\u00e1n k\u00ednh 3cm.<br\/>+ L\u1ea5y m\u1ed9t giao \u0111i\u1ec3m c\u1ee7a hai cung tr\u00ean, g\u1ecdi giao \u0111i\u1ec3m \u0111\u00f3 l\u00e0 A<br\/>+ V\u1ebd \u0111o\u1ea1n th\u1eb3ng AB, AC, ta c\u00f3 $\\triangle$ABC.<\/span>","hint":"","explain":"<span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/><span class='basic_left'><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop6/toan/hinhhoc/kiemtrachuong2/lv3/img\/H627_D101.png' \/><\/center><b>C\u00e1ch v\u1ebd:<\/b><br\/>+ V\u1ebd \u0111o\u1ea1n th\u1eb3ng BC = 4cm<br\/>+ V\u1ebd cung tr\u00f2n t\u00e2m B, b\u00e1n k\u00ednh 2cm<br\/>+ V\u1ebd cung tr\u00f2n t\u00e2m C, b\u00e1n k\u00ednh 3cm.<br\/>+ L\u1ea5y m\u1ed9t giao \u0111i\u1ec3m c\u1ee7a hai cung tr\u00ean, g\u1ecdi giao \u0111i\u1ec3m \u0111\u00f3 l\u00e0 A<br\/>+ V\u1ebd \u0111o\u1ea1n th\u1eb3ng AB, AC, ta c\u00f3 $\\triangle$ABC.<br\/>V\u1eady s\u1ed1 ho\u1eb7c ch\u1eef c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng theo th\u1ee9 t\u1ef1 t\u1eeb tr\u00ean xu\u1ed1ng d\u01b0\u1edbi l\u00e0:<span class='basic_pink'> 2; C<\/span><\/span> <\/span> <br\/> "}],"id_ques":2263},{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":10,"ques":" Tr\u00ean c\u00f9ng m\u1ed9t n\u1eeda m\u1eb7t ph\u1eb3ng b\u1edd c\u00f3 ch\u1ee9a tia OA, v\u1ebd tia OB v\u00e0 OC sao cho $\\widehat{AOB}$ = $115^o$, $\\widehat{AOC}$ = $45^o$. T\u00ednh $\\widehat{BOC}$.","select":["A. $\\widehat{BOC}$ = $60^o$","B. $\\widehat{BOC}$ = $70^o$ ","C. $\\widehat{BOC}$ = $150^o$","D. $\\widehat{BOC}$ = $160^o$"],"hint":"","explain":" <span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/>+ B\u01b0\u1edbc 1: So s\u00e1nh $\\widehat{AOB}$ v\u00e0 $\\widehat{AOC}$ \u0111\u1ec3 t\u00ecm ra tia n\u1eb1m gi\u1eefa<br\/>+ B\u01b0\u1edbc 2: D\u1ef1a v\u00e0o \u0111\u1eb3ng th\u1ee9c c\u1ed9ng g\u00f3c \u0111\u1ec3 t\u00ecm s\u1ed1 \u0111o $\\widehat{BOC}$.<\/span> <br\/><br\/><span class='basic_left'><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop6/toan/hinhhoc/kiemtrachuong2/lv3/img\/H627_D104.png' \/><\/center>Ta c\u00f3: $\\widehat{AOC}$ < $\\widehat{AOB}$ (v\u00ec $45^o$ < $115^o$)<br\/>N\u00ean <b>tia OC n\u1eb1m gi\u1eefa hai tia OA v\u00e0 OB<\/b> <br\/>Suy ra $\\widehat{AOC}$ + $\\widehat{COB}$ = $\\widehat{AOC}$ <br\/>Thay $\\widehat{AOB}$ = $45^o$, $\\widehat{AOC}$ = $115^o$, ta \u0111\u01b0\u1ee3c:<br\/> $45^o$ + $\\widehat{COB}$ = $115^o$<br\/>$\\widehat{COB}$ = $115^o$ - $45^o$ = $70^o$<br\/>Hay $\\widehat{BOC}$ = $70^o$<\/b><br\/>V\u1eady ta ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0: : <span class='basic_pink'>B. $\\widehat{BOC}$ = $70^o$<\/span><\/span> <br\/><\/span><span class='basic_left'><span class='basic_green'>Nh\u1eadn x\u00e9t:<\/span><br\/>Tia Oy n\u1eb1m gi\u1eefa hai tia Ox v\u00e0 Oz th\u00ec: $\\widehat{xOy}$ + $\\widehat{yOz}$ = $\\widehat{xOz}$<\/span>","column":2}],"id_ques":2264},{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":10,"ques":" Cho $\\widehat{xOt}$ = $35^o$, $\\widehat{tOy}$ = $25^o$. Bi\u1ebft tia Ot n\u1eb1m gi\u1eefa hai tia Ox v\u00e0 Oy. T\u00ednh $\\widehat{xOy}$. ","select":["A. $\\widehat{xOy}$ = $15^o$","B. $\\widehat{xOy}$ = $25^o$","C. $\\widehat{xOy}$ = $60^o$","D. $\\widehat{xOy}$ = $70^o$"],"hint":"","explain":" <span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> N\u1ebfu tia Ot n\u1eb1m gi\u1eefa hai tia Ox v\u00e0 Oy th\u00ec $\\widehat{xOt}$ + $\\widehat{tOy}$ = $\\widehat{xOy}$<\/span> <br\/><span class='basic_left'><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop6/toan/hinhhoc/kiemtrachuong2/lv3/img\/H627_D108.png' \/><\/center>Tia Ot n\u1eb1m gi\u1eefa hai tia Ox v\u00e0 Oy<br\/>N\u00ean $\\widehat{xOt}$ + $\\widehat{tOy}$ = $\\widehat{xOy}$<br\/>Thay $\\widehat{xOt}$ = $35^o$, $\\widehat{tOy}$ = $25^o$, ta \u0111\u01b0\u1ee3c:<br\/> $\\widehat{xOy}$ = $35^o$ + $25^o$ = $60^o$<br\/>V\u1eady ta ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0: <span class='basic_pink'>C. $60^o$<\/span><\/span> <br\/><\/span>","column":2}],"id_ques":2265},{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":10,"ques":" Cho $\\widehat{xOy}$ = $80^o$. Bi\u1ebft tia Ot l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a $\\widehat{xOy}$. T\u00ednh $\\widehat{tOy}$","select":["A. $40^o$","B. $45^o$","C. $50^o$","D. $55^o$"],"hint":"","explain":" <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop6/toan/hinhhoc/kiemtrachuong2/lv3/img\/H627_D109.png' \/><\/center>Tia Ot l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a $\\widehat{xOy}$ <br\/>Suy ra $\\widehat{xOt}$ = $\\widehat{tOy}$ = $\\frac{1}{2}$ $\\widehat{xOy}$ = $\\frac{1}{2}$. $80^o$ = $40^o$<br\/>V\u1eady ta ch\u1ecdn \u0111\u00e1p \u00e1n : <span class='basic_pink'>A. $40^o$<\/span><\/span> <br\/>","column":2}],"id_ques":2266},{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":10,"ques":" Bi\u1ebft $\\widehat{xOy}$ = $80^o$, $\\widehat{aOb}$ = $100^o$. V\u1eady hai g\u00f3c xOy v\u00e0 aOb l\u00e0 hai g\u00f3c: ","select":["A. b\u00f9 nhau","B. k\u1ec1 nhau","C. k\u1ec1 b\u00f9","D. ph\u1ee5 nhau"],"hint":"","explain":" <span class='basic_left'><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/>Ta c\u00f3: <br\/>$\\widehat{xOy}$ + $\\widehat{aOb}$ = $80^o$ + $100^o$ = $180^o$<br\/>Suy ra hai g\u00f3c xOy v\u00e0 aOb l\u00e0 hai g\u00f3c b\u00f9 nhau<br\/>V\u1eady ta ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0: <span class='basic_pink'>A. b\u00f9 nhau<\/span><\/span> <br\/><\/span><span class='basic_left'><span class='basic_green'>Nh\u1eadn x\u00e9t:<\/span> Hai g\u00f3c b\u00f9 nhau l\u00e0 hai g\u00f3c c\u00f3 t\u1ed5ng s\u1ed1 \u0111o b\u1eb1ng $180^o$<\/span>","column":2}],"id_ques":2267},{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["25"],["50"]]],"list":[{"point":10,"width":60,"type_input":"","ques":"Cho tia Oy l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c xOz. Bi\u1ebft $\\widehat{xOy}$ = $25^o$. V\u1eady $\\widehat{yOz}$ = _input_$^o$, $\\widehat{xOz}$ = _input_$^o$","hint":"","explain":"<span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop6/toan/hinhhoc/kiemtrachuong2/lv3/img\/H627_D112.png' \/><\/center>Ta c\u00f3: Tia Oy l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a $\\widehat{xOz}$ <br\/>Suy ra $\\widehat{xOy}$ = $\\widehat{yOz}$ = $\\frac{1}{2}$ $\\widehat{xOz}$ = $25^o$<br\/>L\u1ea1i c\u00f3: $\\widehat{xOy}$ = $\\frac{1}{2}$ $\\widehat{xOz}$<br\/>Do \u0111\u00f3: $\\widehat{xOz}$ = 2. $\\widehat{xOy}$ = 2. $25^o$ = $50^o$<br\/>V\u1eady c\u00e1c s\u1ed1 c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u1ea7n l\u01b0\u1ee3t t\u1eeb tr\u00e1i qua ph\u1ea3i l\u00e0: <span class='basic_pink'> 25, 50<\/span><\/span> <br\/> "}],"id_ques":2268},{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":10,"ques":" H\u00e3y ch\u1ecdn c\u00e2u \u0111\u00fang","select":["A. Tia Ox n\u1eb1m gi\u1eefa hai tia Oy v\u00e0 Oz th\u00ec $\\widehat{xOy}$ + $\\widehat{zOy}$ = $\\widehat{xOz}$ ","B. Tia Ox n\u1eb1m gi\u1eefa hai tia Oy v\u00e0 Oz th\u00ec $\\widehat{yOx}$ + $\\widehat{xOz}$ = $\\widehat{yOz}$","C. Tia Ox n\u1eb1m gi\u1eefa hai tia Oy v\u00e0 Oz th\u00ec $\\widehat{xOy}$ + $\\widehat{yOz}$ = $\\widehat{xOz}$","D. Tia Ox n\u1eb1m gi\u1eefa hai tia Oy v\u00e0 Oz th\u00ec $\\widehat{xOz}$ + $\\widehat{zOy}$ = $\\widehat{xOy}$"],"hint":"","explain":" <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/>Ta c\u00f3:<br\/>Tia Ox n\u1eb1m gi\u1eefa hai tia Oy v\u00e0 Oz th\u00ec $\\widehat{yOx}$ + $\\widehat{xOz}$ = $\\widehat{yOz}$<br\/>V\u1eady ta ch\u1ecdn \u0111\u00e1p \u00e1n: <span class='basic_pink'>B. Tia Ox n\u1eb1m gi\u1eefa hai tia Oy v\u00e0 Oz th\u00ec $\\widehat{yOx}$ + $\\widehat{xOz}$ = $\\widehat{yOz}$<\/span><\/span> <br\/>","column":1}],"id_ques":2269},{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":10,"ques":" Cho $\\widehat{xOz}$ = $140^o$. Bi\u1ebft tia Oy l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a $\\widehat{xOz}$. T\u00ednh $\\widehat{xOy}$","select":["A. $70^o$","B. $80^o$","C. $20^o$","D. $30^o$"],"hint":"","explain":" <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop6/toan/hinhhoc/kiemtrachuong2/lv3/img\/H627_D115.png' \/><\/center>Tia Oy l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a $\\widehat{xOz}$ <br\/>Suy ra $\\widehat{xOy}$ = $\\widehat{yOz}$ = $\\frac{1}{2}$ $\\widehat{xOz}$ = $\\frac{1}{2}$. $140^o$ = $70^o$<br\/>V\u1eady ta ch\u1ecdn \u0111\u00e1p \u00e1n : <span class='basic_pink'>A. $70^o$<\/span><\/span> <br\/>","column":2}],"id_ques":2270}],"id_ques":0}],"lesson":{"save":1,"level":3,"time":44}}