{"segment":[{"time":24,"part":[{"title":"\u0110i\u1ec1n \u0111\u00e1p \u00e1n \u0111\u00fang v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["185"],["4"]]],"list":[{"point":5,"width":50,"ques":"T\u00ecm x bi\u1ebft $\\left( \\dfrac{2}{3}x - \\dfrac{1}{2} \\right) . \\dfrac{3}{4} - \\dfrac{2}{5}x = 4\\dfrac{1}{4}$ <br\/> V\u1eady $x$ = <div class=\"frac123\"><div class=\"ts\">_input_<\/div><div class=\"ms\">_input_<\/div><\/div> ","hint":"","explain":" <span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1: <\/b> Nh\u00e2n ph\u00e1 ngo\u1eb7c <br\/> <b> B\u01b0\u1edbc 2: <\/b> chuy\u1ec3n c\u00e1c s\u1ed1 h\u1ea1ng kh\u00f4ng ch\u1eefa x sang v\u1ebf ph\u1ea3i <br\/> <b> B\u01b0\u1edbc 3: <\/b> Bi\u1ebfn \u0111\u1ed5i v\u00e0 t\u00ecm x <\/span> <br\/><br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> $ \\begin{align*} \\left( \\dfrac{2}{3}x - \\dfrac{1}{2} \\right) . \\dfrac{3}{4} - \\dfrac{2}{5}x &= 4\\dfrac{1}{4} \\\\ \\dfrac{1}{2}x - \\dfrac{3}{8} - \\dfrac{2}{5}x &= \\dfrac{17}{4} \\\\ \\dfrac{1}{2}x - \\dfrac{2}{5}x &= \\dfrac{17}{4} + \\dfrac{3}{8} \\\\ \\dfrac{1}{10}x &= \\dfrac{37}{8} \\\\ x &= \\dfrac{37}{8} : \\dfrac{1}{10} \\\\ x &= \\dfrac{185}{4}\\end{align*} $"}]}],"id_ques":1771},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"T\u00ecm x $\\in \\mathbb{Z}$, bi\u1ebft $\\dfrac{-2}{3} + \\dfrac{-5}{12} < x \\leq 4 - \\dfrac{1}{3} : \\dfrac{1}{6}$ ","select":["A. $x \\in \\left \\{ -1; 0; 1; 2 \\right\\}$ ","B. $x \\in \\left\\{ -2; -1; 0; 1 \\right\\}$ ","C. $x \\in \\left\\{ -4; -3; -2; -1; 0 \\right\\}$ ","D. $x \\in \\left\\{ 0; 1; 2; 3; 4 \\right\\}$ "],"hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> T\u00ednh bi\u1ec3u th\u1ee9c v\u1ebf tr\u00e1i v\u00e0 v\u1ebf ph\u1ea3i sau \u0111\u00f3 t\u00ecm x <\/span> <br\/><br\/><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span> <br\/> Ta c\u00f3: <br\/> $\\dfrac{-2}{3} + \\dfrac{-5}{12} = \\dfrac{-8}{12} + \\dfrac{-5}{12} = \\dfrac{-13}{12}$ <br\/> $4 - \\dfrac{1}{3} : \\dfrac{1}{6} = 4 - \\dfrac{1}{3} . 6 = 4 - 2 = 2$ <br\/> $\\Rightarrow$ $\\dfrac{-13}{12} < x \\leq 2$ hay $-1\\dfrac{1}{12} < x \\leq 2$ <br\/> V\u00ec $x \\in \\mathbb{Z}$ $\\Rightarrow$ $x \\in \\left\\{ -1; 0; 1; 2 \\right\\}$ <br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0: A <\/span> ","column":2}]}],"id_ques":1772},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"Cho p v\u00e0 2p + 1 l\u00e0 s\u1ed1 nguy\u00ean t\u1ed1 (p > 5). <br\/> Lan kh\u1eb3ng \u0111\u1ecbnh 4p + 1 l\u00e0 s\u1ed1 nguy\u00ean t\u1ed1 <b> \u0111\u00fang <\/b> hay <b> sai <\/b>? ","select":["A. \u0110\u00daNG ","B. SAI "],"hint":"S\u1ed1 nguy\u00ean t\u1ed1 l\u00e0 s\u1ed1 ch\u1ec9 chia h\u1ebft cho 1 v\u00e0 ch\u00ednh n\u00f3","explain":"<span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span> <br\/> V\u00ec p l\u00e0 s\u1ed1 nguy\u00ean t\u1ed1, p > 5 n\u00ean: p $\\not \\vdots$ 3 $\\Rightarrow$ 4p $\\not \\vdots$ 3 (1) <br\/> Do 2p + 1 l\u00e0 s\u1ed1 nguy\u00ean t\u1ed1 l\u1edbn h\u01a1n 3 n\u00ean: 2p + 1 $\\not \\vdots$ 3 <br\/> $\\Rightarrow$ 2(2p + 1) $\\not \\vdots$ 3 hay 4p + 2 $\\not \\vdots$ 3 (1) <br\/> M\u1eb7t kh\u00e1c trong 3 s\u1ed1 t\u1ef1 nhi\u00ean li\u00ean ti\u1ebfp 4p, 4p + 1; 4p + 2 lu\u00f4n c\u00f3 1 s\u1ed1 chia h\u1ebft cho 3 (3) <br\/> T\u1eeb (1), (2), (3) $\\Rightarrow$ 4p + 1 $\\vdots$ 3 <br\/> M\u00e0 4p + 1 > 3 n\u00ean 4p + 1 l\u00e0 h\u1ee3p s\u1ed1 <br\/> V\u1eady kh\u1eb3ng \u0111\u1ecbnh tr\u00ean c\u1ee7a Lan l\u00e0 <span class='basic_pink'> SAI <\/span> ","column":2}]}],"id_ques":1773},{"time":24,"part":[{"title":"\u0110i\u1ec1n \u0111\u00e1p \u00e1n \u0111\u00fang v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["2"]]],"list":[{"point":5,"width":50,"type_input":"","ques":"T\u00ecm s\u1ed1 t\u1ef1 nhi\u00ean x sao cho 14 $\\vdots$ (2x + 3) <br\/> V\u1eady x = _input_ ","hint":"(2x + 3) $\\in$ \u01af(14) ","explain":" <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> V\u00ec 2x + 3 l\u00e0 \u01b0\u1edbc c\u1ee7a 14 n\u00ean 2x + 3 $\\in$ {1; 2; 7; 14} <br\/> V\u00ec 2x + 3 l\u00e0 s\u1ed1 l\u1ebb, l\u1edbn h\u01a1n ho\u1eb7c b\u1eb1ng 3 n\u00ean 2x + 3 = 7 <br\/> Hay 2x = 7 - 3 = 4 $\\Rightarrow$ x = 2 <br\/> <span class='basic_pink'> V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0: 2 <\/span> <br\/> <span class='basic_green'> <i> Nh\u1eadn x\u00e9t: Khi gi\u1ea3i to\u00e1n \u01b0\u1edbc v\u00e0 b\u1ed9i, ta th\u01b0\u1eddng x\u00e9t t\u00ednh ch\u1eb5n l\u1ebb v\u00e0 ph\u1ea1m vi gi\u00e1 tr\u1ecb c\u00e1c s\u1ed1. Trong v\u00ec d\u1ee5 tr\u00ean, 2x + 3 l\u00e0 s\u1ed1 l\u1ebb, v\u00ec x l\u00e0 s\u1ed1 t\u1ef1 nhi\u00ean n\u00ean 2x + 3 $\\geq$ 0. Vi\u1ec7c \u0111\u00f3 gi\u00fap s\u1ed1 tr\u01b0\u1eddng h\u1ee3p c\u1ee7a b\u00e0i to\u00e1n gi\u1ea3m \u0111i \u0111\u00e1ng k\u1ec3. <\/i> <\/span> "}]}],"id_ques":1774},{"time":24,"part":[{"title":"\u0110i\u1ec1n \u0111\u00e1p \u00e1n \u0111\u00fang v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["45"]]],"list":[{"point":5,"width":50,"type_input":"","ques":"T\u00ecm s\u1ed1 t\u1ef1 nhi\u00ean a, bi\u1ebft r\u1eb1ng chia 332 cho a th\u00ec d\u01b0 17, c\u00f2n khi chia 555 cho a th\u00ec \u0111\u01b0\u1ee3c d\u01b0 l\u00e0 15. <br\/> V\u1eady a = _input_ ","hint":"Quy v\u1ec1 b\u00e0i to\u00e1n t\u00ecm a bi\u1ebft 332 - 17 $\\vdots$ a v\u00e0 555 - 15 $\\vdots$ a ","explain":" <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> V\u00ec 332 chia a d\u01b0 17 n\u00ean (a > 17) v\u00e0 (332 - 17) $\\vdots$ a hay 315 $\\vdots$ a (1) <br\/> V\u00ec 555 chia d\u01b0 15 n\u00ean a > 15 v\u00e0 (555 - 15) $\\vdots$ a hay 540 $\\vdots$ a (2) <br\/> T\u1eeb (1) v\u00e0 (2) $\\Rightarrow$ a $\\in$ \u01afC(315; 540) <br\/> Ta c\u00f3: $315 = 3^2 . 5 . 7$; $540 = 2^2 . 3^3 . 5$ <br\/> V\u00ec \u01afCLN(315; 540) = 45 do \u0111\u00f3 \u01afC(315; 540) = \u01af(45) = {1; 3; 5; 9; 15; 45} <br\/> V\u00ec a > 17 n\u00ean a = 45 <br\/> V\u1eady a = 45 <br\/> <span class='basic_pink'> V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0: 45 <\/span> "}]}],"id_ques":1775},{"time":24,"part":[{"title":"\u0110i\u1ec1n \u0111\u00e1p \u00e1n \u0111\u00fang v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["1890"]]],"list":[{"point":5,"width":50,"type_input":"","ques":"BCNN(270; 135; 35) = _input_ ","hint":"","explain":" <span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1: <\/b> Ph\u00e2n t\u00edch c\u00e1c s\u1ed1 270; 135; 35 ra th\u1eeba s\u1ed1 nguy\u00ean t\u1ed1 <br\/> <b> B\u01b0\u1edbc 2: <\/b> Ch\u1ecdn ra c\u00e1c th\u1eeba s\u1ed1 nguy\u00ean t\u1ed1 chung v\u00e0 ri\u00eang <br\/> <b> B\u01b0\u1edbc 3: <\/b> L\u1eadp t\u00edch c\u00e1c th\u1eeba s\u1ed1 nguy\u00ean t\u1ed1 chung v\u00e0 ri\u00eang c\u1ee7a 270; 135; 35 m\u1ed7i th\u1eeba s\u1ed1 l\u1ea5y v\u1edbi s\u1ed1 m\u0169 l\u1edbn nh\u1ea5t c\u1ee7a n\u00f3 <\/span> <br\/><br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> V\u00ec 270 $\\vdots$ 135 <br\/> $270 = 2 . 3^3 . 5$; $35 = 5 . 7$ <br\/> BCNN(270; 135; 35) = $2 . 3^3 . 5 . 7 = 1890$ <br\/> <span class='basic_pink'> V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0: 1890 <\/span> "}]}],"id_ques":1776},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c $\\dfrac{4^6 . 9^5 + 6^9 . 120}{8^4 . 3^{12} - 6^{11}}$ ","select":["A. $\\dfrac{3}{4}$ ","B. $\\dfrac{2}{3}$ ","C. $\\dfrac{1}{3}$ ","D. $\\dfrac{4}{5}$ "],"hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> Vi\u1ebft m\u1ed7i l\u0169y th\u1eeba tr\u00ean th\u00e0nh t\u00edch c\u00e1c l\u0169y th\u1eeba c\u00f3 c\u01a1 s\u1ed1 l\u00e0 s\u1ed1 nguy\u00ean t\u1ed1 sau \u0111\u00f3 \u0111\u1eb7t c\u00e1c nh\u00e2n t\u1eed chung ra ngo\u00e0i, t\u00ednh v\u00e0 r\u00fat g\u1ecdn m\u1ed9t c\u00e1ch h\u1ee3p l\u00fd <br\/><br\/><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span> <br\/> Ta c\u00f3: <br\/> $\\dfrac{4^6 . 9^5 + 6^9 . 120}{8^4 . 3^{12} - 6^{11}} \\\\ = \\dfrac{(2^2)^6 . (3^2)^5 + (2 . 3)^9 . (2^3 . 3 . 5)}{(2^3)^4 . 3^{12} - (2 . 3)^{11}} \\\\ = \\dfrac{2^{12} . 3^{10} + 2^9 . 3^9 . 2^3 . 3 . 5}{2^{12} . 3^{12} - 2^{11} . 3^{11}} \\\\ = \\dfrac{2^{12} . 3^{10} + 2^{12} . 3^{10} . 5}{2^{12} . 3^{12} - 2^{11} . 3^{11}} \\\\ = \\dfrac{2^{12} . 3^{10} . ( 1 + 5)}{2^{11} . 3^{11} . (2 . 3 - 1)} \\\\ = \\dfrac{2 . 6}{3 . 5} \\\\ = \\dfrac{12}{15} \\\\ = \\dfrac{4}{5} $ <br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0: D <\/span> ","column":2}]}],"id_ques":1777},{"time":24,"part":[{"title":"\u0110i\u1ec1n \u0111\u00e1p \u00e1n \u0111\u00fang v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["-30"]]],"list":[{"point":5,"width":50,"type_input":"","ques":"T\u1ed5ng t\u1ea5t c\u1ea3 c\u00e1c s\u1ed1 nguy\u00ean x th\u1ecfa m\u00e3n $-8 \\leq x \\leq 3$ l\u00e0: _input_ ","hint":"","explain":" <span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1: <\/b> Li\u1ec7t k\u00ea c\u00e1c s\u1ed1 t\u1ef1 nhi\u00ean x th\u1ecfa m\u00e3n $-8 \\leq x \\leq 3$ <br\/> <b> B\u01b0\u1edbc 2: <\/b> T\u00ednh t\u1ed5ng c\u00e1c s\u1ed1 t\u1ef1 nhi\u00ean x <br\/><br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> C\u00e1c s\u1ed1 nguy\u00ean x th\u1ecfa m\u00e3n $-8 \\leq x \\leq 3$ l\u00e0: -8; -7; -6; -5; -4; -3; -2; -1; 0; 1; 2; 3 <br\/> T\u1ed5ng l\u00e0: <br\/> -8 + (-7) + (-6) + (-5) + (-4) + (-3) + (-2) + (-1) + 0 + 1 + 2 + 3 <br\/> = -8 + (-7) + (-6) + (-5) + (-4) + (-3 + 3) + (-2 + 2) + (-1 + 1) + 0 <br\/> = -30 <br\/> <span class='basic_pink'> V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0: -30 <\/span> "}]}],"id_ques":1778},{"time":24,"part":[{"title":"\u0110i\u1ec1n \u0111\u00e1p \u00e1n \u0111\u00fang v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank_random","correct":[[["1"],["3"]]],"list":[{"point":5,"width":50,"type_input":"","ques":"T\u00ecm s\u1ed1 t\u1ef1 nhi\u00ean n th\u1ecfa m\u00e3n $(15 - 4n) \\vdots n$ (v\u1edbi n < 4) <br\/> V\u1eady n = _input_ ho\u1eb7c n = _input_ ","hint":"","explain":" <span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> D\u1ef1a v\u00e0o t\u00ednh ch\u1ea5t chia h\u1ebft c\u1ee7a m\u1ed9t hi\u1ec7u \u0111\u1ec3 t\u00ecm n <br\/><br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> V\u00ec 4n $\\vdots$ n n\u00ean \u0111\u1ec3 $(15 - 4n)$ $\\vdots$ n th\u00ec 15 $\\vdots$ n <br\/> Hay n $\\in$ \u01af(15) = {1; 3; 5; 15} <br\/> V\u00ec n < 4 n\u00ean n = 1 ho\u1eb7c n = 3 <br\/> <span class='basic_pink'> V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0: 1; 3 <\/span> "}]}],"id_ques":1779},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"T\u00ecm hai s\u1ed1, bi\u1ebft r\u1eb1ng $\\dfrac{9}{11}$ c\u1ee7a s\u1ed1 n\u00e0y b\u1eb1ng $\\dfrac{6}{7}$ c\u1ee7a s\u1ed1 kia v\u00e0 t\u1ed5ng c\u1ee7a hai s\u1ed1 \u0111\u00f3 b\u1eb1ng 258. <br\/> Hai s\u1ed1 \u0111\u00f3 l\u00e0: ","select":["A. 132; 126 ","B. 124; 134 ","C. 138; 120 ","D. 127; 131 "],"hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1: <\/b> G\u1ecdi hai s\u1ed1 c\u1ea7n t\u00ecm l\u00e0 a, b <br\/> <b> B\u01b0\u1edbc 2: <\/b> D\u1ef1a v\u00e0o d\u1eef li\u1ec7u c\u1ee7a \u0111\u1ec1 b\u00e0i l\u1eadp t\u1ec9 s\u1ed1 c\u1ee7a hai s\u1ed1 <br\/> <b> B\u01b0\u1edbc 3: <\/b> K\u1ebft h\u1ee3p a + b = 258, b\u00e0i to\u00e1n \u0111\u01b0a v\u1ec1 b\u00e0i to\u00e1n t\u00ecm hai s\u1ed1 bi\u1ebft t\u1ed5ng v\u00e0 t\u1ec9 <br\/><br\/><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span> <br\/> G\u1ecdi hai s\u1ed1 c\u1ea7n t\u00ecm l\u00e0 a v\u00e0 b <br\/> V\u00ec $\\dfrac{9}{11}$ c\u1ee7a s\u1ed1 n\u00e0y b\u1eb1ng $\\dfrac{6}{7}$ c\u1ee7a s\u1ed1 kia n\u00ean $\\dfrac{9a}{11} = \\dfrac{6b}{7}$ hay $\\dfrac{18a}{22} = \\dfrac{18b}{21}$ $\\Rightarrow$ $\\dfrac{a}{b} = \\dfrac{22}{21}$ <br\/> L\u1ea1i c\u00f3: a + b = 258. B\u00e0i to\u00e1n t\u00ecm hai s\u1ed1 bi\u1ebft t\u1ed5ng v\u00e0 t\u1ec9 <br\/> a = 258 : (22 + 21) . 22 = 132; b = 258 - 132 = 126 <br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0: A. 132; 126 <\/span> ","column":2}]}],"id_ques":1780},{"time":24,"part":[{"title":"\u0110i\u1ec1n \u0111\u00e1p \u00e1n \u0111\u00fang v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["-51"],["120"]]],"list":[{"point":5,"width":50,"type_input":"","input_hint":["frac"],"ques":"T\u00ednh. <br\/><br\/> $\\dfrac{1,11 + 0,19 - 1,32}{2,06 + 0,34} - \\left( \\dfrac{1}{2} + \\dfrac{1}{3} \\right) : 2$ = <div class=\"frac123\"><div class=\"ts\">_input_<\/div><div class=\"ms\">_input_<\/div><\/div>","hint":"","explain":" <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> $\\begin{align*} & \\dfrac{1,11 + 0,19 - 1,32}{2,06 + 0,34} - \\left( \\dfrac{1}{2} + \\dfrac{1}{3} \\right) : 2 \\\\ &= \\dfrac{1,3 - 1,32}{2,4} - \\left( \\dfrac{3}{6} + \\dfrac{2}{6} \\right) : 2 \\\\ &= \\dfrac{-0,02}{2,4} - \\dfrac{5}{6} : 2 \\\\ &= \\dfrac{-2}{240} - \\dfrac{5}{12} \\\\ &= \\dfrac{-1}{120} - \\dfrac{50}{120} \\\\ &= \\dfrac{-51}{120} \\end{align*}$ "}]}],"id_ques":1781},{"time":24,"part":[{"title":"\u0110i\u1ec1n \u0111\u00e1p \u00e1n \u0111\u00fang v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["-4"],["13"]]],"list":[{"point":5,"width":50,"type_input":"","input_hint":["frac"],"ques":"T\u00ednh. <br\/><br\/> $1\\dfrac{13}{15} . 0,75 - \\left( \\dfrac{104}{195} + 0,25 \\right) . \\dfrac{24}{47} - 3\\dfrac{12}{13} : 3$ = <div class=\"frac123\"><div class=\"ts\">_input_<\/div><div class=\"ms\">_input_<\/div><\/div>","hint":"","explain":" <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> $\\begin{align*} & 1\\dfrac{13}{15} . 0,75 - \\left( \\dfrac{104}{195} + 0,25 \\right) . \\dfrac{24}{47} - 3\\dfrac{12}{13} : 3 \\\\ &= \\dfrac{28}{15} . \\dfrac{75}{100} - \\left( \\dfrac{104}{195} + \\dfrac{25}{100} \\right) . \\dfrac{24}{47} - \\dfrac{51}{13} : 3 \\\\ &= \\dfrac{7}{5} - \\dfrac{47}{60} . \\dfrac{24}{47} - \\dfrac{17}{13} \\\\ &= \\dfrac{7}{5} - \\dfrac{2}{5} - \\dfrac{17}{13} \\\\ &= \\dfrac{-4}{13} \\end{align*}$"}]}],"id_ques":1782},{"time":24,"part":[{"title":"\u0110i\u1ec1n \u0111\u00e1p \u00e1n \u0111\u00fang v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["24"]]],"list":[{"point":5,"width":50,"type_input":"","ques":"M\u1ed9t ng\u01b0\u1eddi mang 60 qu\u1ea3 tr\u1ee9ng \u0111i b\u00e1n. Ng\u01b0\u1eddi th\u1ee9 nh\u1ea5t mua $\\dfrac{4}{15}$ s\u1ed1 tr\u1ee9ng. Ng\u01b0\u1eddi th\u1ee9 hai mua m\u1ed9t s\u1ed1 tr\u1ee9ng b\u1eb1ng $\\dfrac{5}{4}$ s\u1ed1 tr\u1ee9ng m\u00e0 ng\u01b0\u1eddi th\u1ee9 nh\u1ea5t \u0111\u00e3 mua. T\u00ednh s\u1ed1 tr\u1ee9ng c\u00f2n l\u1ea1i. <br\/> \u0110\u00e1p s\u1ed1: _input_ qu\u1ea3 tr\u1ee9ng ","hint":"","explain":" <span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1: <\/b> T\u00ednh s\u1ed1 tr\u1ee9ng ng\u01b0\u1eddi th\u1ee9 nh\u1ea5t \u0111\u00e3 mua <br\/> <b> B\u01b0\u1edbc 2: <\/b> T\u00ednh s\u1ed1 tr\u1ee9ng ng\u01b0\u1eddi th\u1ee9 hai \u0111\u00e3 mua <br\/> <b> B\u01b0\u1edbc 3: <\/b> T\u00ednh s\u1ed1 tr\u1ee9ng c\u00f2n l\u1ea1i <\/span> <br\/><br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> S\u1ed1 tr\u1ee9ng ng\u01b0\u1eddi th\u1ee9 nh\u1ea5t \u0111\u00e3 mua: <br\/> $60 . \\dfrac{4}{15} = 16$ (qu\u1ea3 tr\u1ee9ng) <br\/> S\u1ed1 tr\u1ee9ng ng\u01b0\u1eddi th\u1ee9 hai \u0111\u00e3 mua l\u00e0: <br\/> $16 . \\dfrac{5}{4} = 20$ (qu\u1ea3 tr\u1ee9ng) <br\/> S\u1ed1 tr\u1ee9ng c\u00f2n l\u1ea1i l\u00e0: <br\/> 60 - 16 - 20 = 24 (qu\u1ea3 tr\u1ee9ng) <br\/> \u0110\u00e1p s\u1ed1: 24 qu\u1ea3 tr\u1ee9ng <br\/> <span class='basic_pink'> V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0: 24 <\/span> "}]}],"id_ques":1783},{"time":24,"part":[{"title":"\u0110i\u1ec1n \u0111\u00e1p \u00e1n \u0111\u00fang v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["30"]]],"list":[{"point":5,"width":50,"type_input":"","ques":" Ba \u0111\u00e1m ru\u1ed9ng thu ho\u1ea1ch \u0111\u01b0\u1ee3c m\u1ed9t s\u1ed1 th\u00f3c. S\u1ed1 th\u00f3c thu ho\u1ea1ch \u1edf \u0111\u00e1m th\u1ee9 nh\u1ea5t chi\u1ebfm $\\dfrac{2}{5}$ t\u1ed5ng s\u1ed1 th\u00f3c. S\u1ed1 th\u00f3c thu ho\u1ea1ch \u1edf \u0111\u00e1m th\u1ee9 hai b\u1eb1ng $\\dfrac{4}{9}$ s\u1ed1 th\u00f3c c\u00f2n l\u1ea1i. Ri\u00eang \u0111\u00e1m th\u1ee9 ba thu ho\u1ea1ch \u0111\u01b0\u1ee3c 10 t\u1ea5n th\u00f3c. T\u00ednh s\u1ed1 th\u00f3c thu ho\u1ea1ch \u0111\u01b0\u1ee3c \u1edf c\u1ea3 ba \u0111\u00e1m ru\u1ed9ng. <br\/> \u0110\u00e1p s\u1ed1: _input_ t\u1ea5n th\u00f3c ","hint":"","explain":" <span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1: <\/b> T\u00ecm ph\u00e2n s\u1ed1 ch\u1ec9 s\u1ed1 th\u00f3c thu ho\u1ea1ch \u1edf \u0111\u00e1m th\u1ee9 hai v\u00e0 \u0111\u00e1m th\u1ee9 ba <br\/> <b> B\u01b0\u1edbc 2: <\/b> T\u00ecm ph\u00e2n s\u1ed1 ch\u1ec9 s\u1ed1 th\u00f3c thu ho\u1ea1ch \u1edf \u0111\u00e1m ru\u1ed9ng th\u1ee9 hai <br\/> <b> B\u01b0\u1edbc 3: <\/b> T\u00ecm ph\u00e2n s\u1ed1 ch\u1ec9 s\u1ed1 th\u00f3c thu ho\u1ea1ch \u1edf \u0111\u00e1m ru\u1ed9ng th\u1ee9 ba <br\/> <b> B\u01b0\u1edbc 4: <\/b> T\u00ednh s\u1ed1 th\u00f3c thu ho\u1ea1ch \u1edf c\u1ea3 ba \u0111\u00e1m ru\u1ed9ng <\/span> <br\/><br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> Ph\u00e2n s\u1ed1 ch\u1ec9 s\u1ed1 th\u00f3c thu ho\u1ea1c \u1edf \u0111\u00e1m ru\u1ed9ng th\u1ee9 hai v\u00e0 th\u1ee9 ba l\u00e0: <br\/> $1 - \\dfrac{2}{5} = \\dfrac{3}{5}$ (t\u1ed5ng s\u1ed1 th\u00f3c) <br\/> Ph\u00e2n s\u1ed1 ch\u1ec9 s\u1ed1 th\u00f3c thu ho\u1ea1ch \u1edf \u0111\u00e1m ru\u1ed9ng th\u1ee9 hai l\u00e0: <br\/> $\\dfrac{4}{9} . \\dfrac{3}{5} = \\dfrac{4}{15}$ (t\u1ed5ng s\u1ed1 th\u00f3c) <br\/> Ph\u00e2n s\u1ed1 ch\u1ec9 s\u1ed1 th\u00f3c thu ho\u1ea1ch \u1edf \u0111\u00e1m ru\u1ed9ng th\u1ee9 ba l\u00e0: <br\/> $\\dfrac{3}{5} - \\dfrac{4}{15} = \\dfrac{1}{3}$ (t\u1ed5ng s\u1ed1 th\u00f3c) <br\/> T\u1ed5ng s\u1ed1 th\u00f3c thu ho\u1ea1ch \u1edf c\u1ea3 ba \u0111\u00e1m ru\u1ed9ng l\u00e0: <br\/> $10 : \\dfrac{1}{3} = 30$ (t\u1ea5n th\u00f3c) <br\/> \u0110\u00e1p s\u1ed1: 30 t\u1ea5n th\u00f3c <br\/> <span class='basic_pink'> V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0: 30 <\/span> "}]}],"id_ques":1784},{"time":24,"part":[{"title":"\u0110i\u1ec1n \u0111\u00e1p \u00e1n \u0111\u00fang v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["6"],["27"]]],"list":[{"point":5,"width":50,"type_input":"","ques":" T\u1ec9 s\u1ed1 gi\u1eefa g\u1ea1o n\u1ebfp v\u00e0 g\u1ea1o t\u1ebb trong m\u1ed9t c\u1eeda h\u00e0ng l\u00e0 $\\dfrac{2}{9}$. Sau khi b\u00e1n \u0111i 3 t\u1ea1 g\u1ea1o t\u1ebb th\u00ec t\u1ec9 s\u1ed1 gi\u1eefa g\u1ea1o n\u1ebfp v\u00e0 g\u1ea1o t\u1ebb l\u00e0 $\\dfrac{1}{4}$. H\u1ecfi l\u00fac \u0111\u1ea7u m\u1ed7i lo\u1ea1i g\u1ea1o c\u00f3 bao nhi\u00eau t\u1ea1? <br\/> \u0110\u00e1p s\u1ed1: G\u1ea1o n\u1ebfp _input_ t\u1ea1 <br\/> G\u1ea1o t\u1ebb: _input_ t\u1ea1 ","hint":"","explain":" <span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> V\u00ec s\u1ed1 g\u1ea1o n\u1ebfp kh\u00f4ng \u0111\u1ed5i n\u00ean ta t\u00ecm t\u1ec9 s\u1ed1 gi\u1eefa g\u1ea1o t\u1ebb v\u00e0 g\u1ea1o n\u1ebfp <br\/> <b> B\u01b0\u1edbc 1: <\/b> T\u00ecm t\u1ec9 s\u1ed1 gi\u1eefa g\u1ea1o t\u1ebb v\u00e0 g\u1ea1o n\u1ebfp l\u00fac \u0111\u1ea7u v\u00e0 sau khi b\u00e1n 3 t\u1ea1 g\u1ea1o t\u1ebb <br\/> <b> B\u01b0\u1edbc 2: <\/b> T\u00ecm ph\u00e2n s\u1ed1 ch\u1ec9 s\u1ed1 g\u1ea1o t\u1ebb \u0111\u00e3 gi\u1ea3m \u0111i <br\/> <b> B\u01b0\u1edbc 3: <\/b> T\u00ednh s\u1ed1 g\u1ea1o n\u1ebfp c\u1ee7a c\u1eeda h\u00e0ng <br\/> <b> B\u01b0\u1edbc 4: <\/b> T\u00ednh s\u1ed1 g\u1ea1o t\u1ebb c\u1ee7a c\u1eeda h\u00e0ng <\/span> <br\/><br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> V\u00ec s\u1ed1 g\u1ea1o n\u1ebfp kh\u00f4ng \u0111\u1ed5i n\u00ean ta so s\u00e1nh s\u1ed1 g\u1ea1o t\u1ebb v\u1edbi s\u1ed1 g\u1ea1o n\u1ebfp trong hai tr\u01b0\u1eddng h\u1ee3p <br\/> L\u00fac \u0111\u1ea7u s\u1ed1 g\u1ea1o t\u1ebb b\u1eb1ng $\\dfrac{9}{2}$ s\u1ed1 g\u1ea1o n\u1ebfp <br\/> V\u1ec1 sau, s\u1ed1 g\u1ea1o t\u1ebb b\u1eb1ng $\\dfrac{4}{1}$ s\u1ed1 g\u1ea1o n\u1ebfp <br\/> S\u1ed1 g\u1ea1o t\u1ebb gi\u1ea3m \u0111i b\u1eb1ng:<br\/> $\\dfrac{9}{2} - \\dfrac{4}{1} = \\dfrac{1}{2}$ (s\u1ed1 g\u1ea1o n\u1ebfp) hay 3 t\u1ea1 <br\/> S\u1ed1 g\u1ea1o n\u1ebfp c\u00f3 l\u00e0: <br\/> $3 : \\dfrac{1}{2} = 6$ (t\u1ea1) <br\/> S\u1ed1 g\u1ea1o t\u1ebb c\u00f3 l\u00e0: <br\/> $6 . \\dfrac{9}{2} = 27$ (t\u1ea1) <br\/> \u0110\u00e1p s\u1ed1: G\u1ea1o n\u1ebfp: 6 t\u1ea1 <br\/> G\u1ea1o t\u1ebb: 27 t\u1ea1 <br\/> <span class='basic_pink'> V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0: 6; 27 <\/span> "}]}],"id_ques":1785},{"time":24,"part":[{"title":"\u0110i\u1ec1n \u0111\u00e1p \u00e1n \u0111\u00fang v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["16"],["99"]]],"list":[{"point":5,"width":50,"ques":"T\u00ednh nhanh. <br\/><br\/> $\\dfrac{1}{3 . 5} + \\dfrac{1}{5 . 7} + ... + \\dfrac{1}{97 . 99}$ = <div class=\"frac123\"><div class=\"ts\">_input_<\/div><div class=\"ms\">_input_<\/div><\/div>","hint":"\u00c1p d\u1ee5ng c\u00f4ng th\u1ee9c $\\dfrac{a}{n . (n + a)} = \\dfrac{1}{n} - \\dfrac{1}{n + a}$ ","explain":" <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> $\\begin{align*} & \\dfrac{1}{3 . 5} + \\dfrac{1}{5 . 7} + ... + \\dfrac{1}{97 . 99} \\\\ &= \\dfrac{1}{2} . \\left( \\dfrac{2}{3 . 5} + \\dfrac{2}{5 . 7} + ... + \\dfrac{2}{97 . 99} \\right) \\\\ &= \\dfrac{1}{2} . \\left( \\dfrac{1}{3} - \\dfrac{1}{5} + \\dfrac{1}{5} - \\dfrac{1}{7} + ... + \\dfrac{1}{97} - \\dfrac{1}{99} \\right) \\\\ &= \\dfrac{1}{2} . \\left( \\dfrac{1}{3} - \\dfrac{1}{99} \\right) \\\\ &= \\dfrac{1}{2} . \\dfrac{32}{99} \\\\ &= \\dfrac{16}{99} \\end{align*}$ "}]}],"id_ques":1786},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"Cho $A = \\dfrac{1}{11^2} + \\dfrac{1}{12^2} + \\dfrac{1}{13^2} + \\dfrac{1}{14^2} + ... + \\dfrac{1}{20^2}$ <br\/> <br\/> Kh\u1eb3ng \u0111\u1ecbnh n\u00e0o sau \u0111\u00e2y \u0111\u00fang? ","select":["A. $A > \\dfrac{1}{10}$ ","B. $A < \\dfrac{1}{10}$","C. $A = \\dfrac{1}{10}$ "],"hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> So s\u00e1nh $\\dfrac{1}{a^2}$ v\u1edbi $\\dfrac{1}{(a - 1) . a}$ r\u1ed3i so s\u00e1nh A v\u1edbi t\u1ed5ng c\u00e1c ph\u00e2n s\u1ed1.... <br\/><br\/><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span> <br\/> Ta c\u00f3: <br\/> $\\dfrac{1}{11^2} < \\dfrac{1}{10 . 11}$ <br\/> $\\dfrac{1}{12^2} < \\dfrac{1}{11 . 12}$ <br\/> ....... <br\/> $\\dfrac{1}{20^2} < \\dfrac{1}{19 . 20}$ <br\/> $\\Rightarrow A < \\dfrac{1}{10 . 11} + \\dfrac{1}{11 . 12} + \\dfrac{1}{12 . 13} + ... + \\dfrac{1}{19 . 20} \\\\ A < \\dfrac{1}{10} - \\dfrac{1}{11} + \\dfrac{1}{11} - \\dfrac{1}{12} + \\dfrac{1}{12} - \\dfrac{1}{13} + ... + \\dfrac{1}{19} - \\dfrac{1}{20} \\\\ A < \\dfrac{1}{10} - \\dfrac{1}{20} \\\\ A < \\dfrac{1}{10}$ <br\/> Hay $\\dfrac{1}{11^2} + \\dfrac{1}{12^2} + \\dfrac{1}{13^2} + \\dfrac{1}{14^2} + ... + \\dfrac{1}{20^2} < \\dfrac{1}{10}$ <br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0: B <\/span> ","column":3}]}],"id_ques":1787},{"time":24,"part":[{"title":"\u0110i\u1ec1n \u0111\u00e1p \u00e1n \u0111\u00fang v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["16"]]],"list":[{"point":5,"width":50,"type_input":"","ques":" Trong m\u1ed9t l\u1edbp h\u1ecdc c\u00f3 ph\u1ea7n th\u01b0\u1edfng c\u1ee7a t\u1ed5ng k\u1ebft k\u00ec I bao g\u1ed3m: 128 quy\u1ec3n v\u1edf, 48 b\u00fat ch\u00ec v\u00e0 192 t\u1eadp gi\u1ea5y. H\u1ecfi chia \u0111\u01b0\u1ee3c nhi\u1ec1u nh\u1ea5t bao nhi\u00eau ph\u1ea7n th\u01b0\u1edfng nh\u01b0 nhau? <br\/> \u0110\u00e1p s\u1ed1: _input_ ph\u1ea7n th\u01b0\u1edfng ","hint":"","explain":" <span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1: <\/b> G\u1ecdi s\u1ed1 ph\u1ea7n th\u01b0\u1edfng nhi\u1ec1u nh\u1ea5t chia \u0111\u01b0\u1ee3c l\u00e0 x (x > 0) <br\/> <b> B\u01b0\u1edbc 2: <\/b> T\u00ecm x, v\u00ec x l\u00e0 s\u1ed1 ph\u1ea7n th\u01b0\u1edfng chia \u0111\u01b0\u1ee3c n\u00ean 128 $\\vdots$ x; 48 $\\vdots$ x v\u00e0 192 $\\vdots$ x <\/span> <br\/><br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> G\u1ecdi s\u1ed1 ph\u1ea7n th\u01b0\u1edfng nhi\u1ec1u nh\u1ea5t chia \u0111\u01b0\u1ee3c l\u00e0 x (x > 0) <br\/> V\u00ec x l\u00e0 s\u1ed1 ph\u1ea7n th\u01b0\u1edfng chia \u0111\u01b0\u1ee3c n\u00ean 128 $\\vdots$ x; 18 $\\vdots$ x v\u00e0 192 $\\vdots$ x <br\/> V\u00e0 v\u00ec x l\u1edbn nh\u1ea5t n\u00ean x = \u01afCLN(128; 48; 192) <br\/> V\u00ec $128 = 2^7$; $48 = 2^4 . 3$; $192 = 2^6 . 3$ <br\/> $\\Rightarrow$ x = \u01afCLN(128; 48; 192) = $2^4 = 16$ <br\/> V\u1eady chia \u0111\u01b0\u1ee3c nhi\u1ec1u nh\u1ea5t 16 ph\u1ea7n th\u01b0\u1edfng nh\u01b0 nhau <br\/> <span class='basic_pink'> V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0: 16 <\/span> "}]}],"id_ques":1788},{"time":24,"part":[{"title":"\u0110i\u1ec1n \u0111\u00e1p \u00e1n \u0111\u00fang v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["6"]]],"list":[{"point":5,"width":50,"type_input":"","ques":" Ch\u1eef s\u1ed1 t\u1eadn c\u00f9ng c\u1ee7a $16^{1991}$ l\u00e0: _input_ ","hint":"","explain":" <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> Ta c\u00f3: <br\/> $16^{1991}$ c\u00f3 ch\u1eef s\u1ed1 t\u1eadn c\u00f9ng l\u00e0 ch\u1eef s\u1ed1 t\u1eadn c\u00f9ng c\u1ee7a $6^{1991}$ <br\/> V\u00ec 6 n\u00e2ng l\u00ean l\u0169y th\u1eeba bao nhi\u00eau c\u0169ng c\u00f3 ch\u1eef s\u1ed1 t\u1eadn c\u00f9ng l\u00e0 6 <br\/> N\u00ean $6^{1991}$ c\u00f3 ch\u1eef s\u1ed1 t\u1eadn c\u00f9ng l\u00e0 6 <br\/> $\\Rightarrow$ $16^{1991}$ c\u00f3 ch\u1eef s\u1ed1 t\u1eadn c\u00f9ng l\u00e0 6 <br\/> <span class='basic_pink'> V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0: 6 <\/span> "}]}],"id_ques":1789},{"time":24,"part":[{"title":"\u0110i\u1ec1n \u0111\u00e1p \u00e1n \u0111\u00fang v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["301"]]],"list":[{"point":5,"width":50,"type_input":"","ques":" Cho d\u00e3y s\u1ed1 4, 7, 10, 13, 16.... <br\/> Ch\u1eef s\u1ed1 th\u1ee9 100 c\u1ee7a d\u00e3y l\u00e0: _input_ ","hint":"T\u00ecm m\u1ed1i li\u00ean quan gi\u1eefa s\u1ed1 h\u1ea1ng sau v\u00e0 s\u1ed1 h\u1ea1ng tr\u01b0\u1edbc t\u1eeb \u0111\u00f3 t\u00ecm quy lu\u1eadt c\u1ee7a d\u00e3y s\u1ed1 sau \u0111\u00f3 t\u00ecm s\u1ed1 h\u1ea1ng th\u1ee9 100","explain":" <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> Ta c\u00f3: <br\/>S\u1ed1 h\u1ea1ng th\u1ee9 nh\u1ea5t: 3 . 1 + 1 = 4 <br\/> S\u1ed1 h\u1ea1ng th\u1ee9 2: 3 . 2 + 1 = 7 <br\/> S\u1ed1 h\u1ea1ng th\u1ee9 3: 3 . 3 + 1 = 10 <br\/> S\u1ed1 h\u1ea1ng th\u1ee9 4: 3 . 4 + 1 = 13 <br\/> ..... <br\/> S\u1ed1 h\u1ea1ng th\u1ee9 n: 3 . n + 1 <br\/> V\u1eady s\u1ed1 h\u1ea1ng th\u1ee9 100 c\u1ee7a d\u00e3y l\u00e0: <br\/> 3 . 100 + 1 = 301 <br\/> <span class='basic_pink'> V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0: 301 <\/span> "}]}],"id_ques":1790}],"lesson":{"save":0,"level":2}}