{"segment":[{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["12"]]],"list":[{"point":10,"width":50,"content":"","type_input":"","ques":"Tr\u00ean tia Oa v\u1ebd \u0111o\u1ea1n th\u1eb3ng OM = 6cm, ON = 14cm. Tr\u00ean tia \u0111\u1ed1i c\u1ee7a tia Oa v\u1ebd OK = 10cm. G\u1ecdi U, V t\u01b0\u01a1ng \u1ee9ng l\u00e0 trung \u0111i\u1ec3m c\u1ee7a c\u00e1c \u0111o\u1ea1n MN, MK. <br\/> Khi \u0111\u00f3 UV = _input_ cm","hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1: <\/b> T\u00ednh MN = ? <br\/> <b> B\u01b0\u1edbc 2: <\/b> T\u00ednh MU = ? <br\/> <b> B\u01b0\u1edbc 3: <\/b> T\u00ednh MK = ? <br\/> <b> B\u01b0\u1edbc 4: <\/b> T\u00ednh MV = ? <br\/> <b> B\u01b0\u1edbc 5: <\/b> T\u00ednh UV = ? <\/span> <br\/><br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop6/toan/hinhhoc/bai7/lv3/img\/H617_K101.png' \/><\/center> <br\/> Tr\u00ean tia Oa c\u00f3: OM = 6cm, ON = 14cm <br\/> V\u00ec 6cm < 14cm n\u00ean OM < ON n\u00ean \u0111i\u1ec3m M n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m O v\u00e0 N <br\/> $\\begin{align*} \\Rightarrow OM + MN &= ON \\\\ 6cm + MN &= 14cm \\\\ MN &= 14cm - 6cm \\\\ MN &= 8cm \\end{align*}$ <br\/> V\u00ec \u0111i\u1ec3m U l\u00e0 trung \u0111i\u1ec3m c\u1ee7a \u0111o\u1ea1n th\u1eb3ng MN n\u00ean: <br\/> $MU = UN = \\dfrac{MN}{2} = \\dfrac{8cm}{2} = 4cm$ <br\/> V\u00ec tia Oa v\u00e0 tia OK l\u00e0 hai tia \u0111\u1ed1i nhau <br\/> \u0110i\u1ec3m M thu\u1ed9c tia OA n\u00ean OM v\u00e0 OK l\u00e0 hai tia \u0111\u1ed1i nhau <br\/> $\\Rightarrow$ \u0110i\u1ec3m O n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m M v\u00e0 K <br\/> $\\begin{align*} \\Rightarrow MK &= OM + OK \\\\ MK &= 6cm + 10cm \\\\ MK &= 16cm \\end{align*}$ <br\/> V\u00ec \u0111i\u1ec3m V l\u00e0 trung \u0111i\u1ec3m c\u1ee7a \u0111o\u1ea1n th\u1eb3ng MK n\u00ean: <br\/> $VK = VM = \\dfrac{MK}{2} = \\dfrac{16cm}{2} = 8cm$ <br\/> V\u00ec \u0111i\u1ec3m M v\u00e0 \u0111i\u1ec3m U thu\u1ed9c tia Oa m\u00e0 U l\u00e0 trung \u0111i\u1ec3m c\u1ee7a \u0111o\u1ea1n th\u1eb3ng MN <br\/> N\u00ean \u0111i\u1ec3m M n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m O v\u00e0 U (1) <br\/> M\u00e0 \u0111i\u1ec3m V thu\u1ed9c tia OK (2) <br\/> Oa v\u00e0 OK l\u00e0 hai tia \u0111\u1ed1i nhau (3) <br\/> T\u1eeb (1), (2) v\u00e0 (3) $\\Rightarrow$ \u0111i\u1ec3m M n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m U v\u00e0 V <br\/> $\\begin{align*} \\Rightarrow UV &= MU + MV \\\\ UV &= 4cm + 8cm \\\\ UV &= 12cm \\end{align*}$ <br\/> <span class='basic_pink'> V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0: 12 <\/span>"}]}],"id_ques":2061},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["5"]]],"list":[{"point":10,"width":50,"content":"","type_input":"","ques":"Cho \u0111o\u1ea1n th\u1eb3ng PQ = 16cm, \u0111i\u1ec3m I n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m P v\u00e0 Q; PI = 5cm. \u0110i\u1ec3m M n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m I, Q sao cho IM = 8cm. G\u1ecdi O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a \u0111o\u1ea1n th\u1eb3ng PQ. <br\/> Khi \u0111\u00f3 \u0111\u1ed9 d\u00e0i \u0111o\u1ea1n th\u1eb3ng OM = _input_ cm","hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1: <\/b> T\u00ednh IQ = ? <br\/> <b> B\u01b0\u1edbc 2: <\/b> T\u00ednh MQ = ? <br\/> <b> B\u01b0\u1edbc 3: <\/b> T\u00ednh OQ = ? <br\/> <b> B\u01b0\u1edbc 4: <\/b> T\u00ednh OM = ? <\/span> <br\/><br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop6/toan/hinhhoc/bai7/lv3/img\/H617_K102.png' \/><\/center> <br\/> V\u00ec \u0111i\u1ec3m I n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m P v\u00e0 Q n\u00ean: <br\/> $\\begin{align*} \\Rightarrow PI + IQ &= PQ \\\\ 5cm + IQ &= 16cm \\\\ IQ &= 16cm - 5cm \\\\ IQ &= 11cm \\end{align*}$ <br\/> V\u00ec \u0111i\u1ec3m M n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m I v\u00e0 Q n\u00ean: <br\/> $\\begin{align*} \\Rightarrow IM + MQ &= IQ \\\\ 8cm + MQ &= 11cm \\\\ MQ &= 11cm - 8cm \\\\ MQ &= 3cm \\end{align*}$ <br\/> V\u00ec \u0111i\u1ec3m O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a \u0111o\u1ea1n th\u1eb3ng PQ n\u00ean: <br\/> $OP = OQ = \\dfrac{PQ}{2} = \\dfrac{16cm}{2} = 8cm$ <br\/> V\u00ec QM = 3cm, QO = 8cm m\u00e0 3cm < 8cm n\u00ean QM < QO <br\/> N\u00ean \u0111i\u1ec3m M n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m O v\u00e0 Q <br\/> $\\begin{align*} \\Rightarrow OM + MQ &= OQ \\\\ OM + 3cm &= 8cm \\\\ OM &= 8cm - 3cm \\\\ OM &= 5cm \\end{align*}$ <br\/> <span class='basic_pink'> V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0: 5 <\/span>"}]}],"id_ques":2062},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":10,"ques":"Bu\u1ed5i h\u1ecdp m\u1eb7t c\u1ee7a m\u1ed9t nh\u00f3m h\u1ecdc sinh g\u1ed3m 6 b\u1ea1n. M\u1ed7i b\u1ea1n \u0111\u1ec1u b\u1eaft tay b\u1ea1n kh\u00e1c m\u1ed9t l\u1ea7n. H\u1ecfi c\u00f3 bao nhi\u00eau c\u00e1i b\u1eaft tay?","select":["A. 6","B. 12","C. 15","D. 30"],"hint":"","explain":" <span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/>T\u00ednh s\u1ed1 \u0111\u01b0\u1eddng th\u1eb3ng v\u1ebd \u0111\u01b0\u1ee3c theo c\u00f4ng th\u1ee9c <br\/> $\\dfrac{n . (n - 1)}{2}$ <\/span> <br\/><br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span> <br\/> V\u00ec m\u1ed7i ng\u01b0\u1eddi \u0111\u1ec1u b\u1eaft tay m\u1ed9t b\u1ea1n kh\u00e1c m\u1ed9t l\u1ea7n n\u00ean m\u1ed7i b\u1ea1n s\u1ebd b\u1eaft tay 5 b\u1ea1n kh\u00e1c \u0111\u01b0\u1ee3c 5 c\u00e1i b\u1eaft tay <br\/> Nh\u01b0ng m\u1ed7i c\u00e1i b\u1eaft tay \u0111\u00e3 \u0111\u01b0\u1ee3c t\u00ednh hai l\u1ea7n <br\/> N\u00ean t\u1ea5t c\u1ea3 c\u00f3 s\u1ed1 c\u00e1i b\u1eaft tay l\u00e0: <br\/> $\\dfrac{6 . 5}{2} = 15$ (c\u00e1i b\u1eaft tay) <br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0: C <\/span> ","column":2}]}],"id_ques":2063},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":10,"ques":"Cho c\u00e1c \u0111i\u1ec3m b\u1ea5t k\u00ec M, N, P, Q, E, F, O trong \u0111\u00f3 kh\u00f4ng c\u00f3 3 \u0111i\u1ec3m n\u00e0o th\u1eb3ng h\u00e0ng. C\u1ee9 qua 2 \u0111i\u1ec3m x\u00e1c \u0111\u1ecbnh \u0111\u01b0\u1ee3c m\u1ed9t \u0111o\u1ea1n th\u1eb3ng. H\u1ecfi v\u1ebd \u0111\u01b0\u1ee3c t\u1ea5t c\u1ea3 bao nhi\u00eau \u0111o\u1ea1n th\u1eb3ng?","select":["A. 20 \u0111o\u1ea1n th\u1eb3ng","B. 21 \u0111o\u1ea1n th\u1eb3ng","C. 14 \u0111o\u1ea1n th\u1eb3ng","D. 42 \u0111o\u1ea1n th\u1eb3ng"],"hint":"","explain":" <span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/>T\u00ednh s\u1ed1 \u0111\u01b0\u1eddng th\u1eb3ng v\u1ebd \u0111\u01b0\u1ee3c theo c\u00f4ng th\u1ee9c <br\/> $\\dfrac{n . (n - 1)}{2}$ <\/span> <br\/><br\/><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span> <br\/> V\u00ec c\u00f3 7 \u0111i\u1ec3m M, N, P, Q, E, F, O trong \u0111\u00f3 kh\u00f4ng c\u00f3 3 \u0111i\u1ec3m n\u00e0o th\u1eb3ng h\u00e0ng <br\/> M\u1ed7i \u0111i\u1ec3m n\u1ed1i v\u1edbi m\u1ed9t \u0111i\u1ec3m kh\u00e1c \u0111\u01b0\u1ee3c m\u1ed9t \u0111o\u1ea1n th\u1eb3ng <br\/> N\u00ean t\u1ea5t c\u1ea3 v\u1ebd \u0111\u01b0\u1ee3c s\u1ed1 \u0111o\u1ea1n th\u1eb3ng l\u00e0: <br\/> $\\dfrac{7 . 6}{2} = 21$ (\u0111o\u1ea1n th\u1eb3ng) <br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0: B <\/span> ","column":2}]}],"id_ques":2064},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":10,"ques":"Tr\u00ean \u0111\u01b0\u1eddng th\u1eb3ng a cho 4 \u0111i\u1ec3m A, B, C, D theo th\u1ee9 t\u1ef1 \u0111\u00f3. Kh\u1eb3ng \u0111\u1ecbnh n\u00e0o sau \u0111\u00e2y sai","select":["A. AB v\u00e0 AC l\u00e0 hai tia tr\u00f9ng nhau","B. BC v\u00e0 CB l\u00e0 hai tia \u0111\u1ed1i nhau","C. AB v\u00e0 AD l\u00e0 hai tia tr\u00f9ng nhau","D. CA v\u00e0 CD l\u00e0 hai tia \u0111\u1ed1i nhau"],"hint":"","explain":" <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop6/toan/hinhhoc/bai7/lv3/img\/H617_K105.png' \/><\/center><\/span><br\/> Quan s\u00e1t h\u00ecnh v\u1ebd ta c\u00f3: <br\/> +) Tia AB v\u00e0 tia AC c\u00f3 chung g\u1ed1c A v\u00e0 c\u00f9ng thu\u1ed9c m\u1ed9t n\u1eeda \u0111\u01b0\u1eddng th\u1eb3ng <br\/> N\u00ean AB v\u00e0 AC l\u00e0 hai tia tr\u00f9ng nhau <br\/> +) Tia AB v\u00e0 tia AD c\u00f3 chung g\u1ed1c A v\u00e0 c\u00f9ng thu\u1ed9c m\u1ed9t n\u1eeda \u0111\u01b0\u1eddng th\u1eb3ng <br\/> N\u00ean AB v\u00e0 AD l\u00e0 hai tia tr\u00f9ng nhau <br\/> +) Tia BC v\u00e0 tia CB l\u00e0 hai tia kh\u00f4ng chung g\u1ed1c n\u00ean BC v\u00e0 CB l\u00e0 hai tia kh\u00f4ng \u0111\u1ed1i nhau <br\/> +) Tia CA v\u00e0 tia CD c\u00f3 chung g\u1ed1c C v\u00e0 hai tia t\u1ea1o th\u00e0nh m\u1ed9t \u0111\u01b0\u1eddng th\u1eb3ng <br\/> N\u00ean CA v\u00e0 CD l\u00e0 hai tia \u0111\u1ed1i nhau <br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n sai l\u00e0: B <\/span> ","column":2}]}],"id_ques":2065},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":10,"ques":"Cho hai tia Ox v\u00e0 Oy \u0111\u1ed1i nhau, c\u00e1c \u0111i\u1ec3m K, H thu\u1ed9c tia Ox (\u0110i\u1ec3m K n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m O v\u00e0 H). \u0110i\u1ec3m G thu\u1ed9c tia Oy. Tia \u0111\u1ed1i c\u1ee7a tia OG l\u00e0:","select":["A. Tia OK ho\u1eb7c tia OH ho\u1eb7c tia Ox","B. Tia Oy","C. Tia Kx","D. Tia Hx"],"hint":"","explain":" <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop6/toan/hinhhoc/bai7/lv3/img\/H617_K106.png' \/><\/center><br\/> V\u00ec Ox v\u00e0 Oy l\u00e0 hai tia \u0111\u1ed1i nhau (1) <br\/> G thu\u1ed9c tia Oy; K, H thu\u1ed9c tia Ox (2) <br\/> T\u1eeb (1) v\u00e0 (2) $\\Rightarrow$ OG v\u00e0 OH l\u00e0 hai tia \u0111\u1ed1i nhau <br\/> OG v\u00e0 OK l\u00e0 hai tia \u0111\u1ed1i nhau <br\/> OG v\u00e0 Ox l\u00e0 hai tia \u0111\u1ed1i nhau <br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0: A <\/span> ","column":2}]}],"id_ques":2066},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":10,"ques":"\u0110i\u1ec3m B n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m A v\u00e0 C trong tr\u01b0\u1eddng h\u1ee3p n\u00e0o sau \u0111\u00e2y?","select":["A. AC = 5cm; BC = 7cm; AB = 12cm","B. AC = 9cm; AB = 9,2cm; BC = 18,2cm","C. AB = 3cm; BC = 4cm; AC = 7cm","D. AB = 4cm; CB = 2cm; CA = 5cm"],"hint":"","explain":" <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> V\u00ec 3 \u0111i\u1ec3m A, B, C th\u1eb3ng h\u00e0ng n\u00ean: <br\/> +) C\u00f3 AC + BC = 5cm + 7cm = 12cm <br\/> M\u00e0 AB = 12cm n\u00ean AC + BC = AB v\u00e0 \u0111i\u1ec3m C n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m A v\u00e0 B <b> (lo\u1ea1i) <\/b> <br\/> +) C\u00f3 AC + AB = 9cm + 9,2cm = 18,2cm <br\/> M\u00e0 BC = 18,2cm n\u00ean AC + AB = BC v\u00e0 \u0111i\u1ec3m A n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m B v\u00e0 C <b> (lo\u1ea1i) <\/b> <br\/> +) C\u00f3 AB + BC = 3cm + 4cm = 7cm <br\/> M\u00e0 AC = 7cm n\u00ean AB + BC = AC v\u00e0 \u0111i\u1ec3m B n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m A v\u00e0 C <b> (th\u1ecfa m\u00e3n) <\/b> <\/b> <br\/> +) C\u00f3 AB + CB = 4cm + 2cm = 6cm <br\/> M\u00e0 CA = 5cm n\u00ean AB + CB $\\neq$ CA n\u00ean \u0111i\u1ec3m B kh\u00f4ng n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m A v\u00e0 C <b> (lo\u1ea1i) <\/b> <br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0: C <\/span> ","column":2}]}],"id_ques":2067},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":10,"ques":"Cho hai \u0111\u01b0\u1eddng th\u1eb3ng xy v\u00e0 zt c\u1eaft nhau t\u1ea1i O. Tr\u00ean tia Ox l\u1ea5y \u0111i\u1ec3m A, tr\u00ean tia Oy l\u1ea5y \u0111i\u1ec3m C sao cho OA = OC = 1cm. Tr\u00ean tia OA l\u1ea5y \u0111i\u1ec3m B sao cho OB = 2cm. Tr\u00ean tia Oy l\u1ea5y \u0111i\u1ec3m D sao cho OD = 2OB. Trong 5 \u0111i\u1ec3m A, B, C, D, O \u0111i\u1ec3m n\u00e0o l\u00e0 trung \u0111i\u1ec3m c\u1ee7a \u0111o\u1ea1n th\u1eb3ng c\u00f3 hai \u0111\u1ea7u m\u00fat l\u00e0 hai trong s\u1ed1 c\u00e1c \u0111i\u1ec3m c\u00f2n l\u1ea1i?","select":["A. O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a \u0111o\u1ea1n th\u1eb3ng AD","B. C l\u00e0 trung \u0111i\u1ec3m c\u1ee7a \u0111o\u1ea1n th\u1eb3ng BD","C. A l\u00e0 trung \u0111i\u1ec3m c\u1ee7a \u0111o\u1ea1n th\u1eb3ng BO","D. \u0110\u00e1p \u00e1n B v\u00e0 C \u0111\u00fang"],"hint":"","explain":" <span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> Ta ki\u1ec3m tra t\u1eebng \u0111\u00e1p \u00e1n <br\/> \u0110\u1ec3 ch\u1ee9ng t\u1ecf m\u1ed9t \u0111i\u1ec3m l\u00e0 trung \u0111i\u1ec3m c\u1ee7a \u0111o\u1ea1n th\u1eb3ng n\u00e0o \u0111\u00f3 th\u00ec \u0111i\u1ec3m \u0111\u00f3 c\u1ea7n th\u1ecfa m\u00e3n 2 \u0111i\u1ec1u ki\u1ec7n: <br\/> +) \u0110i\u1ec3m \u0111\u00f3 n\u1eb1m gi\u1eefa hai \u0111\u1ea7u m\u00fat c\u1ee7a \u0111o\u1ea1n th\u1eb3ng <br\/> +) \u0110i\u1ec3m \u0111\u00f3 c\u00e1ch \u0111\u1ec1u hai \u0111\u1ea7u m\u00fat c\u1ee7a \u0111o\u1ea1n th\u1eb3ng <br\/> <\/span> <br\/><br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop6/toan/hinhhoc/bai7/lv3/img\/H617_K108.png' \/><\/center> <br\/> +) Ta c\u00f3: OD = 2OB = 2 . 2 = 4 (cm) <br\/> M\u00e0 OA = 1cm n\u00ean OA $\\neq$ OD n\u00ean <b> \u0111i\u1ec3m O kh\u00f4ng l\u00e0 trung \u0111i\u1ec3m c\u1ee7a \u0111o\u1ea1n th\u1eb3ng AD <\/b> <br\/> +) Tr\u00ean tia Oy c\u00f3: OC = 1cm; OD = 4cm m\u00e0 1cm < 4cm n\u00ean OC < OD <br\/> $\\Rightarrow$ \u0110i\u1ec3m C n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m O v\u00e0 D <br\/> $\\begin{align*} \\Rightarrow OC + CD &= OD \\\\ 1cm + CD &= 4cm \\\\ CD &= 4cm - 1cm \\\\ CD &= 3cm \\end{align*}$ <br\/> V\u00ec B $\\in$ Ox; C $\\in$ Oy m\u00e0 Ox v\u00e0 Oy l\u00e0 hai tia \u0111\u1ed1i nhau n\u00ean \u0111i\u1ec3m O n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m B v\u00e0 C <br\/> $\\begin{align*} \\Rightarrow CB &= OC + OB \\\\ CB &= 1cm + 2cm \\\\ CB &= 3cm\\end{align*}$ <br\/> CD = 3cm; CB = 3cm n\u00ean CB = CD (1) <br\/> Ta c\u00f3 \u0111i\u1ec3m C n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m O v\u00e0 D, \u0111i\u1ec3m O n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m C v\u00e0 B <br\/> $\\Rightarrow$ \u0110i\u1ec3m O v\u00e0 \u0111i\u1ec3m C n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m B v\u00e0 D (2) <br\/> T\u1eeb (1) v\u00e0 (2) $\\Rightarrow$ <b> \u0110i\u1ec3m C l\u00e0 trung \u0111i\u1ec3m c\u1ee7a \u0111o\u1ea1n th\u1eb3ng BD <\/b> <br\/> +) Tr\u00ean tia Ox c\u00f3 OA = 1cm; OB = 2cm n\u00ean OA < OB <br\/> $\\Rightarrow$ \u0110i\u1ec3m A n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m O v\u00e0 B (3) <br\/> $\\begin{align*} \\Rightarrow OA + AB &= OB \\\\ 1cm + AB &= 2cm \\\\ AB &= 2cm - 1cm \\\\ AB &= 1cm \\end{align*}$ <br\/> V\u00ec OA = 1cm; AB = 1cm n\u00ean OA = AB (4) <br\/> T\u1eeb (3) v\u00e0 (4) $\\Rightarrow$ <b> \u0110i\u1ec3m A l\u00e0 trung \u0111i\u1ec3m c\u1ee7a \u0111o\u1ea1n th\u1eb3ng OB <\/b> <br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0: D. \u0110\u00e1p \u00e1n B v\u00e0 C \u0111\u00fang <\/span> ","column":2}]}],"id_ques":2068},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["4"]]],"list":[{"point":10,"width":50,"content":"","type_input":"","ques":"Cho \u0111o\u1ea1n th\u1eb3ng MN = 8cm, \u0111i\u1ec3m I n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m M v\u00e0 N; c\u00e1c \u0111i\u1ec3m P v\u00e0 Q theo th\u1ee9 t\u1ef1 l\u00e0 trung \u0111i\u1ec3m c\u1ee7a MI v\u00e0 IN. T\u00ednh \u0111\u1ed9 d\u00e0i c\u1ee7a c\u1ee7a \u0111o\u1ea1n th\u1eb3ng PQ. <br\/> \u0110\u00e1p \u00e1n l\u00e0: PQ = _input_ cm","hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1: <\/b> T\u00ednh PI = ? <br\/> <b> B\u01b0\u1edbc 2: <\/b> T\u00ednh IQ = ? <br\/> <b> B\u01b0\u1edbc 3: <\/b> T\u00ednh PQ = ? <\/span> <br\/><br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop6/toan/hinhhoc/bai7/lv3/img\/H617_K110.png' \/><\/center> <br\/> V\u00ec \u0111i\u1ec3m I n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m M v\u00e0 N n\u00ean ta c\u00f3: IM + IN = MN (1) <br\/> V\u00ec P l\u00e0 trung \u0111i\u1ec3m c\u1ee7a IM n\u00ean: $MP = PI = \\dfrac{MI}{2}$ (2) <br\/> V\u00ec Q l\u00e0 trung \u0111i\u1ec3m c\u1ee7a \u0111o\u1ea1n th\u1eb3ng IN n\u00ean: $IQ = QN = \\dfrac{IN}{2}$ (3) <br\/> V\u00ec \u0111i\u1ec3m I n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m P v\u00e0 Q (4) <br\/> T\u1eeb (1), (2), (3) v\u00e0 (4) ta c\u00f3: <br\/> $PQ = PI + IQ = \\dfrac{MI}{2} + \\dfrac{IN}{2} = \\dfrac{MN}{2} = \\dfrac{8}{2} = 4$ (cm) <br\/> <span class='basic_pink'> V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0: 4 <\/span>"}]}],"id_ques":2069},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["5,5","5.5"]]],"list":[{"point":10,"width":80,"content":"","type_input":"","ques":"V\u1ebd tia Ox l\u1ea5y 3 \u0111i\u1ec3m A, B, C sao cho OA = 2cm; OB = 5cm; OC = 8cm. G\u1ecdi H, I, K l\u1ea7n l\u01b0\u1ee3t l\u00e0 trung \u0111i\u1ec3m c\u1ee7a c\u00e1c \u0111o\u1ea1n OA, AB, BC. T\u00ednh HK. <br\/> \u0110\u00e1p \u00e1n l\u00e0: HK = _input_ cm","hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1: <\/b> Ch\u1ec9 ra \u0111i\u1ec3m C n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m A v\u00e0 B, sau \u0111\u00f3 t\u00ednh AC <br\/> <b> B\u01b0\u1edbc 2: <\/b> Ch\u1ec9 ra \u0111i\u1ec3m A n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m O v\u00e0 C sau \u0111\u00f3 t\u00ednh OC <\/span> <br\/><br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> <span class='basic_left'><span class='basic_green'> <b> T\u00f3m t\u1eaft: <\/b> <\/span><br\/> Tr\u00ean tia Ox <br\/> OA = 2cm <br\/> OB = 2cm <br\/> OC = 8cm <br\/> H l\u00e0 trung \u0111i\u1ec3m c\u1ee7a OA <br\/> I l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AB <br\/> K l\u00e0 trung \u0111i\u1ec3m c\u1ee7a BC <br\/> T\u00ednh HK = ? <\/span> <br\/> <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop6/toan/hinhhoc/bai7/lv3/img\/H617_K113.png' \/><\/center> <br\/> Tr\u00ean tia V\u00ec H l\u00e0 trung \u0111i\u1ec3m c\u1ee7a OA n\u00ean: $OH = HA = \\dfrac{OA}{2} = \\dfrac{2}{2} = 1$ (cm) <br\/> Tr\u00ean tia OB c\u00f3 OA = 2cm, OB = 5cm n\u00ean OA < OB n\u00ean \u0111i\u1ec3m A n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m O v\u00e0 B <br\/> $\\begin{align*} \\Rightarrow OA + AB &= OB \\\\ 2cm + AB &= 5cm \\\\ AB &= 5cm - 2cm \\\\ AB &= 3cm \\end{align*}$ <br\/> Tr\u00ean tia OC c\u00f3 OB = 5cm, OC = 8cm n\u00ean OB < OC n\u00ean \u0111i\u1ec3m B n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m O v\u00e0 C <br\/> $\\begin{align*} \\Rightarrow OB + BC &= OC \\\\ 5cm + BC &= 8cm \\\\ BC &= 8cm - 5cm \\\\ BC &= 3cm \\end{align*}$ <br\/> V\u00ec I l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AB n\u00ean: $AI = IB = \\dfrac{AB}{2} = \\dfrac{3}{2} = 1,5$ (cm) <br\/> V\u00ec K l\u00e0 trung \u0111i\u1ec3m c\u1ee7a BC n\u00ean: $BK = KC = \\dfrac{BC}{2} = \\dfrac{3}{2} = 1,5$ (cm) <br\/> V\u00ec AO v\u00e0 AB l\u00e0 hai tia \u0111\u1ed1i nhau, \u0111i\u1ec3m H thu\u1ed9c AO, I thu\u1ed9c AB <br\/> N\u00ean \u0111i\u1ec3m A n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m H v\u00e0 I <br\/> $\\begin{align*} \\Rightarrow IH &= AH + AI \\\\ IH &= 1cm + 1,5cm \\\\ IH &= 2,5cm \\end{align*}$ <br\/> V\u00ec BA v\u00e0 BC l\u00e0 hai tia \u0111\u1ed1i nhau, K thu\u1ed9c tia BC n\u00ean \u0111i\u1ec3m B n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m I v\u00e0 K <br\/> $\\begin{align*} \\Rightarrow IK &= IB + BK \\\\ IK &= 1,5cm + 1,5cm \\\\ IK &= 3cm \\end{align*}$ <br\/> Tr\u00ean tia OC c\u00f3 OA = 2cm, OB = 5cm, OC = 8cm n\u00ean \u0111i\u1ec3m B n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m A v\u00e0 C (1) <br\/> H, I, K l\u00e0 trung \u0111i\u1ec3m c\u00e1c \u0111o\u1ea1n OA, AB, BC (2) <br\/> T\u1eeb (1) v\u00e0 (2) $\\Rightarrow$ \u0111i\u1ec3m I n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m H v\u00e0 K <br\/> $\\begin{align*} \\Rightarrow HK &= IH + IK \\\\ HK &= 2,5cm + 3cm \\\\ HK &= 5,5cm \\end{align*}$ <br\/> <span class='basic_pink'> V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0: 5,5 <\/span>"}]}],"id_ques":2070}],"lesson":{"save":0,"level":3}}