Ba bài toán cơ bản về phân số-level2

Home Lớp 6 Toán lớp 6 - Sách kết nối tri thức Ba bài toán cơ bản về phân sốBài tập trung bình

{"common":{"save":0,"post_id":"815","level":2,"total":20,"point":5,"point_extra":0},"segment":[{"id":"1831","post_id":"815","mon_id":"0","chapter_id":"0","question":"\u0110i\u1ec1n \u0111\u00e1p \u00e1n \u0111\u00fang v\u00e0o \u00f4 tr\u1ed1ng","options":{"time":24,"part":[{"title":"\u0110i\u1ec1n \u0111\u00e1p \u00e1n \u0111\u00fang v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["0"]]],"list":[{"point":5,"width":50,"type_input":"","input_hint":["frac"],"ques":"Hi\u1ec7u gi\u1eefa $5\\dfrac{3}{8}$ c\u1ee7a $1\\dfrac{31}{129}$ v\u1edbi $35 \\%$ c\u1ee7a $19\\dfrac{1}{21}$ l\u00e0: _input_ ","hint":"","explain":" H\u01b0\u1edbng d\u1eabn:<\/span><br\/> B\u01b0\u1edbc 1: <\/b> T\u00ednh $5\\dfrac{3}{8}$ c\u1ee7a $1 \\dfrac{31}{129}$ b\u1eb1ng c\u00e1ch vi\u1ebft c\u00e1c h\u1ed7n s\u1ed1 tr\u00ean d\u01b0\u1edbi d\u1ea1ng ph\u00e2n s\u1ed1 r\u1ed3i nh\u00e2n hai ph\u00e2n s\u1ed1 \u0111\u00f3 <br\/> B\u01b0\u1edbc 2: <\/b> T\u00ednh $35\\%$ c\u1ee7a $19\\dfrac{1}{21}$ b\u1eb1ng c\u00e1ch vi\u1ebft ch\u00fang d\u01b0\u1edbi d\u1ea1ng ph\u00e2n s\u1ed1 r\u1ed3i th\u1ef1c hi\u1ec7n nh\u00e2n hai ph\u00e2n s\u1ed1 <br\/> B\u01b0\u1edbc 3: <\/b> T\u00ednh hi\u1ec7u <\/span> <br\/><br\/> B\u00e0i gi\u1ea3i:<\/span><br\/> $5\\dfrac{3}{8}$ c\u1ee7a $1\\dfrac{31}{129}$ l\u00e0: $5\\dfrac{3}{8} . 1\\dfrac{31}{129} = \\dfrac{43}{8} . \\dfrac{160}{129} = 6\\dfrac{2}{3}$ <br\/> <br\/> $35\\%$ c\u1ee7a $19\\dfrac{1}{21}$ l\u00e0: $35\\% . 19\\dfrac{1}{21} = \\dfrac{35}{100} . \\dfrac{400}{21} = 6\\dfrac{2}{3}$ <br\/> <br\/> Hi\u1ec7u l\u00e0: $6\\dfrac{2}{3} - 6\\dfrac{2}{3} = 0$"}]}]},"correct":"","level":"2","hint":"","answer":"","type":"json","extra_type":"","time":"0","user_id":"0","test":"0","date":"2019-09-30 09:14:55"},{"id":"1832","post_id":"815","mon_id":"0","chapter_id":"0","question":"\u0110i\u1ec1n \u0111\u00e1p \u00e1n \u0111\u00fang v\u00e0o \u00f4 tr\u1ed1ng","options":{"time":24,"part":[{"title":"\u0110i\u1ec1n \u0111\u00e1p \u00e1n \u0111\u00fang v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["0"]]],"list":[{"point":5,"width":50,"type_input":"","input_hint":["frac"],"ques":"Hi\u1ec7u gi\u1eefa $\\dfrac{4}{3}$ c\u1ee7a $\\dfrac{2}{5}$ v\u1edbi $\\dfrac{4}{5}$ c\u1ee7a $\\dfrac{2}{3}$ l\u00e0: _input_ ","hint":"","explain":" H\u01b0\u1edbng d\u1eabn:<\/span><br\/> B\u01b0\u1edbc 1: <\/b> T\u00ednh $\\dfrac{4}{3}$ c\u1ee7a $ \\dfrac{2}{5}$ b\u1eb1ng c\u00e1ch th\u1ef1c hi\u1ec7n nh\u00e2n hai ph\u00e2n s\u1ed1 \u0111\u00f3 <br\/> B\u01b0\u1edbc 2: <\/b> T\u00ednh $\\dfrac{4}{5}$ c\u1ee7a $\\dfrac{2}{3}$ b\u1eb1ng c\u00e1ch th\u1ef1c hi\u1ec7n nh\u00e2n hai ph\u00e2n s\u1ed1 <br\/> B\u01b0\u1edbc 3: <\/b> T\u00ednh hi\u1ec7u <\/span> <br\/><br\/> B\u00e0i gi\u1ea3i:<\/span><br\/> $\\dfrac{4}{3}$ c\u1ee7a $\\dfrac{2}{5}$ l\u00e0: $\\dfrac{4}{3} . \\dfrac{2}{5} = \\dfrac{4 . 2}{3 . 5} = \\dfrac{8}{15}$ <br\/> <br\/> $\\dfrac{4}{5}$ c\u1ee7a $\\dfrac{2}{3}$ l\u00e0: $\\dfrac{4}{5} . \\dfrac{2}{3} = \\dfrac{4 . 2}{5 . 3} = \\dfrac{8}{15}$ <br\/> <br\/> Hi\u1ec7u l\u00e0: $\\dfrac{8}{15} - \\dfrac{8}{15} = 0$ <br\/> Nh\u1eadn x\u00e9t: ($\\dfrac{a}{b}$ c\u1ee7a $\\dfrac{c}{d}$) b\u1eb1ng ($\\dfrac{c}{d}$ c\u1ee7a $\\dfrac{a}{b}$) b\u1eb1ng ($\\dfrac{a}{d}$ c\u1ee7a $\\dfrac{c}{b}$) b\u1eb1ng ($\\dfrac{c}{b}$ c\u1ee7a $\\dfrac{a}{d}$) v\u00ec \u0111\u1ec1u b\u1eb1ng $\\dfrac{a . c}{b . d}$ <\/i> <\/span> "}]}]},"correct":"","level":"2","hint":"","answer":"","type":"json","extra_type":"","time":"0","user_id":"0","test":"0","date":"2019-09-30 09:14:55"},{"id":"1833","post_id":"815","mon_id":"0","chapter_id":"0","question":"\u0110i\u1ec1n \u0111\u00e1p \u00e1n \u0111\u00fang v\u00e0o \u00f4 tr\u1ed1ng","options":{"time":24,"part":[{"title":"\u0110i\u1ec1n \u0111\u00e1p \u00e1n \u0111\u00fang v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["375"]]],"list":[{"point":5,"width":50,"type_input":"","input_hint":["frac"],"ques":"T\u00ecm m\u1ed9t s\u1ed1 bi\u1ebft $\\dfrac{2}{5} \\%$ c\u1ee7a n\u00f3 b\u1eb1ng 1,5 <br\/> S\u1ed1 \u0111\u00f3 l\u00e0: _input_ ","hint":"","explain":" H\u01b0\u1edbng d\u1eabn:<\/span><br\/> B\u01b0\u1edbc 1: <\/b> Vi\u1ebft $\\dfrac{2}{5} \\%$ d\u01b0\u1edbi d\u1ea1ng ph\u00e2n s\u1ed1 <br\/> Vi\u1ebft 1,5 d\u01b0\u1edbi d\u1ea1ng ph\u00e2n s\u1ed1 <br\/> B\u01b0\u1edbc 2: <\/b> S\u1ed1 c\u1ea7n t\u00ecm b\u1eb1ng: $1,5 : \\dfrac{2}{5} \\%$ <\/span> <br\/><br\/> B\u00e0i gi\u1ea3i:<\/span><br\/> $\\dfrac{2}{5} \\% = \\dfrac{\\dfrac{2}{5}}{100} = \\dfrac{2}{5 . 100} = \\dfrac{1}{250}$ <br\/> $1,5 = \\dfrac{15}{10} = \\dfrac{3}{2}$ <br\/> S\u1ed1 c\u1ea7n t\u00ecm l\u00e0: $\\dfrac{3}{2} : \\dfrac{1}{250} = 375$<br\/> Nh\u1eadn x\u00e9t: Mu\u1ed1n t\u00ecm s\u1ed1 x bi\u1ebft $\\dfrac{m}{n}$ c\u1ee7a x b\u1eb1ng b khi \u0111\u00f3 $x = b : \\dfrac{m}{n}$ <\/i> <\/span> "}]}]},"correct":"","level":"2","hint":"","answer":"","type":"json","extra_type":"","time":"0","user_id":"0","test":"0","date":"2019-09-30 09:14:55"}]}