Góc. Số đo góc

Home Lớp 6 Toán lớp 6 - Sách kết nối tri thức Góc. Số đo gócBài tập nâng cao

{"common":{"save":0,"post_id":"1541","level":3,"total":10,"point":10,"point_extra":0},"segment":[{"id":"2131","post_id":"1541","mon_id":"0","chapter_id":"0","question":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","options":{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":10,"ques":" V\u1ebd ba \u0111\u01b0\u1eddng th\u1eb3ng \u0111\u1ed3ng quy t\u1ea1i S. S\u1ed1 g\u00f3c t\u1ea1o th\u00e0nh l\u00e0:","select":["A. 6 g\u00f3c","B. 9 g\u00f3c","C. 12 g\u00f3c","D. 15 g\u00f3c"],"hint":"","explain":" B\u00e0i gi\u1ea3i:<\/span><br\/><center><img src='img\/H622_K101.png' \/><\/center>Ta c\u00f3: S\u1ed1 tia chung g\u1ed1c S l\u00e0: 2 . 3 = 6 (tia) <br\/>S\u1ed1 g\u00f3c t\u1ea1o th\u00e0nh l\u00e0: $\\dfrac{6 . 5}{2}$ = 15 (g\u00f3c)<br\/>V\u1eady ta ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0:D. 15 g\u00f3c<\/span><\/span> <br\/><\/span>Nh\u1eadn x\u00e9t:<\/span><br\/>+ Cho n tia chung g\u1ed1c, m\u1ed7i tia t\u1ea1o v\u1edbi n - 1 tia c\u00f2n l\u1ea1i th\u00e0nh n - 1 g\u00f3c. C\u00f3 n tia n\u00ean t\u1ea1o \u0111\u01b0\u1ee3c n.(n - 1) g\u00f3c. Nh\u01b0ng m\u1ed7i g\u00f3c \u0111\u00e3 \u0111\u01b0\u1ee3c t\u00ednh hai l\u1ea7n, do \u0111\u00f3 t\u1ea5t c\u1ea3 ch\u1ec9 c\u00f3: $\\dfrac{n . (n - 1)}{2}$ g\u00f3c<br\/> V\u1eady g\u1ecdi n l\u00e0 s\u1ed1 tia chung g\u1ed1c, khi \u0111\u00f3 s\u1ed1 g\u00f3c do n tia n\u00e0y t\u1ea1o ra \u0111\u01b0\u1ee3c t\u00ednh theo c\u00f4ng th\u1ee9c: $\\dfrac{n . (n - 1)}{2}$<\/b><\/span>","column":2}]}]},"correct":"","level":"3","hint":"","answer":"","type":"json","extra_type":"","time":"0","user_id":"0","test":"0","date":"2019-09-30 09:14:58"},{"id":"2132","post_id":"1541","mon_id":"0","chapter_id":"0","question":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","options":{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":10,"ques":" Cho 4 tia chung g\u1ed1c. S\u1ed1 g\u00f3c t\u1ea1o th\u00e0nh l\u00e0:","select":["A. 6 g\u00f3c","B. 9 g\u00f3c","C. 12 g\u00f3c","D. 15 g\u00f3c"],"hint":"","explain":" B\u00e0i gi\u1ea3i:<\/span><br\/><center><img src='img\/H622_K102.png' \/><\/center>Ta c\u00f3: <br\/>S\u1ed1 g\u00f3c t\u1ea1o th\u00e0nh l\u00e0: $\\dfrac{4 . 3}{2}$ = 6 (g\u00f3c)<br\/>V\u1eady ta ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0:A. 6 g\u00f3c<\/span><\/span> <br\/><\/span>Nh\u1eadn x\u00e9t:<\/span><br\/>+ Cho n tia chung g\u1ed1c, m\u1ed7i tia t\u1ea1o v\u1edbi n - 1 tia c\u00f2n l\u1ea1i th\u00e0nh n - 1 g\u00f3c. C\u00f3 n tia n\u00ean t\u1ea1o \u0111\u01b0\u1ee3c n.(n - 1) g\u00f3c. Nh\u01b0ng m\u1ed7i g\u00f3c \u0111\u00e3 \u0111\u01b0\u1ee3c t\u00ednh hai l\u1ea7n, do \u0111\u00f3 t\u1ea5t c\u1ea3 ch\u1ec9 c\u00f3: $\\dfrac{n . (n - 1)}{2}$ g\u00f3c<br\/> V\u1eady g\u1ecdi n l\u00e0 s\u1ed1 tia chung g\u1ed1c, khi \u0111\u00f3 s\u1ed1 g\u00f3c do n tia n\u00e0y t\u1ea1o ra \u0111\u01b0\u1ee3c t\u00ednh theo c\u00f4ng th\u1ee9c: $\\dfrac{n . (n - 1)}{2}$<\/b><\/span>","column":2}]}]},"correct":"","level":"3","hint":"","answer":"","type":"json","extra_type":"","time":"0","user_id":"0","test":"0","date":"2019-09-30 09:14:58"},{"id":"2133","post_id":"1541","mon_id":"0","chapter_id":"0","question":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","options":{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":10,"ques":" Cho 10 tia chung g\u1ed1c. S\u1ed1 g\u00f3c t\u1ea1o th\u00e0nh l\u00e0:","select":["A. 42 g\u00f3c","B. 45 g\u00f3c","C. 48 g\u00f3c","D. 50 g\u00f3c"],"hint":"","explain":" B\u00e0i gi\u1ea3i:<\/span><br\/>Ta c\u00f3: <br\/>S\u1ed1 g\u00f3c t\u1ea1o th\u00e0nh l\u00e0: $\\dfrac{10. (10 - 1)}{2}$ = 45 (g\u00f3c)<br\/>V\u1eady ta ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0:B. 45 g\u00f3c<\/span><\/span> <br\/><\/span>Nh\u1eadn x\u00e9t:<\/span><br\/>+ Cho n tia chung g\u1ed1c, m\u1ed7i tia t\u1ea1o v\u1edbi n - 1 tia c\u00f2n l\u1ea1i th\u00e0nh n - 1 g\u00f3c. C\u00f3 n tia n\u00ean t\u1ea1o \u0111\u01b0\u1ee3c n.(n - 1) g\u00f3c. Nh\u01b0ng m\u1ed7i g\u00f3c \u0111\u00e3 \u0111\u01b0\u1ee3c t\u00ednh hai l\u1ea7n, do \u0111\u00f3 t\u1ea5t c\u1ea3 ch\u1ec9 c\u00f3: $\\dfrac{n . (n - 1)}{2}$ g\u00f3c<br\/> V\u1eady g\u1ecdi n l\u00e0 s\u1ed1 tia chung g\u1ed1c, khi \u0111\u00f3 s\u1ed1 g\u00f3c do n tia n\u00e0y t\u1ea1o ra \u0111\u01b0\u1ee3c t\u00ednh theo c\u00f4ng th\u1ee9c: $\\dfrac{n . (n - 1)}{2}$<\/b><\/span>","column":2}]}]},"correct":"","level":"3","hint":"","answer":"","type":"json","extra_type":"","time":"0","user_id":"0","test":"0","date":"2019-09-30 09:14:58"}]}