{"common":{"save":0,"post_id":"840","level":3,"total":10,"point":10,"point_extra":0},"segment":[{"id":"2161","post_id":"840","mon_id":"0","chapter_id":"0","question":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","options":{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":10,"ques":" <center><img src='img\/H623_K101.png' \/><\/center> Cho h\u00ecnh v\u1ebd c\u00f3 s\u1ed1 \u0111o nh\u01b0 tr\u00ean. T\u00ednh $\\widehat{yOz}$. ","select":["A. $\\widehat{yOz}$ = $20^o$","B. $\\widehat{yOz}$ = $30^o$","C. $\\widehat{yOz}$ = $100^o$","D. $\\widehat{yOz}$ = $110^o$"],"hint":"","explain":" <span class='basic_left'><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/><center><img src='img\/H623_K101.png' \/><\/center>Ta c\u00f3: $\\widehat{xOy}$ < $\\widehat{xOz}$ ( v\u00ec $45^o$ < $75^o$)<br\/> N\u00ean tia Oy n\u1eb1m gi\u1eefa hai tia Ox v\u00e0 Oz<br\/>Suy ra $\\widehat{xOy}$ + $\\widehat{yOz}$ = $\\widehat{xOz}$<br\/>Thay $\\widehat{xOy}$ = $45^o$, $\\widehat{xOz}$ = $75^o$, ta \u0111\u01b0\u1ee3c:<br\/> $45^o$ + $\\widehat{yOz}$ = $75^o$ <br\/>Suy ra $\\widehat{yOz}$ = $75^o$ - $45^o$ = $30^o$ <br\/>V\u1eady ta ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0: <span class='basic_pink'>B. <\/span>$\\widehat{yOz}$ = $30^o$<\/span> <br\/><\/span><span class='basic_left'><span class='basic_green'>Nh\u1eadn x\u00e9t:<\/span> $\\widehat{xOy}$ = $m^o$, $\\widehat{xOz}$ = $n^o$. N\u1ebfu $m^o$ < $n^o$ th\u00ec tia Oy n\u1eb1m gi\u1eefa hai tia Ox v\u00e0 Oz<\/span>","column":2}]}]},"correct":"","level":"3","hint":"","answer":"","type":"json","extra_type":"","time":"0","user_id":"0","test":"0","date":"2019-09-30 09:14:58"},{"id":"2162","post_id":"840","mon_id":"0","chapter_id":"0","question":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","options":{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":10,"ques":" <center><img src='img\/H623_K103.png' \/><\/center> Cho h\u00ecnh v\u1ebd c\u00f3 s\u1ed1 \u0111o nh\u01b0 tr\u00ean. T\u00ednh $\\widehat{yOz}$. ","select":["A. $\\widehat{yOz}$ = $20^o$","B. $\\widehat{yOz}$ = $30^o$","C. $\\widehat{yOz}$ = $40^o$","D. $\\widehat{yOz}$ = $50^o$"],"hint":"","explain":" <span class='basic_left'><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/><center><img src='img\/H623_K103.png' \/><\/center>Ta c\u00f3: $\\widehat{xOy}$ < $\\widehat{xOz}$ ( v\u00ec $50^o$ < $100^o$)<br\/> N\u00ean tia Oy n\u1eb1m gi\u1eefa hai tia Ox v\u00e0 Oz<br\/>Suy ra $\\widehat{xOy}$ + $\\widehat{yOz}$ = $\\widehat{xOz}$<br\/>Thay $\\widehat{xOy}$ = $50^o$, $\\widehat{xOz}$ = $100^o$, ta \u0111\u01b0\u1ee3c:<br\/> $50^o$ + $\\widehat{yOz}$ = $100^o$ <br\/>Suy ra $\\widehat{yOz}$ = $100^o$ - $50^o$ = $50^o$ <br\/>V\u1eady ta ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0: <span class='basic_pink'>D. <\/span>$\\widehat{yOz}$ = $50^o$<\/span> <br\/><\/span><span class='basic_left'><span class='basic_green'>Nh\u1eadn x\u00e9t:<\/span> $\\widehat{xOy}$ = $m^o$, $\\widehat{xOz}$ = $n^o$. N\u1ebfu $m^o$ < $n^o$ th\u00ec tia Oy n\u1eb1m gi\u1eefa hai tia Ox v\u00e0 Oz<\/span>","column":2}]}]},"correct":"","level":"3","hint":"","answer":"","type":"json","extra_type":"","time":"0","user_id":"0","test":"0","date":"2019-09-30 09:14:58"},{"id":"2163","post_id":"840","mon_id":"0","chapter_id":"0","question":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","options":{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":10,"ques":" <center><img src='img\/H623_K105.png' \/><\/center> Cho h\u00ecnh v\u1ebd c\u00f3 s\u1ed1 \u0111o nh\u01b0 tr\u00ean. T\u00ednh $\\widehat{xOy}$. ","select":["A. $\\widehat{xOy}$ = $40^o$","B. $\\widehat{xOy}$ = $50^o$","C. $\\widehat{xOy}$ = $60^o$","D. $\\widehat{xOy}$ = $70^o$"],"hint":"","explain":" <span class='basic_left'><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/><center><img src='img\/H623_K105.png' \/><\/center>Ta c\u00f3: $\\widehat{zOy}$ < $\\widehat{zOx}$ ( v\u00ec $50^o$ < $110^o$)<br\/> N\u00ean tia Oy n\u1eb1m gi\u1eefa hai tia Ox v\u00e0 Oz<br\/>Suy ra $\\widehat{xOy}$ + $\\widehat{yOz}$ = $\\widehat{xOz}$<br\/>Thay $\\widehat{yOz}$ = $50^o$, $\\widehat{xOz}$ = $110^o$, ta \u0111\u01b0\u1ee3c:<br\/> $\\widehat{xOy}$ + $50^o$= $110^o$ <br\/>Suy ra $\\widehat{xOy}$ = $110^o$ - $50^o$ = $60^o$ <br\/>V\u1eady ta ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0: <span class='basic_pink'>C. <\/span>$\\widehat{yOz}$ = $60^o$<\/span> <br\/><\/span><span class='basic_left'><span class='basic_green'>Nh\u1eadn x\u00e9t:<\/span> $\\widehat{xOy}$ = $m^o$, $\\widehat{xOz}$ = $n^o$. N\u1ebfu $m^o$ < $n^o$ th\u00ec tia Oy n\u1eb1m gi\u1eefa hai tia Ox v\u00e0 Oz<\/span>","column":2}]}]},"correct":"","level":"3","hint":"","answer":"","type":"json","extra_type":"","time":"0","user_id":"0","test":"0","date":"2019-09-30 09:14:58"}]}