Kiểm chương III

Home Lớp 6 Toán lớp 6 - Sách kết nối tri thức Kiểm tra chương III - Lớp 6Bài tập nâng cao

{"common":{"save":0,"post_id":"813","level":3,"total":10,"point":10,"point_extra":0},"segment":[{"id":"1801","post_id":"813","mon_id":"0","chapter_id":"0","question":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","options":{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":10,"ques":" <center><img src='img\/2.jpg' \/><\/center>$\\dfrac{3}{10} . 5 +\\dfrac{11}{8} . \\dfrac{6}{22}$ = ?<\/span>","select":["A. $\\dfrac{15}{8}$","B. $\\dfrac{7}{8}$","C. $\\dfrac{9}{8}$","D. $\\dfrac{10}{8}$"],"hint":"","explain":" H\u01b0\u1edbng d\u1eabn:<\/span><br\/> Bi\u1ec3u th\u1ee9c ch\u1ee9a ph\u00e9p t\u00ednh nh\u00e2n v\u00e0 ph\u00e9p c\u1ed9ng, tr\u1eeb n\u00ean ta th\u1ef1c hi\u1ec7n t\u00ednh ph\u00e9p nh\u00e2n tr\u01b0\u1edbc, t\u00ednh ph\u00e9p c\u1ed9ng, tr\u1eeb sau.<\/span> <br\/><br\/>B\u00e0i gi\u1ea3i:<\/span><br\/>$\\dfrac{3}{10} . 5 +\\dfrac{11}{8} . \\dfrac{6}{22}$<br\/>= $\\dfrac{3}{2}+\\dfrac{3}{8}$<br\/>= $\\dfrac{12}{8}+\\dfrac{3}{8} $<br\/>= $\\dfrac{15}{8}$<br\/>V\u1eady ta ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0: A. $\\dfrac{15}{8}$<\/span><\/span> <br\/>","column":2}]},"correct":"","level":"3","hint":"","answer":"","type":"json","extra_type":"","time":"44","user_id":"0","test":"0","date":"2019-09-30 09:14:55"},{"id":"1802","post_id":"813","mon_id":"0","chapter_id":"0","question":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","options":{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":10,"ques":" <center><img src='img\/2.jpg' \/><\/center>$\\dfrac{-5}{13} - (\\dfrac{3}{5} + \\dfrac{8}{13} - \\dfrac{4}{10})$ = ?<\/span>","select":["A. $\\dfrac{-4}{5}$","B. $\\dfrac{4}{5}$","C. $\\dfrac{-6}{5}$","D. $\\dfrac{6}{5}$"],"hint":"","explain":" H\u01b0\u1edbng d\u1eabn:<\/span><br\/> B\u1ecf ngo\u1eb7c r\u1ed3i nh\u00f3m c\u00e1c c\u1eb7p sao cho thu\u1eadn ti\u1ec7n \u0111\u1ec3 t\u00ednh.<\/span> <br\/><br\/>B\u00e0i gi\u1ea3i:<\/span><br\/>$\\dfrac{-5}{13} - (\\dfrac{3}{5} + \\dfrac{8}{13} - \\dfrac{4}{10})$<br\/>= $\\dfrac{-5}{13} - \\dfrac{3}{5} - \\dfrac{8}{13} + \\dfrac{4}{10}$ <br\/>= $(\\dfrac{-5}{13} - \\dfrac{8}{13})$ + $(\\dfrac{4}{10} - \\dfrac{3}{5})$<br\/>= $(\\dfrac{-5}{13} + \\dfrac{-8}{13})$ + $(\\dfrac{4}{10} - \\dfrac{6}{10})$<br\/>= $\\dfrac{-13}{13}$ + $\\dfrac{-2}{10}$<br\/>= -1 + $\\dfrac{-1}{5}$<br\/>= $\\dfrac{-5}{5}$ + $\\dfrac{-1}{5}$<br\/>= $\\dfrac{-6}{5}$<br\/>V\u1eady ta ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0: C. $\\dfrac{-6}{5}$<\/span><\/span> <br\/>","column":2}]},"correct":"","level":"3","hint":"","answer":"","type":"json","extra_type":"","time":"44","user_id":"0","test":"0","date":"2019-09-30 09:14:55"},{"id":"1803","post_id":"813","mon_id":"0","chapter_id":"0","question":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","options":{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":10,"ques":" T\u00ecm x, bi\u1ebft: x + $\\dfrac{-1}{3}$ = $\\dfrac{-5}{2}$","select":["A. x = $\\dfrac{-13}{6}$","B. x = $\\dfrac{-17}{6}$","C. x = $\\dfrac{13}{6}$","D. x = $\\dfrac{17}{6}$"],"hint":"","explain":" B\u00e0i gi\u1ea3i:<\/span><br\/>x + $\\dfrac{-1}{3}$ = $\\dfrac{-5}{2}$<br\/>x = $\\dfrac{-5}{2}$ - $\\dfrac{-1}{3}$<br\/>x = $\\dfrac{-15}{6}$ + $\\dfrac{2}{6}$<br\/>x = $\\dfrac{-13}{6}$<br\/>V\u1eady ta ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0: A. x = $\\dfrac{-13}{6}$<\/span><\/span> <br\/>","column":2}]},"correct":"","level":"3","hint":"","answer":"","type":"json","extra_type":"","time":"44","user_id":"0","test":"0","date":"2019-09-30 09:14:55"}]}