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Home Lớp 6 Toán lớp 6 - Sách kết nối tri thức Ôn tập chươngBài tập nâng cao

{"common":{"save":0,"post_id":"847","level":3,"total":10,"point":10,"point_extra":0},"segment":[{"id":"2251","post_id":"847","mon_id":"0","chapter_id":"0","question":"\u0110i\u1ec1n s\u1ed1 ho\u1eb7c ch\u1eef th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","options":{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 ho\u1eb7c ch\u1eef th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["C"],["B"],["7"]]],"list":[{"point":10,"width":60,"type_input":"","ques":"V\u1ebd tam gi\u00e1c ABC, bi\u1ebft ba c\u1ea1nh BC = 12cm, AB = 7cm, AC = 9cm.<br\/>C\u00e1ch v\u1ebd:<\/b><br\/>+ V\u1ebd \u0111o\u1ea1n th\u1eb3ng BC = 12cm<br\/>+ V\u1ebd cung tr\u00f2n t\u00e2m _input_, b\u00e1n k\u00ednh 9cm<br\/>+ V\u1ebd cung tr\u00f2n t\u00e2m _input_, b\u00e1n k\u00ednh _input_cm.<br\/>+ L\u1ea5y m\u1ed9t giao \u0111i\u1ec3m c\u1ee7a hai cung tr\u00ean, g\u1ecdi giao \u0111i\u1ec3m \u0111\u00f3 l\u00e0 A<br\/>+ V\u1ebd \u0111o\u1ea1n th\u1eb3ng AB, AC, ta c\u00f3 $\\triangle$ABC.<\/span>","hint":"","explain":"B\u00e0i gi\u1ea3i:<\/span><br\/><center><img src='img\/H626_K101.png' \/><\/center>C\u00e1ch v\u1ebd:<\/b><br\/>+ V\u1ebd \u0111o\u1ea1n th\u1eb3ng BC = 12cm<br\/>+ V\u1ebd cung tr\u00f2n t\u00e2m C, b\u00e1n k\u00ednh 9cm<br\/>+ V\u1ebd cung tr\u00f2n t\u00e2m B, b\u00e1n k\u00ednh 7cm.<br\/>+ L\u1ea5y m\u1ed9t giao \u0111i\u1ec3m c\u1ee7a hai cung tr\u00ean, g\u1ecdi giao \u0111i\u1ec3m \u0111\u00f3 l\u00e0 A<br\/>+ V\u1ebd \u0111o\u1ea1n th\u1eb3ng AB, AC, ta c\u00f3 $\\triangle$ABC.<br\/>V\u1eady s\u1ed1 ho\u1eb7c ch\u1eef c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng theo th\u1ee9 t\u1ef1 t\u1eeb tr\u00ean xu\u1ed1ng d\u01b0\u1edbi, t\u1eeb tr\u00e1i sang ph\u1ea3i l\u00e0: C, B, 7<\/span><\/span> <\/span> <br\/> "}]}]},"correct":"","level":"3","hint":"","answer":"","type":"json","extra_type":"","time":"0","user_id":"0","test":"0","date":"2019-09-30 09:14:59"},{"id":"2252","post_id":"847","mon_id":"0","chapter_id":"0","question":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","options":{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":10,"ques":"Tr\u00ean \u0111\u01b0\u1eddng tr\u00f2n (O) ta l\u1ea5y m\u1ed9t s\u1ed1 \u0111i\u1ec3m. V\u1ebd c\u00e1c d\u00e2y cung c\u00f3 hai \u0111\u1ea7u l\u00e0 hai trong s\u1ed1 c\u00e1c \u0111i\u1ec3m \u0111\u00e3 cho. Bi\u1ebft r\u1eb1ng c\u00f3 t\u1ea5t c\u1ea3 16 d\u00e2y cung. T\u00ednh s\u1ed1 cung tr\u00f2n \u0111\u00e3 t\u1ea1o th\u00e0nh.","select":["A. 8 cung tr\u00f2n","B. 16 cung tr\u00f2n","C. 32 cung tr\u00f2n","D. 38 cung tr\u00f2n"],"hint":"","explain":" H\u01b0\u1edbng d\u1eabn:<\/span><br\/>Cho n \u0111i\u1ec3m tr\u00ean \u0111\u01b0\u1eddng tr\u00f2n. V\u1ebd c\u00e1c d\u00e2y c\u00f3 hai \u0111\u1ea7u l\u00e0 hai trong n \u0111i\u1ec3m \u0111\u00e3 cho. Khi \u0111\u00f3:<br\/>+ S\u1ed1 d\u00e2y t\u1ea1o th\u00e0nh \u0111\u01b0\u1ee3c t\u00ednh theo c\u00f4ng th\u1ee9c: $\\dfrac{n.(n - 1)}{2}$<br\/>+ S\u1ed1 cung tr\u00f2n \u0111\u01b0\u1ee3c t\u1ea1o th\u00e0nh \u0111\u01b0\u1ee3c t\u00ednh theo c\u00f4ng th\u1ee9c: n . (n - 1) ( ho\u1eb7c s\u1ed1 cung tr\u00f2n = s\u1ed1 d\u00e2y cung . 2)<\/span> <br\/><br\/>B\u00e0i gi\u1ea3i:<\/span><br\/> S\u1ed1 cung tr\u00f2n t\u1ea1o th\u00e0nh l\u00e0:<br\/>16 . 2 = 32 (cung tr\u00f2n)<br\/>V\u1eady ta ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0: C. 32 cung tr\u00f2n<\/span><\/span> <br\/>","column":2}]}]},"correct":"","level":"3","hint":"","answer":"","type":"json","extra_type":"","time":"0","user_id":"0","test":"0","date":"2019-09-30 09:14:59"},{"id":"2253","post_id":"847","mon_id":"0","chapter_id":"0","question":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","options":{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":10,"ques":" Cho hai $\\widehat{xOy}$ v\u00e0 $\\widehat{yOz}$ k\u1ec1 b\u00f9. Bi\u1ebft $\\widehat{xOy}$ = $110^o$. G\u1ecdi Om l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c yOz. S\u1ed1 \u0111o c\u1ee7a g\u00f3c xOm l\u00e0:","select":["A. $70^o$","B. $80^o$","C. $145^o$","D. $150^o$"],"hint":"","explain":" B\u00e0i gi\u1ea3i:<\/span><br\/><center><img src='img\/H626_K103.png' \/><\/center> Ta c\u00f3: $\\widehat{xOy}$ v\u00e0 $\\widehat{yOz}$ k\u1ec1 b\u00f9<br\/>Do \u0111\u00f3: $\\widehat{xOy}$ + $\\widehat{yOz}$ = $\\widehat{xOz}$ = $180^o$<br\/>Thay $\\widehat{xOy}$ = $110^o$ ta \u0111\u01b0\u1ee3c: <br\/>$110^o$ + $\\widehat{yOz}$ = $180^o$<br\/>Suy ra $\\widehat{yOz}$ = $180^o$ - $110^o$ = $70^o$<br\/>+ Om l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c yOz<br\/>Do \u0111\u00f3: $\\widehat{yOm}$ = $\\widehat{mOz}$ = $\\dfrac{1}{2}$ $\\widehat{yOz}$ = $\\dfrac{1}{2}$.$70^o$ = $35^o$<br\/>+ $\\widehat{mOz}$ < $\\widehat{zOx}$ ( v\u00ec $35^o$ < $180^o$) n\u00ean tia Om n\u1eb1m gi\u1eefa hai tia Oz v\u00e0 Ox<br\/>Suy ra: $\\widehat{xOm}$ + $\\widehat{mOz}$ = $\\widehat{xOz}$<br\/>Thay $\\widehat{zOm}$ = $35^o$, $\\widehat{xOz}$ = $180^o$ ta \u0111\u01b0\u1ee3c:<br\/>$35^o$ + $\\widehat{xOm}$ = $180^o$<br\/>$\\widehat{xOm}$ = $180^o$ - $35^o$ = $145^o$<br\/>V\u1eady ta ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0: C. $145^o$<\/span><\/span> <br\/><\/span><\/span>Nh\u1eadn x\u00e9t:<\/span><br\/>Oy l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c xOz khi:<br\/>+ Tia Oy l\u00e0 tia n\u1eb1m gi\u1eefa hai tia Ox v\u00e0 Oz<br\/>+ $\\widehat{xOy}$ = $\\widehat{yOz}$ <\/span>","column":2}]}]},"correct":"","level":"3","hint":"","answer":"","type":"json","extra_type":"","time":"0","user_id":"0","test":"0","date":"2019-09-30 09:14:59"}]}