Ôn tập phần hình học-level3

Home Lớp 6 Toán lớp 6 - Sách kết nối tri thức Ôn tập phần hình họcBài tập nâng cao

{"common":{"save":0,"post_id":"833","level":3,"total":10,"point":10,"point_extra":0},"segment":[{"id":"2061","post_id":"833","mon_id":"0","chapter_id":"0","question":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","options":{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["12"]]],"list":[{"point":10,"width":50,"content":"","type_input":"","ques":"Tr\u00ean tia Oa v\u1ebd \u0111o\u1ea1n th\u1eb3ng OM = 6cm, ON = 14cm. Tr\u00ean tia \u0111\u1ed1i c\u1ee7a tia Oa v\u1ebd OK = 10cm. G\u1ecdi U, V t\u01b0\u01a1ng \u1ee9ng l\u00e0 trung \u0111i\u1ec3m c\u1ee7a c\u00e1c \u0111o\u1ea1n MN, MK. <br\/> Khi \u0111\u00f3 UV = _input_ cm","hint":"","explain":"H\u01b0\u1edbng d\u1eabn:<\/span><br\/> B\u01b0\u1edbc 1: <\/b> T\u00ednh MN = ? <br\/> B\u01b0\u1edbc 2: <\/b> T\u00ednh MU = ? <br\/> B\u01b0\u1edbc 3: <\/b> T\u00ednh MK = ? <br\/> B\u01b0\u1edbc 4: <\/b> T\u00ednh MV = ? <br\/> B\u01b0\u1edbc 5: <\/b> T\u00ednh UV = ? <\/span> <br\/><br\/> B\u00e0i gi\u1ea3i:<\/span><br\/> <center><img src='img\/H617_K101.png' \/><\/center> <br\/> Tr\u00ean tia Oa c\u00f3: OM = 6cm, ON = 14cm <br\/> V\u00ec 6cm < 14cm n\u00ean OM < ON n\u00ean \u0111i\u1ec3m M n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m O v\u00e0 N <br\/> $\\begin{align*} \\Rightarrow OM + MN &= ON \\\\ 6cm + MN &= 14cm \\\\ MN &= 14cm - 6cm \\\\ MN &= 8cm \\end{align*}$ <br\/> V\u00ec \u0111i\u1ec3m U l\u00e0 trung \u0111i\u1ec3m c\u1ee7a \u0111o\u1ea1n th\u1eb3ng MN n\u00ean: <br\/> $MU = UN = \\dfrac{MN}{2} = \\dfrac{8cm}{2} = 4cm$ <br\/> V\u00ec tia Oa v\u00e0 tia OK l\u00e0 hai tia \u0111\u1ed1i nhau <br\/> \u0110i\u1ec3m M thu\u1ed9c tia OA n\u00ean OM v\u00e0 OK l\u00e0 hai tia \u0111\u1ed1i nhau <br\/> $\\Rightarrow$ \u0110i\u1ec3m O n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m M v\u00e0 K <br\/> $\\begin{align*} \\Rightarrow MK &= OM + OK \\\\ MK &= 6cm + 10cm \\\\ MK &= 16cm \\end{align*}$ <br\/> V\u00ec \u0111i\u1ec3m V l\u00e0 trung \u0111i\u1ec3m c\u1ee7a \u0111o\u1ea1n th\u1eb3ng MK n\u00ean: <br\/> $VK = VM = \\dfrac{MK}{2} = \\dfrac{16cm}{2} = 8cm$ <br\/> V\u00ec \u0111i\u1ec3m M v\u00e0 \u0111i\u1ec3m U thu\u1ed9c tia Oa m\u00e0 U l\u00e0 trung \u0111i\u1ec3m c\u1ee7a \u0111o\u1ea1n th\u1eb3ng MN <br\/> N\u00ean \u0111i\u1ec3m M n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m O v\u00e0 U (1) <br\/> M\u00e0 \u0111i\u1ec3m V thu\u1ed9c tia OK (2) <br\/> Oa v\u00e0 OK l\u00e0 hai tia \u0111\u1ed1i nhau (3) <br\/> T\u1eeb (1), (2) v\u00e0 (3) $\\Rightarrow$ \u0111i\u1ec3m M n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m U v\u00e0 V <br\/> $\\begin{align*} \\Rightarrow UV &= MU + MV \\\\ UV &= 4cm + 8cm \\\\ UV &= 12cm \\end{align*}$ <br\/> V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0: 12 <\/span>"}]}]},"correct":"","level":"3","hint":"","answer":"","type":"json","extra_type":"","time":"0","user_id":"0","test":"0","date":"2019-09-30 09:14:58"},{"id":"2062","post_id":"833","mon_id":"0","chapter_id":"0","question":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","options":{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["5"]]],"list":[{"point":10,"width":50,"content":"","type_input":"","ques":"Cho \u0111o\u1ea1n th\u1eb3ng PQ = 16cm, \u0111i\u1ec3m I n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m P v\u00e0 Q; PI = 5cm. \u0110i\u1ec3m M n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m I, Q sao cho IM = 8cm. G\u1ecdi O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a \u0111o\u1ea1n th\u1eb3ng PQ. <br\/> Khi \u0111\u00f3 \u0111\u1ed9 d\u00e0i \u0111o\u1ea1n th\u1eb3ng OM = _input_ cm","hint":"","explain":"H\u01b0\u1edbng d\u1eabn:<\/span><br\/> B\u01b0\u1edbc 1: <\/b> T\u00ednh IQ = ? <br\/> B\u01b0\u1edbc 2: <\/b> T\u00ednh MQ = ? <br\/> B\u01b0\u1edbc 3: <\/b> T\u00ednh OQ = ? <br\/> B\u01b0\u1edbc 4: <\/b> T\u00ednh OM = ? <\/span> <br\/><br\/> B\u00e0i gi\u1ea3i:<\/span><br\/> <center><img src='img\/H617_K102.png' \/><\/center> <br\/> V\u00ec \u0111i\u1ec3m I n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m P v\u00e0 Q n\u00ean: <br\/> $\\begin{align*} \\Rightarrow PI + IQ &= PQ \\\\ 5cm + IQ &= 16cm \\\\ IQ &= 16cm - 5cm \\\\ IQ &= 11cm \\end{align*}$ <br\/> V\u00ec \u0111i\u1ec3m M n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m I v\u00e0 Q n\u00ean: <br\/> $\\begin{align*} \\Rightarrow IM + MQ &= IQ \\\\ 8cm + MQ &= 11cm \\\\ MQ &= 11cm - 8cm \\\\ MQ &= 3cm \\end{align*}$ <br\/> V\u00ec \u0111i\u1ec3m O l\u00e0 trung \u0111i\u1ec3m c\u1ee7a \u0111o\u1ea1n th\u1eb3ng PQ n\u00ean: <br\/> $OP = OQ = \\dfrac{PQ}{2} = \\dfrac{16cm}{2} = 8cm$ <br\/> V\u00ec QM = 3cm, QO = 8cm m\u00e0 3cm < 8cm n\u00ean QM < QO <br\/> N\u00ean \u0111i\u1ec3m M n\u1eb1m gi\u1eefa hai \u0111i\u1ec3m O v\u00e0 Q <br\/> $\\begin{align*} \\Rightarrow OM + MQ &= OQ \\\\ OM + 3cm &= 8cm \\\\ OM &= 8cm - 3cm \\\\ OM &= 5cm \\end{align*}$ <br\/> V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0: 5 <\/span>"}]}]},"correct":"","level":"3","hint":"","answer":"","type":"json","extra_type":"","time":"0","user_id":"0","test":"0","date":"2019-09-30 09:14:58"},{"id":"2063","post_id":"833","mon_id":"0","chapter_id":"0","question":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","options":{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":10,"ques":"Bu\u1ed5i h\u1ecdp m\u1eb7t c\u1ee7a m\u1ed9t nh\u00f3m h\u1ecdc sinh g\u1ed3m 6 b\u1ea1n. M\u1ed7i b\u1ea1n \u0111\u1ec1u b\u1eaft tay b\u1ea1n kh\u00e1c m\u1ed9t l\u1ea7n. H\u1ecfi c\u00f3 bao nhi\u00eau c\u00e1i b\u1eaft tay?","select":["A. 6","B. 12","C. 15","D. 30"],"hint":"","explain":" H\u01b0\u1edbng d\u1eabn:<\/span><br\/>T\u00ednh s\u1ed1 \u0111\u01b0\u1eddng th\u1eb3ng v\u1ebd \u0111\u01b0\u1ee3c theo c\u00f4ng th\u1ee9c <br\/> $\\dfrac{n . (n - 1)}{2}$ <\/span> <br\/><br\/> B\u00e0i gi\u1ea3i:<\/span> <br\/> V\u00ec m\u1ed7i ng\u01b0\u1eddi \u0111\u1ec1u b\u1eaft tay m\u1ed9t b\u1ea1n kh\u00e1c m\u1ed9t l\u1ea7n n\u00ean m\u1ed7i b\u1ea1n s\u1ebd b\u1eaft tay 5 b\u1ea1n kh\u00e1c \u0111\u01b0\u1ee3c 5 c\u00e1i b\u1eaft tay <br\/> Nh\u01b0ng m\u1ed7i c\u00e1i b\u1eaft tay \u0111\u00e3 \u0111\u01b0\u1ee3c t\u00ednh hai l\u1ea7n <br\/> N\u00ean t\u1ea5t c\u1ea3 c\u00f3 s\u1ed1 c\u00e1i b\u1eaft tay l\u00e0: <br\/> $\\dfrac{6 . 5}{2} = 15$ (c\u00e1i b\u1eaft tay) <br\/> V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0: C <\/span> ","column":2}]}]},"correct":"","level":"3","hint":"","answer":"","type":"json","extra_type":"","time":"0","user_id":"0","test":"0","date":"2019-09-30 09:14:58"}]}