{"segment":[{"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["3"],["1"],["4"],["-12"]]],"list":[{"point":10,"width":80,"type_input":"","ques":"Cho $x$ v\u00e0 $y$ l\u00e0 hai \u0111\u1ea1i l\u01b0\u1ee3ng t\u1ec9 l\u1ec7 ngh\u1ecbch. <br\/> \u0110i\u1ec1n v\u00e0o c\u00e1c \u00f4 tr\u1ed1ng trong b\u1ea3ng sau: <br\/> <table><tr><td>x<\/td><td>$-3$<\/td><td>$-2$<\/td><td>1<\/td><td>_input_<\/td><td>_input_<\/td><\/tr><tr><td>y<\/td><td>_input_<\/td><td>6<\/td><td>_input_<\/td><td>$-4$<\/td><td>$-12$<\/td><\/tr><\/table>","explain":"V\u00ec $x$ v\u00e0 $y$ l\u00e0 hai \u0111\u1ea1i l\u01b0\u1ee3ng t\u1ec9 l\u1ec7 ngh\u1ecbch n\u00ean: $a = xy = (-2).6 = -12 $ <br\/> K\u1ebft qu\u1ea3 \u0111\u01b0\u1ee3c cho trong b\u1ea3ng sau: <br\/> <table><tr><td>x<\/td><td>$-3$<\/td><td>$-2$<\/td><td>1<\/td><td>3<\/td><td>1<\/td><\/tr><tr><td>y<\/td><td>4<\/td><td>6<\/td><td>$-12$<\/td><td>$-4$<\/td><td>$-12$<\/td><\/tr><\/table> "}],"id_ques":861},{"title":"\u0110i\u1ec1n t\u1eeb th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank_random","correct":[[["15"]]],"list":[{"point":10,"width":20,"content":"","type_input":"","ques":"10 c\u00f4ng nh\u00e2n l\u00e0m xong m\u1ed9t c\u00f4ng vi\u1ec7c trong 18 ng\u00e0y. H\u1ecfi mu\u1ed1n l\u00e0m xong c\u00f4ng vi\u1ec7c \u0111\u00f3 trong 12 ng\u00e0y th\u00ec c\u1ea7n bao nhi\u00eau c\u00f4ng nh\u00e2n? <br\/> <b> \u0110\u00e1p s\u1ed1: <\/b> $\\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{} $ ","explain":"<span class='basic_left'>T\u00f3m t\u1eaft \u0111\u1ec1 b\u00e0i: <br\/> <table><tr><th>Th\u1eddi gian<\/th><th>S\u1ed1 c\u00f4ng nh\u00e2n<\/th><\/tr><tr><td>18 ng\u00e0y<\/td><td>10 c\u00f4ng nh\u00e2n<\/td><\/tr><tr><td>12 ng\u00e0y <\/td><td>x c\u00f4ng nh\u00e2n?<\/td><\/tr><\/table> <br\/> V\u1edbi c\u00f9ng m\u1ed9t c\u00f4ng vi\u1ec7c th\u00ec th\u1eddi gian v\u00e0 s\u1ed1 ng\u01b0\u1eddi l\u00e0m l\u00e0 hai \u0111\u1ea1i l\u01b0\u1ee3ng t\u1ec9 l\u1ec7 ngh\u1ecbch. <br\/> Theo t\u00ednh ch\u1ea5t c\u1ee7a hai \u0111\u1ea1i l\u01b0\u1ee3ng t\u1ec9 l\u1ec7 ngh\u1ecbch, ta c\u00f3: $\\dfrac{18}{12} = \\dfrac{x}{10} $ <br\/> Suy ra: $x = \\dfrac{18.10}{12} = 15 $ <br\/> V\u1eady mu\u1ed1n ho\u00e0n th\u00e0nh c\u00f4ng vi\u1ec7c trong 12 ng\u00e0y th\u00ec c\u1ea7n 15 c\u00f4ng nh\u00e2n. <br\/><br\/> <span class='basic_pink'> V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0 $ 15 $<\/span>"}],"id_ques":862},{"title":"\u0110i\u1ec1n t\u1eeb th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank_random","correct":[[["33"],["44"],["99"]]],"list":[{"point":10,"width":20,"content":"","type_input":"","ques":"Chia s\u1ed1 176 th\u00e0nh ba ph\u1ea7n t\u1ec9 l\u1ec7 thu\u1eadn v\u1edbi c\u00e1c s\u1ed1 3; 4; 9. <br\/>T\u00edm ba ph\u1ea7n \u0111\u00f3.<br\/> <b> \u0110\u00e1p s\u1ed1: <\/b> $\\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}; \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}; \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}$","explain":"<span class='basic_left'>G\u1ecdi ba ph\u1ea7n c\u1ea7n t\u00ecm l\u00e0 $x, y, z$ <br\/> Theo \u0111\u1ec1 b\u00e0i ta c\u00f3: $\\dfrac{x}{3} = \\dfrac{y}{4} = \\dfrac{z}{9} = \\dfrac{x+y+z}{3+4+9} = \\dfrac{176}{16} = 11 $ <br\/> Do \u0111\u00f3: $x = 3.11 = 33 \\\\ y = 4.11 = 44 \\\\ z = 9.11 = 99 $ <br\/><br\/> <span class='basic_pink'>V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u1ea7n l\u01b0\u1ee3t l\u00e0 $ 33, 44, 99. $ <\/span>"}],"id_ques":863},{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng ","title_trans":"","temp":"fill_the_blank","correct":[[["450"]]],"list":[{"point":10,"width":50,"type_input":"","ques":" <span class='basic_left'> Hai \u00f4 t\u00f4 kh\u1edfi h\u00e0nh c\u00f9ng m\u1ed9t l\u00fac t\u1eeb hai \u0111\u1ecba \u0111i\u1ec3m A v\u00e0 B, \u0111i ng\u01b0\u1ee3c chi\u1ec1u nhau. Khi g\u1eb7p nhau \u00f4 t\u00f4 t\u1eeb B \u0111i \u0111\u01b0\u1ee3c qu\u00e3ng \u0111\u01b0\u1eddng d\u00e0i h\u01a1n qu\u00e3ng \u0111\u01b0\u1eddng \u00f4 t\u00f4 \u0111i t\u1eeb A l\u00e0 50 km. T\u00ednh qu\u00e3ng \u0111\u01b0\u1eddng AB. (bi\u1ebft v\u1eadn t\u1ed1c c\u1ee7a \u00f4 t\u00f4 \u0111i t\u1eeb A v\u00e0 B t\u1ec9 l\u1ec7 thu\u1eadn v\u1edbi 4 v\u00e0 5) <br\/><b> \u0110\u00e1p s\u1ed1: <\/b> $\\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{} (km)$ <\/span> ","hint":"L\u1ea5y t\u1ec9 l\u1ec7 v\u1ec1 qu\u00e3ng \u0111\u01b0\u1eddng v\u00e0 v\u1eadn t\u1ed1c. ","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> B\u01b0\u1edbc 1: X\u00e1c \u0111\u1ecbnh quan h\u1ec7 t\u1ec9 l\u1ec7 thu\u1eadn gi\u1eefa hai \u0111\u1ea1i l\u01b0\u1ee3ng $y$ v\u00e0 $x$. <br\/> B\u01b0\u1edbc 2: \u00c1p d\u1ee5ng t\u00ednh ch\u1ea5t t\u1ec9 s\u1ed1 hai gi\u00e1 tr\u1ecb b\u1ea5t k\u00ec c\u1ee7a \u0111\u1ea1i l\u01b0\u1ee3ng n\u00e0y b\u1eb1ng t\u1ec9 s\u1ed1 hai gi\u00e1 tr\u1ecb t\u01b0\u01a1ng \u1ee9ng c\u1ee7a \u0111\u1ea1i l\u01b0\u1ee3ng kia. <\/span> <br\/><br\/><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span> <br\/> <span class='basic_left'> G\u1ecdi qu\u00e3ng \u0111\u01b0\u1eddng \u00f4 t\u00f4 xu\u1ea5t ph\u00e1t t\u1eeb A \u0111\u1ebfn ch\u1ed7 g\u1eb7p nhau l\u00e0 $S_{1}$ (km), v\u1edbi v\u1eadn t\u1ed1c l\u00e0 $v_{1}$ (km\/h); ($S_1; v_1 > 0$). <br\/> Qu\u00e3ng \u0111\u01b0\u1eddng \u00f4 t\u00f4 xu\u1ea5t ph\u00e1t t\u1eeb B \u0111\u1ec5n ch\u1ed7 g\u1eb7p nhau l\u00e0 $S_{2}$ (km), v\u1edbi v\u1eadn t\u1ed1c l\u00e0 $v_{2}$ (km\/h) ($S_2;v_2 > 0$). <br\/> Theo \u0111\u1ec1 b\u00e0i ta c\u00f3: $S_{2} - S_{1} = 50$ v\u00e0 $ \\dfrac{v_{1}}{4} = \\dfrac{v_{2}}{5} \\Rightarrow \\dfrac{v_{1}}{v_{2}} = \\dfrac{4}{5} $ <br\/> V\u1edbi c\u00f9ng m\u1ed9t th\u1eddi gian th\u00ec qu\u00e3ng \u0111\u01b0\u1eddng v\u00e0 v\u1eadn t\u1ed1c l\u00e0 hai \u0111\u1ea1i l\u01b0\u1ee3ng t\u1ec9 l\u1ec7 thu\u1eadn, n\u00ean ta c\u00f3: <br\/> $ \\dfrac{S_{1}}{S_{2}} = \\dfrac{v_{1}}{v_{2}} = \\dfrac{4}{5} $ <br\/> Do \u0111\u00f3 $\\dfrac{S_{1}}{4} = \\dfrac{S_{2}}{5} = \\dfrac{S_{2}-S_{1}}{5-4} = \\dfrac{50}{1} = 50 $ <br\/> V\u1eady $S_{1} = 50.4 = 200 \\\\ S_{2} = 50.5 = 250$ <br\/> Qu\u00e3ng \u0111\u01b0\u1eddng AB d\u00e0i l\u00e0 : 200 + 250 = 450 (km) <br\/><br\/><span class='basic_pink'> V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0 $ 450 $ <\/span><\/span> "}],"id_ques":864},{"title":"X\u00e1c \u0111\u1ecbnh h\u1ec7 t\u1ecda \u0111\u1ed9 - d\u1ea1ng click","title_trans":"","temp":"coordinates","correct":[["1,2"]],"list":[{"point":10,"toa_do":[["0","0"]],"is_click":1,"name_toado_click":"A","draw_line":0,"ques":"_inputduongthang_ \u0110\u00e1nh d\u1ea5u \u0111i\u1ec3m $A(1; 2)$ tr\u00ean m\u1eb7t ph\u1eb3ng t\u1ecda \u0111\u1ed9. ","explain":"T\u1ea1i \u0111i\u1ec3m 1 tr\u00ean tr\u1ee5c ho\u00e0nh v\u1ebd \u0111\u01b0\u1eddng th\u1eb3ng vu\u00f4ng g\u00f3c v\u1edbi tr\u1ee5c ho\u00e0nh. <br\/> T\u1ea1i \u0111i\u1ec3m 2 tr\u00ean tr\u1ee5c tung v\u1ebd \u0111\u01b0\u1eddng th\u1eb3ng vu\u00f4ng g\u00f3c v\u1edbi tr\u1ee5c tung, <br\/> hai \u0111\u01b0\u1eddng vu\u00f4ng g\u00f3c c\u1eaft nhau t\u1ea1i $A(1; 2)$ <br\/><br\/> <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/daiso/bai19/lv3/img\/D7B19-01.png' \/><\/center>"}],"id_ques":865},{"title":"V\u1ebd \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1.","title_trans":"","temp":"coordinates","correct":[["1,-2.5","-1,2.5"]],"list":[{"point":10,"toa_do":[["0","0",""]],"is_click":1,"name_toado_click":"A","draw_line":1,"ques":"V\u1ebd \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y = \\dfrac{-5}{2}x $ <br\/> <br\/>_inputduongthang_ <br\/> H\u00e3y click th\u00eam m\u1ed9t \u0111i\u1ec3m thu\u1ed9c \u0111\u1ed3 th\u1ecb \u0111\u1ec3 v\u1ebd \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1.","explain":"\u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y = \\dfrac{-5}{2}x $ l\u00e0 \u0111\u01b0\u1eddng th\u1eb3ng $OA$ v\u1edbi $O(0; 0)$ v\u00e0 $A(1; -2,5)$ <br\/> <br\/><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/daiso/bai19/lv3/img\/D7B19-02.png' \/><\/center> "}],"id_ques":866},{"title":"V\u1ebd \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1.","title_trans":"","temp":"coordinates","correct":[["4,-0.5","-4,0.5"]],"list":[{"point":10,"toa_do":[["0","0",""]],"is_click":1,"name_toado_click":"A","draw_line":1,"ques":"Cho \u0111i\u1ec3m $C\\left(-2; \\dfrac{1}{4} \\right) $ thu\u1ed9c \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y = ax .$ X\u00e1c \u0111\u1ecbnh a v\u00e0 v\u1ebd \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 v\u1edbi a v\u1eeba t\u00ecm \u0111\u01b0\u1ee3c. <br\/> <br\/>_inputduongthang_ <br\/> H\u00e3y click th\u00eam m\u1ed9t \u0111i\u1ec3m thu\u1ed9c \u0111\u1ed3 th\u1ecb \u0111\u1ec3 v\u1ebd \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1.","explain":" Thay $x = -2; y = \\dfrac{1}{4} $ v\u00e0o h\u00e0m s\u1ed1 $y = ax $ ta \u0111\u01b0\u1ee3c: <br\/> $\\dfrac{1}{4} = a.(-2) \\\\ \\Rightarrow a = \\dfrac{-1}{8} $ <br\/> H\u00e0m s\u1ed1 \u0111\u00e3 cho c\u00f3 d\u1ea1ng: $y = \\dfrac{-1}{8}x $ <br\/> \u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y = \\dfrac{-1}{8}x $ l\u00e0 \u0111\u01b0\u1eddng th\u1eb3ng $OA$ v\u1edbi $O(0; 0)$ v\u00e0 $A(4; -0,5)$ <br\/><br\/><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/daiso/bai19/lv3/img\/D7B19-07.png' \/><\/center> "}],"id_ques":867},{"title":"Ch\u1ecdn <u>nh\u1eefng<\/u> \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"Ch\u1ecdn \u0111\u01b0\u1ee3c nhi\u1ec1u \u0111\u00e1p \u00e1n","temp":"checkbox","correct":[["1","3","4"]],"list":[{"point":10,"img":"","ques":"Cho h\u00e0m s\u1ed1 $y = \\dfrac{2}{x} .$ Nh\u1eefng \u0111i\u1ec3m n\u00e0o sau \u0111\u00e2y thu\u1ed9c \u0111\u1ed3 th\u1ecb c\u1ee7a h\u00e0m s\u1ed1 tr\u00ean? ","column":1,"number_true":3,"select":["$A(2; 1)$","$B(-1; 2) $","$C\\left(-\\dfrac{2}{5}; -5 \\right) $","$D\\left(3; \\dfrac{2}{3} \\right) $"],"explain":"* Thay $x = 2, y = 1 $ v\u00e0o h\u00e0m s\u1ed1 $y = \\dfrac{2}{x}$, ta \u0111\u01b0\u1ee3c: $1 = \\dfrac{2}{2} $ <br\/> $\\Rightarrow $ \u0111i\u1ec3m A(2; 1) thu\u1ed9c \u0111\u1ed3 th\u1ecb c\u1ee7a h\u00e0m s\u1ed1 tr\u00ean. <br\/> T\u01b0\u01a1ng t\u1ef1, ta c\u0169ng th\u1ea5y c\u00e1c \u0111i\u1ec3m $C\\left(-\\dfrac{2}{5}; -5 \\right), D\\left(3; \\dfrac{2}{3} \\right) $ c\u00f3 ho\u00e0nh \u0111\u1ed9 v\u00e0 tung \u0111\u1ed9 th\u1ecfa m\u00e3n \u0111\u1eb3ng th\u1ee9c $y = \\dfrac{2}{x} $ <br\/> V\u1eady c\u00f3 3 \u0111i\u1ec3m A, C, D thu\u1ed9c \u0111\u1ed3 th\u1ecb c\u1ee7a h\u00e0m s\u1ed1 \u0111\u00e3 cho. "}],"id_ques":868},{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":10,"ques":"\u0110i\u1ec3m $M(-2; 3)$ kh\u00f4ng thu\u1ed9c \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 n\u00e0o sau \u0111\u00e2y? ","select":["A. $y = -\\dfrac{3}{2}x $","B. $y = 3x + 9 $","C. $y = x^{2} - 1 $","D. $y = -x + 5 $"],"explain":"\u0110i\u1ec3m $M(-2; 3)$ kh\u00f4ng thu\u1ed9c \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y = -x + 5 $ <br\/> Th\u1eadt v\u1eady, thay $x = -2 $ v\u00e0o $y = -x + 5$ ta \u0111\u01b0\u1ee3c $y = -(-2) + 5 = 7 \\neq 3$ <br\/><br\/> <span class='basic_pink'>\u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0 D. <\/span> ","column":2}],"id_ques":869},{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["8"],["4"]]],"list":[{"point":10,"width":50,"type_input":"","ques":" <span class='basic_left'>Tr\u00ean m\u1eb7t ph\u1eb3ng t\u1ecda \u0111\u1ed9 Oxy cho h\u00ecnh vu\u00f4ng ABCD c\u00f3 $A(-4; -1), B(-2; -1)$ v\u00e0 $C(-2; -3).$ T\u00ednh chu vi v\u00e0 di\u1ec7n t\u00edch c\u1ee7a h\u00ecnh vu\u00f4ng ABCD? <br\/> <b> \u0110\u00e1p s\u1ed1: <\/b> Chu vi b\u1eb1ng $\\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{} \\quad $ (\u0111\u01a1n v\u1ecb \u0111\u1ed9 d\u00e0i)<br\/> $\\qquad $ Di\u1ec7n t\u00edch: = $\\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{} \\quad $ (\u0111\u01a1n v\u1ecb di\u1ec7n t\u00edch)<\/span> ","hint":"X\u00e1c \u0111\u1ecbnh t\u1ecda \u0111\u1ed9 \u0111i\u1ec3m D c\u1ee7a h\u00ecnh vu\u00f4ng ABCD.","explain":" <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/daiso/bai19/lv3/img\/D7B19-08.png' \/><\/center> <span class='basic_left'>Bi\u1ec3u di\u1ec5n c\u00e1c \u0111i\u1ec3m $A(-4; -1), B(-2; -1)$ v\u00e0 $C(-2; -3)$ tr\u00ean m\u1eb7t ph\u1eb3ng t\u1ecda \u0111\u1ed9 $Oxy.$ <br\/> Theo b\u00e0i c\u00f3 $ABCD$ l\u00e0 h\u00ecnh vu\u00f4ng n\u00ean t\u1ecda \u0111\u1ed9 c\u1ee7a \u0111i\u1ec3m $D$ l\u00e0 $D(-4; -3)$ <br\/> C\u00f3 $AB = 2$ (\u0111\u01a1n v\u1ecb \u0111\u1ed9 d\u00e0i) n\u00ean: <br\/> Chu vi h\u00ecnh vu\u00f4ng $ABCD$ b\u1eb1ng $2.4 = 8$ (\u0111\u01a1n v\u1ecb \u0111\u1ed9 d\u00e0i) <br\/> Di\u1ec7n t\u00edch h\u00ecnh vu\u00f4ng $ABCD$ b\u1eb1ng: $2^{2} = 4 $ (\u0111\u01a1n v\u1ecb di\u1ec7n t\u00edch) <br\/><br\/> <span class='basic_pink'> V\u1eady c\u00e1c s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u1ea7n l\u01b0\u1ee3t l\u00e0 $ 8; 4 $ <\/span> "}],"id_ques":870}],"id_ques":0}],"lesson":{"save":1,"level":3,"time":44}}