{"segment":[{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["180"]]],"list":[{"point":10,"width":50,"type_input":"","ques":" Cho H\u00ecnh 17 <br\/> <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai3/lv3/img\/H7C13-17.png' \/><\/center> <br\/> S\u1ed1 \u0111o g\u00f3c $\\widehat{BAx'} + \\widehat{ABy'} $ l\u00e0: $\\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}^{o} $ ","hint":"","explain":" <span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span> <br\/> N\u1ebfu m\u1ed9t \u0111\u01b0\u1eddng th\u1eb3ng c\u1eaft hai \u0111\u01b0\u1eddng th\u1eb3ng v\u00e0 trong c\u00e1c g\u00f3c t\u1ea1o th\u00e0nh c\u00f3 m\u1ed9t c\u1eb7p g\u00f3c so le trong b\u1eb1ng nhau th\u00ec: <br\/> - Hai c\u1eb7p g\u00f3c trong c\u00f9ng ph\u00eda b\u00f9 nhau. <\/span> <br\/> <br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span> <br\/> Ta c\u00f3: $\\widehat{zAx'} + \\widehat{BAx'} = 180^{o} $ (hai g\u00f3c k\u1ec1 b\u00f9) <br\/> Suy ra $ \\widehat{BAx'}$$ = 180^{o} - \\widehat{zAx'} \\\\ = 180^{o} - 70^{o} \\\\= 110^{o} = \\widehat{yBA} $ <br\/> C\u00f3 $\\widehat{BAx'} $ v\u00e0 $\\widehat{yBA} $ l\u00e0 hai g\u00f3c so le trong b\u1eb1ng nhau <br\/> N\u00ean: $\\widehat{BAx'} + \\widehat{ABy'} = 180^{o} $(hai g\u00f3c trong c\u00f9ng ph\u00eda) <br\/> <br\/><span class='basic_pink'> \u0110\u00e1p s\u1ed1 l\u00e0: $180^{o} $ <\/span><\/span> "}]}],"id_ques":1411},{"time":14,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":10,"ques":" Cho H\u00ecnh 11, bi\u1ebft $\\widehat{A_{1}} = \\widehat{B_{5}} $ <br\/> Kh\u1eb3ng \u0111\u1ecbnh n\u00e0o sau \u0111\u00e2y kh\u00f4ng \u0111\u00fang? <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai3/lv3/img\/H7C13-11.png' \/><\/center> ","select":["A. $\\widehat{A_{3}} = \\widehat{B_{7}} $ ","B. $\\widehat{A_{4}} = \\widehat{B_{8}} $ ","C. $\\widehat{A_{2}} = \\widehat{B_{6}} $ ","D. $\\widehat{A_{1}} = \\widehat{B_{6}} $ "],"hint":"","explain":" Ta c\u00f3: $ \\widehat{A_{1}} = \\widehat{A_{3}}; \\widehat{B_{5}} = \\widehat{B_{7}} $ (\u0111\u1ed1i \u0111\u1ec9nh) <br\/> m\u00e0 $\\widehat{A_{1}} = \\widehat{B_{5}} \\Rightarrow \\widehat{A_{3}} = \\widehat{B_{7}} \\Rightarrow $ (A \u0111\u00fang). <br\/> Ta c\u00f3: $\\widehat{A_{1}} + \\widehat{A_{4}} = 180^{o}; \\widehat{B_{5}} + \\widehat{B_{8}} = 180^{o} $ (hai g\u00f3c k\u1ec1 b\u00f9) <br\/> m\u00e0 $\\widehat{A_{1}} = \\widehat{B_{5}} \\Rightarrow \\widehat{A_{4}} = \\widehat{B_{8}} \\Rightarrow $ (B \u0111\u00fang). <br\/> Ta c\u00f3: $\\widehat{A_{1}} + \\widehat{A_{2}} = 180^{o}; \\widehat{B_{5}} + \\widehat{B_{6}} = 180^{o} $ (hai g\u00f3c k\u1ec1 b\u00f9) <br\/> m\u00e0 $\\widehat{A_{1}} = \\widehat{B_{5}} \\Rightarrow \\widehat{A_{2}} = \\widehat{B_{6}} \\Rightarrow $ (C \u0111\u00fang). <br\/> Ta c\u00f3 $\\widehat{B_{5}} + \\widehat{B_{6}} = 180^{o} $ (hai g\u00f3c k\u1ec1 b\u00f9) m\u00e0 $\\widehat{A_{1}} = \\widehat{B_{5}} \\Rightarrow \\widehat{A_{1}} + \\widehat{B_{6}} = 180^{o} \\Rightarrow $ (D Sai). <br\/><br\/> <span class='basic_pink'> Ch\u1ecdn D. <\/span><\/span> <span class='basic_left'> <u> Nh\u1eadn x\u00e9t: <\/u> <br\/> N\u1ebfu m\u1ed9t \u0111\u01b0\u1eddng th\u1eb3ng c\u1eaft hai \u0111\u01b0\u1eddng th\u1eb3ng v\u00e0 trong c\u00e1c g\u00f3c t\u1ea1o th\u00e0nh c\u00f3 m\u1ed9t c\u1eb7p g\u00f3c \u0111\u1ed3ng v\u1ecb b\u1eb1ng nhau th\u00ec: <br\/> - C\u00e1c c\u1eb7p g\u00f3c \u0111\u1ed3ng v\u1ecb c\u00f2n l\u1ea1i b\u1eb1ng nhau. <br\/> - Hai c\u1eb7p g\u00f3c so le trong b\u1eb1ng nhau. <br\/> - Hai c\u1eb7p g\u00f3c trong c\u00f9ng ph\u00eda b\u00f9 nhau. <br\/> - Hai c\u1eb7p g\u00f3c ngo\u00e0i c\u00f9ng ph\u00eda b\u00f9 nhau. <\/span> ","column":2}]}],"id_ques":1412},{"time":14,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":10,"ques":" Cho H\u00ecnh 32, bi\u1ebft $\\widehat{S_{1}} + \\widehat{R_{2}} = 180^{o}. $ <br\/> <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai3/lv3/img\/H7C13-32.png' \/><\/center> ","select":["A. $\\widehat{S_{2}} < \\widehat{R_{3}}; \\widehat{S_{4}} > \\widehat{R_{1}} $ ","B. $\\widehat{S_{1}} < \\widehat{R_{3}}; \\widehat{S_{3}} > \\widehat{R_{1}} $ ","C. $\\widehat{S_{3}} + \\widehat{R_{4}} = \\widehat{S_{2}} + \\widehat{R_{1}} $ ","D. $\\widehat{S_{3}} + \\widehat{R_{1}} = 180^{o} $ "],"hint":"","explain":" <span class='basic_pink'> \u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0 C. <br\/> $\\widehat{S_{3}} + \\widehat{R_{4}} = \\widehat{S_{2}} + \\widehat{R_{1}} = 180^{o} $<\/span><\/span> ","column":2}]}],"id_ques":1413},{"time":14,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00fang hay sai","title_trans":"","temp":"true_false","correct":[["t","f","f","t","f","t"]],"list":[{"point":10,"ques":" Cho h\u00ecnh v\u1ebd (H\u00ecnh 31). <br\/> H\u00e3y x\u00e1c \u0111\u1ecbnh c\u00e2u \u0111\u00fang, sai trong c\u00e1c c\u00e2u sau: <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai3/lv3/img\/H7C13-31.png' \/><\/center> ","col_name":["","\u0110\u00fang","Sai"],"arr_ques":["$\\widehat{ABC}$ v\u00e0 $\\widehat{BCx'}$ l\u00e0 hai g\u00f3c so le trong ","$\\widehat{BAC}$ v\u00e0 $\\widehat{ACB}$ l\u00e0 hai g\u00f3c so le trong ","$\\widehat{xAB}$ v\u00e0 $\\widehat{BCx'}$ l\u00e0 hai g\u00f3c \u0111\u1ed3ng v\u1ecb","$\\widehat{y'BC}$ v\u00e0 $\\widehat{x'Cz'}$ l\u00e0 hai g\u00f3c \u0111\u1ed3ng v\u1ecb","$\\widehat{yAC}$ v\u00e0 $\\widehat{BCA}$ l\u00e0 hai g\u00f3c trong c\u00f9ng ph\u00eda ","$\\widehat{xAB}$ v\u00e0 $\\widehat{zBA}$ l\u00e0 hai g\u00f3c trong c\u00f9ng ph\u00eda "],"hint":"","explain":["\u0110\u00fang","<br\/> Sai. V\u00ec $\\widehat{BAC}$ v\u00e0 $\\widehat{ACB}$ l\u00e0 hai g\u00f3c trong c\u00f9ng ph\u00eda. ","<br\/> Sai. V\u00ec $\\widehat{xAB}$ v\u00e0 $\\widehat{BCx'}$ l\u00e0 hai g\u00f3c ngo\u00e0i c\u00f9ng ph\u00eda ","<br\/> \u0110\u00fang ","<br\/> Sai. V\u00ec $\\widehat{yAC}$ v\u00e0 $\\widehat{BCA}$ l\u00e0 hai g\u00f3c so le trong","<br\/> \u0110\u00fang"]}]}],"id_ques":1414},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["105"],["90"]]],"list":[{"point":10,"width":50,"type_input":"","ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai3/lv3/img\/H7C13-30.png' \/><\/center><br\/> <span class='basic_left'> a) T\u00ednh $\\widehat{ADC} = \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}^{o} $ <br\/> b) N\u1ebfu bi\u1ebft $\\widehat{BAD} + \\widehat{ADC} + \\widehat{DCB} + \\widehat{CBA} = 360^{o} $ <br\/> T\u00ednh $ x = \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{} $ <\/span> ","hint":"","explain":" <span class='basic_left'> a) Ta c\u00f3: $\\widehat{ADz} + \\widehat{ADC} = 180^{o} $ (hai g\u00f3c k\u1ec1 b\u00f9) <br\/> Suy ra $\\widehat{ADC} $$ = 180^{o} - \\widehat{ADz} \\\\ = 180^{o} - 75^{o} \\\\ = 105^{o} $ <br\/> b) T\u01b0\u01a1ng t\u1ef1 ta t\u00ednh \u0111\u01b0\u1ee3c $\\widehat{DCB} = 75^{o} $ <br\/> Theo b\u00e0i c\u00f3 $\\widehat{BAD} + \\widehat{ADC} + \\widehat{DCB} + \\widehat{CBA} = 360^{o} \\\\ \\Rightarrow \\widehat{BAD} = 360^{o} - (105^{o} + 75^{o} + 90^{o} ) \\\\ = 90^{o} $ <br\/> Do \u0111\u00f3 : $\\widehat{yAB} = 180^{o} - 90^{o} = 90^{o} $ <br\/> Hay x = 90 <\/span> <br\/> <br\/> <span class='basic_pink'> \u0110\u00e1p s\u1ed1: $\\widehat{ADC} = 180^{o} \\\\ x = 90 $ <\/span><\/span> "}]}],"id_ques":1415},{"time":14,"part":[{"time":3,"title":"N\u1ed1i t\u1eeb ho\u1eb7c c\u1ee5m t\u1eeb \u1edf c\u1ed9t b\u00ean tr\u00e1i v\u1edbi c\u1ed9t b\u00ean ph\u1ea3i \u0111\u1ec3 \u0111\u01b0\u1ee3c c\u00e2u ho\u00e0n ch\u1ec9nh","title_trans":"","audio":"","temp":"matching","correct":[["4","2","1","3","5"]],"list":[{"point":10,"image":"https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai3/lv3/img\/H7C13-29.png","left":["$\\widehat{B_{4}} $ v\u00e0 ... l\u00e0 m\u1ed9t c\u1eb7p g\u00f3c so le trong. ","$\\widehat{B_{4}} $ v\u00e0 ... l\u00e0 m\u1ed9t c\u1eb7p g\u00f3c trong c\u00f9ng ph\u00eda. ","$\\widehat{C_{3}} $ v\u00e0 ... l\u00e0 m\u1ed9t c\u1eb7p g\u00f3c k\u1ec1 b\u00f9. ","$\\widehat{A_{2}} $ v\u00e0 ... l\u00e0 m\u1ed9t c\u1eb7p g\u00f3c \u0111\u1ed3ng v\u1ecb. ","$\\widehat{B_{2}} $ v\u00e0 ... l\u00e0 m\u1ed9t c\u1eb7p g\u00f3c \u0111\u1ed1i \u0111\u1ec9nh. "],"right":["$\\widehat{C_{2}} $ ","$\\widehat{C_{3}} $ "," $\\widehat{B_{2}} $ ","$\\widehat{A_{2}} $ ","$\\widehat{B_{4}} $ "],"top":100,"hint":"","explain":"$\\widehat{B_{4}} $ v\u00e0 $\\widehat{A_{2}} $ l\u00e0 m\u1ed9t c\u1eb7p g\u00f3c so le trong. <br\/> $\\widehat{B_{4}} $ v\u00e0 $\\widehat{C_{3}} $ l\u00e0 m\u1ed9t c\u1eb7p g\u00f3c trong c\u00f9ng ph\u00eda. <br\/> $\\widehat{C_{3}} $ v\u00e0 $\\widehat{C_{2}} $ l\u00e0 m\u1ed9t c\u1eb7p g\u00f3c k\u1ec1 b\u00f9. <br\/> $\\widehat{A_{2}} $ v\u00e0 $\\widehat{B_{2}} $ l\u00e0 m\u1ed9t c\u1eb7p g\u00f3c \u0111\u1ed3ng v\u1ecb. <br\/> $\\widehat{B_{2}} $ v\u00e0 $\\widehat{B_{4}} $ l\u00e0 m\u1ed9t c\u1eb7p g\u00f3c \u0111\u1ed1i \u0111\u1ec9nh. "}]}],"id_ques":1416},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["144"],["144"]]],"list":[{"point":10,"width":50,"type_input":"","ques":"<span class='basic_left'>Hai \u0111\u01b0\u1eddng th\u1eb3ng mn v\u00e0 pq kh\u00f4ng c\u00f3 \u0111i\u1ec3m chung. \u0110\u01b0\u1eddng th\u1eb3ng xy c\u1eaft \u0111\u01b0\u1eddng th\u1eb3ng mn t\u1ea1i \u0111i\u1ec3m U v\u00e0 c\u1eaft \u0111\u01b0\u1eddng th\u1eb3ng pq t\u1ea1i \u0111i\u1ec3m V. Bi\u1ebft r\u1eb1ng: $\\widehat{V_{1}} $ v\u00e0 $\\widehat{U_{1}} $ l\u00e0 hai g\u00f3c trong c\u00f9ng ph\u00eda; $\\widehat{U_{2}} $ v\u00e0 $\\widehat{V_{1}} $ l\u00e0 hai g\u00f3c \u0111\u1ed3ng v\u1ecb; $\\widehat{V_{2}} $ v\u00e0 $\\widehat{U_{1}} $ l\u00e0 hai g\u00f3c so le trong. S\u1ed1 \u0111o g\u00f3c $\\widehat{U_{1}} = \\widehat{V_{2}} = 36^{o} $ <br\/> T\u00ednh: $\\widehat{V_{1}} = \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}^{o} \\\\ \\widehat{U_{2}} = \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}^{o}$<\/span> ","hint":"","explain":" <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai3/lv3/img\/H7C13-26.png' \/><\/center> <br\/> Ta c\u00f3: $\\widehat{U_{1}} = \\widehat{V_{2}} = 36^{o} $ l\u00e0 hai g\u00f3c so le trong b\u1eb1ng nhau. <br\/> N\u00ean $\\widehat{V_{1}} = \\widehat{U_{2}} = 180 - 36^{o} = 144^{o} $ (hai g\u00f3c \u0111\u1ed3ng v\u1ecb) <br\/> <br\/> <span class='basic_pink'> \u0110\u00e1p s\u1ed1 l\u00e0: $144^{o}; 144^{o} $ <\/span><\/span> "}]}],"id_ques":1417},{"time":14,"part":[{"time":3,"title":"N\u1ed1i t\u1eeb ho\u1eb7c c\u1ee5m t\u1eeb \u1edf c\u1ed9t b\u00ean tr\u00e1i v\u1edbi c\u1ed9t b\u00ean ph\u1ea3i \u0111\u1ec3 \u0111\u01b0\u1ee3c c\u00e2u ho\u00e0n ch\u1ec9nh","title_trans":"","audio":"","temp":"matching","correct":[["2","3","4","1"]],"list":[{"point":10,"image":"https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai3/lv3/img\/H7C13-25.png","left":["$\\widehat{EDC} $ v\u00e0 $\\widehat{AEB} $ l\u00e0 c\u1eb7p g\u00f3c ","$\\widehat{BED} $ v\u00e0 $\\widehat{CDE} $ l\u00e0 c\u1eb7p g\u00f3c","$\\widehat{TAB} $ v\u00e0 $\\widehat{DEB} $ l\u00e0 c\u1eb7p g\u00f3c","$\\widehat{EAB} $ v\u00e0 $\\widehat{MEA} $ l\u00e0 c\u1eb7p g\u00f3c"],"right":["so le trong.","\u0111\u1ed3ng v\u1ecb.","trong c\u00f9ng ph\u00eda.","ngo\u00e0i c\u00f9ng ph\u00eda."],"top":100,"hint":"","explain":"$\\widehat{EDC} $ v\u00e0 $\\widehat{AEB} $ l\u00e0 c\u1eb7p g\u00f3c \u0111\u1ed3ng v\u1ecb. <br\/> $\\widehat{BED} $ v\u00e0 $\\widehat{CDE} $ l\u00e0 c\u1eb7p g\u00f3c trong c\u00f9ng ph\u00eda. <br\/> $\\widehat{TAB} $ v\u00e0 $\\widehat{DEB} $ l\u00e0 c\u1eb7p g\u00f3c ngo\u00e0i c\u00f9ng ph\u00eda. <br\/> $\\widehat{EAB} $ v\u00e0 $\\widehat{MEA} $ l\u00e0 c\u1eb7p g\u00f3c so le trong. "}]}],"id_ques":1418},{"time":14,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":10,"ques":" Hai g\u00f3c ph\u1ee5 nhau c\u00f3 hi\u1ec7u s\u1ed1 \u0111o l\u00e0 $30^{o}$. S\u1ed1 \u0111o c\u1ee7a g\u00f3c nh\u1ecf h\u01a1n l\u00e0: ","select":["A. $45^{o}$ ","B. $50^{o}$ ","C. $30^{o}$","D. $60^{o}$ "],"hint":"Hai g\u00f3c ph\u1ee5 nhau c\u00f3 t\u1ed5ng s\u1ed1 \u0111o l\u00e0 $90^{o}$","explain":" G\u1ecdi s\u1ed1 \u0111o 2 g\u00f3c l\u00e0 a, b (\u0111\u1ed9; a, b > 0) <br\/> Ta c\u00f3: $\\begin{cases} a - b = 30 \\\\ a + b = 90 \\end{cases}$ <br\/> Suy ra $2a = 120 \\Rightarrow a = 60 \\Rightarrow b = 30 $ <br\/> V\u1eady s\u1ed1 \u0111o c\u1ee7a g\u00f3c nh\u1ecf h\u01a1n l\u00e0 $30^{o} $<br\/> <br\/> <span class='basic_pink'> \u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0 C. <\/span><\/span> ","column":4}]}],"id_ques":1419},{"time":14,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n sai","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":10,"ques":" Cho h\u00ecnh v\u1ebd nh\u01b0 sau: <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai3/lv3/img\/H7C13-41.png' \/><\/center> H\u00e3y l\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n sai. ","select":["A. $\\widehat{A_{3}} = \\widehat{B_{3}}$","B. $\\widehat{A_{4}} = \\widehat{B_{4}}$ ","C. $\\widehat{A_{4}} = \\widehat{B_{2}}$","D. $\\widehat{A_{1}} = \\widehat{B_{2}}$ "],"hint":"","explain":"<span class='basic_left'><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai3/lv3/img\/H7C13-41.png' \/><\/center><br\/>$\\widehat{A_{2}} = \\widehat{A_{4}}$ ( hai g\u00f3c \u0111\u1ed1i \u0111\u1ec9nh)<br\/>M\u00e0 $\\widehat{A_{2}} = 50^{o}$ n\u00ean $\\widehat{A_{4}} = 50^{o}$<br\/>L\u1ea1i c\u00f3 $\\widehat{A_{4}}$ v\u00e0 $\\widehat{B_{4}}$ \u1edf v\u1ecb tr\u00ed \u0111\u1ed3ng v\u1ecb, $\\widehat{A_{4}} = \\widehat{B_{4}} = 50^{o}$<br\/> $\\Rightarrow$ Hai g\u00f3c so le trong b\u1eb1ng nhau, hai g\u00f3c \u0111\u1ed3ng v\u1ecb b\u1eb1ng nhau<br\/>Hay $\\widehat{A_{3}} = \\widehat{B_{3}}$, $\\widehat{A_{2}} = \\widehat{B_{2}}$, $\\widehat{A_{1}} = \\widehat{B_{1}}$, $\\widehat{A_{4}} = \\widehat{B_{2}}$, $\\widehat{A_{1}} = \\widehat{B_{3}}$<br\/> V\u1eady \u0111\u00e1p \u00e1n sai l\u00e0: <span class='basic_pink'>D<\/span><\/span> <br\/><\/span> ","column":4}]}],"id_ques":1420}],"lesson":{"save":0,"level":3}}