{"segment":[{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00fang hay sai","title_trans":"","temp":"true_false","correct":[["t","t","t","f"]],"list":[{"point":10,"image":"","col_name":["","\u0110\u00fang","Sai"],"arr_ques":["N\u1ebfu hai tam gi\u00e1c b\u1eb1ng nhau th\u00ec c\u00e1c c\u1ea1nh t\u01b0\u01a1ng \u1ee9ng b\u1eb1ng nhau. ","N\u1ebfu ba c\u1ea1nh c\u1ee7a tam gi\u00e1c n\u00e0y b\u1eb1ng ba c\u1ea1nh c\u1ee7a tam gi\u00e1c kia th\u00ec hai tam \u0111\u00f3 b\u1eb1ng nhau.","N\u1ebfu ba c\u1ea1nh c\u1ee7a tam gi\u00e1c n\u00e0y b\u1eb1ng ba c\u1ea1nh c\u1ee7a tam gi\u00e1c kia th\u00ec ba g\u00f3c c\u1ee7a tam gi\u00e1c n\u00e0y t\u01b0\u01a1ng \u1ee9ng b\u1eb1ng ba g\u00f3c c\u1ee7a tam gi\u00e1c kia.","N\u1ebfu ba g\u00f3c c\u1ee7a tam gi\u00e1c n\u00e0y b\u1eb1ng ba g\u00f3c c\u1ee7a tam gi\u00e1c kia th\u00ec ba c\u1ea1nh c\u1ee7a tam gi\u00e1c n\u00e0y t\u01b0\u01a1ng \u1ee9ng b\u1eb1ng ba c\u1ea1nh c\u1ee7a tam gi\u00e1c kia. "],"explain":["\u0110\u00fang","<br\/>\u0110\u00fang","<br\/>\u0110\u00fang","<br\/> Sai, ch\u1eb3ng h\u1ea1n ta x\u00e9t hai tam gi\u00e1c $ABC$ v\u00e0 $AB'C'$ c\u00f3 $BC \/\/ B'C'$ <br\/> N\u00ean $\\widehat{A} = \\widehat{A}, \\widehat{B} = \\widehat{B'}, \\widehat{C} = \\widehat{C'} $ <br\/> Nh\u01b0ng hai tam gi\u00e1c $ABC$ v\u00e0 $AB'C'$ kh\u00f4ng b\u1eb1ng nhau n\u00ean ba c\u1ea1nh c\u1ee7a tam gi\u00e1c $ABC$ kh\u00f4ng b\u1eb1ng ba c\u1ea1nh c\u1ee7a tam gi\u00e1c $AB'C'$. <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai10/lv3/img\/H7B10-12.png' \/><\/center> "]}]}],"id_ques":1601},{"time":24,"part":[{"title":"\u0110i\u1ec1n t\u1eeb th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["11"]]],"list":[{"point":10,"width":40,"content":"","type_input":"","ques":"Cho $\\triangle ABC = \\triangle MNP $. <br\/> Bi\u1ebft $AB + BC = 7cm$, $MP = 4cm$. <br\/> Chu vi tam gi\u00e1c $ABC$ l\u00e0: $\\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}(cm)$ ","hint":"T\u00ecm \u0111\u1ed9 d\u00e0i c\u1ea1nh $AC$","explain":" Ta c\u00f3: $\\triangle ABC = \\triangle MNP $ n\u00ean $ AC = MP$ <br\/> M\u00e0 $MP=4cm$ $\\Rightarrow$ $AC=4cm$ <br\/> Theo b\u00e0i c\u00f3 $AB + BC = 7cm$ <br\/> V\u1eady chu vi tam gi\u00e1c $ABC$ b\u1eb1ng: <br\/> $AB + BC + AC = 7 + 4 = 11cm.$ <br\/><span class='basic_pink'>\u0110\u00e1p s\u1ed1: 11(cm) <\/span> "}]}],"id_ques":1602},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":10,"ques":" <span class='basic_left'> Cho $\\triangle DEF = \\triangle HIK $ trong \u0111\u00f3 $DE = 2cm, \\widehat{E} = 40^{o}, EF = 5cm$ th\u00ec: <\/span> ","select":[" A. $HI = 2cm, \\widehat{I} = 40^{o}, IK = 5cm $ "," B. $HI = 5cm, \\widehat{I} = 40^{o}, IK = 2cm $"," C. $HI = 2cm, \\widehat{H} = 40^{o}, IK = 5cm $ ","D. $HI = 2cm, \\widehat{K} = 40^{o}, IK = 5cm $ "],"explain":" <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai10/lv3/img\/H7B10-15.png' \/> <\/center> Ta c\u00f3 $\\triangle DEF = \\triangle HIK $ n\u00ean <br\/> $HI = DE = 2cm, \\widehat{E} = \\widehat{I} = 40^{o}, EF = IK = 5cm $ <br\/><br\/><span class='basic_pink'>\u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0 A. <\/span>","column":2}]}],"id_ques":1603},{"time":24,"part":[{"time":3,"title":"S\u1eafp x\u1ebfp c\u00e1c c\u00e2u <br\/> (B\u00e0i n\u00e0y g\u1ed3m 2 c\u00e2u h\u1ecfi)","title_trans":"<b><u> C\u00e2u 1: <\/u><\/b> H\u00e3y s\u1eafp x\u1ebfp c\u00e1c \u00fd ch\u1ee9ng minh tam gi\u00e1c A'BC l\u00e0 tam gi\u00e1c vu\u00f4ng. ","temp":"sequence","correct":[[[1],[4],[2],[3],[5]]],"list":[{"point":10,"image":"https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai10/lv3/img\/H7B10-13.png","left":["X\u00e9t tam gi\u00e1c $ABC$ v\u00e0 $A'BC$ c\u00f3:","Do d\u00f3 $\\widehat{BA'C} = \\widehat{BAC} = 90^{o} $","$AB = A'C, AC = A'B$, c\u1ea1nh $BC$ chung","$\\Rightarrow \\Delta ABC=\\Delta A'BC$ (c - c - c)"," V\u1eady tam gi\u00e1c $A'BC$ l\u00e0 tam gi\u00e1c vu\u00f4ng t\u1ea1i A'. "],"top":55,"explain":"X\u00e9t tam gi\u00e1c $ABC$ v\u00e0 $A'BC$ c\u00f3: <br\/>+ $AB = A'C$ <br\/> + $ AC = A'B$<br\/> + c\u1ea1nh $BC$ chung <br\/> $\\Rightarrow \\triangle ABC = \\triangle A'BC $ (c.c.c) <br\/> Do d\u00f3 $\\widehat{BA'C} = \\widehat{BAC} = 90^{o} $ <br\/> V\u1eady tam gi\u00e1c A'BC l\u00e0 tam gi\u00e1c vu\u00f4ng t\u1ea1i A'. "}]}],"id_ques":1604},{"time":24,"part":[{"title":"\u0110i\u1ec1n t\u1eeb th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"B\u00e0i n\u00e0y g\u1ed3m 2 c\u00e2u h\u1ecfi","temp":"fill_the_blank","correct":[[["30"],["60"]]],"list":[{"point":10,"width":40,"content":"","type_input":"","ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai10/lv3/img\/H7B10-13.png' \/><\/center> <b><u> C\u00e2u 2: <\/u><\/b> T\u00ednh $\\widehat{A'BC} = \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}^{o} \\\\ \\widehat{A'CB} = \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}^{o} $","explain":" Ta c\u00f3 $\\triangle ABC = \\triangle A'BC $ (ch\u1ee9ng minh \u1edf c\u00e2u 1) <br\/> N\u00ean $\\widehat{A'BC} = \\widehat{ACB} = 30^{o} $ <br\/> Tam gi\u00e1c $A'BC$ vu\u00f4ng t\u1ea1i A' n\u00ean $\\widehat{A'BC} + \\widehat{A'CB} = 90^{o} $ <br\/> Suy ra $\\widehat{A'CB} = 90^{o} - 30^{o} = 60^{o}$ <br\/> <br\/> <span class='basic_pink'> V\u1eady $\\widehat{A'BC} = 30^{o} \\\\ \\widehat{A'CB} = 60^{o} $<\/span><\/span> <br\/>"}]}],"id_ques":1605},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":10,"ques":" <span class='basic_left'> Cho $\\triangle MNP $ c\u00f3 $MN = MP = NP$ v\u00e0 \u0111i\u1ec3m O n\u1eb1m trong tam gi\u00e1c sao cho <br\/> $OM = ON = OP$. <br\/> S\u1ed1 \u0111o g\u00f3c $\\widehat{NOP} $ l\u00e0: <\/span> ","select":[" A. $60^{o} $ "," B. $90^{o} $ "," C. $120^{o} $ ","D. $150^{o} $ "],"explain":" <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai10/lv3/img\/H7B10-14.png' \/> <\/center> <span class='basic_left'> X\u00e9t $\\triangle MON $ v\u00e0 $\\triangle PON $ c\u00f3: <br\/> + c\u1ea1nh $ON$ chung<br\/> + $MO = PO$ (gi\u1ea3 thi\u1ebft)<br\/> + $ MN = PN$ (gi\u1ea3 thi\u1ebft) <br\/> $\\Rightarrow \\triangle MON = \\triangle PON$ (c.c.c) (1) <br\/> T\u01b0\u01a1ng t\u1ef1, X\u00e9t $\\triangle MON $ v\u00e0 $\\triangle MOP $ c\u00f3: <br\/> + c\u1ea1nh MO chung<br\/> + $MN = MP$ (gi\u1ea3 thi\u1ebft)<br\/> + $ ON = OP$ (gi\u1ea3 thi\u1ebft) <br\/> $\\Rightarrow \\triangle MON = \\triangle MOP$ (c.c.c) (2) <br\/> T\u1eeb (1) v\u00e0 (2) $\\Rightarrow \\triangle MON = \\triangle PON = \\triangle MOP $ <br\/> Suy ra $\\widehat{MON} = \\widehat{NOP} = \\widehat{MOP} $ <br\/> M\u00e0 $\\widehat{MON} + \\widehat{NOP} + \\widehat{MOP} = 360^{o} $ <br\/> Do \u0111\u00f3: $3\\widehat{NOP} = 360^{o} \\Rightarrow \\widehat{NOP} = 120^{o} $ <\/span><br\/><br\/><span class='basic_pink'>\u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0 C. <\/span>","column":4}]}],"id_ques":1606},{"time":14,"part":[{"title":"Ch\u1ecdn <u>nh\u1eefng<\/u> \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"Ch\u1ecdn \u0111\u01b0\u1ee3c nhi\u1ec1u \u0111\u00e1p \u00e1n","temp":"checkbox","correct":[["1","5","6"]],"list":[{"point":10,"img":" <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai10/lv3/img\/H7B10-21.png' \/><\/center>","ques":"$\\triangle FGH = \\triangle IGH $ v\u00ec c\u00f3 c\u00e1c \u0111i\u1ec1u ki\u1ec7n sau: ","hint":"","column":3,"number_true":3,"select":["C\u1ea1nh GH chung","C\u1ea1nh GI chung","HF = GI","GF = HI","HF = HI","GF = GI"],"explain":"X\u00e9t tam gi\u00e1c $FGH$ v\u00e0 tam gi\u00e1c $IGH$ c\u00f3: <br\/> + C\u1ea1nh GH chung <br\/> + $HF = HI$ <br\/> + $GF = GI$ <br\/> Suy ra $\\triangle FGH = \\triangle IGH $"}]}],"id_ques":1607},{"time":24,"part":[{"title":"\u0110i\u1ec1n t\u1eeb th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["5"],["6"],["3"]]],"list":[{"point":10,"width":40,"content":"","type_input":"","ques":"Cho $\\triangle ABC = \\triangle MNP $, bi\u1ebft $AC = 6cm, AB + BC = 8 cm, MN - NP = 2 cm$<br\/> T\u00ednh: $MN = \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{} (cm) \\\\ MP = \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{} (cm) \\\\ NP = \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{} (cm) $ ","explain":" Ta c\u00f3: $\\triangle ABC = \\triangle MNP $ n\u00ean $AB = MN, BC = NP, AC = MP$ <br\/> Do \u0111\u00f3: $AB + BC = MN + NP = 8 cm, AC = MP = 6cm$ <br\/> Ta c\u00f3: $MN + NP = 8 cm, MN - NP = 2 cm$ <br\/> Suy ra $2.MN = 10 cm$ $\\Rightarrow $ $MN = 5 cm$ <br\/> $NP = 8 - MN = 8 - 5 = 3 cm$ <br\/><br\/><span class='basic_pink'> V\u1eady $MN = 5 cm, MP = 6 cm, NP = 3 cm$<\/span> "}]}],"id_ques":1608},{"time":24,"part":[{"title":"\u0110i\u1ec1n t\u1eeb th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["60"],["65"],["55"]]],"list":[{"point":10,"width":40,"content":"","type_input":"","ques":"Cho $\\triangle ABC = \\triangle DEF $, bi\u1ebft $\\widehat{B} - \\widehat{C} = 10^{o}, \\widehat{E} + \\widehat{F} = 120^{o} $. <br\/> T\u00ednh s\u1ed1 \u0111o c\u00e1c g\u00f3c c\u1ee7a tam gi\u00e1c ABC. <br\/> <b>\u0110\u00e1p \u00e1n:<\/b> $\\widehat{A} = \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{} ^o \\\\ \\widehat{B}= \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{} ^o \\\\ \\widehat{C} = \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{} ^o $ ","explain":" <span class='basic_left'> Ta c\u00f3: $\\triangle ABC = \\triangle MNP $ n\u00ean $\\widehat{B} = \\widehat{E}, \\widehat{C} = \\widehat{F} $ <br\/> M\u00e0 theo b\u00e0i c\u00f3 $\\widehat{E} + \\widehat{F} = 120^{o} \\Rightarrow \\widehat{B} + \\widehat{C} = 120^{o}$ (1) <br\/> M\u1eb7t kh\u00e1c $\\widehat{B} - \\widehat{C} = 10^{o}$ (gi\u1ea3 thi\u1ebft) (2) <br\/> T\u1eeb (1) v\u00e0 (2) $\\Rightarrow 2\\widehat{B} = 120^{o} + 10^{o} = 130^{o} \\\\ \\Rightarrow \\widehat{B} = 65^{o} \\\\ \\Rightarrow \\widehat{C} = 120^{o} - \\widehat{B} = 55^{o} $ <br\/> Tam gi\u00e1c $ABC$ c\u00f3: $ \\widehat{A} + \\widehat{B} + \\widehat{C} = 180^{o} \\\\ \\Leftrightarrow \\widehat{A} + 120^{o} = 180^{o} \\\\ \\Rightarrow \\widehat{A} = 60^{o} $ <\/span> <br\/><br\/><span class='basic_pink'> V\u1eady $\\widehat{A} = 60^{o} \\\\ \\widehat{B} = 65^{o} \\\\ \\widehat{A} = 55^{o}$ <\/span> "}]}],"id_ques":1609},{"time":24,"part":[{"title":"\u0110i\u1ec1n t\u1eeb th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["8"],["16"],["12"]]],"list":[{"point":10,"width":40,"content":"","type_input":"","ques":" <span class='basic_left'> Cho $\\triangle ABC = \\triangle GIK $, bi\u1ebft $IG : IK : GK = 2 : 3 : 4$ v\u00e0 chu vi tam gi\u00e1c GIK b\u1eb1ng 36cm. <br\/> T\u00ednh c\u00e1c c\u1ea1nh c\u1ee7a tam gi\u00e1c ABC. <br\/> <b>\u0110\u00e1p \u00e1n:<\/b> $AB = \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{} (cm) \\\\ AC = \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{} (cm) \\\\ BC = \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{} (cm) $ <\/span>","explain":" Ta c\u00f3 $IG : IK : GK = 2 : 3 : 4$, suy ra $\\dfrac{IG}{2} = \\dfrac{IK}{3} = \\dfrac{KG}{4} $ <br\/> Theo t\u00ednh ch\u1ea5t d\u00e3y t\u1ec9 s\u1ed1 b\u1eb1ng nhau, ta c\u00f3: <br\/> $\\dfrac{IG}{2} = \\dfrac{IK}{3} = \\dfrac{KG}{4} = \\dfrac{IG+IK+KG}{2+3+4} = \\dfrac{36}{9} = 4 $ (cm) <br\/> Suy ra $IG = 4.2 = 8(cm); IK = 4.3 = 12(cm); KG = 4.4 = 16(cm)$ <br\/> V\u00ec $\\triangle ABC = \\triangle GIK $ n\u00ean: $AB = GI = 8cm, AC = GK = 16cm, BC = IK = 12cm $ <br\/><br\/><span class='basic_pink'> V\u1eady $AB = 8cm, AC = 16cm, BC = 12cm$<\/span> "}]}],"id_ques":1610}],"lesson":{"save":0,"level":3}}