{"segment":[{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" <span class='basic_left'> Trong c\u00e1c bi\u1ec3u th\u1ee9c sau, bi\u1ec3u th\u1ee9c n\u00e0o kh\u00f4ng ph\u1ea3i l\u00e0 <b> \u0111\u01a1n th\u1ee9c<\/b>? <\/span>","select":["A. $-y$","B. $3-(xy)^2$","C. $-\\dfrac{2}{3}$","D. $abc$"],"hint":"\u0110\u01a1n th\u1ee9c l\u00e0 bi\u1ec3u th\u1ee9c \u0111\u1ea1i s\u1ed1 ch\u1ec9 g\u1ed3m m\u1ed9t s\u1ed1, ho\u1eb7c m\u1ed9t bi\u1ebfn, ho\u1eb7c m\u1ed9t t\u00edch gi\u1eefa c\u00e1c s\u1ed1 v\u00e0 c\u00e1c bi\u1ebfn.","explain":"<span class='basic_left'> Bi\u1ec3u th\u1ee9c $3-(xy)^2$ kh\u00f4ng ph\u1ea3i l\u00e0 <b> \u0111\u01a1n th\u1ee9c<\/b> <br\/><span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span>","column":2}]}],"id_ques":1251},{"time":24,"part":[{"title":"Kh\u1eb3ng \u0111\u1ecbnh sau \u0111\u00e2y \u0110\u00fang hay Sai","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" $-1999$ \u0111\u01b0\u1ee3c coi l\u00e0 m\u1ed9t \u0111a th\u1ee9c v\u00e0 c\u00f3 b\u1eadc l\u00e0 $0.$","select":["\u0110\u00fang","Sai"],"explain":"<span class='basic_left'> Kh\u1eb3ng \u0111\u1ecbnh tr\u00ean l\u00e0 \u0111\u00fang. <br\/><span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 \u0110\u00fang.<\/span> <br\/> <b> L\u01b0u \u00fd:<\/b> <i> M\u1ed7i s\u1ed1 \u0111\u01b0\u1ee3c coi l\u00e0 m\u1ed9t \u0111a th\u1ee9c v\u00e0 c\u00f3 b\u1eadc l\u00e0 $0.$<\/i><\/span>","column":2}]}],"id_ques":1252},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" <span class='basic_left'> \u0110\u01a1n th\u1ee9c n\u00e0o sau \u0111\u00e2y \u0111\u1ed3ng d\u1ea1ng v\u1edbi \u0111\u01a1n th\u1ee9c $-\\dfrac{2}{3}xy^2$?<\/span>","select":["A. $3xy(-y)$","B. $-\\dfrac{2}{3}(xy)^2$","C. $-\\dfrac{2}{3}x^2y$","D. $-\\dfrac{2}{3}xy$"],"hint":"Hai \u0111\u01a1n th\u1ee9c \u0111\u1ed3ng d\u1ea1ng l\u00e0 hai \u0111\u01a1n th\u1ee9c c\u00f3 h\u1ec7 s\u1ed1 kh\u00e1c $0$ v\u00e0 c\u00f3 c\u00f9ng ph\u1ea7n bi\u1ebfn.","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/>X\u00e9t xem \u0111\u01a1n th\u1ee9c \u1edf \u0111\u00e1p \u00e1n n\u00e0o c\u00f3 c\u00f9ng ph\u1ea7n bi\u1ebfn v\u1edbi \u0111\u01a1n th\u1ee9c \u0111\u00e3 cho \u1edf \u0111\u1ec1 b\u00e0i. <br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> \u0110\u01a1n th\u1ee9c $-\\dfrac{2}{3}xy^2$ c\u00f3 ph\u1ea7n bi\u1ebfn l\u00e0 $xy^2$ <br\/> X\u00e9t c\u00e1c \u0111\u00e1p \u00e1n: <br\/> A. $3xy(-y)=-3xy^2$ c\u00f3 ph\u1ea7n bi\u1ebfn l\u00e0 $xy^2$ <br\/> B. $-\\dfrac{2}{3}(xy)^2$ c\u00f3 ph\u1ea7n bi\u1ebfn l\u00e0 $(xy)^2=x^2y^2$ <br\/> C. $-\\dfrac{2}{3}x^2y$ c\u00f3 ph\u1ea7n bi\u1ebfn l\u00e0 $x^2y$ <br\/> D. $-\\dfrac{2}{3}xy$ c\u00f3 ph\u1ea7n bi\u1ebfn l\u00e0 $xy$ <br\/> Do \u0111\u00f3, \u0111\u01a1n th\u1ee9c $3xy(-y)$ \u0111\u1ed3ng d\u1ea1ng v\u1edbi \u0111\u01a1n th\u1ee9c $-\\dfrac{2}{3}xy^2$ <br\/><span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span>","column":2}]}],"id_ques":1253},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" <span class='basic_left'> K\u1ebft qu\u1ea3 thu g\u1ecdn bi\u1ec3u th\u1ee9c $-4x^5y^3+3x^5y^3-7x^5y^3$ l\u00e0: <\/span>","select":["A. $-x^5y^3$","B. $17x^5y^3$","C. $10x^5y^3$","D. $-8x^5y^3$"],"hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/>C\u1ed9ng (tr\u1eeb) c\u00e1c \u0111\u01a1n th\u1ee9c \u0111\u1ed3ng d\u1ea1ng ta c\u1ed9ng (tr\u1eeb) c\u00e1c h\u1ec7 s\u1ed1 v\u1edbi nhau v\u00e0 gi\u1eef nguy\u00ean ph\u1ea7n bi\u1ebfn. <br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> Ta c\u00f3: <br\/> $-4x^5y^3+3x^5y^3-7x^5y^3$ <br\/> $=(-4+3-7)x^5y^3$ <br\/> $=-8x^5y^3$ <br\/><span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span>","column":2}]}],"id_ques":1254},{"time":24,"part":[{"title":"\u0110i\u1ec1n k\u1ebft qu\u1ea3 \u0111\u00fang nh\u1ea5t v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["-7"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","ques":" Gi\u00e1 tr\u1ecb c\u1ee7a \u0111a th\u1ee9c $x^3y-x^2y^2-5$ t\u1ea1i $x=1;y=-1$ l\u00e0 _input_ ","explain":"<span class='basic_left'>Thay $x=1;y=-1$ v\u00e0o \u0111a th\u1ee9c $x^3y-x^2y^2-5$ ta \u0111\u01b0\u1ee3c: <br\/> $1^3.(-1)-1^2.(-1)^2-5=-1-1-5=-7$ <br\/> <span class='basic_pink'> V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $-7$.<\/span><\/span>"}]}],"id_ques":1255},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00fang hay sai","title_trans":"","temp":"true_false","correct":[["t","f","f"]],"list":[{"point":5,"image":"","col_name":["Kh\u1eb3ng \u0111\u1ecbnh","\u0110\u00fang","Sai"],"arr_ques":[" \u0110\u01a1n th\u1ee9c l\u00e0 m\u1ed9t bi\u1ec3u th\u1ee9c \u0111\u1ea1i s\u1ed1 g\u1ed3m m\u1ed9t s\u1ed1, m\u1ed9t bi\u1ebfn ho\u1eb7c t\u00edch c\u1ee7a c\u00e1c s\u1ed1 v\u00e0 c\u00e1c bi\u1ebfn. "," B\u1eadc c\u1ee7a \u0111\u01a1n th\u1ee9c c\u00f3 h\u1ec7 s\u1ed1 kh\u00e1c $0$ l\u00e0 t\u00edch s\u1ed1 m\u0169 c\u1ee7a t\u1ea5t c\u1ea3 c\u00e1c bi\u1ebfn c\u00f3 trong \u0111\u01a1n th\u1ee9c \u0111\u00f3.","$0$ l\u00e0 \u0111\u01a1n th\u1ee9c b\u1eadc $1.$"],"hint":"","explain":[" <span class='basic_left'>\u0110\u00fang<\/span>"," <br\/> <span class='basic_left'>Sai, v\u00ec: B\u1eadc c\u1ee7a \u0111\u01a1n th\u1ee9c c\u00f3 h\u1ec7 s\u1ed1 kh\u00e1c $0$ l\u00e0 t\u1ed5ng s\u1ed1 m\u0169 c\u1ee7a t\u1ea5t c\u1ea3 c\u00e1c bi\u1ebfn c\u00f3 trong \u0111\u01a1n th\u1ee9c \u0111\u00f3.<\/span> ","<br\/> <span class='basic_left'> Sai, v\u00ec: S\u1ed1 $0$ c\u0169ng \u0111\u01b0\u1ee3c coi l\u00e0 m\u1ed9t \u0111\u01a1n th\u1ee9c. N\u00f3 \u0111\u01b0\u1ee3c g\u1ecdi l\u00e0 <b> \u0111\u01a1n th\u1ee9c kh\u00f4ng<\/b> v\u00e0 kh\u00f4ng c\u00f3 b\u1eadc. <\/span>"]}]}],"id_ques":1256},{"time":24,"part":[{"title":"\u0110i\u1ec1n k\u1ebft qu\u1ea3 \u0111\u00fang nh\u1ea5t v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["7"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","ques":" Cho \u0111a th\u1ee9c $P=-4{{x}^{3}}{{y}^{3}}-3{{x}^{4}}{{y}^{3}}+{{x}^{4}}{{y}^{3}}-6x{{y}^{2}}+4{{x}^{3}}{{y}^{3}}$ <br\/> B\u1eadc c\u1ee7a \u0111a th\u1ee9c $P$ l\u00e0 _input_ ","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/>Thu g\u1ecdn \u0111a th\u1ee9c $P$ r\u1ed3i t\u00ecm b\u1eadc c\u1ee7a n\u00f3.<br\/><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/>Ta c\u00f3: <br\/> $\\begin{align} & P=-4{{x}^{3}}{{y}^{3}}-3{{x}^{4}}{{y}^{3}}+{{x}^{4}}{{y}^{3}}-6x{{y}^{2}}+4{{x}^{3}}{{y}^{3}} \\\\ & \\,\\,\\,\\,\\,=\\left( -4{{x}^{3}}{{y}^{3}}+4{{x}^{3}}{{y}^{3}} \\right)+\\left( -3{{x}^{4}}{{y}^{3}}+{{x}^{4}}{{y}^{3}} \\right)-6x{{y}^{2}} \\\\ & \\,\\,\\,\\,\\,=0-2{{x}^{4}}{{y}^{3}}-6x{{y}^{2}} \\\\ & \\,\\,\\,\\,\\,=-2{{x}^{4}}{{y}^{3}}-6x{{y}^{2}} \\\\ \\end{align}$ <br\/> B\u1eadc c\u1ee7a \u0111a th\u1ee9c $P$ l\u00e0 4+3= $7$ <br\/> <span class='basic_pink'> V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $7$.<\/span><\/span>"}]}],"id_ques":1257},{"time":24,"part":[{"title":"\u0110i\u1ec1n k\u1ebft qu\u1ea3 \u0111\u00fang nh\u1ea5t v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["-13"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","ques":" Cho \u0111a th\u1ee9c $Q=xy-x+1+2xy-\\left( xy-x+2 \\right)$ <br\/> Gi\u00e1 tr\u1ecb c\u1ee7a $Q$ t\u1ea1i $x=2;y=-3$ l\u00e0 _input_ ","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/>Thu g\u1ecdn \u0111a th\u1ee9c $Q$ <br\/> Thay $x=2;y=-3$ v\u00e0o \u0111a th\u1ee9c $Q$ \u0111\u00e3 thu g\u1ecdn \u0111\u1ec3 t\u00ednh gi\u00e1 tr\u1ecb c\u1ee7a n\u00f3.<br\/><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/>Ta c\u00f3: <br\/> $\\begin{align} & Q=xy-x+1+2xy-\\left( xy-x+2 \\right) \\\\ & \\,\\,\\,\\,\\,=xy-x+1+2xy-xy+x-2 \\\\ & \\,\\,\\,\\,\\,=\\left( xy+2xy-xy \\right)+\\left( -x+x \\right)+\\left( 1-2 \\right) \\\\ & \\,\\,\\,\\,\\,=2xy-1 \\\\ \\end{align}$ <br\/> Thay $x=2;y=-3$ v\u00e0o $2xy-1$ ta \u0111\u01b0\u1ee3c: <br\/> $2.2.(-3)-1=-13$ <br\/> <span class='basic_pink'> V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $-13$.<\/span><\/span>"}]}],"id_ques":1258},{"time":24,"part":[{"title":"\u0110i\u1ec1n k\u1ebft qu\u1ea3 \u0111\u00fang nh\u1ea5t v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["18"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","ques":" <span class='basic_left'>T\u00ecm $x,$ bi\u1ebft: $(2x-3)+(3x-4)-(4x+5)=6$ <br\/> <b> \u0110\u00e1p \u00e1n: <\/b> $x=\\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}$ <\/span> ","explain":"<span class='basic_left'> Ta c\u00f3: <br\/> $\\begin{align} (2x-3)+(3x-4)-(4x+5)&=6 \\\\ 2x-3+3x-4-4x-5 &=6 \\\\ x-12 &=6 \\\\ x&=18 \\\\ \\end{align}$ <br\/> <span class='basic_pink'> V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $18$.<\/span><\/span>"}]}],"id_ques":1259},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" <span class='basic_left'> T\u00ecm \u0111a th\u1ee9c $M,$ bi\u1ebft: <br\/> $M+(5x^2-2xy)=6x^2+9xy-y^2$ <\/span>","select":["A. $M=x^2+11y^2+y^2$","B. $M=11x^2+11xy-y^2$","C. $M=x^2+11xy-y^2$","D. $M=11x^2+11y^2+y^2$"],"hint":"Mu\u1ed1n t\u00ecm m\u1ed9t \u0111a th\u1ee9c ch\u01b0a bi\u1ebft trong m\u1ed9t t\u1ed5ng ta l\u1ea5y \u0111a th\u1ee9c t\u1ed5ng tr\u1eeb \u0111i \u0111a th\u1ee9c \u0111\u00e3 bi\u1ebft.","explain":"<span class='basic_left'> Ta c\u00f3: <br\/> $\\begin{align} & M+(5{{x}^{2}}-2xy)=6{{x}^{2}}+9xy-{{y}^{2}} \\\\ & M=\\left( 6{{x}^{2}}+9xy-{{y}^{2}} \\right)-(5{{x}^{2}}-2xy) \\\\ & M=6{{x}^{2}}+9xy-{{y}^{2}}-5{{x}^{2}}+2xy \\\\ & M={{x}^{2}}+11xy-{{y}^{2}} \\\\ \\end{align}$ <br\/><span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span><\/span>","column":2}]}],"id_ques":1260},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" <span class='basic_left'> Ph\u1ea7n bi\u1ebfn c\u1ee7a \u0111\u01a1n th\u1ee9c $3(2y)(3y^2)(xy)(x^2y^2)$ l\u00e0: <\/span>","select":["A. $x^2y^6$","B. $x^3y^6$","C. $x^3y^5$","D. $x^2y^5$"],"hint":"Thu g\u1ecdn \u0111\u01a1n th\u1ee9c ta nh\u00e2n h\u1ec7 s\u1ed1 v\u1edbi h\u1ec7 s\u1ed1, bi\u1ebfn v\u1edbi bi\u1ebfn.","explain":"<span class='basic_left'> Ta c\u00f3: <br\/> $\\begin{align} & 3(2y)(3{{y}^{2}})(xy)({{x}^{2}}{{y}^{2}}) \\\\ & =\\left( 3.2.3 \\right)\\left( x{{x}^{2}} \\right)\\left( y{{y}^{2}}y{{y}^{2}} \\right) \\\\ & =18{{x}^{3}}{{y}^{6}} \\\\ \\end{align}$ <br\/> Ph\u1ea7n bi\u1ebfn c\u1ee7a \u0111\u01a1n th\u1ee9c \u0111\u00e3 cho l\u00e0 $x^3y^6$ <br\/><span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span><\/span>","column":2}]}],"id_ques":1261},{"time":24,"part":[{"title":"Ch\u1ecdn <u>nh\u1eefng<\/u> \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"Ch\u1ecdn \u0111\u01b0\u1ee3c nhi\u1ec1u \u0111\u00e1p \u00e1n","temp":"checkbox","correct":[["2","3","4"]],"list":[{"point":5,"img":"","ques":"Trong c\u00e1c \u0111a th\u1ee9c sau, nh\u1eefng \u0111a th\u1ee9c n\u00e0o l\u00e0 <b> \u0111a th\u1ee9c m\u1ed9t bi\u1ebfn<\/b>?","hint":"","column":2,"number_true":3,"select":["A. $x+x^2+y-1$","B. $x^3$","C. $28-x-x^2$","D. $y$"],"explain":"<span class='basic_left'> \u0110a th\u1ee9c $x+x^2+y-1$ c\u00f3 hai bi\u1ebfn l\u00e0 $x$ v\u00e0 $y$ n\u00ean kh\u00f4ng ph\u1ea3i l\u00e0 \u0111a th\u1ee9c m\u1ed9t bi\u1ebfn. <br\/> C\u00e1c \u0111a th\u1ee9c $x^3$ v\u00e0 $28-x-x^2$ ch\u1ec9 c\u00f3 m\u1ed9t bi\u1ebfn l\u00e0 $x$ n\u00ean l\u00e0 \u0111a th\u1ee9c m\u1ed9t bi\u1ebfn. <br\/> \u0110a th\u1ee9c $y$ c\u00f3 m\u1ed9t bi\u1ebfn l\u00e0 $y$ n\u00ean l\u00e0 \u0111a th\u1ee9c m\u1ed9t bi\u1ebfn. <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n c\u1ea7n ch\u1ecdn l\u00e0 B, C v\u00e0 D.<\/span><\/span>"}]}],"id_ques":1262},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"\u0110\u1ec1 chung cho hai c\u00e2u","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" <span class='basic_left'> Cho hai \u0111a th\u1ee9c sau: <br\/> $ A=3{{x}^{4}}-5{{x}^{3}}+2{{x}^{2}}+6x-1$ <br\/> $ B={{x}^{4}}+3{{x}^{3}}-4{{x}^{2}}+7x+5 $ <br\/> <b> C\u00e2u 1.<\/b> T\u1ed5ng $A+B$ l\u00e0: <\/span>","select":["A. $4{{x}^{4}}-2{{x}^{3}}-2{{x}^{2}}+13x+4$","B. $3{{x}^{4}}+2{{x}^{3}}-2{{x}^{2}}+13x+4$","C. $3{{x}^{4}}-2{{x}^{3}}+2{{x}^{2}}+13x+4$","D. $4{{x}^{4}}+2{{x}^{3}}+2{{x}^{2}}+13x+4$"],"hint":"","explain":"<span class='basic_left'> Ta c\u00f3: <br\/> $\\begin{align} & A+B=\\left( 3{{x}^{4}}-5{{x}^{3}}+2{{x}^{2}}+6x-1 \\right)+\\left( {{x}^{4}}+3{{x}^{3}}-4{{x}^{2}}+7x+5 \\right) \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,=3{{x}^{4}}-5{{x}^{3}}+2{{x}^{2}}+6x-1+{{x}^{4}}+3{{x}^{3}}-4{{x}^{2}}+7x+5 \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,=\\left( 3{{x}^{4}}+{{x}^{4}} \\right)+\\left( -5{{x}^{3}}+3{{x}^{3}} \\right)+\\left( 2{{x}^{2}}-4{{x}^{2}} \\right)+\\left( 6x+7x \\right)+\\left( -1+5 \\right) \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,=4{{x}^{4}}-2{{x}^{3}}-2{{x}^{2}}+13x+4 \\\\ \\end{align}$ <br\/><span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span><\/span>","column":2}]}],"id_ques":1263},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"\u0110\u1ec1 chung cho hai c\u00e2u","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":" <span class='basic_left'> Cho hai \u0111a th\u1ee9c sau: <br\/> $ A=3{{x}^{4}}-5{{x}^{3}}+2{{x}^{2}}+6x-1$ <br\/> $ B={{x}^{4}}+3{{x}^{3}}-4{{x}^{2}}+7x+5 $ <br\/> <b> C\u00e2u 2.<\/b> Hi\u1ec7u $A-B$ l\u00e0: <\/span>","select":["A. $4{{x}^{4}}-2{{x}^{3}}-2{{x}^{2}}+13x+4$","B. $2{{x}^{4}}+8{{x}^{3}}+6{{x}^{2}}+x-6$","C. $3{{x}^{4}}-2{{x}^{3}}+2{{x}^{2}}+13x+4$","D. $2{{x}^{4}}-8{{x}^{3}}+6{{x}^{2}}-x-6$"],"hint":"","explain":"<span class='basic_left'> Ta c\u00f3: <br\/> $\\begin{align} & A-B=\\left( 3{{x}^{4}}-5{{x}^{3}}+2{{x}^{2}}+6x-1 \\right)-\\left( {{x}^{4}}+3{{x}^{3}}-4{{x}^{2}}+7x+5 \\right) \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,=3{{x}^{4}}-5{{x}^{3}}+2{{x}^{2}}+6x-1-{{x}^{4}}-3{{x}^{3}}+4{{x}^{2}}-7x-5 \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,=\\left( 3{{x}^{4}}-{{x}^{4}} \\right)+\\left( -5{{x}^{3}}-3{{x}^{3}} \\right)+\\left( 2{{x}^{2}}+4{{x}^{2}} \\right)+\\left( 6x-7x \\right)+\\left( -1-5 \\right) \\\\ & \\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,=2{{x}^{4}}-8{{x}^{3}}+6{{x}^{2}}-x-6 \\\\ \\end{align}$ <br\/><span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span><\/span>","column":2}]}],"id_ques":1264},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" <span class='basic_left'> B\u1eadc c\u1ee7a \u0111a th\u1ee9c $6x^3+5x^2-x^4-6x^3+2x+x^4+1$ l\u00e0: <\/span>","select":["A. $4$","B. $3$","C. $2$","D. $1$"],"hint":"Thu g\u1ecdn \u0111a th\u1ee9c r\u1ed3i m\u1edbi t\u00ecm b\u1eadc c\u1ee7a n\u00f3.","explain":"<span class='basic_left'> Ta c\u00f3: <br\/> $\\begin{align} & 6{{x}^{3}}+5{{x}^{2}}-{{x}^{4}}-6{{x}^{3}}+2x+{{x}^{4}}+1 \\\\ & =\\left( -{{x}^{4}}+{{x}^{4}} \\right)+\\left( 6{{x}^{3}}-6{{x}^{3}} \\right)+5{{x}^{2}}+2x+1 \\\\ & =0+0+5{{x}^{2}}+2x+1 \\\\ & =5{{x}^{2}}+2x+1 \\\\ \\end{align}$ <br\/> B\u1eadc c\u1ee7a \u0111a th\u1ee9c \u0111\u00e3 cho l\u00e0 $2$ <br\/><span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span> <br\/> <b> L\u01b0u \u00fd:<\/b> \u0110\u1ed1i v\u1edbi d\u1ea1ng b\u00e0i t\u00ecm b\u1eadc c\u1ee7a \u0111a th\u1ee9c, bao gi\u1edd ta c\u0169ng ph\u1ea3i thu g\u1ecdn \u0111a th\u1ee9c tr\u01b0\u1edbc (n\u1ebfu \u0111a th\u1ee9c ch\u01b0a \u1edf d\u1ea1ng thu g\u1ecdn) r\u1ed3i m\u1edbi t\u00ecm b\u1eadc c\u1ee7a n\u00f3.<\/span>","column":4}]}],"id_ques":1265},{"time":24,"part":[{"title":"\u0110i\u1ec1n k\u1ebft qu\u1ea3 \u0111\u00fang nh\u1ea5t v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["111"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","ques":" Gi\u00e1 tr\u1ecb c\u1ee7a \u0111a th\u1ee9c $x^3+9x^2-7x+3$ t\u1ea1i $x=-4$ l\u00e0 _input_ ","explain":"<span class='basic_left'> Do \u0111a th\u1ee9c $x^3+9x^2-7x+3$ \u0111\u00e3 \u1edf d\u1ea1ng thu g\u1ecdn n\u00ean ta thay $x=-4$ v\u00e0o \u0111a th\u1ee9c: <br\/> $x^3+9x^2-7x+3$ <br\/> $=(-4)^3+9.(-4)^2-7.(-4)+3$ <br\/> $=-64+144+28+3$ <br\/> $=111$ <br\/> <span class='basic_pink'> V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $111$.<\/span><\/span>"}]}],"id_ques":1266},{"time":24,"part":[{"title":"Kh\u1eb3ng \u0111\u1ecbnh sau \u0111\u00e2y \u0110\u00fang hay Sai","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" \u0110a th\u1ee9c $A(x)=x^2+11$ c\u00f3 hai nghi\u1ec7m. ","select":["\u0110\u00fang","Sai"],"explain":"<span class='basic_left'> Ta c\u00f3 $x^2\\ge 0$ v\u1edbi m\u1ecdi $x$ <br\/> $\\Rightarrow x^2+11 \\ge 11 > 0$ v\u1edbi m\u1ecdi $x$ <br\/> Do \u0111\u00f3, \u0111a th\u1ee9c $A(x)=x^2+11$ kh\u00f4ng c\u00f3 nghi\u1ec7m. <br\/> Kh\u1eb3ng \u0111\u1ecbnh: ''\u0110a th\u1ee9c $A(x)=x^2+11$ c\u00f3 hai nghi\u1ec7m'' l\u00e0 Sai.<br\/><span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 Sai.<\/span> <\/span>","column":2}]}],"id_ques":1267},{"time":24,"part":[{"title":"Ch\u1ecdn <u>nh\u1eefng<\/u> \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"Ch\u1ecdn \u0111\u01b0\u1ee3c nhi\u1ec1u \u0111\u00e1p \u00e1n","temp":"checkbox","correct":[["1","3"]],"list":[{"point":5,"img":"","ques":" Trong c\u00e1c gi\u00e1 tr\u1ecb sau, nh\u1eefng gi\u00e1 tr\u1ecb n\u00e0o l\u00e0 nghi\u1ec7m c\u1ee7a \u0111a th\u1ee9c $B(x)=x^2+7x$?","hint":"Cho $B(x)=0$ r\u1ed3i t\u00ecm $x$","column":3,"number_true":2,"select":["A. $-7$","B. $7$","C. $0$","D. $1$","E. $-1$","F. $-2$"],"explain":"<span class='basic_left'>Ta c\u00f3: <br\/> $B(x)=0$ <br\/> $\\Rightarrow x^2+7x=0$ <br\/> $\\Rightarrow x(x+7)=0$ <br\/> $\\Rightarrow x=0$ ho\u1eb7c $x=-7$ <br\/> Do \u0111\u00f3, $0$ v\u00e0 $-7$ l\u00e0 c\u00e1c nghi\u1ec7m c\u1ee7a \u0111a th\u1ee9c $B(x)=x^2+7x$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n c\u1ea7n ch\u1ecdn l\u00e0 A v\u00e0 C.<\/span><\/span>"}]}],"id_ques":1268},{"time":24,"part":[{"title":"\u0110i\u1ec1n k\u1ebft qu\u1ea3 \u0111\u00fang nh\u1ea5t v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["-1"],["2017"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","ques":" <span class='basic_left'>T\u00ecm c\u00e1c h\u1ec7 s\u1ed1 $a,b$ c\u1ee7a \u0111a th\u1ee9c $P(x)=ax+b$, bi\u1ebft $P(0)=2017$ v\u00e0 $P(1)=2016$ <br\/> <b> \u0110\u00e1p \u00e1n: <\/b> $\\left\\{ \\begin{align} & a=\\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{} \\\\ & b=\\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{} \\\\ \\end{align} \\right.$ <\/span> ","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1:<\/b> $P(0)=2017$ t\u1ee9c l\u00e0 ta thay $x=0$ th\u00ec \u0111a th\u1ee9c $P$ c\u00f3 gi\u00e1 tr\u1ecb l\u00e0 $2017$, t\u1eeb \u0111\u00f3 suy ra gi\u00e1 tr\u1ecb c\u1ee7a $b$ <br\/> <b> B\u01b0\u1edbc 2:<\/b> T\u00ecm gi\u00e1 tr\u1ecb c\u1ee7a $a$ t\u1eeb $P(1)=2016$ v\u00e0 gi\u00e1 tr\u1ecb c\u1ee7a $b$ \u0111\u00e3 bi\u1ebft \u1edf b\u01b0\u1edbc 1. <br\/><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/>Ta c\u00f3: <br\/> $\\begin{align} & P\\left( 0 \\right)=2017 \\\\ & \\Rightarrow a.0+b=2017 \\\\ & \\Rightarrow b=2017 \\\\ \\end{align}$ <br\/> Bi\u1ebft $b=2017$ v\u00e0 $P(1)=2016$ ta c\u00f3: <br\/> $\\begin{align} & a.1+2017=2016 \\\\ & \\Rightarrow a=2016-2017 \\\\ & \\Rightarrow a=-1 \\\\ \\end{align}$ <br\/> <span class='basic_pink'> V\u1eady c\u00e1c s\u1ed1 c\u1ea7n \u0111i\u1ec1n v\u00e0o c\u00e1c \u00f4 tr\u1ed1ng l\u1ea7n l\u01b0\u1ee3t l\u00e0 $-1;2017$.<\/span><\/span>"}]}],"id_ques":1269},{"time":24,"part":[{"title":"N\u1ed1i kh\u1eb3ng \u0111\u1ecbnh \u1edf v\u1ebf ph\u1ea3i \u0111\u00fang v\u1edbi \u0111a th\u1ee9c \u0111\u00e3 cho \u1edf v\u1ebf tr\u00e1i","title_trans":"","audio":"","temp":"matching","correct":[["3","2","1","4"]],"list":[{"point":5,"image":"","left":["$14-2x^2-x^4+7x^6$","$6x^{10}+3$","$5x^3+7+x$","$6+7x$"],"right":["C\u00f3 h\u1ec7 s\u1ed1 t\u1ef1 do l\u00e0 $7$","C\u00f3 h\u1ec7 s\u1ed1 cao nh\u1ea5t l\u00e0 $6$ ","C\u00f3 b\u1eadc l\u00e0 $6$","L\u00e0 \u0111a th\u1ee9c b\u1eadc nh\u1ea5t"],"top":100,"hint":"","explain":" <span class='basic_left'> Ta c\u00f3: <br\/> - \u0110a th\u1ee9c c\u00f3 h\u1ec7 s\u1ed1 t\u1ef1 do l\u00e0 $7$ l\u00e0 $5x^3+7+x$ <br\/> - \u0110a th\u1ee9c c\u00f3 h\u1ec7 s\u1ed1 cao nh\u1ea5t l\u00e0 $6$ l\u00e0 $6x^{10}+3$ <br\/> - \u0110a th\u1ee9c c\u00f3 b\u1eadc $6$ l\u00e0 $14-2x^2-x^4+7x^6$ <br\/> - \u0110a th\u1ee9c b\u1eadc nh\u1ea5t l\u00e0 $6+7x$ <\/span> "}]}],"id_ques":1270}],"lesson":{"save":0,"level":1}}