{"segment":[{"time":24,"part":[{"title":"\u0110i\u1ec1n t\u1eeb th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["70"]]],"list":[{"point":10,"width":40,"content":"","type_input":"","ques":"Cho h\u00ecnh v\u1ebd, bi\u1ebft a \/\/ b. <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai5/lv3/img\/H7C14-44A.png' \/><\/center> <br\/> S\u1ed1 \u0111o c\u1ee7a g\u00f3c $\\widehat{AOB} $ l\u00e0: $\\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}^{o} $ ","hint":"","explain":" <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai5/lv3/img\/H7C14-44B.png' \/><\/center> <br\/> K\u1ebb tia Oz \/\/ a \/\/ b <br\/> C\u00f3 a \/\/ Oz n\u00ean $\\widehat{O_{1}} = \\widehat{A} = 40^{o} $ (hai g\u00f3c so le trong) <br\/> C\u00f3 Oz \/\/ b n\u00ean $\\widehat{O_{2}} = \\widehat{B} = 30^{o} $ (hai g\u00f3c so le trong) <br\/> Do \u0111\u00f3 $ \\widehat{AOB} = \\widehat{O_{1}} + \\widehat{O_{2}} = 40^{o} + 30^{o} = 70^{o} $ <br\/> <br\/> <span class='basic_pink'>V\u1eady $ \\widehat{AOB} = 70^{o} $ <\/span><\/span> <br\/>"}]}],"id_ques":1471},{"time":24,"part":[{"time":3,"title":"S\u1eafp x\u1ebfp c\u00e1c c\u00e2u","title_trans":"Cho tam gi\u00e1c ABC. V\u1ebd tia ph\u00e2n gi\u00e1c BD c\u1ee7a g\u00f3c B. T\u1eeb A k\u1ebb \u0111\u01b0\u1eddng th\u1eb3ng song song v\u1edbi BD, c\u1eaft tia \u0111\u1ed1i c\u1ee7a tia BC t\u1ea1i E. <br\/> H\u00e3y s\u1eafp x\u1ebfp c\u00e1c \u00fd ch\u1ee9ng minh $\\widehat{BAE} = \\widehat{BEA} $ ","temp":"sequence","correct":[[[3],[1],[2],[4]]],"list":[{"point":10,"image":"","left":["M\u00e0 $\\widehat{B_{1}} = \\widehat{B_{2}}$ ","Ta c\u00f3 AE \/\/ BD n\u00ean $\\widehat{BAE} = \\widehat{B_{1}} $ ","L\u1ea1i c\u00f3 AE \/\/ BD n\u00ean $\\widehat{BEA} = \\widehat{B_{2}}$","V\u1eady $\\widehat{BAE} = \\widehat{BEA} $"],"top":70,"hint":"","explain":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai5/lv3/img\/H7C15-22.png' \/><\/center> <br\/> Ta c\u00f3 AE \/\/ BD n\u00ean $\\widehat{BAE} = \\widehat{B_{1}} $ (hai g\u00f3c so le trong) <br\/> L\u1ea1i c\u00f3 AE \/\/ BD n\u00ean $\\widehat{BEA} = \\widehat{B_{2}}$ (c\u1eb7p g\u00f3c \u0111\u1ed3ng v\u1ecb) <br\/> M\u00e0 BD l\u00e0 ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c B n\u00ean $\\widehat{B_{1}} = \\widehat{B_{2}}$ <br\/> Do v\u1eady $\\widehat{BAE} = \\widehat{BEA} $. "}]}],"id_ques":1472},{"time":24,"part":[{"title":"\u0110i\u1ec1n t\u1eeb th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["40"]]],"list":[{"point":10,"width":40,"content":"","type_input":"","ques":" Cho h\u00ecnh v\u1ebd nh\u01b0 sau, bi\u1ebft Ax \/\/ By <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai5/lv3/img\/H7C14-46A.png' \/><\/center> <br\/> S\u1ed1 \u0111o c\u1ee7a g\u00f3c $\\widehat{OBy} $ l\u00e0: $\\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}^{o} $ ","hint":"","explain":" <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai5/lv3/img\/H7C14-46B.png' \/><\/center> <br\/> K\u1ebb tia Oz \/\/ Ax \/\/ By <br\/> C\u00f3 Ax \/\/ Oz n\u00ean $\\widehat{O_{1}} = \\widehat{A} = 60^{o} $ (hai g\u00f3c so le trong) <br\/> C\u00f3 $\\widehat{O_{1}} + \\widehat{O_{2}} = \\widehat{AOB} $<br\/> $ \\Rightarrow \\widehat{O_{2}} $$ = \\widehat{AOB} - \\widehat{O_{1}} \\\\ = 100^{o} - 60^{o} \\\\ = 40^{o} $ <br\/> V\u00ec Oz \/\/ By n\u00ean $\\widehat{OBy} = \\widehat{O_{2}} = 40^{o} $ (hai g\u00f3c so le trong) <br\/> <br\/> <span class='basic_pink'>V\u1eady $ \\widehat{OBy} = 40^{o} $ <\/span><\/span> <br\/>"}]}],"id_ques":1473},{"time":24,"part":[{"title":"\u0110i\u1ec1n t\u1eeb th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["60"],["70"]]],"list":[{"point":10,"width":40,"content":"","type_input":"","ques":"Cho h\u00ecnh v\u1ebd, bi\u1ebft: a, b, c l\u00e0 ba \u0111\u01b0\u1eddng th\u1eb3ng song song. <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai5/lv3/img\/H7C14-12.png' \/><\/center> <br\/>T\u00ednh: $\\widehat{C_{1}} = \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}^{o} \\\\ \\widehat{D_{2}} = \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}^{o} $ ","hint":"","explain":"Ta c\u00f3 a \/\/ c n\u00ean : <br\/> $ \\widehat{A_{1}} = \\widehat{C_{1}} = 60^{o} $ (c\u1eb7p g\u00f3c so le trong) <br\/> M\u1eb7t kh\u00e1c a \/\/ b n\u00ean: <br\/> $ \\widehat{D_{2}} + \\widehat{E_{2}} = 180^{o} $ (c\u1eb7p g\u00f3c ngo\u00e0i c\u00f9ng ph\u00eda) <br\/> $\\Rightarrow \\widehat{D_{2}} $ $ = 180^{o} - \\widehat{E_{2}} \\\\ = 180^{o} - 110^{o} \\\\ = 70^{o} $ <br\/> <br\/> <span class='basic_pink'>V\u1eady $\\widehat{C_{1}} = 60^{o} \\\\ \\widehat{D_{2}} = 70^{o} $ <\/span><\/span> <br\/>"}]}],"id_ques":1474},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":10,"ques":"Cho h\u00ecnh v\u1ebd, bi\u1ebft: a \/\/ b, $\\widehat{A_{1}} - \\widehat{B_{1}} = 40^{o} $. <br\/> S\u1ed1 \u0111o g\u00f3c $\\widehat{B_{1}}$ l\u00e0: <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai5/lv3/img\/H7C14-13.png' \/><\/center> ","select":["A. $50^{o} $","B. $60^{o} $","C. $70^{o} $","D. $80^{o} $ "],"hint":"","explain":" Ta c\u00f3 a \/\/ b n\u00ean $\\widehat{A_{1}} + \\widehat{B_{1}} = 180^{o} $ (hai g\u00f3c trong c\u00f9ng ph\u00eda) <br\/> m\u00e0 $\\widehat{A_{1}} - \\widehat{B_{1}} = 40^{o} $ (gi\u1ea3 thi\u1ebft) <br\/> $\\Rightarrow 2\\widehat{B_{1}} = 180^{o} - 40^{o} \\\\ \\Rightarrow 2\\widehat{B_{1}} = 140^{o} \\\\ \\Rightarrow \\widehat{B_{1}} = 70^{o} $ <br\/> <br\/> <span class='basic_pink'>\u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0 C. <\/span>","column":4}]}],"id_ques":1475},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":10,"ques":"Cho h\u00ecnh v\u1ebd, AB \/\/ CD. Khi \u0111\u00f3: <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai5/lv3/img\/H7C14-14.png' \/><\/center> ","select":["A. $ x = y $ ","B. $ y = 180^{o} + x $ ","C. $ y = x - 180^{o} $","D. $x + y = 180^{o} $ "],"hint":"","explain":" Ta c\u00f3 AB \/\/ CD n\u00ean $y = \\widehat{BAC} $ (hai g\u00f3c so le trong th\u00ec b\u1eb1ng nhau) <br\/> m\u00e0 $\\widehat{BAC} $ v\u00e0 $\\widehat{BAE} $ l\u00e0 hai g\u00f3c k\u1ec1 b\u00f9 n\u00ean $\\widehat{BAE} + \\widehat{BAC} = 180^{o} $ <br\/> hay $x + y = 180^{o} $ <br\/> <br\/> <span class='basic_pink'>\u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0 D. <\/span><\/span> <br\/>","column":2}]}],"id_ques":1476},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":10,"ques":"Cho h\u00ecnh v\u1ebd, bi\u1ebft An \/\/ Cm. <br\/> T\u00ednh x. <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai5/lv3/img\/H7C14-15A.png' \/><\/center> ","select":["A. $ 112^{o}$ ","B. $ 133^{o} $ ","C. $ 65^{o} $","D. $ 47^{o} $ "],"hint":"","explain":" <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai5/lv3/img\/H7C14-15B.png' \/><\/center> <span class='basic_left'> * T\u1eeb B k\u1ebb BD \/\/ An m\u00e0 An \/\/ Cm $\\Rightarrow $ BD \/\/ Cm <br\/> * Ta c\u00f3: BD \/\/ Cm $\\Rightarrow \\widehat{CBD} + \\widehat{BCm} = 180^{o}$ (hai g\u00f3c trong c\u00f9ng ph\u00eda) <br\/> $\\Rightarrow \\widehat{CBD} = 180^{o} - \\widehat{BCm} = 180^{o} - 133^{o} = 47^{o} $ <br\/> * Do An \/\/ BD n\u00ean $\\widehat{nAB} = \\widehat{ABD} = 112^{o}$ (so le trong) <br\/> * Tia BC n\u1eb1m gi\u1eefa hai tia BA v\u00e0 BD n\u00ean $ x + \\widehat{CBD} = \\widehat{ABD} $ <br\/> $\\Rightarrow x = \\widehat{ABD} - \\widehat{CBD} = 112^{o} - 47^{o} = 65^{o} $ <br\/> V\u1eady $x = 65^{o} $<\/span> <br\/> <br\/> <span class='basic_pink'>\u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0 C. <\/span><\/span> <br\/>","column":4}]}],"id_ques":1477},{"time":24,"part":[{"title":"\u0110i\u1ec1n t\u1eeb th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["90"]]],"list":[{"point":10,"width":40,"content":"","type_input":"","ques":"Cho H\u00ecnh 23, bi\u1ebft Mz \/\/ Ny \/\/ Ox <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai5/lv3/img\/H7C14-23A1.png' \/><\/center> <br\/> S\u1ed1 \u0111o g\u00f3c $\\widehat{MNO }$ l\u00e0: $ \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}^{o} $ ","hint":"K\u1ebb Ny' l\u00e0 tia \u0111\u1ed1i c\u1ee7a tia Ny r\u1ed3i t\u00ednh $\\widehat{MNO} = \\widehat{MNy'} + \\widehat{ONy'}$","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/>N\u1ebfu \u0111\u01b0\u1eddng th\u1eb3ng c c\u1eaft hai \u0111\u01b0\u1eddng th\u1eb3ng song song a v\u00e0 b th\u00ec t\u1ea1o th\u00e0nh c\u00e1c c\u1eb7p g\u00f3c so le trong b\u1eb1ng nhau, c\u1eb7p g\u00f3c \u0111\u1ed3ng v\u1ecb b\u1eb1ng nhau, c\u1eb7p g\u00f3c trong c\u00f9ng ph\u00eda b\u00f9 nhau. <\/span> <br\/> <br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/> <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai5/lv3/img\/H7C14-23B1.png' \/><\/center> <br\/> K\u1ebb Ny' l\u00e0 tia \u0111\u1ed1i c\u1ee7a tia Ny, ta c\u00f3 Mz \/\/ Ny \/\/ Ox th\u00ec Mz \/\/ Ny' \/\/ Ox. <br\/> C\u00f3 Mz \/\/ Ny' n\u00ean $\\widehat{MNy'} = \\widehat{M} = 30^{o} $ (hai g\u00f3c \u0111\u1ed3ng v\u1ecb) <br\/> L\u1ea1i c\u00f3 Ny' \/\/ Ox n\u00ean $\\widehat{ONy'} + \\widehat{O} = 180^{o} $ (hai g\u00f3c trong c\u00f9ng ph\u00eda) <br\/> $\\Rightarrow \\widehat{ONy'} $ $ = 180^{o} - \\widehat{O} \\\\ = 180^{o} - 120^{o} \\\\ = 60^{o} $ <br\/> Do \u0111\u00f3 $\\widehat{MNO} = \\widehat{MNy'} + \\widehat{ONy'} = 30^{o} + 60^{o} = 90^{o} $ <br\/> <br\/> <span class='basic_pink'>V\u1eady $\\widehat{MNO} = 90^{o} $<\/span> "}]}],"id_ques":1478},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":10,"ques":"Cho h\u00ecnh v\u1ebd, c\u00f3 a, b, c, d l\u00e0 c\u00e1c \u0111\u01b0\u1eddng th\u1eb3ng. Bi\u1ebft a \/\/ b v\u00e0 $\\widehat{BAD} + \\widehat{BCD} = 180^{o} $ <br\/> \u0110\u00e1p \u00e1n n\u00e0o sau \u0111\u00e2y kh\u00f4ng \u0111\u00fang. <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai5/lv3/img\/H7C14-25.png' \/> ","select":["A. $\\widehat{BAD} = \\widehat{ADC}$","B. $\\widehat{ABC} + \\widehat{BCD} = 180^{o} $ ","C. $\\widehat{ABC} = \\widehat{BCD}$","D. $\\widehat{ABC} + \\widehat{ADC} = 180^{o} $"],"hint":"","explain":" C\u00e2u kh\u00f4ng \u0111\u00fang l\u00e0 B. V\u00ec: <br\/> C\u00f3 a \/\/ b n\u00ean $\\widehat{BAD} + \\widehat{ABC} = 180^{o} $ (hai g\u00f3c trong c\u00f9ng ph\u00eda) <br\/> m\u00e0 $\\widehat{BAD} + \\widehat{BCD} = 180^{o} $ (gi\u1ea3 thi\u1ebft) <br\/> Do \u0111\u00f3 $\\widehat{ABC} = \\widehat{BCD} $","column":2}]}],"id_ques":1479},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":10,"ques":"Cho h\u00ecnh v\u1ebd, bi\u1ebft a \/\/ b. <br\/> Gi\u00e1 tr\u1ecb c\u1ee7a t\u1ed5ng $x^{o} + y^{o} $ b\u1eb1ng: <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai5/lv3/img\/H7C14-26A.png' \/><\/center> ","select":["A. $90^{o} $ ","B. $80^{o} $","C. $70^{o} $ ","D. $60^{o} $ "],"hint":"","explain":" <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai5/lv3/img\/H7C14-26B.png' \/><\/center> <br\/> K\u1ebb tia At \/\/ a \/\/ b <br\/> C\u00f3 a \/\/ At n\u00ean $\\widehat{A_{1}} = x^{o} $ (hai g\u00f3c so le trong) <br\/> C\u00f3 At \/\/ b n\u00ean $\\widehat{A_{2}} = y^{o} $ (hai g\u00f3c so le trong) <br\/> Do \u0111\u00f3 $ x^{o} + y^{o} = \\widehat{A_{1}} + \\widehat{A_{2}} = \\widehat{A} = 60^{o} $ <br\/> <br\/> <span class='basic_pink'>\u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0 D. <\/span><\/span> <br\/>","column":4}]}],"id_ques":1480}],"lesson":{"save":0,"level":3}}