{"segment":[{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"T\u00ecm c\u00e2u tr\u1ea3 l\u1eddi sai: <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai12/lv1/img\/H7B12-06.png' \/><\/center> ","select":["A. $\\triangle BDA = \\triangle CEA$ ","B. $\\triangle BEA = \\triangle CDA$ ","C. $\\widehat{EAB} = \\widehat{DAC}, AD = AE$ ","D. $\\triangle ADB = \\triangle ACE$ "],"explain":"<span class='basic_left'> X\u00e9t $\\triangle BDA$ v\u00e0 $\\triangle CEA$ c\u00f3: <br\/> $\\begin{cases} \\widehat{ADB} = \\widehat{AEC} (gt) \\\\ BD = CE (gt) \\\\ \\widehat{B_{2}} = \\widehat{C_{2}} \\hspace{0,2cm} \\text{(c\u00f9ng b\u00f9 v\u1edbi}\\, \\widehat{B_{1}}\\, \\text{ho\u1eb7c}\\, \\widehat{C_{1}}) \\end{cases}$ <br\/> $\\Rightarrow$ $\\triangle BDA = \\triangle CEA$ (g . c . g) $\\Rightarrow $ <b>\u0110\u00e1p \u00e1n A \u0111\u00fang <\/b> <br\/> $\\Rightarrow BD=CE$ (hai c\u1ea1nh t\u01b0\u01a1ng \u1ee9ng) <br\/> X\u00e9t $\\triangle BEA$ v\u00e0 $\\triangle CDA$ c\u00f3: <br\/> $\\begin{cases} \\widehat{E} = \\widehat{D} (gt) \\\\ DC = BE \\hspace{0,2cm} \\text{ (= DB + BC)} \\\\ \\widehat{B_{1}} = \\widehat{C_{1}} (gt) \\end{cases}$ <br\/> $\\Rightarrow$ $\\triangle BEA = \\triangle CDA$ (g . c . g) <br\/> $\\Rightarrow \\widehat {EAB} = \\widehat {DAC}$ (g\u00f3c t\u01b0\u01a1ng \u1ee9ng) <br\/> $\\Rightarrow AD = AE$ (c\u1ea1nh t\u01b0\u01a1ng \u1ee9ng) <br\/> <span class='basic_pink'>C\u00e2u tr\u1ea3 l\u1eddi sai l\u00e0 D <\/span> <\/span>","column":2}]}],"id_ques":1641},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"<span class='basic_left'>Cho Oz l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c $\\widehat{xOy} $. Tr\u00ean c\u1ea1nh Ox l\u1ea5y \u0111i\u1ec3m A sao cho $OA = 1cm$. K\u1ebb t\u1eeb A \u0111\u01b0\u1eddng vu\u00f4ng g\u00f3c v\u1edbi Oz, n\u00f3 c\u1eaft Oy t\u1ea1i B. \u0110\u1ed9 d\u00e0i c\u1ea1nh OB l\u00e0: <\/span> ","select":["A. $1 cm $ ","B. $2 cm $ ","C. $3 cm $ ","D. $4 cm $ "],"explain":" <span class='basic_left'> <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai12/lv1/img\/H7B12-56.png' \/><\/center> G\u1ecdi H l\u00e0 giao \u0111i\u1ec3m c\u1ee7a $AB$ v\u00e0 tia $Oz$. <br\/> X\u00e9t hai tam gi\u00e1c vu\u00f4ng $AOH$ v\u00e0 $BOH$ c\u00f3: <br\/> + $\\widehat{O_{1}} = \\widehat{O_{2}} $ (gi\u1ea3 thi\u1ebft) <br\/> + c\u1ea1nh g\u00f3c vu\u00f4ng OH chung <br\/> $\\widehat{AHO}=\\widehat{BHO}=90^o$ <br\/> $\\Rightarrow \\triangle AOH = \\triangle BOH $ (g - c - g) <br\/> $\\Rightarrow OA = OB $ (hai c\u1ea1nh t\u01b0\u01a1ng \u1ee9ng) <br\/> M\u00e0 $OA = 1cm \\Rightarrow OB = 1cm $<br\/> <span class='basic_pink'> \u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0 A. <\/span> ","column":2}]}],"id_ques":1642},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"<span class='basic_left'>Cho $\\triangle ABC $ v\u00e0 $\\triangle KHI $ c\u00f3 $\\widehat{A} = \\widehat{H} = 90^{o}, AC = IH, \\widehat{C} = \\widehat{I} $. <br\/> Ph\u00e1t bi\u1ec3u n\u00e0o trong c\u00e1c ph\u00e1t bi\u1ec3u sau l\u00e0 \u0111\u00fang? <\/span> ","select":["A. $\\triangle ABC > \\triangle HIK $ ","B. $\\triangle ACB = \\triangle HIK $","C. $\\triangle ACB < \\triangle KIH $"],"hint":"V\u1ebd h\u00ecnh r\u1ed3i t\u00ecm \u0111\u00fang th\u1ee9 t\u1ef1 c\u00e1c \u0111\u1ec9nh. ","explain":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai12/lv1/img\/H7B12-54.png' \/><\/center> <span class='basic_left'> Tam gi\u00e1c $ABC$ v\u00e0 tam gi\u00e1c $MNP$ c\u00f3: <br\/> + $\\widehat{A} = \\widehat{H}=90^o$ <br\/> + $AC=IH$ (gi\u1ea3 thi\u1ebft) <br\/> + $\\widehat{C} = \\widehat{I}$ (gi\u1ea3 thi\u1ebft) <br\/> $\\Rightarrow \\triangle ACB = \\triangle HIK (g.c.g) $ <br\/><br\/> <span class='basic_pink'> \u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0 B. <\/span> <\/span> ","column":2}]}],"id_ques":1643},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"<span class='basic_left'> N\u1ebfu $\\triangle ABC $ v\u00e0 $\\triangle DEF $ c\u00f3: $\\widehat{B} = \\widehat{E}, BC = DE, \\widehat{C} = \\widehat{D} $ th\u00ec: <\/span> ","select":["A. $\\triangle ACB = \\triangle DEF $ ","B. $\\triangle ACB = \\triangle EDF $ ","C. $\\triangle ABC = \\triangle FDE $ ","D. $\\triangle ABC = \\triangle FED $ "],"explain":"<span class='basic_left'> <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai12/lv1/img\/H7B12-47.png' \/><\/center> X\u00e9t $\\triangle ABC $ v\u00e0 $\\triangle DEF $ c\u00f3: <br\/> + $\\widehat{B} = \\widehat{E}$ <br\/> + $ BC = DE$ (gi\u1ea3 thi\u1ebft) <br\/> + $ \\widehat{C} = \\widehat{D} $ <br\/> $\\Rightarrow \\triangle ABC = \\triangle FED $ (g - c - g) <br\/><br\/> <span class='basic_pink'>\u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0 D. <\/span> <\/span> ","column":2}]}],"id_ques":1644},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"\u0110i\u1ec1n v\u00e0o ch\u1ed7 tr\u1ed1ng (...) trong ph\u00e1t bi\u1ec3u sau \u0111\u1ec3 \u0111\u01b0\u1ee3c kh\u1eb3ng \u0111\u1ecbnh \u0111\u00fang. <br\/> ''N\u1ebfu ... c\u1ee7a tam gi\u00e1c n\u00e0y b\u1eb1ng ... c\u1ee7a tam gi\u00e1c kia th\u00ec hai tam gi\u00e1c \u0111\u00f3 b\u1eb1ng nhau (g\u00f3c-c\u1ea1nh-g\u00f3c).'' ","select":[" A. m\u1ed9t c\u1ea1nh v\u00e0 hai g\u00f3c k\u1ec1 .... m\u1ed9t c\u1ea1nh v\u00e0 hai g\u00f3c k\u1ec1 "," B. hai c\u1ea1nh v\u00e0 g\u00f3c xen gi\u1eefa... hai c\u1ea1nh v\u00e0 g\u00f3c xen gi\u1eefa "," C. hai g\u00f3c ... hai g\u00f3c ","D. m\u1ed9t c\u1ea1nh v\u00e0 hai g\u00f3c ... m\u1ed9t c\u1ea1nh v\u00e0 hai g\u00f3c "],"explain":"<span class='basic_left'> Tr\u01b0\u1eddng h\u1ee3p b\u1eb1ng nhau g\u00f3c-c\u1ea1nh-g\u00f3c c\u1ee7a hai tam gi\u00e1c l\u00e0: <br\/> N\u1ebfu m\u1ed9t c\u1ea1nh v\u00e0 hai g\u00f3c k\u1ec1 c\u1ee7a tam gi\u00e1c n\u00e0y b\u1eb1ng m\u1ed9t c\u1ea1nh v\u00e0 hai g\u00f3c k\u1ec1 c\u1ee7a tam gi\u00e1c kia th\u00ec hai tam gi\u00e1c \u0111\u00f3 b\u1eb1ng nhau. <br\/><br\/><span class='basic_pink'>\u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0 A. <\/span>","column":1}]}],"id_ques":1645},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"<span class='basic_left'> Cho h\u00ecnh v\u1ebd, bi\u1ebft $\\widehat{BAC} = \\widehat{DAC} $. <br\/> C\u1ea7n ph\u1ea3i c\u00f3 th\u00eam \u0111i\u1ec1u ki\u1ec7n g\u00ec \u0111\u1ec3 $\\triangle ABC = \\triangle ADC $ theo tr\u01b0\u1eddng h\u1ee3p g\u00f3c-c\u1ea1nh-g\u00f3c? <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai12/lv1/img\/H7B12-45.png' \/><\/center> <\/span>","select":["$AB = AD $ ","$\\widehat{ABC} = \\widehat{ADC} $ ","$\\widehat{ACB} = \\widehat{ACD} $"],"explain":"<span class='basic_left'> X\u00e9t $\\triangle ABC $ v\u00e0 $\\triangle ADC $ c\u00f3: <br\/> + $\\widehat{BAC} = \\widehat{DAC} $ (gi\u1ea3 thi\u1ebft) <br\/> + c\u1ea1nh AC chung <br\/> Do \u0111\u00f3 \u0111\u1ec3 $\\Delta ABC=\\Delta ADC$ theo tr\u01b0\u1eddng h\u1ee3p g\u00f3c - c\u1ea1nh - g\u00f3c th\u00ec c\u1ea7n th\u00eam c\u1eb7p g\u00f3c k\u1ec1 v\u1edbi c\u1ea1nh AC chung <br\/> T\u1ee9c l\u00e0 c\u1ea7n th\u00eam: $\\widehat{ACB} = \\widehat{ACD} $ <\/span> ","column":3}]}],"id_ques":1646},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":" Tr\u01b0\u1eddng h\u1ee3p b\u1eb1ng nhau g\u00f3c-c\u1ea1nh-g\u00f3c c\u1ee7a hai tam gi\u00e1c l\u00e0: ","select":[" A. N\u1ebfu m\u1ed9t c\u1ea1nh v\u00e0 m\u1ed9t g\u00f3c k\u1ec1 c\u1ee7a tam gi\u00e1c n\u00e0y b\u1eb1ng m\u1ed9t c\u1ea1nh v\u00e0 m\u1ed9t g\u00f3c k\u1ec1 c\u1ee7a tam gi\u00e1c kia th\u00ec hai tam gi\u00e1c \u0111\u00f3 b\u1eb1ng nhau. "," B. N\u1ebfu hai g\u00f3c k\u1ec1 c\u1ee7a tam gi\u00e1c n\u00e0y b\u1eb1ng hai g\u00f3c k\u1ec1 c\u1ee7a tam gi\u00e1c kia th\u00ec hai tam gi\u00e1c \u0111\u00f3 b\u1eb1ng nhau. "," C. N\u1ebfu m\u1ed9t c\u1ea1nh v\u00e0 hai g\u00f3c k\u1ec1 c\u1ee7a tam gi\u00e1c n\u00e0y b\u1eb1ng m\u1ed9t c\u1ea1nh v\u00e0 hai g\u00f3c k\u1ec1 c\u1ee7a tam gi\u00e1c kia th\u00ec hai tam gi\u00e1c \u0111\u00f3 b\u1eb1ng nhau. ","D. N\u1ebfu hai c\u1ea1nh v\u00e0 m\u1ed9t g\u00f3c c\u1ee7a tam gi\u00e1c n\u00e0y b\u1eb1ng hai c\u1ea1nh v\u00e0 m\u1ed9t g\u00f3c c\u1ee7a tam gi\u00e1c kia th\u00ec hai tam gi\u00e1c \u0111\u00f3 b\u1eb1ng nhau. "],"explain":" Tr\u01b0\u1eddng h\u1ee3p b\u1eb1ng nhau g\u00f3c-c\u1ea1nh-g\u00f3c c\u1ee7a hai tam gi\u00e1c l\u00e0: <br\/> N\u1ebfu m\u1ed9t c\u1ea1nh v\u00e0 hai g\u00f3c k\u1ec1 c\u1ee7a tam gi\u00e1c n\u00e0y b\u1eb1ng m\u1ed9t c\u1ea1nh v\u00e0 hai g\u00f3c k\u1ec1 c\u1ee7a tam gi\u00e1c kia th\u00ec hai tam gi\u00e1c \u0111\u00f3 b\u1eb1ng nhau. <br\/><br\/><span class='basic_pink'>\u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0 C. <\/span>","column":1}]}],"id_ques":1647},{"time":24,"part":[{"title":"\u0110i\u1ec1n t\u1eeb th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["4"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","ques":"<span class='basic_left'> V\u1ebd tam gi\u00e1c $ABC$ bi\u1ebft $\\widehat{B} = 90^{o}$, $BC = 2cm$, $\\widehat{C} = 60^{o} $<br\/> \u0110o \u0111\u01b0\u1ee3c \u0111\u1ed9 d\u00e0i c\u1ea1nh AC l\u00e0: $\\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{} (cm)$","explain":"<span class='basic_left'> <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai12/lv1/img\/H7B12-03.png' \/><\/center> - V\u1ebd \u0111o\u1ea1n th\u1eb3ng $BC = 2cm.$ <br\/> - Tr\u00ean c\u00f9ng m\u1ed9t n\u1eeda m\u1eb7t ph\u1eb3ng b\u1edd BC v\u1ebd c\u00e1c tia Bx v\u00e0 By sao cho $\\widehat{CBx} = 90^{o}, \\widehat{BCy} = 60^{o} $ ch\u00fang c\u1eaft nhau t\u1ea1i A. <br\/> - D\u00f9ng th\u01b0\u1edbc th\u1eb3ng \u0111o \u0111\u01b0\u1ee3c $AC = 4cm.$ <br\/> <span class='basic_pink'>\u0110\u00e1p \u00e1n c\u1ea7n \u0111i\u1ec1n l\u00e0: 4<\/span> <\/span> "}]}],"id_ques":1648},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Cho h\u00ecnh v\u1ebd: <br\/> <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai12/lv1/img\/H7B12-05A.png' \/><\/center> <br\/> H\u00e3y ch\u1ecdn c\u1eb7p tam gi\u00e1c b\u1eb1ng nhau. ","select":["$\\triangle ABC = \\triangle BDA $ ","$\\triangle ABC = \\triangle ABD $ ","$\\triangle ABC = \\triangle DAB $ "],"explain":"<span class='basic_left'> <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai12/lv1/img\/H7B12-05B.png' \/><\/center> X\u00e9t $\\triangle ABC $ v\u00e0 $\\triangle ABD $ c\u00f3: <br\/> + $\\widehat{A_{1}} = \\widehat{A_{2}} $ (gi\u1ea3 thi\u1ebft) <br\/>+ c\u1ea1nh AB chung <br\/>+ $\\widehat{B_{1}} = \\widehat{B_{2}} $ (gi\u1ea3 thi\u1ebft) <br\/> $\\Rightarrow \\triangle ABC = \\triangle ABD $ (g\u00f3c-c\u1ea1nh-g\u00f3c) ","column":3}]}],"id_ques":1649},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"<b>T\u00ecm c\u00e2u tr\u1ea3 l\u1eddi sai:<\/b> <br\/> Cho tam gi\u00e1c $ABC$ c\u00f3 $\\widehat{B} = \\widehat{C} $. <br\/> Tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c A c\u1eaft BC t\u1ea1i D. Ta c\u00f3: ","select":["A. $\\triangle ABD = \\triangle ACD $ ","B. $AB = AC $ ","C. $BD = CD $ ","D. $\\widehat{ABD} = \\widehat{ADC} $ "],"explain":"<span class='basic_left'> <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai12/lv1/img\/H7B12-14.png' \/><\/center> $\\triangle{ABD} $ v\u00e0 $\\triangle{ACD} $ c\u00f3 $\\widehat{B} = \\widehat{C}, \\widehat{A_{1}} = \\widehat{A_{2}} $ n\u00ean $\\widehat{D_{1}} = \\widehat{D_{2}}$ <br\/> X\u00e9t $\\triangle ABD $ v\u00e0 $ \\triangle ACD $ c\u00f3: <br\/> + $\\widehat{A_{1}} = \\widehat{A_{2}}$ <br\/> + c\u1ea1nh AD chung<br\/> + $\\widehat{D_{1}} = \\widehat{D_{2}}$ <br\/>$ \\Rightarrow \\triangle ABD = \\triangle ACD $ (g.c.g) <br\/> Suy ra $AB = AC, BD = CD, \\widehat{ABD} = \\widehat{ACD} $ <br\/> <span class='basic_pink'>\u0110\u00e1p \u00e1n sai l\u00e0 D v\u00ec c\u00e1c \u0111\u1ec9nh kh\u00f4ng t\u01b0\u01a1ng \u1ee9ng <\/span> <br\/> <b> Ch\u00fa \u00fd: <\/b> T\u1eeb b\u00e0i to\u00e1n tr\u00ean, ta suy ra: <br\/> N\u1ebfu m\u1ed9t tam gi\u00e1c c\u00f3 hai g\u00f3c b\u1eb1ng nhau th\u00ec tam gi\u00e1c \u0111\u00f3 c\u00f3 hai c\u1ea1nh b\u1eb1ng nhau. <\/span> ","column":2}]}],"id_ques":1650},{"time":24,"part":[{"title":"\u0110i\u1ec1n t\u1eeb th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["AHC"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","ques":"Cho h\u00ecnh v\u1ebd: <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai12/lv1/img\/H7B12-16.png' \/><\/center> $\\triangle AHB = \\Delta \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{} (g.c.g) $ <br\/> (L\u01b0u \u00fd: Nh\u1eadp \u0111\u00fang th\u1ee9 t\u1ef1 c\u00e1c \u0111\u1ec9nh) ","explain":"<span class='basic_left'> X\u00e9t $\\triangle AHB $ v\u00e0 $\\triangle AHC $ c\u00f3: <br\/> + $\\widehat{BAH} = \\widehat{CAH} $ (gi\u1ea3 thi\u1ebft)<br\/> + c\u1ea1nh AH chung <br\/>+ $\\widehat{AHB} = \\widehat{AHC} (= 90^{o}) $ <br\/> Do \u0111\u00f3 $\\triangle AHB = \\triangle AHC (g.c.g) $"}]}],"id_ques":1651},{"time":24,"part":[{"title":"\u0110i\u1ec1n t\u1eeb th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["ACD"],["DCH"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","ques":"Cho h\u00ecnh v\u1ebd: <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai12/lv1/img\/H7B12-17.png' \/><\/center> $\\triangle ABD = \\Delta \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{} (g.c.g) \\\\ \\triangle DBE =\\Delta \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{} (g.c.g) $ <br\/> (L\u01b0u \u00fd: Nh\u1eadp \u0111\u00fang th\u1ee9 t\u1ef1 c\u00e1c \u0111\u1ec9nh) ","explain":" <span class='basic_left'> X\u00e9t $\\triangle ABD $ v\u00e0 $\\triangle ACD $ c\u00f3: <br\/>+ $\\widehat{BAD} = \\widehat{CAD} $ (gi\u1ea3 thi\u1ebft)<br\/> + $AB=AC$ (gi\u1ea3 thi\u1ebft) <br\/> + $\\widehat{ABD} = \\widehat{ACD} (= 90^{o}) $ <br\/> Do \u0111\u00f3 $\\triangle ABD = \\triangle ACD (g.c.g) $ <br\/> $\\Rightarrow BD = CD $ (hai c\u1ea1nh t\u01b0\u01a1ng \u1ee9ng) <br\/> X\u00e9t $\\triangle DBE $ v\u00e0 $\\triangle DCH $ c\u00f3: <br\/> + $\\widehat{DBE} = \\widehat{DCH} (= 90^{o})$ <br\/> + $BD = CD$ (ch\u1ee9ng minh tr\u00ean)<br\/> + $\\widehat{BDE} = \\widehat{CDH} $ (\u0111\u1ed1i \u0111\u1ec9nh) <br\/> Do \u0111\u00f3 $\\triangle BDE = \\triangle CDH (g.c.g) $ "}]}],"id_ques":1652},{"time":24,"part":[{"title":"\u0110i\u1ec1n t\u1eeb th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["CEM"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","ques":"Cho h\u00ecnh v\u1ebd: <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai12/lv1/img\/H7B12-21.png' \/><\/center> $\\triangle BDM =\\Delta \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{} (g.c.g) $ <br\/> (L\u01b0u \u00fd: nh\u1eadp \u0111\u00fang th\u1ee9 t\u1ef1 c\u00e1c \u0111\u1ec9nh) ","explain":"<span class='basic_left'> Tam gi\u00e1c $BDM$ v\u00e0 tam gi\u00e1c $CEM$ c\u00f3: <br\/> + $\\widehat{BMD} = \\widehat{CME}$ (\u0111\u1ed1i \u0111\u1ec9nh) <br\/> + $\\widehat{BDM} = \\widehat{CEM} (= 90^{o}) $ (gi\u1ea3 thi\u1ebft) <br\/>$\\Rightarrow \\widehat{DBM} = \\widehat{ECM} $ <br\/> X\u00e9t $\\triangle BDM $ v\u00e0 $ \\triangle CEM $ c\u00f3: <br\/> + $\\widehat{DBM} = \\widehat{ECM}$ <br\/> + $MB = MC $ (gi\u1ea3 thi\u1ebft) <br\/> + $\\widehat{BMD} = \\widehat{CME}$ <br\/> Do \u0111\u00f3 $\\triangle BDM = \\triangle CEM $ (g.c.g) "}]}],"id_ques":1653},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang ho\u1eb7c sai","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" <span class='basic_left'>Cho tam gi\u00e1c $ABC$, \u0111i\u1ec3m D thu\u1ed9c c\u1ea1nh BC. K\u1ebb $DE \/\/ AC\\, (E \\in AB)$, k\u1ebb $DF \/\/ AB\\, (F \\in AC)$. G\u1ecdi I l\u00e0 trung \u0111i\u1ec3m c\u1ee7a $EF$. Khi \u0111\u00f3 I l\u00e0 trung \u0111i\u1ec3m c\u1ee7a $AD$ <\/span>","select":["\u0110\u00fang","Sai"],"explain":" <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai12/lv1/img\/H7B12-22.png' \/> <br\/> <span class='basic_left'> Ta c\u00f3: $\\triangle AEF = \\triangle DFE$ (g.c.g) v\u00ec: <br\/> $\\begin{cases} \\widehat{E_{2}} = \\widehat{D_{2}} \\hspace{0,2cm} (\\text{so le trong}) \\\\ \\text{C\u1ea1nh} \\,EF \\hspace{0,2cm} \\text{(chung)} \\\\ \\widehat{E_{1}} = \\widehat{F_{1}} \\hspace{0,2cm} (\\text{so le trong}) \\end{cases}$ <br\/> $\\Rightarrow AE = DF$ <br\/> $\\triangle AIE = \\triangle DIF$ (c.g.c) v\u00ec <br\/> $\\begin{cases} AE = DF \\hspace{0,2cm} \\text{(ch\u1ee9ng minh tr\u00ean)} \\\\ \\widehat{E_{2}} = \\widehat{F_{2}} \\hspace{0,2cm} \\text{(so le trong)} \\\\ IE = IF (gt) \\end{cases}$ <br\/> $\\Rightarrow AI = DI $ (1) <br\/> $ \\widehat{I_{1}} = \\widehat{I_{2}} $ <br\/> Ta l\u1ea1i c\u00f3 $\\widehat{I_{2}} + \\widehat{I_{3}} = 180^{o} $ n\u00ean $\\widehat{I_{1}} + \\widehat{I_{3}} = 180^{o} $ do \u0111\u00f3 A, I, D th\u1eb3ng h\u00e0ng (2) <br\/> T\u1eeb (1) v\u00e0 (2) $\\Rightarrow$ <span class='basic_pink'> I l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AD <\/span>","column":2}]}],"id_ques":1654},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang ho\u1eb7c sai","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" <span class='basic_left'>Cho tam gi\u00e1c $ABC, M$ l\u00e0 trung \u0111i\u1ec3m c\u1ee7a $AC$. Tr\u00ean tia \u0111\u1ed1i c\u1ee7a tia $MB$ l\u1ea5y \u0111i\u1ec3m D sao cho $MD = MB$. Tr\u00ean tia \u0111\u1ed1i c\u1ee7a tia $BC$ l\u1ea5y \u0111i\u1ec3m E sao cho $BE = BC$. G\u1ecdi I l\u00e0 giao \u0111i\u1ec3m c\u1ee7a $AB$ v\u00e0 $DE$. <br\/> Khi \u0111\u00f3 $IA = IB$ <\/span>","select":["\u0110\u00fang","Sai"],"explain":" <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai12/lv1/img\/H7B12-25.png' \/><\/center> <span class='basic_left'> X\u00e9t $\\triangle AMD$ v\u00e0 $\\triangle CMB $ c\u00f3: <br\/> + $MA = MC$ (gi\u1ea3 thi\u1ebft) <br\/> + $\\widehat{AMD} = \\widehat{CMB} $ (\u0111\u1ed1i \u0111\u1ec9nh) <br\/>+ $MB = MD$ (gi\u1ea3 thi\u1ebft) <br\/> $\\Rightarrow \\triangle AMD = \\triangle CMB (c.g.c) $ <br\/> $\\Rightarrow AD = BC \\\\ \\Rightarrow \\widehat{A_{1}} = \\widehat{C} \\Rightarrow AD \/\/ BC $ <br\/> C\u00f3 $AD = BC$ v\u00e0 $EB = BC$ n\u00ean $AD = EB$ <br\/> X\u00e9t $\\triangle AID $ v\u00e0 $\\triangle BIE $ c\u00f3: <br\/> + $\\widehat{E} = \\widehat{D_{1}} $ (do $AD \/\/ EC$) <br\/> + $AD = EB$ (ch\u1ee9ng minh tr\u00ean) <br\/> + $\\widehat{EBA} = \\widehat{DAB} $ (do $AD \/\/ EC$) <br\/> Do \u0111\u00f3 $\\triangle AID = \\triangle BIE (g.c.g) \\\\ \\Rightarrow IA = IB $<\/span>","column":2}]}],"id_ques":1655},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" <span class='basic_left'>Cho tam gi\u00e1c $ABC$ c\u00f3 $\\widehat{A} = 90^{o}, AB = AC, $ \u0111i\u1ec3m D thu\u1ed9c c\u1ea1nh AB. \u0110\u01b0\u1eddng th\u1eb3ng qua B v\u00e0 vu\u00f4ng g\u00f3c v\u1edbi CD c\u1eaft \u0111\u01b0\u1eddng th\u1eb3ng CA \u1edf K. Khi \u0111\u00f3: <\/span>","select":["$AK < AD$ ","$AK = AD$ ","$AK > AD$ "],"explain":" <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai12/lv1/img\/H7B12-26.png' \/><\/center> <span class='basic_left'>Ta c\u00f3 $\\widehat{ABK} = \\widehat{ACD} $ (c\u00f9ng ph\u1ee5 v\u1edbi $\\widehat{K} $) <br\/> X\u00e9t $\\triangle ABK$ v\u00e0 $\\triangle ACD $ c\u00f3: <br\/>+ $ \\widehat{ABK} = \\widehat{ACD}$ <br\/> + $AB = AC$ (gi\u1ea3 thi\u1ebft) <br\/>+ $\\widehat{DAC} = \\widehat{KAB} (= 90^{o})$ <br\/> Do \u0111\u00f3 $\\triangle ABK = \\triangle ACD (g.c.g) \\\\ \\Rightarrow AD = AK $ <\/span>","column":3}]}],"id_ques":1656},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" H\u00ecnh b\u1eb1ng tam gi\u00e1c $ABC$ l\u00e0: <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai12/lv1/img\/H7B12-29A.png' \/> <img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai12/lv1/img\/H7B12-29B.png' \/><\/center> ","select":["H\u00ecnh 1","H\u00ecnh 2"],"explain":"H\u00ecnh \u0111\u00fang l\u00e0 H\u00ecnh 2. <br\/> Hai tam gi\u00e1c b\u1eb1ng nhau theo tr\u01b0\u1eddng h\u1ee3p g\u00f3c-c\u1ea1nh-g\u00f3c. ","column":2}]}],"id_ques":1657},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":" Quan s\u00e1t h\u00ecnh v\u1ebd r\u1ed3i cho bi\u1ebft kh\u1eb3ng \u0111\u1ecbnh n\u00e0o sau \u0111\u00e2y \u0111\u00fang <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai12/lv1/img\/H7B12-30A.png' \/> <img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai12/lv1/img\/H7B12-30B.png' \/><\/center> ","select":["$MN = JK$","$PR = JK$","$NO = KL$"],"explain":"Ta th\u1ea5y $\\triangle QRP = \\triangle LJK $ (g\u00f3c-c\u1ea1nh-g\u00f3c) <br\/> N\u00ean $PR = JK$ ","column":3}]}],"id_ques":1658},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":" Hai tam gi\u00e1c sau c\u00f3 b\u1eb1ng nhau kh\u00f4ng? <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai12/lv1/img\/H7B12-33.png' \/><\/center> ","select":["C\u00f3","Kh\u00f4ng"],"explain":"<span class='basic_left'> Ta x\u00e9t $\\triangle TPR$ v\u00e0 $\\triangle QPS$ c\u00f3: <br\/> + $\\widehat{T} = \\widehat{Q}$ <br\/> + $PT = PQ$ <br\/> + $\\widehat{TPR} = \\widehat{QPS} $ (\u0111\u1ed1i \u0111\u1ec9nh) <br\/> $\\Rightarrow \\Delta TPR =\\Delta QPS$ (g - c - g) ","column":2}]}],"id_ques":1659},{"time":9,"part":[{"title":"Ch\u1ecdn <u>nh\u1eefng<\/u> \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"Ch\u1ecdn \u0111\u01b0\u1ee3c nhi\u1ec1u \u0111\u00e1p \u00e1n","temp":"checkbox","correct":[["1","2","4"]],"list":[{"point":5,"ques":"$\\triangle OAC = \\triangle OBD $ theo tr\u01b0\u1eddng h\u1ee3p g\u00f3c-c\u1ea1nh-g\u00f3c n\u1ebfu c\u00f3 c\u00e1c \u0111i\u1ec1u ki\u1ec7n sau: <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai12/lv1/img\/H7B12-36.png' \/><\/center> ","column":2,"number_true":3,"select":["$\\widehat{AOB}$ chung","$OA = OB$","$OD = OC$","$\\widehat{OAC} = \\widehat{OBD} $"],"explain":"X\u00e9t $\\triangle OAC $ v\u00e0 $\\triangle OBD $ c\u00f3: <br\/> + $\\widehat{AOB}$ chung <br\/>+ $OA = OB$ <br\/>+ $\\widehat{OAC} = \\widehat{OBD}$ <br\/> $\\Rightarrow \\triangle OAC = \\triangle OBD (g.c.g)$ "}]}],"id_ques":1660}],"lesson":{"save":0,"level":1}}