{"segment":[{"time":24,"part":[{"time":3,"title":"N\u1ed1i t\u1eeb ho\u1eb7c c\u1ee5m t\u1eeb \u1edf c\u1ed9t b\u00ean tr\u00e1i v\u1edbi c\u1ed9t b\u00ean ph\u1ea3i \u0111\u1ec3 \u0111\u01b0\u1ee3c c\u00e2u ho\u00e0n ch\u1ec9nh","title_trans":"Cho h\u00ecnh v\u1ebd d\u01b0\u1edbi \u0111\u00e2y. Bi\u1ebft r\u1eb1ng C l\u00e0 trung \u0111i\u1ec3m c\u1ee7a $AD$ v\u00e0 $\\widehat{A} = \\widehat{D}$ <br\/> H\u00e3y s\u1eafp x\u1ebfp c\u00e1c \u00fd ch\u1ee9ng minh $BC = EC$ ","audio":"","temp":"matching","correct":[["2","4","5","1","3"]],"list":[{"point":10,"ques":"","image":"https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai12/lv3/img\/H7B12-35.png","left":["C l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AD v\u00e0 $\\widehat{A} = \\widehat{D}$ ","$AC = CD$","$\\widehat{ACB} = \\widehat{DCE} $","$\\triangle ABC = \\triangle DEC $","$BC = EC$"],"right":["theo tr\u01b0\u1eddng h\u1ee3p g\u00f3c-c\u1ea1nh-g\u00f3c","gi\u1ea3 thi\u1ebft","\u0111i\u1ec1u ph\u1ea3i ch\u1ee9ng minh","\u0111\u1ecbnh ngh\u0129a trung \u0111i\u1ec3m","g\u00f3c \u0111\u1ed1i \u0111\u1ec9nh"],"top":100,"explain":"<span class='basic_left'> Ta c\u00f3: <br\/> C l\u00e0 trung \u0111i\u1ec3m c\u1ee7a AD v\u00e0 $\\widehat{A} = \\widehat{D}$ (gi\u1ea3 thi\u1ebft) <br\/> $AC = CD$ (\u0111\u1ecbnh ngh\u0129a trung \u0111i\u1ec3m) <br\/> $\\widehat{ACB} = \\widehat{DCE} $ (g\u00f3c \u0111\u1ed1i \u0111\u1ec9nh) <br\/> $\\Rightarrow$ $\\triangle ABC = \\triangle DEC $ <br\/> $\\Rightarrow$ BC = EC <\/span> "}]}],"id_ques":1661},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00fang hay sai","title_trans":"","temp":"true_false","correct":[["t","t","t","f"]],"list":[{"point":10,"image":"","col_name":["","\u0110\u00fang","Sai"],"arr_ques":["N\u1ebfu hai tam gi\u00e1c b\u1eb1ng nhau th\u00ec m\u1ed9t c\u1ea1nh v\u00e0 hai g\u00f3c k\u1ec1 c\u1ee7a tam gi\u00e1c n\u00e0y b\u1eb1ng m\u1ed9t c\u1ea1nh v\u00e0 hai g\u00f3c k\u1ec1 c\u1ee7a tam gi\u00e1c kia. ","N\u1ebfu m\u1ed9t c\u1ea1nh v\u00e0 hai g\u00f3c k\u1ec1 c\u1ee7a tam gi\u00e1c n\u00e0y b\u1eb1ng m\u1ed9t c\u1ea1nh v\u00e0 hai g\u00f3c k\u1ec1 c\u1ee7a tam gi\u00e1c kia th\u00ec hai tam gi\u00e1c \u0111\u00f3 b\u1eb1ng nhau. ","N\u1ebfu m\u1ed9t c\u1ea1nh v\u00e0 hai g\u00f3c k\u1ec1 c\u1ee7a tam gi\u00e1c n\u00e0y b\u1eb1ng m\u1ed9t c\u1ea1nh v\u00e0 hai g\u00f3c k\u1ec1 c\u1ee7a tam gi\u00e1c kia th\u00ec c\u1eb7p g\u00f3c c\u00f2n l\u1ea1i c\u0169ng b\u1eb1ng nhau.","N\u1ebfu m\u1ed9t c\u1ea1nh v\u00e0 hai g\u00f3c c\u1ee7a tam gi\u00e1c n\u00e0y b\u1eb1ng m\u1ed9t c\u1ea1nh v\u00e0 hai g\u00f3c c\u1ee7a tam gi\u00e1c kia th\u00ec hai tam gi\u00e1c \u0111\u00f3 b\u1eb1ng nhau. "],"explain":[" <span class='basic_left'>1 - \u0110\u00fang, do \u0111\u1ecbnh ngh\u0129a hai tam gi\u00e1c b\u1eb1ng nhau. <\/span>","<span class='basic_left'>2 - \u0110\u00fang, do g\u00f3c-c\u1ea1nh-g\u00f3c <\/span>","<span class='basic_left'>3 - \u0110\u00fang do g\u00f3c-c\u1ea1nh-g\u00f3c v\u00e0 \u0111\u1ecbnh ngh\u0129a hai tam gi\u00e1c b\u1eb1ng nhau. <\/span>"," <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai12/lv3/img\/H7B12-39.png' \/><\/center> <br\/> <span class='basic_left'>4 - Sai, v\u00ed d\u1ee5 X\u00e9t $\\triangle ABC $ c\u00f3 $AC > AB$, <br\/> Tr\u00ean $AC$ l\u1ea5y $A'C' = AB$ <br\/> V\u1ebd $A'B' \/\/ AB, B'C' \/\/ BC$ th\u00ec hai tam gi\u00e1c $ABC$ v\u00e0 $A'B'C'$ c\u00f3: <br\/> + $AB = A'C'$ <br\/> + $\\widehat{A} = \\widehat{A'}$ <br\/> + $ \\widehat{C} = \\widehat{C'} $ <br\/> Nh\u01b0ng hai tam gi\u00e1c kh\u00f4ng b\u1eb1ng nhau. <\/span> "]}]}],"id_ques":1662},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":10,"ques":"Cho tam gi\u00e1c $ABC$ (AB $\\neq$ AC), tia $Ax$ \u0111i qua trung \u0111i\u1ec3m M c\u1ee7a $BC$. <br\/> K\u1ebb $BE$ v\u00e0 $CF$ vu\u00f4ng g\u00f3c v\u1edbi $Ax (E \\in Ax, F \\in Ax)$. Khi \u0111\u00f3: ","select":["$BE < CF$ ","$BE = CF$ ","$BE > CF$ "],"explain":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai12/lv3/img\/H7B12-40.png' \/><\/center> <span class='basic_left'> Theo gi\u1ea3 thi\u1ebft $ BE \\perp Ax, CF \\perp Ax$ <br\/> Suy ra $BE \/\/ CF$ (v\u00ec c\u00f9ng vu\u00f4ng g\u00f3c v\u1edbi \u0111\u01b0\u1eddng th\u1eb3ng th\u1ee9 ba) <br\/> T\u1eeb \u0111\u00f3 $\\widehat{B_{1}} = \\widehat{C_{2}} $ (so le trong) (1) <br\/>M\u1eb7t kh\u00e1c c\u00f3: $MB = MC$ (gi\u1ea3 thi\u1ebft) (2) <br\/> $\\qquad \\widehat{BME} = \\widehat{CMF} $ (\u0111\u1ed1i \u0111\u1ec9nh) (3) <br\/> T\u1eeb (1), (2) v\u00e0 (3), ta c\u00f3: $\\triangle BME = \\triangle CMF (g.c.g) $ <br\/> Suy ra: $BE = CF$ <\/span> ","column":3}]}],"id_ques":1663},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":10,"ques":"<span class='basic_left'>Cho tam gi\u00e1c $ABC$ (AB $\\neq$ AC). C\u00e1c tia ph\u00e2n gi\u00e1c c\u1ee7a c\u00e1c g\u00f3c B v\u00e0 C c\u1eaft nhau t\u1ea1i I. <br\/> V\u1ebd $ID \\perp AB (D \\in AB), IE \\perp BC (E \\in BC), IF \\perp AC (F \\in AC) $. Khi \u0111\u00f3: <\/span> ","select":["A. $ID = IE $","B. $ID = IE = IF $ ","C. $ID \\neq IE = IF $","D. $ID = IE \\neq IF $"],"explain":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai12/lv3/img\/H7B12-19.png' \/><\/center> <span class='basic_left'> Tam gi\u00e1c $BID$ v\u00e0 tam gi\u00e1c $BIE$ c\u00f3: $\\widehat{B_{1}} = \\widehat{B_{2}}, \\widehat{BDI} = \\widehat{BEI} $ (gi\u1ea3 thi\u1ebft) n\u00ean $\\widehat{I_{1}} = \\widehat{I_{2}} $ <br\/> X\u00e9t $\\triangle BID $ v\u00e0 $ \\triangle BIE $ c\u00f3: <br\/> + $\\widehat{B_{1}} = \\widehat{B_{2}}$ <br\/> + c\u1ea1nh BI chung<br\/> + $\\widehat{I_{1}} = \\widehat{I_{2}}$ <br\/> Do \u0111\u00f3 $\\triangle BID = \\triangle BIE $ (g.c.g) <br\/> Suy ra $ID = IE$ (hai c\u1ea1nh t\u01b0\u01a1ng \u1ee9ng) <br\/> Ch\u1ee9ng minh t\u01b0\u01a1ng t\u1ef1 c\u00f3 $ \\triangle CIE = \\triangle CIF $ (g.c.g) <br\/> Suy ra $IE = IF$ (hai c\u1ea1nh t\u01b0\u01a1ng \u1ee9ng) <br\/> Do \u0111\u00f3 $ ID = IE = IF$ <br\/><br\/><span class='basic_pink'>\u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0 B. <\/span> ","column":2}]}],"id_ques":1664},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang ho\u1eb7c sai","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":10,"ques":"Cho hai tam gi\u00e1c $ABC $ v\u00e0 $A'B'C'$ c\u00f3 $\\widehat{B} = \\widehat{B'}, \\widehat{A} = \\widehat{A'}$. V\u1ebd $AH \\perp BC (H \\in BC), A'H' \\perp B'C' (H' \\in B'C') $, bi\u1ebft $AH = A'H'$. Khi \u0111\u00f3 $\\triangle ABC = \\triangle A'B'C' $ ","select":["\u0110\u00fang","Sai"],"explain":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai12/lv3/img\/H7B12-43.png' \/><\/center> <span class='basic_left'> Ta c\u00f3 $AH \\perp BC, A'H' \\perp B'C' $ (gi\u1ea3 thi\u1ebft) n\u00ean $\\widehat{AHB} = \\widehat{A'H'B'} = 90^{o} $ <br\/> Do \u0111\u00f3 trong tam gi\u00e1c $AHB$ v\u00e0 $A'H'B'$ c\u00f3: <br\/> $\\widehat{B} + \\widehat{BAH} = \\widehat{B'} + \\widehat{B'A'H'} = 90^{o}$ <br\/> M\u00e0 $\\widehat{B} = \\widehat{B'}$ (gi\u1ea3 thi\u1ebft) n\u00ean $ \\widehat{BAH} = \\widehat{B'A'H'} $ <br\/> X\u00e9t $\\triangle BAH $ v\u00e0 $\\triangle B'A'H' $ c\u00f3: <br\/> + $ \\widehat{BAH} = \\widehat{B'A'H'} $ (ch\u1ee9ng minh tr\u00ean)<br\/> + $ AH = A'H'$ (gi\u1ea3 thi\u1ebft)<br\/> + $\\widehat{AHB} = \\widehat{A'H'B'} $ <br\/> Do \u0111\u00f3 $\\triangle BAH = \\triangle B'A'H' (g.c.g) $ <br\/> $ \\Rightarrow AB = A'B' $ (hai c\u1ea1nh t\u01b0\u01a1ng \u1ee9ng) <br\/> X\u00e9t $\\triangle ABC $ v\u00e0 $\\triangle A'B'C' $ c\u00f3: <br\/> + $AB = A'B'$ (ch\u1ee9ng minh tr\u00ean) <br\/>+ $\\widehat{B} = \\widehat{B'}$ <br\/> + $ \\widehat{A} = \\widehat{A'}$ (gi\u1ea3 thi\u1ebft) <br\/> Do \u0111\u00f3 $\\triangle ABC = \\triangle A'B'C'. $ <\/span> ","column":2}]}],"id_ques":1665},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":10,"ques":"<span class='basic_left'>Tr\u00ean c\u1ea1nh $BC$ c\u1ee7a tam gi\u00e1c $ABC$ l\u1ea5y c\u00e1c \u0111i\u1ec3m D, E sao cho $BD = CE < \\dfrac{1}{2}BC $. <br\/> Qua D v\u00e0 E v\u1ebd c\u00e1c \u0111\u01b0\u1eddng th\u1eb3ng song song v\u1edbi AB, c\u1eaft c\u1ea1nh AC \u1edf F v\u00e0 G. Khi \u0111\u00f3: <\/span> ","select":["$DF + EG = AB $","$DF + EG = \\dfrac{AB}{2} $","$DF + EG = \\dfrac{AB}{3} $"],"explain":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai12/lv3/img\/H7B12-44.png' \/><\/center> <span class='basic_left'> * K\u1ebb $DK \/\/ AC$ $\\Rightarrow \\widehat{BDK} = \\widehat{C} $ (\u0111\u1ed3ng v\u1ecb) <br\/> C\u00f3 $EG \/\/ AB$ (gi\u1ea3 thi\u1ebft) $\\Rightarrow \\widehat{B} = \\widehat{CEG} $ (\u0111\u1ed3ng v\u1ecb) <br\/> X\u00e9t $\\triangle BKD $ v\u00e0 $\\triangle EGC $ c\u00f3: <br\/> + $\\widehat{B} = \\widehat{CEG}$ <br\/> + $BD = CE$ (gi\u1ea3 thi\u1ebft) <br\/> + $\\widehat{BDK} = \\widehat{C}$ (ch\u1ee9ng minh tr\u00ean) <br\/> Do \u0111\u00f3 $\\triangle BKD = \\triangle EGC (g.c.g)$ <br\/> Suy ra $BK = EG$ (hai c\u1ea1nh t\u01b0\u01a1ng \u1ee9ng) (1) <br\/> * Ta c\u00f3: $DF \/\/ AK, AF \/\/ DK$ n\u00ean $\\widehat{A_{1}} = \\widehat{D_{1}}$ <br\/> X\u00e9t $\\triangle ADK$ v\u00e0 $ \\triangle DAF$ c\u00f3: <br\/> + $\\widehat{A_{1}} = \\widehat{D_{1}}$ (ch\u1ee9ng minh tr\u00ean) <br\/> + c\u1ea1nh AD chung <br\/> + $\\widehat{A_{2}} = \\widehat{D_{2}} $ (so le trong) <br\/> Do \u0111\u00f3 $\\triangle ADK = \\triangle DAF (g.c.g) $ <br\/> $\\Rightarrow AK = DF $ (hai c\u1ea1nh t\u01b0\u01a1ng \u1ee9ng) (2) <br\/> T\u1eeb (1) v\u00e0 (2) ta c\u00f3: $DF + EG = AK + BK = AB $<\/span> ","column":3}]}],"id_ques":1666},{"time":24,"part":[{"title":"N\u1ed1i t\u1eeb ho\u1eb7c c\u1ee5m t\u1eeb \u1edf c\u1ed9t b\u00ean tr\u00e1i v\u1edbi c\u1ed9t b\u00ean ph\u1ea3i \u0111\u1ec3 \u0111\u01b0\u1ee3c c\u00e2u ho\u00e0n ch\u1ec9nh","title_trans":"","audio":"","temp":"matching","correct":[["3","2","1","5","4"]],"list":[{"point":10,"image":"https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai12/lv3/img\/H7B12-15.png","left":["$\\triangle AHB = $","$\\triangle CEB = $","$\\triangle ABD = $","$AB = $","$BC = $"],"right":["$\\triangle CDB (c.c.c) $","$\\triangle AFD (c.g.c) $ ","$\\triangle CKD (c.g.c) $ ","$AD$","$CD$"],"top":100,"explain":"<span class='basic_left'> X\u00e9t $\\triangle AHB $ v\u00e0 $\\triangle CKD $ c\u00f3: <br\/> + $AH = CK $ <br\/> + $\\widehat{AHB} = \\widehat{CKD}$ <br\/> + $ BH = DK $ <br\/> Do \u0111\u00f3 $\\triangle AHB = \\triangle CKD $ (c.g.c) $\\Rightarrow AB = CD $ <br\/> T\u01b0\u01a1ng t\u1ef1 c\u00f3: $\\triangle CEB = \\triangle AFD $ (c.g.c) $\\Rightarrow BC = AD $ <br\/> $\\triangle ABD $ v\u00e0 $\\triangle CDB $ c\u00f3: $AB = CD$ <br\/>+ $BC = AD$ <br\/> + BD chung <br\/> n\u00ean $ \\triangle ABD = \\triangle CDB $ (c.c.c) "}]}],"id_ques":1667},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":10,"ques":"<span class='basic_left'> <b>T\u00ecm c\u00e2u tr\u1ea3 l\u1eddi sai<\/b> <br\/> Cho h\u00ecnh v\u1ebd, bi\u1ebft: $\\widehat{EAD} = \\widehat{HAD} $ <br\/> $HB \\perp AE (B \\in AE), EC \\perp AH (C \\in AH) $ Khi \u0111\u00f3: <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai12/lv3/img\/H7B12-10.png' \/><\/center> ","select":["A. $\\triangle ABD = \\triangle ACD $ ","B. $\\triangle DBE = \\triangle DCH $ ","C. $\\triangle ADE = \\triangle AHD $ ","D. $\\triangle ABH = \\triangle ACE $ "],"explain":" <span class='basic_left'> Ta d\u1ec5 d\u00e0ng ch\u1ee9ng minh \u0111\u01b0\u1ee3c: $\\triangle ABD = \\triangle ACD $ ( g - c - g) <br\/> $\\Rightarrow BD=CD$ (hai c\u1ea1nh t\u01b0\u01a1ng \u1ee9ng) <br\/> Do \u0111\u00f3, ta c\u0169ng ch\u1ee9ng minh \u0111\u01b0\u1ee3c d\u1ec5 d\u00e0ng: $\\triangle DBE = \\triangle DCH $ (g - c - g) <br\/> V\u00e0 $\\triangle ABH = \\triangle ACE $ ( g- c - g) <br\/> C\u00e2u tr\u1ea3 l\u1eddi sai l\u00e0 C. V\u00ec $\\triangle ADE = \\triangle ADH $ ( c - c - c) ","column":2}]}],"id_ques":1668},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":10,"ques":"<span class='basic_left'>Cho tam gi\u00e1c $ABC$. \u1ede ph\u00eda ngo\u00e0i tam gi\u00e1c $ABC$, v\u1ebd c\u00e1c tam gi\u00e1c vu\u00f4ng t\u1ea1i A l\u00e0 $ABD$ v\u00e0 $ACE$ c\u00f3 $AB = AD, AC = AE$. K\u1ebb $AH$ vu\u00f4ng g\u00f3c v\u1edbi $BC$. G\u1ecdi I l\u00e0 giao \u0111i\u1ec3m c\u1ee7a $HA$ v\u00e0 $DE$. Khi \u0111\u00f3: <\/span> ","select":["$DI < IE$ ","$DI = IE$ ","$DI > IE$ "],"explain":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai12/lv3/img\/H7B12-55.png' \/><\/center> <span class='basic_left'> K\u1ebb $DM \\perp IH, EN \\perp IH $ <br\/> * Ta c\u00f3 $\\widehat{A_{1}} + \\widehat{A_{2}} = 90^{o} $ (do $\\widehat{DAB} = 90^{o} $) <br\/> M\u00e0 $\\widehat{D_{1}} + \\widehat{A_{2}} = 90^{o} $ ($\\triangle DMA $ vu\u00f4ng t\u1ea1i M) <br\/> $\\widehat{A_{1}} + \\widehat{B_{2}} = 90^{o}$ ($\\triangle BAH $ vu\u00f4ng t\u1ea1i H) <br\/> $\\Rightarrow \\widehat{A_{1}} = \\widehat{D_{1}}, \\widehat{A_{2}} = \\widehat{B_{2}} $ <br\/> X\u00e9t $\\triangle DAM $ v\u00e0 $\\triangle ABH $ c\u00f3: <br\/> + $ \\widehat{D_{1}} = \\widehat{A_{1}} $ (ch\u1ee9ng minh tr\u00ean) <br\/> + $AD = AB$ (gi\u1ea3 thi\u1ebft) <br\/> + $\\widehat{A_{2}} = \\widehat{D_{2}} $ (ch\u1ee9ng minh tr\u00ean) <br\/> Do \u0111\u00f3 $\\triangle DAM = \\triangle ABH (g.c.g) $ <br\/> $\\Rightarrow MD = AH (1) $ <br\/> * Ch\u1ee9ng minh t\u01b0\u01a1ng t\u1ef1 $\\triangle ANE = \\triangle CHA (g.c.g) $ <br\/> $\\Rightarrow EN = AH (2) $ <br\/> T\u1eeb (1) v\u00e0 (2) $\\Rightarrow EN = MD $ <br\/> * Hai tam gi\u00e1c $INE$ v\u00e0 $IMD c\u00f3$: <br\/> + $\\widehat{N} = \\widehat{M} (= 90^{o})$ <br\/> + $\\widehat{NIE} = \\widehat{IDM} $ (\u0111\u1ed1i \u0111\u1ec9nh) n\u00ean $\\widehat{IEN} = \\widehat{IDM} $ <br\/> X\u00e9t $\\triangle DIM $ v\u00e0 $\\triangle EIN $ c\u00f3: <br\/> + $\\widehat{IMD} = \\widehat{INE} (= 90^{o})$<br\/> + $DM = EN$ (ch\u1ee9ng minh tr\u00ean)<br\/> + $\\widehat{IEN} = \\widehat{IDM} $ (ch\u1ee9ng minh tr\u00ean) <br\/> Do \u0111\u00f3 $\\triangle DIM = \\triangle EIN (g.c.g)$ <br\/> $\\Rightarrow DI = IE $ (hai c\u1ea1nh t\u01b0\u01a1ng \u1ee9ng) <br\/> <span class='basic_pink'>V\u1eady DI = IE <\/span>","column":3}]}],"id_ques":1669},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":10,"ques":"Cho tam gi\u00e1c $ABC$ vu\u00f4ng t\u1ea1i A. <br\/> V\u1ebd AH vu\u00f4ng g\u00f3c v\u1edbi BC (H $\\in$ BC ). Khi \u0111\u00f3: ","select":["A. $\\widehat{ACB} = \\widehat{HAB}, \\widehat{ABC} = \\widehat{HAC} $ ","B. $\\triangle AHB = \\triangle CAB $ ","C. $\\triangle AHB = \\triangle CAH $ ","D. $\\triangle AHC= \\triangle BAC $ "],"explain":" <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop7/toan/hinhhoc/bai12/lv3/img\/H7B12-12.png' \/><\/center> \u0110\u00e1p \u00e1n \u0111\u00fang l\u00e0 A. V\u00ec: <br\/> $\\widehat{ACB} = \\widehat{HAB} $ (c\u00f9ng ph\u1ee5 v\u1edbi g\u00f3c $\\widehat{HAC} $) <br\/> $\\widehat{ABC} = \\widehat{HAC} $ (c\u00f9ng ph\u1ee5 v\u1edbi g\u00f3c $\\widehat{BAH} $)","column":2}]}],"id_ques":1670}],"lesson":{"save":0,"level":3}}