Bài ôn tập chương 4: Tam giác bằng nhau

Home Lớp 7 Toán lớp 7 - Sách kết nối tri thức Bài ôn tập chương 4: Tam giác bằng nhauBài tập cơ bản

{"common":{"save":0,"post_id":"5674","level":1,"total":10,"point":10,"point_extra":0},"segment":[{"id":"7579","post_id":"5674","mon_id":"1158532","chapter_id":"1158548","question":"Ch\u1ecdn phát bi\u1ec3u \u0111úng trong các phát bi\u1ec3u sau.<\/p>","options":["A.<\/strong> T\u1ed5ng s\u1ed1 \u0111o các góc trong c\u1ee7a m\u1ed9t tam giác b\u1eb1ng 180º.","B.<\/strong> N\u1ebfu hai c\u1ea1nh c\u1ee7a tam giác này l\u1ea7n l\u01b0\u1ee3t b\u1eb1ng hai c\u1ea1nh c\u1ee7a tam giác kia thì hai tam giác \u0111ó b\u1eb1ng nhau.","C.<\/strong> N\u1ebfu tam giác này có hai góc l\u1ea7n l\u01b0\u1ee3t b\u1eb1ng hai góc c\u1ee7a tam giác kia thì hai tam giác \u0111ó b\u1eb1ng nhau.","D. <\/strong>Góc ngoài c\u1ee7a tam giác có s\u1ed1 \u0111o b\u1eb1ng góc trong k\u1ec1 v\u1edbi nó."],"correct":"1","level":"1","hint":"","answer":"A.<\/strong> T\u1ed5ng s\u1ed1 \u0111o các góc trong c\u1ee7a m\u1ed9t tam giác b\u1eb1ng 180º.  (\u0111úng)<\/p>B.<\/strong> N\u1ebfu hai c\u1ea1nh c\u1ee7a tam giác này l\u1ea7n l\u01b0\u1ee3t b\u1eb1ng hai c\u1ea1nh c\u1ee7a tam giác kia thì hai tam giác \u0111ó b\u1eb1ng nhau.  (sai)<\/p>C.<\/strong> N\u1ebfu tam giác này có hai góc l\u1ea7n l\u01b0\u1ee3t b\u1eb1ng hai góc c\u1ee7a tam giác kia thì hai tam giác \u0111ó b\u1eb1ng nhau.  (sai)<\/p>D. <\/strong>Góc ngoài c\u1ee7a tam giác có s\u1ed1 \u0111o b\u1eb1ng góc trong k\u1ec1 v\u1edbi nó.  (sai)<\/p>\u0110áp án \u0111úng là  A.<\/strong> T\u1ed5ng s\u1ed1 \u0111o các góc trong c\u1ee7a m\u1ed9t tam giác b\u1eb1ng 180º.<\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"3","date":"2022-04-29 09:13:15","option_type":"txt","len":3},{"id":"7580","post_id":"5674","mon_id":"1158532","chapter_id":"1158548","question":"\u0110\u01b0\u1eddng th\u1eb3ng nào trong hình là \u0111\u01b0\u1eddng trung tr\u1ef1c c\u1ee7a \u0111o\u1ea1n th\u1eb3ng AB?<\/p><svg height=\"200\" width=\"310\" xmlns:xlink=\"http:\/\/www.w3.org\/1999\/xlink\"> <g><title><\/title><rect 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y=\"2\"><\/image> <\/g> <\/svg><\/span><\/p>","options":["m","n","p","q"],"correct":"4","level":"1","hint":"","answer":"Quan sát hình v\u1ebd ta th\u1ea5y \u0111\u01b0\u1eddng th\u1eb3ng q \u0111i qua trung \u0111i\u1ec3m c\u1ee7a \u0111o\u1ea1n th\u1eb3ng AB và vuông góc v\u1edbi \u0111o\u1ea1n th\u1eb3ng AB nên \u0111\u01b0\u1eddng th\u1eb3ng q là \u0111\u01b0\u1eddng trung tr\u1ef1c c\u1ee7a \u0111o\u1ea1n th\u1eb3ng AB.<\/p>\u0110áp án \u0111úng là   q<\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"1","date":"2022-04-29 09:22:41","option_type":"txt","len":0},{"id":"7587","post_id":"5674","mon_id":"1158532","chapter_id":"1158548","question":"Cho tam giác ABC có góc A có s\u1ed1 \u0111o b\u1eb1ng 30º , góc B có s\u1ed1 \u0111o b\u1eb1ng 40º. Tính s\u1ed1 \u0111o góc C.<\/p>","options":["100º","110º","120º","130º"],"correct":"2","level":"1","hint":"T\u1ed5ng ba góc trong c\u1ee7a m\u1ed9t tam giác b\u1eb1ng 180º.<\/p>","answer":"Xét tam giác ABC có<\/p>$\\widehat{A}+\\widehat{B}+\\widehat{C}=$<\/span> 180º<\/p>⇒ $\\widehat{C}=180^0-\\widehat{A}-\\widehat{B}$<\/span> = 180º - 30º - 40º = 110º<\/p>\u0110áp án \u0111úng là   110º<\/strong><\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"1","date":"2022-04-30 02:09:39","option_type":"txt","len":0}]}