{"common":{"save":0,"post_id":"1008","level":3,"total":10,"point":10,"point_extra":0},"segment":[{"id":"1441","post_id":"1008","mon_id":"0","chapter_id":"0","question":"S\u1eafp x\u1ebfp c\u00e1c c\u00e2u","options":{"time":24,"part":[{"time":3,"title":"S\u1eafp x\u1ebfp c\u00e1c c\u00e2u","title_trans":"Cho g\u00f3c vu\u00f4ng $\\widehat{xOy} $, \u0111i\u1ec3m A thu\u1ed9c tia Ox. <br\/> K\u1ebb tia Az vu\u00f4ng g\u00f3c v\u1edbi Ox (tia Az n\u1eb1m trong g\u00f3c $\\widehat{xOy} $). <br\/> G\u1ecdi Om l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c $\\widehat{xOy} $, An l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c $\\widehat{xAz} $ <br\/> H\u00e3y s\u1eafp x\u1ebfp c\u00e1c \u00fd ch\u1ee9ng minh Om \/\/ An ","temp":"sequence","correct":[[[1],[5],[2],[3],[4],[6]]],"list":[{"point":10,"image":"","left":["Ta c\u00f3 Om l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c $\\widehat{xOy} $ "," Do d\u00f3 $\\widehat{mOx} = \\widehat{nAx} (= 45^{o}) $"," n\u00ean $\\widehat{mOx} = 45^{o} $ "," M\u1eb7t kh\u00e1c An l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c $\\widehat{xAz} $ ","n\u00ean $\\widehat{nAx} = 45^{o} $ ","V\u1eady Om \/\/ An "],"top":55,"hint":"","explain":" <center><img src='img\/H7C14-59.png' \/><\/center> <br\/>Ta c\u00f3 Om l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c $\\widehat{xOy} $ <br\/> n\u00ean $\\widehat{mOx} = \\dfrac{\\widehat{xOy}}{2} = \\dfrac{90^{o}}{2} = 45^{o} $ <br\/> M\u1eb7t kh\u00e1c An l\u00e0 tia ph\u00e2n gi\u00e1c c\u1ee7a g\u00f3c $\\widehat{xAz} $ <br\/> n\u00ean $\\widehat{nAx} = \\dfrac{\\widehat{xAz}}{2} = \\dfrac{90^{o}}{2} = 45^{o} $ <br\/> Do d\u00f3 $\\widehat{mOx} = \\widehat{nAx} (= 45^{o}) $ <br\/> Hai g\u00f3c n\u00e0y l\u00e0 hai g\u00f3c \u0111\u1ed3ng v\u1ecb t\u1ea1o b\u1edfi Ox c\u1eaft hai \u0111\u01b0\u1eddng th\u1eb3ng Om v\u00e0 An n\u00ean Om \/\/ An. <br\/> V\u1eady Om \/\/ An "}]}]},"correct":"","level":"3","hint":"","answer":"","type":"json","extra_type":"","time":"0","user_id":"0","test":"0","date":"2019-09-30 09:22:59"},{"id":"1442","post_id":"1008","mon_id":"0","chapter_id":"0","question":"S\u1eafp x\u1ebfp c\u00e1c c\u00e2u","options":{"time":24,"part":[{"time":3,"title":"S\u1eafp x\u1ebfp c\u00e1c c\u00e2u","title_trans":"Cho h\u00ecnh v\u1ebd, bi\u1ebft $\\widehat{A_{1}} = 72^{o}; \\widehat{B_{2}} = \\dfrac{2}{3}\\widehat{B_{1}} $ <br\/> H\u00e3y s\u1eafp x\u1ebfp ch\u1ee9ng minh a \/\/ b. ","temp":"sequence","correct":[[[2],[3],[5],[1],[4]]],"list":[{"point":10,"image":"img\/H7C14-19.png","left":["m\u00e0 $\\widehat{B_{2}} = \\dfrac{2}{3}\\widehat{B_{1}} $","n\u00ean $\\widehat{B_{2}} = 72^{o} $","V\u1eady a \/\/ b (v\u00ec c\u00f3 c\u1eb7p g\u00f3c \u0111\u1ed3ng v\u1ecb b\u1eb1ng nhau)","Ta c\u00f3: $\\widehat{B_{1}} + \\widehat{B_{2}} = 180^{o} $(k\u1ec1 b\u00f9) ","Suy ra: $\\widehat{A_{1}} = \\widehat{B_{2}} (= 72^{o}) $, l\u1ea1i c\u00f3 $\\widehat{A_{1}}$ v\u00e0 $\\widehat{B_{2}}$ \u1edf v\u1ecb tr\u00ed \u0111\u1ed3ng v\u1ecb v\u1edbi nhau"],"top":70,"hint":"","explain":"Ta c\u00f3: $\\widehat{B_{1}} + \\widehat{B_{2}} = 180^{o} $(k\u1ec1 b\u00f9), m\u00e0 $\\widehat{B_{2}} = \\dfrac{2}{3}\\widehat{B_{1}} $ <br\/> n\u00ean: $\\dfrac{\\widehat{B_{2}}}{2} = \\dfrac{\\widehat{B_{1}}}{3} = \\dfrac{\\widehat{B_{2}}+\\widehat{B_{1}}}{2+3} = \\dfrac{180^{o}}{5} = 36^{o} \\\\ \\Rightarrow\\widehat{B_{2}} = 36^{o}.2 = 72^{o} $ <br\/> Suy ra: $\\widehat{A_{1}} = \\widehat{B_{2}} (= 72^{o}) $<br\/>L\u1ea1i c\u00f3: $\\widehat{A_{1}}$ v\u00e0 $\\widehat{B_{2}}$ \u1edf v\u1ecb tr\u00ed \u0111\u1ed3ng v\u1ecb v\u1edbi nhau <br\/> V\u1eady a \/\/ b (v\u00ec c\u00f3 c\u1eb7p g\u00f3c \u0111\u1ed3ng v\u1ecb b\u1eb1ng nhau) "}]}]},"correct":"","level":"3","hint":"","answer":"","type":"json","extra_type":"","time":"0","user_id":"0","test":"0","date":"2019-09-30 09:22:59"},{"id":"1443","post_id":"1008","mon_id":"0","chapter_id":"0","question":"S\u1eafp x\u1ebfp c\u00e1c c\u00e2u","options":{"time":24,"part":[{"time":3,"title":"S\u1eafp x\u1ebfp c\u00e1c c\u00e2u","title_trans":"Cho h\u00ecnh v\u1ebd <br\/> H\u00e3y s\u1eafp x\u1ebfp c\u00e1c \u00fd ch\u1ee9ng minh By \/\/ Cz","temp":"sequence","correct":[[[1],[4],[5],[3],[2],[6]]],"list":[{"point":10,"image":"img\/H7C14-55A.png","left":["Trong g\u00f3c aBC v\u1ebd tia By' l\u00e0 tia \u0111\u1ed1i c\u1ee7a tia By","n\u00ean $\\widehat{y'BC} = 40^{o} $","Do \u0111\u00f3 $\\widehat{y'BC} = \\widehat{BCz} $ ","Bi\u1ebft By' n\u1eb1m gi\u1eefa hai tia Ba v\u00e0 BC","n\u00ean $\\widehat{aBy'} = 70^{o} $ ","V\u1eady By \/\/ Cz"],"top":55,"hint":"","explain":" <center><img src='img\/H7C14-55B.png' \/><\/center> <br\/> Trong g\u00f3c aBC v\u1ebd tia By' l\u00e0 tia \u0111\u1ed1i c\u1ee7a tia By <br\/> n\u00ean $\\widehat{aBy'} = 180^{o} - 110^{o} = 70^{o} $ <br\/> Bi\u1ebft By' n\u1eb1m gi\u1eefa hai tia Ba v\u00e0 BC <br\/> $\\Rightarrow \\widehat{aBy'} + \\widehat{y'BC} = \\widehat{aBC} \\\\ \\Rightarrow \\widehat{y'BC} = 110^{o} - 70^{o} = 40^{o} $ <br\/> Do \u0111\u00f3 $\\widehat{y'BC} = \\widehat{BCz} (= 40^{o}) $ <br\/> Hai g\u00f3c n\u00e0y l\u00e0 hai g\u00f3c so le trong t\u1ea1o b\u1edfi BC c\u1eaft hai \u0111\u01b0\u1eddng th\u1eb3ng yy' v\u00e0 Cz n\u00ean yy' \/\/ Cz. <br\/> V\u1eady By \/\/ Cz "}]}]},"correct":"","level":"3","hint":"","answer":"","type":"json","extra_type":"","time":"0","user_id":"0","test":"0","date":"2019-09-30 09:22:59"}]}