Phép cộng và phép trừ đa thức một biến

Home Lớp 7 Toán lớp 7 - Sách kết nối tri thức Bài 26: Phép cộng và phép trừ đa thức một biếnBài tập trung bình

{"common":{"save":0,"post_id":"5810","level":2,"total":10,"point":10,"point_extra":0},"segment":[{"id":"8530","post_id":"5810","mon_id":"1158532","chapter_id":"1158660","question":"Cho tam giác ABC v\u1edbi các \u0111\u1ed9 dài nh\u01b0 hình v\u1ebd. Vi\u1ebft bi\u1ec3u th\u1ee9c tính chu vi tam giác ABC.<\/p><svg height=\"150\" width=\"200\"> <g><title><\/title><rect fill=\"#fff\" height=\"152\" id=\"canvas_background\" width=\"202\" x=\"-1\" y=\"-1\"><\/rect> <g display=\"none\" height=\"100%\" id=\"canvasGrid\" overflow=\"visible\" width=\"100%\" x=\"0\" y=\"0\"> <rect fill=\"url(#gridpattern)\" height=\"100%\" stroke-width=\"0\" width=\"100%\" x=\"0\" y=\"0\"><\/rect> <\/g> <\/g> <g><title><\/title><g id=\"svg_4\"> <line fill=\"none\" id=\"svg_1\" stroke=\"#000\" stroke-linecap=\"undefined\" stroke-linejoin=\"undefined\" stroke-width=\"1.5\" transform=\"rotate(8.20460033416748 42.00000000000011,71.25000000000003) \" x1=\"54.43354\" x2=\"29.56647\" y1=\"21.29472\" y2=\"121.20527\"><\/line> <line fill=\"none\" fill-opacity=\"null\" id=\"svg_2\" stroke=\"#000\" stroke-linecap=\"undefined\" stroke-linejoin=\"undefined\" stroke-opacity=\"null\" stroke-width=\"1.5\" x1=\"21\" x2=\"170\" y1=\"119.25\" y2=\"119.25\"><\/line> <line fill=\"none\" fill-opacity=\"null\" id=\"svg_3\" stroke=\"#000\" stroke-linecap=\"undefined\" stroke-linejoin=\"undefined\" stroke-opacity=\"null\" stroke-width=\"1.5\" x1=\"60\" x2=\"170\" y1=\"24.25\" y2=\"118.25\"><\/line> <\/g> <text fill=\"#000000\" fill-opacity=\"null\" font-family=\"Helvetica, Arial, sans-serif\" font-size=\"15\" id=\"svg_5\" stroke=\"#000\" stroke-opacity=\"null\" stroke-width=\"0\" style=\"cursor: move;\" text-anchor=\"start\" x=\"53\" xml:space=\"preserve\" y=\"21.25\">A<\/text> <text fill=\"#000000\" fill-opacity=\"null\" font-family=\"Helvetica, Arial, sans-serif\" font-size=\"15\" id=\"svg_6\" stroke=\"#000\" stroke-opacity=\"null\" stroke-width=\"0\" text-anchor=\"start\" x=\"9\" xml:space=\"preserve\" y=\"126.25\">B<\/text> <text fill=\"#000000\" fill-opacity=\"null\" font-family=\"Helvetica, Arial, sans-serif\" font-size=\"15\" id=\"svg_7\" stroke=\"#000\" stroke-opacity=\"null\" stroke-width=\"0\" text-anchor=\"start\" x=\"173\" xml:space=\"preserve\" y=\"124.25\">C<\/text> <text fill=\"#000000\" fill-opacity=\"null\" font-family=\"Helvetica, Arial, sans-serif\" font-size=\"15\" id=\"svg_8\" stroke=\"#000\" stroke-opacity=\"null\" stroke-width=\"0\" text-anchor=\"start\" x=\"23\" xml:space=\"preserve\" y=\"75.25\">x<\/text> <text fill=\"#000000\" fill-opacity=\"null\" font-family=\"Helvetica, Arial, sans-serif\" font-size=\"15\" id=\"svg_10\" stroke=\"#000\" stroke-opacity=\"null\" stroke-width=\"0\" style=\"cursor: move;\" text-anchor=\"start\" x=\"116\" xml:space=\"preserve\" y=\"71.25\">x - 1<\/text> <text fill=\"#000000\" fill-opacity=\"null\" font-family=\"Helvetica, Arial, sans-serif\" font-size=\"15\" id=\"svg_11\" stroke=\"#000\" stroke-opacity=\"null\" stroke-width=\"0\" text-anchor=\"start\" x=\"79\" xml:space=\"preserve\" y=\"134.25\">3x - 5<\/text> <\/g> <\/svg><\/span><\/p>","options":["A. <\/strong>$5x-6$<\/span>","B.<\/strong> $5x-4$<\/span>","C.<\/strong> $5x+4$<\/span>","D. <\/strong>$5x+6$<\/span>"],"correct":"1","level":"2","hint":"Chu vi tam giác b\u1eb1ng t\u1ed5ng ba c\u1ea1nh.<\/p>","answer":"Chu vi tam giác ABC là<\/p>    AB +    BC    + CA<\/p>$=\u00a0 \u00a0x\u00a0 \u00a0+ (x - 1)\u00a0 + (3x - 5)\\n$<\/span><\/p>$=\u00a0 \u00a0x + x - 1 + 3x - 5$<\/span><\/p>$= x + x + 3x - 1 - 5$<\/span><\/p>$=\u00a0 \u00a0 \u00a0 5x\u00a0 \u00a0 -\u00a0 6$<\/span><\/p>V\u1eady chu vi tam giác ABC là    $5x-6$<\/span><\/p>\u0110áp án \u0111úng là   A. <\/strong>$5x-6$<\/span><\/span><\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"2","date":"2022-06-01 08:28:19","option_type":"math","len":0},{"id":"8531","post_id":"5810","mon_id":"1158532","chapter_id":"1158660","question":"K\u1ebft qu\u1ea3 c\u1ee7a phép tính $(- 3x^3 - 2x^2 +x - 1) + (3x^2 - 2x - 5)$<\/span>  là<\/p>","options":["A.<\/strong> $-3x^3-4x^2-2x-6$<\/span>","B.<\/strong> $-6x^3+3x^2-x-6$<\/span>","C.<\/strong> $-3x^3+x^2-x-6$<\/span>","D.<\/strong> $-3x^3-2x^2-3x+6$<\/span>"],"correct":"3","level":"2","hint":"","answer":"   $(- 3x^3 - 2x^2 +x - 1) + (3x^2 - 2x - 5)$<\/span><\/p>= $-3x^3-2x^2+x-1+3x^2-2x-5$<\/span><\/p>= $-3x^3-2x^2+3x^2+x-2x-1-5$<\/span><\/p>= $-3x^3+x^2-x-6$<\/span><\/p>\u0110áp án \u0111úng là   C.<\/strong> $-3x^3+x^2-x-6$<\/span><\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"1","date":"2022-06-01 08:38:32","option_type":"math","len":0},{"id":"8533","post_id":"5810","mon_id":"1158532","chapter_id":"1158660","question":"K\u1ebft qu\u1ea3 c\u1ee7a phép tính $(- 3x^3 - 2x^2 +x - 1) - (3x^2 - 2x - 5)$<\/span>  là<\/p>","options":["A.<\/strong> $-3x^3-5x^2+3x+4$<\/span>","B.<\/strong> $-3x^3+5x^2-3x-4$<\/span>","C. <\/strong>$-3x^3-5x^2-3x+4$<\/span>","D. <\/strong>$-3x^3+5x^2+3x-4$<\/span>"],"correct":"1","level":"2","hint":"","answer":"   $(- 3x^3 - 2x^2 +x - 1) - (3x^2 - 2x - 5)$<\/span><\/p>= $- 3x^3 - 2x^2 +x - 1 - 3x^2 + 2x + 5$<\/span><\/p>= $-3x^3-2x^2-3x^2+x+2x-1+5$<\/span><\/p>= $-3x^3-5x^2+3x+4$<\/span><\/p>\u0110áp án \u0111úng là   A.<\/strong> $-3x^3-5x^2+3x+4$<\/span><\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"1","date":"2022-06-01 08:44:41","option_type":"math","len":0}]}