Phép cộng và phép trừ đa thức một biến

Home Lớp 7 Toán lớp 7 - Sách kết nối tri thức Bài 26: Phép cộng và phép trừ đa thức một biếnBài tập nâng cao

{"common":{"save":0,"post_id":"5811","level":3,"total":10,"point":10,"point_extra":0},"segment":[{"id":"8538","post_id":"5811","mon_id":"1158532","chapter_id":"1158660","question":"Vi\u1ebft \u0111a th\u1ee9c bi\u1ec3u di\u1ec5n ph\u1ea7n di\u1ec7n tích S màu xanh phía trong khung trang \u1edf hình d\u01b0\u1edbi<\/p><svg height=\"170\" width=\"260\"> <g><title><\/title><rect fill=\"#fff\" height=\"172\" id=\"canvas_background\" width=\"262\" x=\"-1\" y=\"-1\"><\/rect> <g display=\"none\" id=\"canvasGrid\"> <rect fill=\"url(#gridpattern)\" height=\"100%\" id=\"svg_2\" stroke-width=\"0\" width=\"100%\" x=\"0\" y=\"0\"><\/rect> <\/g> <\/g> <g><title><\/title><g id=\"svg_18\"> <g id=\"svg_19\"> <rect fill=\"#fff\" height=\"99\" id=\"svg_1\" stroke=\"#000\" stroke-width=\"1.5\" width=\"178\" x=\"25\" y=\"22.25\"><\/rect> <path d=\"m25.6,50.71713l51.84183,-28.70338l73.31634,0l51.84183,28.70338l0,40.59322l-51.84183,28.70338l-73.31634,0l-51.84183,-28.70338l0,-40.59322z\" fill=\"#aaffd4\" 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<path d=\"m115.06361,82.3834c0,-15.56747 -1.02212,-25.16386 -4.81858,-27.08313l0.09735,-0.42651c5.5,0.42651 7.00885,7.67711 7.00885,30.92169l0,32.20121c0,14.28795 0.34071,21.11205 3.89381,24.9506l0,0.42651c-3.50442,3.83855 -3.89381,10.66265 -3.89381,24.73735l0,34.33374c0,22.39157 -1.89823,28.78916 -7.00885,29.42892l-0.09735,-0.42544c3.89381,-2.55904 4.81858,-11.08916 4.81858,-27.29745l0,-34.33374c0,-14.50121 0.43805,-22.81807 4.0885,-26.44337l0,-0.42651c-3.69911,-3.83855 -4.0885,-12.79518 -4.0885,-27.29639l0,-33.26747z\" fill=\"#fff\" id=\"svg_15\" stroke=\"#000\" stroke-width=\"1.5\" transform=\"rotate(90 115.74502563476561,143.3737487792969) \"><\/path> <text fill=\"#000000\" fill-opacity=\"null\" font-family=\"Helvetica, Arial, sans-serif\" font-size=\"15\" id=\"svg_16\" stroke=\"#000\" stroke-opacity=\"null\" stroke-width=\"0\" text-anchor=\"start\" x=\"245\" xml:space=\"preserve\" y=\"78.25\">6<\/text> <text fill=\"#000000\" fill-opacity=\"null\" font-family=\"Helvetica, Arial, sans-serif\" font-size=\"15\" id=\"svg_17\" stroke=\"#000\" stroke-opacity=\"null\" stroke-width=\"0\" text-anchor=\"start\" x=\"112\" xml:space=\"preserve\" y=\"167.25\">8<\/text> <\/g> <\/g> <\/g> <\/svg><\/span><\/p>","options":["A.<\/strong> S = 48 - 4x²","B. <\/strong>S = 4x²","C.<\/strong> S = 48 - 8x²","D.<\/strong> S = 8x²"],"correct":"1","level":"3","hint":"Tính di\u1ec7n tích c\u1ee7a hình ch\u1eef nh\u1eadt bên ngoài, tính di\u1ec7n tích c\u1ee7a các hình tam giác nh\u1ecf màu tr\u1eafng. S b\u1eb1ng di\u1ec7n tích hình ch\u1eef nh\u1eadt tr\u1eeb di\u1ec7n tích c\u1ee7a các tam giác nh\u1ecf.<\/p>","answer":"Di\u1ec7n tích c\u1ee7a hình ch\u1eef nh\u1eadt bên ngoài là<\/p>6 . 8 = 48<\/p>Vì các tam giác nh\u1ecf màu tr\u1eafng là các tam giác vuông có hai c\u1ea1nh góc vuông l\u1ea7n l\u01b0\u1ee3t là x và 2x nên di\u1ec7n tích c\u1ee7a m\u1ed9t tam giác nh\u1ecf màu tr\u1eafng là <\/p>$\\dfrac{1}{2}$<\/span> . x . 2x = x²<\/p>Vì b\u1ed1n tam giác nh\u1ecf b\u1eb1ng nhau nên t\u1ed5ng di\u1ec7n tích các tam giác là <\/p>4 . x² = 4x²  <\/p>Di\u1ec7n tích S màu xanh là<\/p>S = 48 - 4x²<\/p>\u0110áp án \u0111úng là   A.<\/strong> S = 48 - 4x²<\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"1","date":"2022-06-01 09:20:59","option_type":"txt","len":2},{"id":"8552","post_id":"5811","mon_id":"1158532","chapter_id":"1158660","question":"Tìm \u0111a th\u1ee9c P bi\u1ebft  M + P = N và <\/p>M = $x^3 - 5x^2 + x + 2$<\/span> ; N = $5x^3 - x^2 + 8x - 3$<\/span><\/p>","options":["A.<\/strong> P = $4x^3+4x^2+7x-5$<\/span>","B.<\/strong> P = $6x^3-6x^2+9x-1$<\/span>","C. <\/strong>P = $-4x^3-4x^2-7x+5$<\/span>","D. <\/strong>P = $-6x^3+6x^2-9x+1$<\/span>"],"correct":"1","level":"3","hint":"M + P = N ⇒ P = N - M<\/p>","answer":"M + P = N ⇒ P = N - M<\/p>Do \u0111ó P = ($5x^3 - x^2 + 8x - 3$<\/span>) – ($x^3 - 5x^2 + x + 2$<\/span>)<\/p>              = $5x^3 - x^2 + 8x - 3 - x^3 + 5x^2 - x - 2$<\/span><\/p>              = $5x^3 - x^3 - x^2 + 5x^2 + 8x - x - 3 - 2$<\/span><\/p>              = $4x^3 + 4x^2 + 7x - 5$<\/span><\/p>\u0110áp án \u0111úng là   A.<\/strong> P = $4x^3+4x^2+7x-5$<\/span><\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"1","date":"2022-06-01 10:12:23","option_type":"math","len":0},{"id":"8554","post_id":"5811","mon_id":"1158532","chapter_id":"1158660","question":"Bi\u1ebft M + P = N và M = $x^3 - 5x^2 + x + 2$<\/span> ; N = $5x^3 - x^2 + 8x - 3$<\/span> .<\/p>H\u1ec7 s\u1ed1 cao nh\u1ea5t c\u1ee7a \u0111a th\u1ee9c P là<\/p>","options":["4","5","0","3"],"correct":"1","level":"3","hint":"M + P = N ⇒ P = N - M<\/p>","answer":"Ta có   M + P = N <\/p>Do \u0111ó  P = N – M<\/p>               = ($5x^3 - x^2 + 8x - 3$<\/span>) – ($x^3 - 5x^2 + x + 2$<\/span>)<\/p>               = $5x^3 - x^2 + 8x - 3 - x^3 + 5x^2 - x - 2$<\/span><\/p>               = $5x^3 - x^3 - x^2 + 5x^2 + 8x - x - 3 - 2$<\/span><\/p>               = $4x^3 + 4x^2 + 7x - 5$<\/span><\/p>V\u1eady h\u1ec7 s\u1ed1 cao nh\u1ea5t c\u1ee7a P là   4<\/p>\u0110áp án \u0111úng là     4<\/strong><\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"1","date":"2022-06-01 10:15:26","option_type":"number","len":0}]}