Thứ tự thực hiện các phép tính, quy tắc chuyển vế

Home Lớp 7 Toán lớp 7 - Sách kết nối tri thức Bài 4: Thứ tự thực hiện các phép tính, quy tắc chuyển vếBài tập trung bình

{"common":{"save":0,"post_id":"5660","level":2,"total":10,"point":10,"point_extra":0},"segment":[{"id":"6923","post_id":"5660","mon_id":"1158532","chapter_id":"1158544","question":"Tìm s\u1ed1 h\u1eefu t\u1ec9 x bi\u1ebft r\u1eb1ng t\u1ed5ng c\u1ee7a 5x và 7,5 b\u1eb1ng 90.<\/p>","options":["A. <\/strong>x = 16,5","B.<\/strong> x = -16,5","C.<\/strong> x = 19,5","D.<\/strong> x = -19,5"],"correct":"1","level":"2","hint":"","answer":"T\u1eeb \u0111\u1ec1 bài ta có<\/p>5x + 7,5 = 90<\/p>5x          = 90 - 7,5<\/p>5x          = 82,5<\/p>  x          = 82,5 : 5<\/p>  x          = 16,5<\/p>\u0110áp án \u0111úng là  A. <\/strong>x = 16,5<\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"1","date":"2022-04-05 08:30:06","option_type":"txt","len":1},{"id":"6925","post_id":"5660","mon_id":"1158532","chapter_id":"1158544","question":"Tính giá tr\u1ecb c\u1ee7a M b\u1eb1ng cách h\u1ee3p lí<\/p>M = $\\left( \\dfrac{17}{16}-\\dfrac{1}{8} +\\dfrac{7}{13}\\right)-\\left( \\dfrac{11}{16}+\\dfrac{7}{8}-\\dfrac{8}{13} \\right)-\\left( \\dfrac{6}{16}+3+\\dfrac{15}{13} \\right)$<\/span><\/p>\u0110áp s\u1ed1 M = <input class=\"tim_x input_number\" tpl=\"dien_so\" type=\"text\"\/><\/p>","options":"","correct":["[\"-4\"]"],"level":"2","hint":"","answer":"M = $\\left( \\dfrac{17}{16}-\\dfrac{1}{8} +\\dfrac{7}{13}\\right)-\\left( \\dfrac{11}{16}+\\dfrac{7}{8}-\\dfrac{8}{13} \\right)-\\left( \\dfrac{6}{16}+3+\\dfrac{15}{13} \\right)$<\/span><\/p>= $ \\dfrac{17}{16}-\\dfrac{1}{8} +\\dfrac{7}{13}-\\dfrac{11}{16}-\\dfrac{7}{8}+\\dfrac{8}{13} - \\dfrac{6}{16}-3-\\dfrac{15}{13} $<\/span> <\/p>= $ \\dfrac{17}{16}-\\dfrac{11}{16} - \\dfrac{6}{16} - \\dfrac{1}{8} -\\dfrac{7}{8}+\\dfrac{7}{13}+\\dfrac{8}{13} -\\dfrac{15}{13} -3$<\/span><\/p>= $\\left( \\dfrac{17}{16}-\\dfrac{11}{16} - \\dfrac{6}{16} \\right) - \\left( \\dfrac{1}{8} + \\dfrac{7}{8} \\right) + \\left(\\dfrac{7}{13}+\\dfrac{8}{13} -\\dfrac{15}{13} \\right) -3$<\/span> <\/p>= $0 -\\dfrac{8}{8}+0-3$<\/span><\/p>= $-1-3 = -4$<\/span><\/p>V\u1eady M = -4<\/p>S\u1ed1 c\u1ea7n \u0111i\u1ec1n là  -4<\/span><\/p>","type":"blank","extra_type":"","time":"0","user_id":"131","test":"1","date":"2022-04-05 08:41:21"},{"id":"6926","post_id":"5660","mon_id":"1158532","chapter_id":"1158544","question":"Tìm s\u1ed1 h\u1eefu t\u1ec9 y bi\u1ebft hi\u1ec7u c\u1ee7a 9 và 6y b\u1eb1ng 78.<\/p>","options":["A.<\/strong> $y = \\dfrac{23}{2}$<\/span>","B.<\/strong> $y = \\dfrac{-23}{2}$<\/span>","C.<\/strong> $y= \\dfrac{29}{2}$<\/span>","D.<\/strong> $y = \\dfrac{-29}{2}$<\/span>"],"correct":"2","level":"2","hint":"","answer":"Theo \u0111\u1ec1 bài ta có<\/p>9 - 6y = 78<\/p>   - 6y = 78 - 9<\/p>   - 6y = 69<\/p>       y = 69 : (-6)<\/p>       y = $ \\dfrac{-69}{6}$<\/span><\/p>       y = $\\dfrac{-23}{2}$<\/span><\/p>\u0110áp án \u0111úng là  B.<\/strong> $y = \\dfrac{-23}{2}$<\/span><\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"1","date":"2022-04-05 08:47:27","option_type":"math","len":0}]}