Cách tính xác suất của biến cố bằng tỉ số

Home Lớp 8 Toán lớp 8 - Sách Kết nối tri thức Bài 31. Cách tính xác suất của biến cố bằng tỉ sốBài tập trung bình

{"common":{"save":0,"post_id":"6679","level":2,"total":10,"point":10,"point_extra":0},"segment":[{"id":"6748","post_id":"6679","mon_id":"1158921","chapter_id":"1158935","question":"M\u1ed9t h\u1ed9p có 12 t\u1ea5m th\u1ebb gi\u1ed1ng nhau \u0111\u01b0\u1ee3c \u0111ánh s\u1ed1 t\u1eeb 1 \u0111\u1ebfn 12. L\u1ea5y ng\u1eabu nhiên m\u1ed9t t\u1ea5m th\u1ebb. Tính xác su\u1ea5t c\u1ee7a bi\u1ebfn c\u1ed1 G: "L\u1ea5y \u0111\u01b0\u1ee3c t\u1ea5m th\u1ebb ghi s\u1ed1 có hai ch\u1eef s\u1ed1".<\/p>","options":["A.<\/strong> $\\dfrac{1}{3}$<\/span>","B.<\/strong> $\\dfrac{1}{4}$<\/span>","C.<\/strong> $1$<\/span>","D.<\/strong> $\\dfrac{1}{2}$<\/span>"],"correct":"2","level":"2","hint":"","answer":"Có 12 t\u1ea5m th\u1ebb gi\u1ed1ng nhau \u0111\u01b0\u1ee3c \u0111ánh s\u1ed1 t\u1eeb 1 \u0111\u1ebfn 12 nên có 12 k\u1ebft qu\u1ea3 có th\u1ec3. Vì l\u1ea5y ng\u1eabu nhiên m\u1ed9t t\u1ea5m th\u1ebb trong h\u1ed9p nên các k\u1ebft qu\u1ea3 này là \u0111\u1ed3ng kh\u1ea3 n\u0103ng.<\/p>Có 3 t\u1ea5m th\u1ebb ghi s\u1ed1 có hai ch\u1eef s\u1ed1 là 10 ; 11 ; 12 nên có 3 k\u1ebft qu\u1ea3 thu\u1eadn l\u1ee3i cho bi\u1ebfn c\u1ed1 G. <\/p>Xác su\u1ea5t c\u1ee7a bi\u1ebfn c\u1ed1 G là   $P(G)=\\dfrac{3}{12}=\\dfrac{1}{4}$<\/span> .<\/p>\u0110áp án \u0111úng là    B.<\/strong> $\\dfrac{1}{4}$<\/span> .<\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"0","date":"2023-09-02 03:58:12","option_type":"math","len":0},{"id":"6750","post_id":"6679","mon_id":"1158921","chapter_id":"1158935","question":"M\u1ed9t h\u1ed9p có 12 t\u1ea5m th\u1ebb gi\u1ed1ng nhau \u0111\u01b0\u1ee3c \u0111ánh s\u1ed1 t\u1eeb 1 \u0111\u1ebfn 12. L\u1ea5y ng\u1eabu nhiên m\u1ed9t t\u1ea5m th\u1ebb. Tính xác su\u1ea5t c\u1ee7a bi\u1ebfn c\u1ed1 E: "L\u1ea5y \u0111\u01b0\u1ee3c t\u1ea5m th\u1ebb ghi s\u1ed1 có m\u1ed9t ch\u1eef s\u1ed1".<\/p>","options":["A.<\/strong> $\\dfrac{3}{4}$<\/span>","B.<\/strong> $\\dfrac{1}{4}$<\/span>","C.<\/strong> $\\dfrac{1}{2}$<\/span>","D.<\/strong> $\\dfrac{1}{6}$<\/span>"],"correct":"1","level":"2","hint":"","answer":"Có 12 t\u1ea5m th\u1ebb gi\u1ed1ng nhau \u0111\u01b0\u1ee3c \u0111ánh s\u1ed1 t\u1eeb 1 \u0111\u1ebfn 12 nên có 12 k\u1ebft qu\u1ea3 có th\u1ec3. Vì l\u1ea5y ng\u1eabu nhiên m\u1ed9t t\u1ea5m th\u1ebb trong h\u1ed9p nên các k\u1ebft qu\u1ea3 này là \u0111\u1ed3ng kh\u1ea3 n\u0103ng.<\/p>Có 9 t\u1ea5m th\u1ebb ghi s\u1ed1 có m\u1ed9t ch\u1eef s\u1ed1 là 1 ; 2 ; 3 ; 4 ; 5 ; 6 ; 7 ; 8 ; 9 nên có 9 k\u1ebft qu\u1ea3 thu\u1eadn l\u1ee3i cho bi\u1ebfn c\u1ed1 E. <\/p>Xác su\u1ea5t c\u1ee7a bi\u1ebfn c\u1ed1 E là  $P(E)=\\dfrac{9}{12}=\\dfrac{3}{4}$<\/span> .<\/p>\u0110áp án \u0111úng là    A.<\/strong> $\\dfrac{3}{4}$<\/span> .<\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"0","date":"2023-09-02 04:01:41","option_type":"math","len":0},{"id":"6752","post_id":"6679","mon_id":"1158921","chapter_id":"1158935","question":"M\u1ed9t h\u1ed9p có 12 t\u1ea5m th\u1ebb gi\u1ed1ng nhau \u0111\u01b0\u1ee3c \u0111ánh s\u1ed1 t\u1eeb 1 \u0111\u1ebfn 12. L\u1ea5y ng\u1eabu nhiên m\u1ed9t t\u1ea5m th\u1ebb. Tính xác su\u1ea5t c\u1ee7a bi\u1ebfn c\u1ed1 H: "L\u1ea5y \u0111\u01b0\u1ee3c t\u1ea5m th\u1ebb ghi s\u1ed1 nguyên t\u1ed1".<\/p>","options":["A.<\/strong> $\\dfrac{5}{8}$<\/span>","B.<\/strong> $\\dfrac{7}{12}$<\/span>","C.<\/strong> $\\dfrac{5}{12}$<\/span>","D.<\/strong> $\\dfrac{1}{12}$<\/span>"],"correct":"3","level":"2","hint":"","answer":"Có 12 t\u1ea5m th\u1ebb gi\u1ed1ng nhau \u0111\u01b0\u1ee3c \u0111ánh s\u1ed1 t\u1eeb 1 \u0111\u1ebfn 12 nên có 12 k\u1ebft qu\u1ea3 có th\u1ec3. Vì l\u1ea5y ng\u1eabu nhiên m\u1ed9t t\u1ea5m th\u1ebb trong h\u1ed9p nên các k\u1ebft qu\u1ea3 này là \u0111\u1ed3ng kh\u1ea3 n\u0103ng.<\/p>Có 5 t\u1ea5m th\u1ebb ghi s\u1ed1 nguyên t\u1ed1 là 2 ; 3 ; 5 ; 7 ; 11 nên có 5 k\u1ebft qu\u1ea3 thu\u1eadn l\u1ee3i cho bi\u1ebfn c\u1ed1 H. <\/p>Xác su\u1ea5t c\u1ee7a bi\u1ebfn c\u1ed1 H là   $P(H)=\\dfrac{5}{12}$<\/span> .<\/p>\u0110áp án \u0111úng là   C.<\/strong> $\\dfrac{5}{12}$<\/span> .<\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"0","date":"2023-09-02 04:04:32","option_type":"math","len":0}]}