{"common":{"save":0,"post_id":"6545","level":2,"total":10,"point":10,"point_extra":0},"segment":[{"id":"5870","post_id":"6545","mon_id":"1158921","chapter_id":"1158928","question":"<p>Khai tri\u1ec3n <span class=\"math-tex\">$\\bigg( 2a-\\dfrac{1}{3} \\bigg)^2$<\/span> ta \u0111\u01b0\u1ee3c \u0111a th\u1ee9c: <\/p>","options":["<strong>A. <\/strong><span class=\"math-tex\">$4a^2+\\dfrac{4}{3}a+\\dfrac{1}{9}$<\/span>","<strong>B. <\/strong><span class=\"math-tex\">$4a^2-\\dfrac{4}{3}a+\\dfrac{1}{9}$<\/span>","<strong>C. <\/strong><span class=\"math-tex\">$2a^2-\\dfrac{2}{3}a+\\dfrac{1}{3}$<\/span>","<strong>D. <\/strong><span class=\"math-tex\">$2a^2-\\dfrac{2}{3}a+\\dfrac{1}{9}$<\/span>"],"correct":"2","level":"2","hint":"","answer":"<p><span class=\"math-tex\">$\\bigg( 2a-\\dfrac{1}{3} \\bigg)^2$<\/span> <span class=\"math-tex\">$=(2a)^2-2.2a.\\dfrac{1}{3} + \\bigg( \\dfrac{1}{3} \\bigg)^2$<\/span> <span style=\"color:#16a085;\"><span class=\"math-tex\">$=4a^2-\\dfrac{4}{3}a+\\dfrac{1}{9}$<\/span><\/span><\/p><p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>B. <\/strong><span class=\"math-tex\">$4a^2-\\dfrac{4}{3}a+\\dfrac{1}{9}$<\/span><\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"0","date":"2023-07-04 15:07:05","option_type":"math","len":0},{"id":"5871","post_id":"6545","mon_id":"1158921","chapter_id":"1158928","question":"<p>Khai tri\u1ec3n <span class=\"math-tex\">$a^2-2$<\/span> d\u01b0\u1edbi d\u1ea1ng tích c\u1ee7a hai \u0111a th\u1ee9c ta \u0111\u01b0\u1ee3c: <\/p>","options":["<strong>A. <span class=\"math-tex\">$(a-2)(a+2)$<\/span><\/strong>","<strong>B. <span class=\"math-tex\">$(a-1)(a+2)$<\/span><\/strong>","<strong>C. <span class=\"math-tex\">$(a-\\sqrt{2})(a+\\sqrt{2})$<\/span><\/strong>","<strong>D. <span class=\"math-tex\">$(a-2)(a+1)$<\/span><\/strong>"],"correct":"3","level":"2","hint":"","answer":"<p><span class=\"math-tex\">$a^2-2$<\/span> <span class=\"math-tex\">$=a^2-(\\sqrt{2})^2$<\/span> <strong><span class=\"math-tex\">$=(a-\\sqrt{2})(a+\\sqrt{2})$<\/span><\/strong><\/p><p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>C. <span class=\"math-tex\">$(a-\\sqrt{2})(a+\\sqrt{2})$<\/span> <\/strong><\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"0","date":"2023-07-04 15:09:49","option_type":"math","len":0},{"id":"5872","post_id":"6545","mon_id":"1158921","chapter_id":"1158928","question":"<p>Vi\u1ebft <span class=\"math-tex\">$9a^2-1$<\/span> d\u01b0\u1edbi d\u1ea1ng tích c\u1ee7a hai \u0111a th\u1ee9c.<\/p>","options":["<strong>A. <\/strong><span class=\"math-tex\">$(a-3)(a+3)$<\/span>","<strong>B. <\/strong><span class=\"math-tex\">$(a-1)(a+1)$<\/span>","<strong>C. <\/strong><span class=\"math-tex\">$(9a-1)(9a+1)$<\/span>","<strong>D. <\/strong><span class=\"math-tex\">$(3a-1)(3a+1)$<\/span>"],"correct":"4","level":"2","hint":"","answer":"<p><span class=\"math-tex\">$9a^2-1$<\/span> <span class=\"math-tex\">$=(3a)^2-1^2$<\/span> <span class=\"math-tex\">$=(3a-1)(3a+1)$<\/span><\/p><p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>D. <\/strong><span class=\"math-tex\">$(3a-1)(3a+1)$<\/span><\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"0","date":"2023-07-04 15:11:33","option_type":"math","len":0}]}