{"common":{"save":0,"post_id":"6555","level":3,"total":10,"point":10,"point_extra":0},"segment":[{"id":"5927","post_id":"6555","mon_id":"1158921","chapter_id":"1158928","question":"<p>Phân tích \u0111a th\u1ee9c thành nhân t\u1eed x² + 4x + 3.<\/p>","options":["<strong>A.<\/strong> (x – 1)(x – 3)","<strong>B.<\/strong> (x + 1)(x + 3)","<strong>C.<\/strong> (x + 1)(x – 3)","<strong>D.<\/strong> (x – 1)(x + 3)"],"correct":"2","level":"3","hint":"<p>Phân tích \u0111a th\u1ee9c thành nhân t\u1eed b\u1eb1ng cách tách h\u1ea1ng t\u1eed, nhóm h\u1ea1ng t\u1eed và \u0111\u1eb7t nhân t\u1eed chung.<\/p>","answer":"<p>x² + 4x + 3<\/p><p>= x² + x + 3x + 3<\/p><p>= (x² + x) + (3x + 3)<\/p><p>= x(x + 1) + 3(x + 1)<\/p><p>= (x + 1)(x + 3)<\/p><p>\u0110áp án \u0111úng là <span style=\"color:#16a085;\"><strong>B.<\/strong> (x + 1)(x + 3) .<\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"0","date":"2023-07-09 03:00:19","option_type":"txt","len":2},{"id":"5929","post_id":"6555","mon_id":"1158921","chapter_id":"1158928","question":"<p>Phân tích \u0111a th\u1ee9c thành nhân t\u1eed x² – 5x + 6 .<\/p>","options":["<strong>A.<\/strong> (x – 2)(x + 3)","<strong>B.<\/strong> (x + 2)(x – 3)","<strong>C.<\/strong> (x – 2)(x – 3)","<strong>D.<\/strong> (x + 2)(x + 3)"],"correct":"3","level":"3","hint":"<p>Phân tích \u0111a th\u1ee9c thành nhân t\u1eed b\u1eb1ng cách tách h\u1ea1ng t\u1eed, nhóm h\u1ea1ng t\u1eed và \u0111\u1eb7t nhân t\u1eed chung.<\/p>","answer":"<p>x² – 5x + 6<\/p><p>= x² – 2x – 3x + 6<\/p><p>= (x² – 2x) + (– 3x + 6)<\/p><p>= x(x – 2) – 3(x – 2)<\/p><p>= (x – 2)(x – 3)<\/p><p>\u0110áp án \u0111úng là <span style=\"color:#16a085;\"><strong>C.<\/strong> (x – 2)(x – 3) .<\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"0","date":"2023-07-09 03:04:44","option_type":"txt","len":2},{"id":"5931","post_id":"6555","mon_id":"1158921","chapter_id":"1158928","question":"<p>Phân tích \u0111a th\u1ee9c thành nhân t\u1eed x³ – 5x² + 6x .<\/p>","options":["<strong>A.<\/strong> x(x – 2)(x – 3)","<strong>B.<\/strong> x(x – 2)(x + 3)","<strong>C.<\/strong> x(x + 2)(x – 3)","<strong>D.<\/strong> x(x + 2)(x + 3)"],"correct":"1","level":"3","hint":"<p>Phân tích \u0111a th\u1ee9c thành nhân t\u1eed b\u1eb1ng cách \u0111\u1eb7t nhân t\u1eed chung, tách h\u1ea1ng t\u1eed, nhóm h\u1ea1ng t\u1eed.<\/p>","answer":"<p>x³ – 5x² + 6x<\/p><p>= x(x² – 5x + 6)<\/p><p>= x(x² – 2x – 3x + 6)<\/p><p>= x [(x² – 2x) + (– 3x + 6)]<\/p><p>= x [x(x – 2) – 3(x – 2)]<\/p><p>= x(x – 2)(x – 3)<\/p><p>\u0110áp án \u0111úng là <span style=\"color:#16a085;\"> <strong>A.<\/strong> x(x – 2)(x – 3) .<\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"0","date":"2023-07-09 03:10:06","option_type":"txt","len":2}]}
