Chú ý: Để đảm bảo quyền lợi và bảo vệ tài khoản của mình
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{"common":{"save":0,"post_id":"6534","level":3,"total":10,"point":10,"point_extra":0},"segment":[{"id":"5767","post_id":"6534","mon_id":"1158921","chapter_id":"1158927","question":"<p>Tính giá tr\u1ecb c\u1ee7a \u0111a th\u1ee9c P t\u1ea1i <span class=\"math-tex\">$x=\\dfrac{1}{2}, y=\\dfrac{1}{3}$<\/span>, bi\u1ebft <span class=\"math-tex\">$P=(6xy+2x^2-7y^3)+(-10x^2-20y^3-18xy^2)$<\/span>.<\/p>","options":["<strong>A. <\/strong>–5","<strong>B. <\/strong>–2","<strong>C. <\/strong>–1","<strong>D. <\/strong>–3"],"correct":"4","level":"3","hint":"","answer":"<p>Thu g\u1ecdn \u0111a th\u1ee9c P:<\/p><p><span class=\"math-tex\">$P=(6xy+2x^2-7y^3)+(-10x^2-20y^3-18xy^2)$<\/span><\/p><p><span class=\"math-tex\">$P=6xy+2x^2-7y^3-10x^2-20y^3-18xy^2$<\/span><\/p><p><span class=\"math-tex\">$P=6xy+2x^2-10x^2-7y^3-20y^3-18xy^2$<\/span><\/p><p><span class=\"math-tex\">$P=6xy-8x^2-27y^3-18xy^2$<\/span><\/p><p>T\u1ea1i <span class=\"math-tex\">$x=\\dfrac{1}{2}, y=\\dfrac{1}{3}$<\/span>, ta \u0111\u01b0\u1ee3c <span class=\"math-tex\">$6.\\dfrac{1}{2}.\\dfrac{1}{3}-8.\\bigg(\\dfrac{1}{2}\\bigg)^2-27.\\bigg(\\dfrac{1}{3}\\bigg)^3-18.\\dfrac{1}{2}.\\bigg(\\dfrac{1}{3}\\bigg)^2=-3$<\/span><\/p><p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>D. <\/strong>–3<\/span><\/p>","type":"choose","extra_type":"shape2","time":"0","user_id":"131","test":"0","date":"2023-07-02 03:33:12","option_type":"txt","len":0},{"id":"5769","post_id":"6534","mon_id":"1158921","chapter_id":"1158927","question":"<p>Rút g\u1ecdn bi\u1ec3u th\u1ee9c sau: <span class=\"math-tex\">$(-x^3+xy^2-3xy+y^5)-(2x^3+5xy-2y^5)$<\/span>.<\/p>","options":["<strong>A. <\/strong><span class=\"math-tex\">$-x^3+xy^2-2xy+3y^5$<\/span>","<strong>B. <\/strong><span class=\"math-tex\">$-3x^3+xy^2-8xy+3y^5$<\/span>","<strong>C. <\/strong><span class=\"math-tex\">$3x^3+xy^2-2xy+y^5$<\/span>","<strong>D. <\/strong><span class=\"math-tex\">$x^3+xy^2-6xy+3y^5$<\/span>"],"correct":"2","level":"3","hint":"","answer":"<p> <span class=\"math-tex\">$(-x^3+xy^2-3xy+y^5)-(2x^3+5xy-2y^5)$<\/span><\/p><p>= <span class=\"math-tex\">$-x^3+xy^2-3xy+y^5-2x^3-5xy+2y^5$<\/span><\/p><p>= <span class=\"math-tex\">$-x^3-2x^3+xy^2-3xy-5xy+y^5+2y^5$<\/span><\/p><p>= <span class=\"math-tex\">$-3x^3+xy^2-8xy+3y^5$<\/span><\/p><p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>B. <\/strong><span class=\"math-tex\">$-3x^3+xy^2-8xy+3y^5$<\/span><\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"0","date":"2023-07-02 03:40:28","option_type":"math","len":0},{"id":"5772","post_id":"6534","mon_id":"1158921","chapter_id":"1158927","question":"<p>M\u1ed9t khách s\u1ea1n có 2 b\u1ec3 b\u01a1i d\u1ea1ng hình h\u1ed9p ch\u1eef nh\u1eadt. B\u1ec3 th\u1ee9 nh\u1ea5t có chi\u1ec1u sâu là 1,1 m, \u0111áy là hình ch\u1eef nh\u1eadt có chi\u1ec1u dài x (m), chi\u1ec1u r\u1ed9ng y(m). B\u1ec3 th\u1ee9 hai có chi\u1ec1u sâu là 1,3 m, hai kích th\u01b0\u1edbc \u0111áy g\u1ea5p 3 l\u1ea7n hai kích th\u01b0\u1edbc \u0111áy c\u1ee7a b\u1ec3 th\u1ee9 nh\u1ea5t. Tìm \u0111a th\u1ee9c bi\u1ec3u th\u1ecb s\u1ed1 mét kh\u1ed1i n\u01b0\u1edbc c\u1ea7n \u0111\u1ec3 b\u01a1m \u0111\u1ea7y c\u1ea3 hai b\u1ec3 b\u01a1i.<\/p>","options":["<strong>A. <\/strong>12,8xy","<strong>B. <\/strong>11,7xy","<strong>C. <\/strong>2,4xy","<strong>D. <\/strong>10,6xy"],"correct":"1","level":"3","hint":"","answer":"<p>Th\u1ec3 tích b\u1ec3 th\u1ee9 nh\u1ea5t là 1,1 . x . y = 1,1xy (m³).<\/p><p>Th\u1ec3 tích b\u1ec3 th\u1ee9 hai là 1,3 . 3x . 3y = 11,7xy (m³).<\/p><p>\u0110a th\u1ee9c bi\u1ec3u th\u1ecb s\u1ed1 mét kh\u1ed1i n\u01b0\u1edbc c\u1ea7n \u0111\u1ec3 b\u01a1m \u0111\u1ea7y c\u1ea3 hai b\u1ec3 b\u01a1i là: 1,1xy + 11,7xy = 12,8xy (m³).<\/p><p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>A. <\/strong>12,8xy<\/span><\/p>","type":"choose","extra_type":"shape2","time":"0","user_id":"131","test":"0","date":"2023-07-02 03:51:03","option_type":"txt","len":0}]}