{"common":{"save":0,"post_id":"6597","level":2,"total":10,"point":10,"point_extra":0},"segment":[{"id":"6481","post_id":"6597","mon_id":"1158921","chapter_id":"1158930","question":"<p>R&uacute;t g\u1ecdn ph&acirc;n th\u1ee9c&nbsp;<span class=\"math-tex\">$\\dfrac{3x^2-6x+3}{(1-x)^3}$<\/span>.<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$\\dfrac{3}{1+x}$<\/span>","<strong>B.<\/strong> <span class=\"math-tex\">$\\dfrac{-3}{1-x}$<\/span>","<strong>C.<\/strong> <span class=\"math-tex\">$\\dfrac{3}{1-x}$<\/span>","<strong>D.<\/strong> <span class=\"math-tex\">$\\dfrac{-3}{1+x}$<\/span>"],"correct":"3","level":"2","hint":"","answer":"<p>Ta c&oacute;:&nbsp;<span class=\"math-tex\">$\\dfrac{3x^2-6x+3}{(1-x)^3}=\\dfrac{3(x^2-2x+1)}{(1-x)^3}\\n=\\dfrac{3(x-1)^2}{(1-x)^3}=\\dfrac{3(1-x)^2}{(1-x)^3}=\\dfrac{3}{1-x}$<\/span><\/p><p>Ch\u1ecdn&nbsp;<span style=\"color:#16a085;\"><strong>C.<\/strong>&nbsp;<span class=\"math-tex\">$\\dfrac{3}{1-x}$<\/span><\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"0","date":"2023-08-26 22:58:47","option_type":"math","len":0},{"id":"6483","post_id":"6597","mon_id":"1158921","chapter_id":"1158930","question":"<p>Ch\u1ecdn c&acirc;u \u0111&uacute;ng.<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$\\dfrac{x}{x+1}=\\dfrac{x^2}{x^2(x+1)}$<\/span>","<strong>B.<\/strong> <span class=\"math-tex\">$\\dfrac{x-1}{2}=\\dfrac{(x-1)^2}{2x-2}$<\/span>","<strong>C.<\/strong> <span class=\"math-tex\">$\\dfrac{x}{x+1}=\\dfrac{-x}{x-1}$<\/span>","<strong>D.<\/strong> <span class=\"math-tex\">$\\dfrac{x-1}{2}=\\dfrac{1-x}{2}$<\/span>"],"correct":"2","level":"2","hint":"","answer":"<p>Ta c&oacute;:&nbsp;<span class=\"math-tex\">$\\dfrac{x-1}{2}=\\dfrac{(x-1)(x-1)}{2(x-1)}=\\dfrac{(x-1)^2}{2x-2}$<\/span><\/p><p>Ch\u1ecdn&nbsp;<span style=\"color:#16a085;\"><strong>B.<\/strong>&nbsp;<span class=\"math-tex\">$\\dfrac{x-1}{2}=\\dfrac{(x-1)^2}{2x-2}$<\/span><\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"0","date":"2023-08-26 23:03:39","option_type":"math","len":0},{"id":"6484","post_id":"6597","mon_id":"1158921","chapter_id":"1158930","question":"<p>T&igrave;m a sao cho hai \u0111a th\u1ee9c sau b\u1eb1ng nhau:&nbsp;<span class=\"math-tex\">$\\dfrac{-ax^2-ax}{x^2-1}$<\/span>&nbsp;v&agrave;&nbsp;<span class=\"math-tex\">$\\dfrac{5x}{x-1}$<\/span>.<\/p>","options":["<strong>A.<\/strong> a = 5","<strong>B.<\/strong> a = &ndash;5","<strong>C.<\/strong> a = 1","<strong>D.<\/strong> a = &ndash;1"],"correct":"2","level":"2","hint":"","answer":"<p>Ta c&oacute;:&nbsp;<span class=\"math-tex\">$\\dfrac{-ax^2-ax}{x^2-1}$<\/span>&nbsp;<span class=\"math-tex\">$=\\dfrac{-ax(x+1)}{(x-1)(x+1)}$<\/span>&nbsp;<span class=\"math-tex\">$=\\dfrac{-ax}{x-1}$<\/span><\/p><p>\u0110\u1ec3&nbsp;<span class=\"math-tex\">$\\dfrac{-ax^2-ax}{x^2-1}$<\/span>&nbsp;=&nbsp;<span class=\"math-tex\">$\\dfrac{5x}{x-1}$<\/span><\/p><p>th&igrave;&nbsp;<span class=\"math-tex\">$\\dfrac{-ax}{x-1}$<\/span>&nbsp;=&nbsp;<span class=\"math-tex\">$\\dfrac{5x}{x-1}$<\/span><\/p><p>suy ra&nbsp;<span class=\"math-tex\">$a=-5$<\/span><\/p><p>Ch\u1ecdn&nbsp;<span style=\"color:#16a085;\"><strong>B.<\/strong> a = &ndash;5<\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"131","test":"0","date":"2023-08-26 23:09:35","option_type":"txt","len":1}]}