{"segment":[{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai1/lv1/img\/1.png' \/><\/center>K\u1ebft qu\u1ea3 c\u1ee7a ph\u00e9p nh\u00e2n ${{x}^{3}}\\left( 1+5{{x}^{3}} \\right)$ l\u00e0 \u0111a th\u1ee9c b\u1eadc $6$ <b> \u0111\u00fang <\/b> hay <b> sai <\/b>? ","select":["\u0110\u00fang","Sai"],"hint":"Ta nh\u00e2n \u0111\u01a1n th\u1ee9c v\u1edbi \u0111a th\u1ee9c, s\u1eed d\u1ee5ng c\u00f4ng th\u1ee9c: $a.(b+c)=a.b+a.c$<br\/> Sau \u0111\u00f3 t\u00ecm b\u1eadc c\u1ee7a \u0111a th\u1ee9c thu \u0111\u01b0\u1ee3c.","explain":"<span class='basic_left'>Ta c\u00f3:<br\/>${{x}^{3}}\\left( 1+5{{x}^{3}} \\right)={{x}^{3}}+5{{x}^{6}}=5{{x}^{6}}+{{x}^{3}}$<br\/> L\u0169y th\u1eeba b\u1eadc cao nh\u1ea5t trong \u0111a th\u1ee9c l\u00e0 $x^6$ <br\/> Do \u0111\u00f3 b\u1eadc c\u1ee7a \u0111a th\u1ee9c l\u00e0 $6$.<br\/> <span class='basic_pink'> V\u1eady kh\u1eb3ng \u0111\u1ecbnh tr\u00ean l\u00e0 \u0110\u00fang.<\/span>","column":2}]}],"id_ques":281},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai1/lv1/img\/1.png' \/><\/center>K\u1ebft qu\u1ea3 c\u1ee7a ph\u00e9p nh\u00e2n $2x\\left( {{x}^{2}}-1+3{{x}^{3}} \\right)$ l\u00e0 \u0111a th\u1ee9c b\u1eadc $4$ <b> \u0111\u00fang <\/b> hay <b> sai <\/b>?","select":["\u0110\u00fang","Sai"],"hint":"Ta nh\u00e2n \u0111\u01a1n th\u1ee9c v\u1edbi \u0111a th\u1ee9c, s\u1eed d\u1ee5ng c\u00f4ng th\u1ee9c: $a.(b+c)=a.b+a.c$<br\/> Sau \u0111\u00f3 t\u00ecm b\u1eadc c\u1ee7a \u0111a th\u1ee9c thu \u0111\u01b0\u1ee3c.","explain":"<span class='basic_left'>Ta c\u00f3:<br\/>$2x\\left( {{x}^{2}}-1+3{{x}^{3}} \\right) =2{{x}^{3}}-2x+6{{x}^{4}}=6{{x}^{4}}+2{{x}^{3}}-2x$<br\/> L\u0169y th\u1eeba b\u1eadc cao nh\u1ea5t c\u1ee7a \u0111a th\u1ee9c thu \u0111\u01b0\u1ee3c l\u00e0 $x^4$ <br\/> Do \u0111\u00f3 b\u1eadc c\u1ee7a \u0111a th\u1ee9c l\u00e0 $4$.<br\/> <span class='basic_pink'> V\u1eady kh\u1eb3ng \u0111\u1ecbnh tr\u00ean l\u00e0 \u0110\u00fang.<\/span>","column":2}]}],"id_ques":282},{"time":24,"part":[{"title":"\u0110i\u1ec1n k\u1ebft qu\u1ea3 \u0111\u00fang nh\u1ea5t v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank_random","correct":[[["-2"],["0"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","ques":"<span class='basic_left'> T\u00ecm $x$, bi\u1ebft: $\\left( 2x+4 \\right)\\left( -\\dfrac{1}{2}x \\right)=0$. <br\/> Gi\u00e1 tr\u1ecb c\u1ee7a $x$ c\u1ea7n t\u00ecm l\u00e0 _input_ho\u1eb7c_input_ <\/span>","hint":"","explain":"<span class='basic_left'>$ \\left( 2x+4 \\right)\\left( -\\dfrac{1}{2}x \\right)=0 $<br\/>$ \\Leftrightarrow\\left[ \\begin{aligned} & 2x+4=0 \\\\ & -\\dfrac{1}{2}x=0 \\\\ \\end{aligned} \\right. \\Leftrightarrow \\left[ \\begin{aligned}& 2x=-4 \\\\ & x=0 \\\\ \\end{aligned} \\right.\\Leftrightarrow \\left[ \\begin{aligned} & x=-2 \\\\ & x=0 \\\\ \\end{aligned} \\right. $ <br\/><span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $-2$ v\u00e0 $0$.<\/span><\/span>"}]}],"id_ques":283},{"time":24,"part":[{"title":"\u0110i\u1ec1n k\u1ebft qu\u1ea3 \u0111\u00fang nh\u1ea5t v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["-3"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","ques":"<span class='basic_left'>T\u00ecm $x$, bi\u1ebft: $x\\left( {{x}^{2}}-3 \\right)=9+{{x}^{3}}$. <br\/> Gi\u00e1 tr\u1ecb c\u1ee7a $x$ c\u1ea7n t\u00ecm l\u00e0 _input_ <\/span>","hint":"T\u1eeb gi\u1ea3 thi\u1ebft, ta bi\u1ebfn \u0111\u1ed5i \u0111\u1eb3ng th\u1ee9c \u0111\u1ec3 t\u00ecm $x$.","explain":"<span class='basic_left'> $ x\\left( {{x}^{2}}-3 \\right)=9+{{x}^{3}} \\\\ \\Leftrightarrow {{x}^{3}}-3x=9+{{x}^{3}} \\\\ \\Leftrightarrow -3x=9 \\\\ \\Leftrightarrow x=9:\\left( -3 \\right)=-3 $<br\/> <span class='basic_pink'> V\u1eady gi\u00e1 tr\u1ecb $x$ c\u1ea7n \u0111i\u1ec1n l\u00e0 $- 3$.<\/span><\/span>"}]}],"id_ques":284},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai1/lv1/img\/1.png' \/><\/center>Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c $x^2\\left( y-3 \\right)$ b\u1eb1ng $0$ t\u1ea1i: ","select":["A. $x = 0; y = 3$","B. $x = 1 ; y = 0$","C. $x = y = 1$","D. $x = 3; y = 0$"],"hint":"Cho bi\u1ec3u th\u1ee9c tr\u00ean b\u1eb1ng $0$ r\u1ed3i bi\u1ebfn \u0111\u1ed5i \u0111\u1ec3 t\u00ecm $x, y$ th\u1ecfa m\u00e3n","explain":"<span class='basic_left'> $x^2\\left( y-3 \\right)=0$ <br\/> $\\Rightarrow $ $\\left[ \\begin{aligned} & {{x}^{2}}=0 \\\\ & y-3=0 \\\\ \\end{aligned} \\right.\\Rightarrow \\left[ \\begin{aligned} & x=0 \\\\ & y=3 \\\\ \\end{aligned} \\right.$ <br\/><span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A.<\/span><\/span>","column":2}]}],"id_ques":285},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai1/lv1/img\/1.png' \/><\/center>Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c $xy^2\\left( x+2 \\right)$ b\u1eb1ng $3$ t\u1ea1i: ","select":["A. $x = 0; y = 1$","B. $x = 1 ; y = 0$","C. $x = y = 1$","D. $x = y = 2$"],"hint":"","explain":"<span class='basic_left'> Ta nh\u1eadn th\u1ea5y \u0111\u00e1n \u00e1n A v\u00e0 B kh\u00f4ng th\u1ecfa m\u00e3n v\u00ec khi \u0111\u00f3 gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c l\u00e0 0.<br\/>Thay c\u00e1c gi\u00e1 tr\u1ecb c\u1ee7a $x, y$ \u1edf hai \u0111\u00e1p \u00e1n C v\u00e0 D v\u00e0o bi\u1ec3u th\u1ee9c: <br\/>+ V\u1edbi $x = y = 1$ th\u00ec $x{{y}^{2}}\\left( x+2 \\right)=1.1\\left( 1+2 \\right)=3$ (th\u1ecfa m\u00e3n) <br\/>+ V\u1edbi $x = y = 2$ th\u00ec $x{{y}^{2}}\\left( x+2 \\right)=2.2^2\\left( 2+2 \\right)=16$ (lo\u1ea1i) <br\/><span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C.<\/span><\/span>","column":2}]}],"id_ques":286},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai1/lv1/img\/1.png' \/><\/center>Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c $x\\left( y+4 \\right)$ t\u1ea1i $x = 2; y = 0$ l\u00e0: ","select":["A. $8$","B. $6$","C. $0$","D. $12$"],"hint":"","explain":"<span class='basic_left'>V\u1edbi $x = 2; y = 0$ ta c\u00f3:<br\/> $x\\left( y+4 \\right)=2\\left( 0+4 \\right)=2.4=8$<br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A.<\/span><\/span>","column":2}]}],"id_ques":287},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai1/lv1/img\/1.png' \/><\/center>Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c $xy\\left( x+5 \\right)$ t\u1ea1i $x = y = 1$ l\u00e0: ","select":["A. $12$","B. $10$","C. $6$","D. $5$"],"hint":"Thay gi\u00e1 tr\u1ecb c\u1ee7a $x$ v\u00e0 $ y$ v\u00e0o bi\u1ec3u th\u1ee9c \u0111\u00e3 cho \u0111\u1ec3 t\u00ednh","explain":"<span class='basic_left'>V\u1edbi $x = y = 1$ ta c\u00f3:<br\/> $xy\\left( x+5 \\right)=1.1\\left( 1+5 \\right)=1.6=6$<br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C.<\/span><\/span>","column":2}]}],"id_ques":288},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai1/lv1/img\/1.png' \/><\/center>Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c $5x\\left( y+3 \\right)$ t\u1ea1i $x = 1; y = 2$ l\u00e0: ","select":["A. $40$","B. $25$","C. $50$","D. $30$"],"hint":"Thay gi\u00e1 tr\u1ecb c\u1ee7a $x$ v\u00e0 $y$ v\u00e0o bi\u1ec3u th\u1ee9c \u0111\u00e3 cho \u0111\u1ec3 t\u00ednh","explain":"<span class='basic_left'>V\u1edbi $x = 1; y = 2$ ta c\u00f3:<br\/> $5x\\left( y+3 \\right)=5.1\\left( 2+3 \\right)=5.5=25$<br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 B.<\/span><\/span>","column":2}]}],"id_ques":289},{"time":24,"part":[{"title":"\u0110i\u1ec1n k\u1ebft qu\u1ea3 \u0111\u00fang nh\u1ea5t v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["3"]]],"list":[{"point":5,"width":40,"type_input":"","ques":"Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c $x^2\\left( y+1 \\right)$ t\u1ea1i $x = 1; y = 2$ l\u00e0 _input_","hint":"Thay gi\u00e1 tr\u1ecb c\u1ee7a $x$ v\u00e0 $y$ v\u00e0o bi\u1ec3u th\u1ee9c \u0111\u00e3 cho v\u00e0 t\u00ednh.","explain":"<span class='basic_left'>V\u1edbi $x = 1; y = 2$ ta c\u00f3:<br\/> $x^2\\left( y+1 \\right)=1\\left( 2+1 \\right)=1.3=3$<br\/> <span class='basic_pink'> V\u1eady c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $3$.<\/span><\/span>"}]}],"id_ques":290},{"time":24,"part":[{"title":"\u0110i\u1ec1n k\u1ebft qu\u1ea3 \u0111\u00fang nh\u1ea5t v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["2"]]],"list":[{"point":5,"width":40,"type_input":"","ques":"Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c $y\\left( x^2+1 \\right)$ t\u1ea1i $x = 1; y = 1$ l\u00e0 _input_","hint":"Thay gi\u00e1 tr\u1ecb c\u1ee7a $x$ v\u00e0 $y$ v\u00e0o bi\u1ec3u th\u1ee9c \u0111\u00e3 cho v\u00e0 t\u00ednh.","explain":"<span class='basic_left'>Thay gi\u00e1 tr\u1ecb c\u1ee7a $x = 1; y = 1$ v\u00e0o bi\u1ec3u th\u1ee9c \u0111\u00e3 cho, ta \u0111\u01b0\u1ee3c:<br\/> $1\\left( 1^2+1 \\right)=1.2=2$<br\/> <span class='basic_pink'> V\u1eady c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $2$.<\/span><\/span>"}]}],"id_ques":291},{"time":24,"part":[{"title":"\u0110i\u1ec1n k\u1ebft qu\u1ea3 \u0111\u00fang nh\u1ea5t v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["0"]]],"list":[{"point":5,"width":40,"type_input":"","ques":"Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c $xy\\left( x+1 \\right)$ t\u1ea1i $x = 1; y = 0$ l\u00e0 _input_","hint":"Thay gi\u00e1 tr\u1ecb c\u1ee7a $x$ v\u00e0 $y$ v\u00e0o bi\u1ec3u th\u1ee9c \u0111\u00e3 cho v\u00e0 t\u00ednh.","explain":"<span class='basic_left'>Thay gi\u00e1 tr\u1ecb c\u1ee7a $x = 1; y = 0$ v\u00e0o bi\u1ec3u th\u1ee9c \u0111\u00e3 cho, ta \u0111\u01b0\u1ee3c: <br\/> $1.0\\left( 1+1 \\right)=0.2=0$<br\/> <span class='basic_pink'> V\u1eady c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $0$.<\/span><\/span>"}]}],"id_ques":292},{"time":24,"part":[{"title":"\u0110i\u1ec1n t\u1eeb th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank_random","correct":[[["z"]]],"list":[{"point":5,"width":40,"type_input":"","type_check":"","ques":"$y\\left(\\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}+3 \\right)=yz+3y$ ","hint":"Nh\u00f3m y \u1edf VP \u0111\u1ec3 xu\u1ea5t hi\u1ec7n nh\u00e2n t\u1eed gi\u1ed1ng VT, v\u00ec VP = VT $\\Rightarrow$ Th\u1eeba s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng","explain":"<span class='basic_left'> Ta c\u00f3: <br\/> VP = $yz + 3y = y(z + 3)$ <br\/> M\u00e0 VT = VP $\\Rightarrow$ $y(... + 3) = y(z + 3)$<br\/><span class='basic_pink'>V\u1eady c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $z$.<\/span><\/span>"}]}],"id_ques":293},{"time":24,"part":[{"title":"\u0110i\u1ec1n t\u1eeb th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank_random","correct":[[["x"]]],"list":[{"point":5,"width":40,"type_input":"","type_check":"","ques":"$\\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}\\left( y+1 \\right)=xy+x$ ","hint":"Bi\u1ebfn \u0111\u1ed5i VP l\u00e0m xu\u1ea5t hi\u1ec7n nh\u00e2n t\u1eed $y + 1$. V\u00ec VT = VP $\\Rightarrow$ Th\u1eeba s\u1ed1 c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng.","explain":"<span class='basic_left'> Ta c\u00f3: <br\/> VP $= xy + x = x(y + 1)$ <br\/> M\u00e0 VT = VP $\\Rightarrow$ $....(y + 1) = x(y + 1)$ <br\/> <span class='basic_pink'>V\u1eady c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $x$.<\/span><\/span>"}]}],"id_ques":294},{"time":24,"part":[{"title":"\u0110i\u1ec1n t\u1eeb th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank_random","correct":[[["xy","yx"],["yz","zy"]]],"list":[{"point":5,"width":40,"type_input":"","type_check":"","ques":"$y\\left( x+z \\right)$$= \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}+ \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}$","hint":"Th\u1ef1c hi\u1ec7n nh\u00e2n \u0111\u01a1n th\u1ee9c v\u1edbi t\u1eebng h\u1ea1ng t\u1eed c\u1ee7a \u0111a th\u1ee9c: $a(b+c) = a.b+a.c$","explain":"<span class='basic_left'>Ta th\u1ef1c hi\u1ec7n ph\u00e9p nh\u00e2n: <br\/>$y\\left( x+z \\right)=y.x+y.z=xy+yz$ <br\/><span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n c\u1ea7n \u0111i\u1ec1n v\u00e0o hai \u00f4 l\u00e0 $xy$ v\u00e0 $yz$<\/span><\/span>"}]}],"id_ques":295},{"time":24,"part":[{"title":"\u0110i\u1ec1n t\u1eeb th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank_random","correct":[[["2x"],["2xy"]]],"list":[{"point":5,"width":40,"type_input":"","type_check":"","ques":"$2x\\left( 1+y \\right)$$= \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}+ \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}$","hint":"Th\u1ef1c hi\u1ec7n nh\u00e2n \u0111\u01a1n th\u1ee9c v\u1edbi t\u1eebng h\u1ea1ng t\u1eed c\u1ee7a \u0111a th\u1ee9c: $a(b+c) = a.b+a.c$","explain":"<span class='basic_left'>Ta th\u1ef1c hi\u1ec7n ph\u00e9p nh\u00e2n: <br\/>$2x\\left( 1+y \\right)=2x.1+2x.y=2x+2xy$ <br\/><span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n c\u1ea7n \u0111i\u1ec1n v\u00e0o hai \u00f4 l\u00e0 $2x$ v\u00e0 $2xy$<\/span><\/span>"}]}],"id_ques":296},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai1/lv1/img\/1.png' \/><\/center>K\u1ebft qu\u1ea3 c\u1ee7a ph\u00e9p nh\u00e2n $x\\left( x+1 \\right)$ l\u00e0:","select":["A. ${{x}^{2}}-1$","B. ${{x}^{2}}+x$","C. ${{x}^{2}}-x$","D. $2x+x$"],"hint":"Nh\u00e2n \u0111\u01a1n th\u1ee9c v\u1edbi t\u1eebng h\u1ea1ng t\u1eed c\u1ee7a \u0111a th\u1ee9c: $a(b+c) = a.b+a.c$","explain":" Ta c\u00f3: $x\\left( x+1 \\right)={{x}^{2}}+x$ <br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 B <\/span>","column":2}]}],"id_ques":297},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai1/lv1/img\/1.png' \/><\/center>K\u1ebft qu\u1ea3 ph\u00e9p nh\u00e2n $x\\left( x+2 \\right)$ l\u00e0","select":["A. ${{x}^{2}}+2x$","B. ${{x}^{2}}+2$","C. $2x+2$","D. $2x-x$"],"hint":"Nh\u00e2n \u0111\u01a1n th\u1ee9c v\u1edbi t\u1eebng h\u1ea1ng t\u1eed c\u1ee7a \u0111a th\u1ee9c: $a(b+c) = a.b+a.c$","explain":" Ta c\u00f3: $x\\left( x+2 \\right)={{x}^{2}}+2x$ <br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A <\/span>","column":2}]}],"id_ques":298},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai1/lv1/img\/1.png' \/><\/center>K\u1ebft qu\u1ea3 ph\u00e9p nh\u00e2n $x\\left( x+y \\right)$ l\u00e0","select":["A. ${{x}^{2}}+xy$","B. ${{x}^{2}}-xy$","C. $2x+xy$","D. $2x-x+y$"],"hint":"Nh\u00e2n \u0111\u01a1n th\u1ee9c v\u1edbi t\u1eebng h\u1ea1ng t\u1eed c\u1ee7a \u0111a th\u1ee9c: $a(b+c) = a.b+a.c$","explain":" Ta c\u00f3: $x\\left( x+y \\right)={{x}^{2}}+xy$ <br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A <\/span>","column":2}]}],"id_ques":299},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai1/lv1/img\/1.png' \/><\/center>K\u1ebft qu\u1ea3 ph\u00e9p t\u00ednh nh\u00e2n $x\\left( x+z \\right)$ l\u00e0","select":["A. ${{x}^{2}}-xz$","B. ${{x}^{2}}-x+z$","C. $x^2+xz$","D. $2x+xz$"],"hint":"Nh\u00e2n \u0111\u01a1n th\u1ee9c v\u1edbi t\u1eebng h\u1ea1ng t\u1eed c\u1ee7a \u0111a th\u1ee9c: $a(b+c) = a.b+a.c$","explain":" Ta c\u00f3: $x\\left( x+z \\right)={{x}^{2}}+xz$ <br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C <\/span>","column":2}]}],"id_ques":300}],"lesson":{"save":0,"level":1}}