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{"segment":[{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai1/lv1/img\/1.png' \/><\/center>K\u1ebft qu\u1ea3 c\u1ee7a ph\u00e9p nh\u00e2n ${{x}^{3}}\\left( 1+5{{x}^{3}} \\right)$ l\u00e0 \u0111a th\u1ee9c b\u1eadc $6$ <b> \u0111\u00fang <\/b> hay <b> sai <\/b>? ","select":["\u0110\u00fang","Sai"],"hint":"Ta nh\u00e2n \u0111\u01a1n th\u1ee9c v\u1edbi \u0111a th\u1ee9c, s\u1eed d\u1ee5ng c\u00f4ng th\u1ee9c: $a.(b+c)=a.b+a.c$<br\/> Sau \u0111\u00f3 t\u00ecm b\u1eadc c\u1ee7a \u0111a th\u1ee9c thu \u0111\u01b0\u1ee3c.","explain":"<span class='basic_left'>Ta c\u00f3:<br\/>${{x}^{3}}\\left( 1+5{{x}^{3}} \\right)={{x}^{3}}+5{{x}^{6}}=5{{x}^{6}}+{{x}^{3}}$<br\/> L\u0169y th\u1eeba b\u1eadc cao nh\u1ea5t trong \u0111a th\u1ee9c l\u00e0 $x^6$ <br\/> Do \u0111\u00f3 b\u1eadc c\u1ee7a \u0111a th\u1ee9c l\u00e0 $6$.<br\/> <span class='basic_pink'> V\u1eady kh\u1eb3ng \u0111\u1ecbnh tr\u00ean l\u00e0 \u0110\u00fang.<\/span>","column":2}]}],"id_ques":281},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai1/lv1/img\/1.png' \/><\/center>K\u1ebft qu\u1ea3 c\u1ee7a ph\u00e9p nh\u00e2n $2x\\left( {{x}^{2}}-1+3{{x}^{3}} \\right)$ l\u00e0 \u0111a th\u1ee9c b\u1eadc $4$ <b> \u0111\u00fang <\/b> hay <b> sai <\/b>?","select":["\u0110\u00fang","Sai"],"hint":"Ta nh\u00e2n \u0111\u01a1n th\u1ee9c v\u1edbi \u0111a th\u1ee9c, s\u1eed d\u1ee5ng c\u00f4ng th\u1ee9c: $a.(b+c)=a.b+a.c$<br\/> Sau \u0111\u00f3 t\u00ecm b\u1eadc c\u1ee7a \u0111a th\u1ee9c thu \u0111\u01b0\u1ee3c.","explain":"<span class='basic_left'>Ta c\u00f3:<br\/>$2x\\left( {{x}^{2}}-1+3{{x}^{3}} \\right) =2{{x}^{3}}-2x+6{{x}^{4}}=6{{x}^{4}}+2{{x}^{3}}-2x$<br\/> L\u0169y th\u1eeba b\u1eadc cao nh\u1ea5t c\u1ee7a \u0111a th\u1ee9c thu \u0111\u01b0\u1ee3c l\u00e0 $x^4$ <br\/> Do \u0111\u00f3 b\u1eadc c\u1ee7a \u0111a th\u1ee9c l\u00e0 $4$.<br\/> <span class='basic_pink'> V\u1eady kh\u1eb3ng \u0111\u1ecbnh tr\u00ean l\u00e0 \u0110\u00fang.<\/span>","column":2}]}],"id_ques":282},{"time":24,"part":[{"title":"\u0110i\u1ec1n k\u1ebft qu\u1ea3 \u0111\u00fang nh\u1ea5t v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank_random","correct":[[["-2"],["0"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","ques":"<span class='basic_left'> T\u00ecm $x$, bi\u1ebft: $\\left( 2x+4 \\right)\\left( -\\dfrac{1}{2}x \\right)=0$. <br\/> Gi\u00e1 tr\u1ecb c\u1ee7a $x$ c\u1ea7n t\u00ecm l\u00e0 _input_ho\u1eb7c_input_ <\/span>","hint":"","explain":"<span class='basic_left'>$ \\left( 2x+4 \\right)\\left( -\\dfrac{1}{2}x \\right)=0 $<br\/>$ \\Leftrightarrow\\left[ \\begin{aligned} & 2x+4=0 \\\\ & -\\dfrac{1}{2}x=0 \\\\ \\end{aligned} \\right. \\Leftrightarrow \\left[ \\begin{aligned}& 2x=-4 \\\\ & x=0 \\\\ \\end{aligned} \\right.\\Leftrightarrow \\left[ \\begin{aligned} & x=-2 \\\\ & x=0 \\\\ \\end{aligned} \\right. $ <br\/><span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $-2$ v\u00e0 $0$.<\/span><\/span>"}]}],"id_ques":283},{"time":24,"part":[{"title":"\u0110i\u1ec1n k\u1ebft qu\u1ea3 \u0111\u00fang nh\u1ea5t v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["-3"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","ques":"<span class='basic_left'>T\u00ecm $x$, bi\u1ebft: $x\\left( {{x}^{2}}-3 \\right)=9+{{x}^{3}}$. <br\/> Gi\u00e1 tr\u1ecb c\u1ee7a $x$ c\u1ea7n t\u00ecm l\u00e0 _input_ <\/span>","hint":"T\u1eeb gi\u1ea3 thi\u1ebft, ta bi\u1ebfn \u0111\u1ed5i \u0111\u1eb3ng th\u1ee9c \u0111\u1ec3 t\u00ecm $x$.","explain":"<span class='basic_left'> $ x\\left( {{x}^{2}}-3 \\right)=9+{{x}^{3}} \\\\ \\Leftrightarrow {{x}^{3}}-3x=9+{{x}^{3}} \\\\ \\Leftrightarrow -3x=9 \\\\ \\Leftrightarrow x=9:\\left( -3 \\right)=-3 $<br\/> <span class='basic_pink'> V\u1eady gi\u00e1 tr\u1ecb $x$ c\u1ea7n \u0111i\u1ec1n l\u00e0 $- 3$.<\/span><\/span>"}]}],"id_ques":284},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai1/lv1/img\/1.png' \/><\/center>Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c $x^2\\left( y-3 \\right)$ b\u1eb1ng $0$ t\u1ea1i: ","select":["A. $x = 0; y = 3$","B. $x = 1 ; y = 0$","C. $x = y = 1$","D. $x = 3; y = 0$"],"hint":"Cho bi\u1ec3u th\u1ee9c tr\u00ean b\u1eb1ng $0$ r\u1ed3i bi\u1ebfn \u0111\u1ed5i \u0111\u1ec3 t\u00ecm $x, y$ th\u1ecfa m\u00e3n","explain":"<span class='basic_left'> $x^2\\left( y-3 \\right)=0$ <br\/> $\\Rightarrow $ $\\left[ \\begin{aligned} & {{x}^{2}}=0 \\\\ & y-3=0 \\\\ \\end{aligned} \\right.\\Rightarrow \\left[ \\begin{aligned} & x=0 \\\\ & y=3 \\\\ \\end{aligned} \\right.$ <br\/><span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A.<\/span><\/span>","column":2}]}],"id_ques":285},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai1/lv1/img\/1.png' \/><\/center>Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c $xy^2\\left( x+2 \\right)$ b\u1eb1ng $3$ t\u1ea1i: ","select":["A. $x = 0; y = 1$","B. $x = 1 ; y = 0$","C. $x = y = 1$","D. $x = y = 2$"],"hint":"","explain":"<span class='basic_left'> Ta nh\u1eadn th\u1ea5y \u0111\u00e1n \u00e1n A v\u00e0 B kh\u00f4ng th\u1ecfa m\u00e3n v\u00ec khi \u0111\u00f3 gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c l\u00e0 0.<br\/>Thay c\u00e1c gi\u00e1 tr\u1ecb c\u1ee7a $x, y$ \u1edf hai \u0111\u00e1p \u00e1n C v\u00e0 D v\u00e0o bi\u1ec3u th\u1ee9c: <br\/>+ V\u1edbi $x = y = 1$ th\u00ec $x{{y}^{2}}\\left( x+2 \\right)=1.1\\left( 1+2 \\right)=3$ (th\u1ecfa m\u00e3n) <br\/>+ V\u1edbi $x = y = 2$ th\u00ec $x{{y}^{2}}\\left( x+2 \\right)=2.2^2\\left( 2+2 \\right)=16$ (lo\u1ea1i) <br\/><span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C.<\/span><\/span>","column":2}]}],"id_ques":286},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai1/lv1/img\/1.png' \/><\/center>Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c $x\\left( y+4 \\right)$ t\u1ea1i $x = 2; y = 0$ l\u00e0: ","select":["A. $8$","B. $6$","C. $0$","D. $12$"],"hint":"","explain":"<span class='basic_left'>V\u1edbi $x = 2; y = 0$ ta c\u00f3:<br\/> $x\\left( y+4 \\right)=2\\left( 0+4 \\right)=2.4=8$<br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A.<\/span><\/span>","column":2}]}],"id_ques":287},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai1/lv1/img\/1.png' \/><\/center>Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c $xy\\left( x+5 \\right)$ t\u1ea1i $x = y = 1$ l\u00e0: ","select":["A. $12$","B. $10$","C. $6$","D. $5$"],"hint":"Thay gi\u00e1 tr\u1ecb c\u1ee7a $x$ v\u00e0 $ y$ v\u00e0o bi\u1ec3u th\u1ee9c \u0111\u00e3 cho \u0111\u1ec3 t\u00ednh","explain":"<span class='basic_left'>V\u1edbi $x = y = 1$ ta c\u00f3:<br\/> $xy\\left( x+5 \\right)=1.1\\left( 1+5 \\right)=1.6=6$<br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C.<\/span><\/span>","column":2}]}],"id_ques":288},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai1/lv1/img\/1.png' \/><\/center>Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c $5x\\left( y+3 \\right)$ t\u1ea1i $x = 1; y = 2$ l\u00e0: ","select":["A. $40$","B. $25$","C. $50$","D. $30$"],"hint":"Thay gi\u00e1 tr\u1ecb c\u1ee7a $x$ v\u00e0 $y$ v\u00e0o bi\u1ec3u th\u1ee9c \u0111\u00e3 cho \u0111\u1ec3 t\u00ednh","explain":"<span class='basic_left'>V\u1edbi $x = 1; y = 2$ ta c\u00f3:<br\/> $5x\\left( y+3 \\right)=5.1\\left( 2+3 \\right)=5.5=25$<br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 B.<\/span><\/span>","column":2}]}],"id_ques":289},{"time":24,"part":[{"title":"\u0110i\u1ec1n k\u1ebft qu\u1ea3 \u0111\u00fang nh\u1ea5t v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["3"]]],"list":[{"point":5,"width":40,"type_input":"","ques":"Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c $x^2\\left( y+1 \\right)$ t\u1ea1i $x = 1; y = 2$ l\u00e0 _input_","hint":"Thay gi\u00e1 tr\u1ecb c\u1ee7a $x$ v\u00e0 $y$ v\u00e0o bi\u1ec3u th\u1ee9c \u0111\u00e3 cho v\u00e0 t\u00ednh.","explain":"<span class='basic_left'>V\u1edbi $x = 1; y = 2$ ta c\u00f3:<br\/> $x^2\\left( y+1 \\right)=1\\left( 2+1 \\right)=1.3=3$<br\/> <span class='basic_pink'> V\u1eady c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $3$.<\/span><\/span>"}]}],"id_ques":290},{"time":24,"part":[{"title":"\u0110i\u1ec1n k\u1ebft qu\u1ea3 \u0111\u00fang nh\u1ea5t v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["2"]]],"list":[{"point":5,"width":40,"type_input":"","ques":"Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c $y\\left( x^2+1 \\right)$ t\u1ea1i $x = 1; y = 1$ l\u00e0 _input_","hint":"Thay gi\u00e1 tr\u1ecb c\u1ee7a $x$ v\u00e0 $y$ v\u00e0o bi\u1ec3u th\u1ee9c \u0111\u00e3 cho v\u00e0 t\u00ednh.","explain":"<span class='basic_left'>Thay gi\u00e1 tr\u1ecb c\u1ee7a $x = 1; y = 1$ v\u00e0o bi\u1ec3u th\u1ee9c \u0111\u00e3 cho, ta \u0111\u01b0\u1ee3c:<br\/> $1\\left( 1^2+1 \\right)=1.2=2$<br\/> <span class='basic_pink'> V\u1eady c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $2$.<\/span><\/span>"}]}],"id_ques":291},{"time":24,"part":[{"title":"\u0110i\u1ec1n k\u1ebft qu\u1ea3 \u0111\u00fang nh\u1ea5t v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["0"]]],"list":[{"point":5,"width":40,"type_input":"","ques":"Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c $xy\\left( x+1 \\right)$ t\u1ea1i $x = 1; y = 0$ l\u00e0 _input_","hint":"Thay gi\u00e1 tr\u1ecb c\u1ee7a $x$ v\u00e0 $y$ v\u00e0o bi\u1ec3u th\u1ee9c \u0111\u00e3 cho v\u00e0 t\u00ednh.","explain":"<span class='basic_left'>Thay gi\u00e1 tr\u1ecb c\u1ee7a $x = 1; y = 0$ v\u00e0o bi\u1ec3u th\u1ee9c \u0111\u00e3 cho, ta \u0111\u01b0\u1ee3c: <br\/> $1.0\\left( 1+1 \\right)=0.2=0$<br\/> <span class='basic_pink'> V\u1eady c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $0$.<\/span><\/span>"}]}],"id_ques":292},{"time":24,"part":[{"title":"\u0110i\u1ec1n t\u1eeb th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank_random","correct":[[["z"]]],"list":[{"point":5,"width":40,"type_input":"","type_check":"","ques":"$y\\left(\\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}+3 \\right)=yz+3y$ ","hint":"Nh\u00f3m y \u1edf VP \u0111\u1ec3 xu\u1ea5t hi\u1ec7n nh\u00e2n t\u1eed gi\u1ed1ng VT, v\u00ec VP = VT $\\Rightarrow$ Th\u1eeba s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng","explain":"<span class='basic_left'> Ta c\u00f3: <br\/> VP = $yz + 3y = y(z + 3)$ <br\/> M\u00e0 VT = VP $\\Rightarrow$ $y(... + 3) = y(z + 3)$<br\/><span class='basic_pink'>V\u1eady c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $z$.<\/span><\/span>"}]}],"id_ques":293},{"time":24,"part":[{"title":"\u0110i\u1ec1n t\u1eeb th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank_random","correct":[[["x"]]],"list":[{"point":5,"width":40,"type_input":"","type_check":"","ques":"$\\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}\\left( y+1 \\right)=xy+x$ ","hint":"Bi\u1ebfn \u0111\u1ed5i VP l\u00e0m xu\u1ea5t hi\u1ec7n nh\u00e2n t\u1eed $y + 1$. V\u00ec VT = VP $\\Rightarrow$ Th\u1eeba s\u1ed1 c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng.","explain":"<span class='basic_left'> Ta c\u00f3: <br\/> VP $= xy + x = x(y + 1)$ <br\/> M\u00e0 VT = VP $\\Rightarrow$ $....(y + 1) = x(y + 1)$ <br\/> <span class='basic_pink'>V\u1eady c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $x$.<\/span><\/span>"}]}],"id_ques":294},{"time":24,"part":[{"title":"\u0110i\u1ec1n t\u1eeb th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank_random","correct":[[["xy","yx"],["yz","zy"]]],"list":[{"point":5,"width":40,"type_input":"","type_check":"","ques":"$y\\left( x+z \\right)$$= \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}+ \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}$","hint":"Th\u1ef1c hi\u1ec7n nh\u00e2n \u0111\u01a1n th\u1ee9c v\u1edbi t\u1eebng h\u1ea1ng t\u1eed c\u1ee7a \u0111a th\u1ee9c: $a(b+c) = a.b+a.c$","explain":"<span class='basic_left'>Ta th\u1ef1c hi\u1ec7n ph\u00e9p nh\u00e2n: <br\/>$y\\left( x+z \\right)=y.x+y.z=xy+yz$ <br\/><span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n c\u1ea7n \u0111i\u1ec1n v\u00e0o hai \u00f4 l\u00e0 $xy$ v\u00e0 $yz$<\/span><\/span>"}]}],"id_ques":295},{"time":24,"part":[{"title":"\u0110i\u1ec1n t\u1eeb th\u00edch h\u1ee3p v\u00e0o ch\u1ed7 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank_random","correct":[[["2x"],["2xy"]]],"list":[{"point":5,"width":40,"type_input":"","type_check":"","ques":"$2x\\left( 1+y \\right)$$= \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}+ \\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}$","hint":"Th\u1ef1c hi\u1ec7n nh\u00e2n \u0111\u01a1n th\u1ee9c v\u1edbi t\u1eebng h\u1ea1ng t\u1eed c\u1ee7a \u0111a th\u1ee9c: $a(b+c) = a.b+a.c$","explain":"<span class='basic_left'>Ta th\u1ef1c hi\u1ec7n ph\u00e9p nh\u00e2n: <br\/>$2x\\left( 1+y \\right)=2x.1+2x.y=2x+2xy$ <br\/><span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n c\u1ea7n \u0111i\u1ec1n v\u00e0o hai \u00f4 l\u00e0 $2x$ v\u00e0 $2xy$<\/span><\/span>"}]}],"id_ques":296},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai1/lv1/img\/1.png' \/><\/center>K\u1ebft qu\u1ea3 c\u1ee7a ph\u00e9p nh\u00e2n $x\\left( x+1 \\right)$ l\u00e0:","select":["A. ${{x}^{2}}-1$","B. ${{x}^{2}}+x$","C. ${{x}^{2}}-x$","D. $2x+x$"],"hint":"Nh\u00e2n \u0111\u01a1n th\u1ee9c v\u1edbi t\u1eebng h\u1ea1ng t\u1eed c\u1ee7a \u0111a th\u1ee9c: $a(b+c) = a.b+a.c$","explain":" Ta c\u00f3: $x\\left( x+1 \\right)={{x}^{2}}+x$ <br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 B <\/span>","column":2}]}],"id_ques":297},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai1/lv1/img\/1.png' \/><\/center>K\u1ebft qu\u1ea3 ph\u00e9p nh\u00e2n $x\\left( x+2 \\right)$ l\u00e0","select":["A. ${{x}^{2}}+2x$","B. ${{x}^{2}}+2$","C. $2x+2$","D. $2x-x$"],"hint":"Nh\u00e2n \u0111\u01a1n th\u1ee9c v\u1edbi t\u1eebng h\u1ea1ng t\u1eed c\u1ee7a \u0111a th\u1ee9c: $a(b+c) = a.b+a.c$","explain":" Ta c\u00f3: $x\\left( x+2 \\right)={{x}^{2}}+2x$ <br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A <\/span>","column":2}]}],"id_ques":298},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai1/lv1/img\/1.png' \/><\/center>K\u1ebft qu\u1ea3 ph\u00e9p nh\u00e2n $x\\left( x+y \\right)$ l\u00e0","select":["A. ${{x}^{2}}+xy$","B. ${{x}^{2}}-xy$","C. $2x+xy$","D. $2x-x+y$"],"hint":"Nh\u00e2n \u0111\u01a1n th\u1ee9c v\u1edbi t\u1eebng h\u1ea1ng t\u1eed c\u1ee7a \u0111a th\u1ee9c: $a(b+c) = a.b+a.c$","explain":" Ta c\u00f3: $x\\left( x+y \\right)={{x}^{2}}+xy$ <br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A <\/span>","column":2}]}],"id_ques":299},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop8/toan/daiso/bai1/lv1/img\/1.png' \/><\/center>K\u1ebft qu\u1ea3 ph\u00e9p t\u00ednh nh\u00e2n $x\\left( x+z \\right)$ l\u00e0","select":["A. ${{x}^{2}}-xz$","B. ${{x}^{2}}-x+z$","C. $x^2+xz$","D. $2x+xz$"],"hint":"Nh\u00e2n \u0111\u01a1n th\u1ee9c v\u1edbi t\u1eebng h\u1ea1ng t\u1eed c\u1ee7a \u0111a th\u1ee9c: $a(b+c) = a.b+a.c$","explain":" Ta c\u00f3: $x\\left( x+z \\right)={{x}^{2}}+xz$ <br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C <\/span>","column":2}]}],"id_ques":300}],"lesson":{"save":0,"level":1}}

Điểm của bạn.

Câu hỏi này theo dạng chọn đáp án đúng, sau khi đọc xong câu hỏi, bạn bấm vào một trong số các đáp án mà chương trình đưa ra bên dưới, sau đó bấm vào nút gửi để kiểm tra đáp án và sẵn sàng chuyển sang câu hỏi kế tiếp

Trả lời đúng trong khoảng thời gian quy định bạn sẽ được + số điểm như sau:
Trong khoảng 1 phút đầu tiên + 5 điểm
Trong khoảng 1 phút -> 2 phút + 4 điểm
Trong khoảng 2 phút -> 3 phút + 3 điểm
Trong khoảng 3 phút -> 4 phút + 2 điểm
Trong khoảng 4 phút -> 5 phút + 1 điểm

Quá 5 phút: không được cộng điểm

Tổng thời gian làm mỗi câu (không giới hạn)

Điểm của bạn.

Bấm vào đây nếu phát hiện có lỗi hoặc muốn gửi góp ý