{"common":{"save":0,"post_id":"7793","level":1,"total":10,"point":10,"point_extra":0},"segment":[{"id":"7373","post_id":"7793","mon_id":"1159278","chapter_id":"1159327","question":"<p>\u0110\u01b0a th\u1eeba s\u1ed1 <span class=\"math-tex\">$-2\\sqrt{3}$<\/span> vào trong d\u1ea5u c\u0103n có k\u1ebft qu\u1ea3 là:<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$-\\sqrt{12}$<\/span>","<strong>B.<\/strong> <span class=\"math-tex\">$-\\sqrt{6}$<\/span>","<strong>C.<\/strong> <span class=\"math-tex\">$\\sqrt{-12}$<\/span>","<strong>D.<\/strong> <span class=\"math-tex\">$\\sqrt{-6}$<\/span>"],"correct":"1","level":"1","hint":"","answer":"<p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>A.<\/strong> <span class=\"math-tex\">$-\\sqrt{12}$<\/span><\/span><\/p><p><span class=\"math-tex\">$-2\\sqrt{3}=-\\sqrt{2^2.3}=-\\sqrt{12}$<\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"127","test":"0","date":"2024-10-06 10:12:41","option_type":"math","len":0},{"id":"7374","post_id":"7793","mon_id":"1159278","chapter_id":"1159327","question":"<p>\u0110\u01b0a th\u1eeba s\u1ed1 <span class=\"math-tex\">$\\sqrt{48y^4}$<\/span> ra ngoài d\u1ea5u c\u0103n ta \u0111\u01b0\u1ee3c k\u1ebft qu\u1ea3 là:<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$16|y^2|\\sqrt{3}$<\/span>","<strong>B.<\/strong> <span class=\"math-tex\">$16y^2\\sqrt{3}$<\/span>","<strong>C.<\/strong> <span class=\"math-tex\">$-4y^2\\sqrt{3}$<\/span>","<strong>D.<\/strong> <span class=\"math-tex\">$4y^2\\sqrt{3}$<\/span>"],"correct":"4","level":"1","hint":"","answer":"<p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>D.<\/strong> <span class=\"math-tex\">$4y^2\\sqrt{3}$<\/span><\/span><\/p><p><span class=\"math-tex\">$\\sqrt{48y^4}=\\sqrt{4^2.3.(y^2)^4}=4y^2\\sqrt{3}$<\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"127","test":"0","date":"2024-10-06 10:15:36","option_type":"math","len":0},{"id":"7376","post_id":"7793","mon_id":"1159278","chapter_id":"1159327","question":"<p>Kh\u1eb3ng \u0111\u1ecbnh nào sau \u0111ây <strong>\u0111úng<\/strong>?<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$-4\\sqrt{3}=\\sqrt{(-4)^2.3}$<\/span>","<strong>B.<\/strong> <span class=\"math-tex\">$\\sqrt{(-3)^2.5}=-3\\sqrt{5}$<\/span>","<strong>C.<\/strong> <span class=\"math-tex\">$2\\sqrt{7}=\\sqrt{14}$<\/span>","<strong>D.<\/strong> <span class=\"math-tex\">$\\dfrac{-3}{5}\\sqrt{\\dfrac{5}{27}}=\\dfrac{-1}{\\sqrt{15}}$<\/span>"],"correct":"4","level":"1","hint":"","answer":"<p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>D.<\/strong> <span class=\"math-tex\">$\\dfrac{-3}{5}\\sqrt{\\dfrac{5}{27}}=\\dfrac{-1}{\\sqrt{15}}$<\/span><\/span><\/p><p><strong>A.<\/strong> sai vì <span class=\"math-tex\">$-4\\sqrt{3}=-\\sqrt{4^2.3}$<\/span><\/p><p><strong>B.<\/strong> sai vì <span class=\"math-tex\">$\\sqrt{(-3)^2.5}=|-3|.\\sqrt{5}=3\\sqrt{5}$<\/span><\/p><p><strong>C.<\/strong> sai vì <span class=\"math-tex\">$2\\sqrt{7}=\\sqrt{2^2.7}=\\sqrt{28}$<\/span><\/p><p><strong>D.<\/strong> \u0111úng vì <span class=\"math-tex\">$\\dfrac{-3}{5}\\sqrt{\\dfrac{5}{27}}=-\\sqrt{\\dfrac{3^2}{5^2}.\\dfrac{5}{27}}=-\\sqrt{\\dfrac{1}{15}}=\\dfrac{-1}{\\sqrt{15}}$<\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"127","test":"0","date":"2024-10-06 10:23:48","option_type":"math","len":0}]}
