{"common":{"save":0,"post_id":"7794","level":2,"total":10,"point":10,"point_extra":0},"segment":[{"id":"7397","post_id":"7794","mon_id":"1159278","chapter_id":"1159327","question":"<p>V\u1edbi <span class=\"math-tex\">$a > 0$<\/span> thì <span class=\"math-tex\">$-\\sqrt{a}$<\/span> là k\u1ebft qu\u1ea3 rút g\u1ecdn c\u1ee7a bi\u1ec3u th\u1ee9c nào d\u01b0\u1edbi \u0111ây?<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$\\dfrac{a-\\sqrt{a}}{1-\\sqrt{a}}$<\/span>","<strong>B.<\/strong> <span class=\"math-tex\">$\\dfrac{a-2\\sqrt{a}}{\\sqrt{a}-2}$<\/span>","<strong>C.<\/strong> <span class=\"math-tex\">$\\dfrac{a+\\sqrt{a}}{1+\\sqrt{a}}$<\/span>","<strong>D.<\/strong> <span class=\"math-tex\">$\\dfrac{a+\\sqrt{a}}{\\sqrt{a}}$<\/span>"],"correct":"1","level":"2","hint":"","answer":"<p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>A.<\/strong> <span class=\"math-tex\">$\\dfrac{a-\\sqrt{a}}{1-\\sqrt{a}}$<\/span><\/span><\/p><p><strong>A.<\/strong> <span class=\"math-tex\">$\\dfrac{a-\\sqrt{a}}{1-\\sqrt{a}}=\\dfrac{\\sqrt{a}(\\sqrt{a}-1)}{1-\\sqrt{a}}$<\/span> <span style=\"color:#16a085;\"><span class=\"math-tex\">$=-\\sqrt{a}$<\/span><\/span><\/p><p><strong>B.<\/strong> <span class=\"math-tex\">$\\dfrac{a-2\\sqrt{a}}{\\sqrt{a}-2}=\\dfrac{\\sqrt{a}(\\sqrt{a}-2)}{\\sqrt{a}-2}$<\/span> <span style=\"color:#c0392b;\"><span class=\"math-tex\">$=\\sqrt{a}$<\/span><\/span><\/p><p><strong>C.<\/strong> <span class=\"math-tex\">$\\dfrac{a+\\sqrt{a}}{1+\\sqrt{a}}=\\dfrac{\\sqrt{a}(\\sqrt{a}+1)}{1+\\sqrt{a}}$<\/span> <span style=\"color:#c0392b;\"><span class=\"math-tex\">$=\\sqrt{a}$<\/span><\/span><\/p><p><strong>D.<\/strong> <span class=\"math-tex\">$\\dfrac{a+\\sqrt{a}}{\\sqrt{a}}=\\dfrac{\\sqrt{a}(\\sqrt{a}+1)}{\\sqrt{a}}$<\/span> <span style=\"color:#c0392b;\"><span class=\"math-tex\">$=\\sqrt{a}+1$<\/span><\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"127","test":"0","date":"2024-10-07 02:12:22","option_type":"math","len":0},{"id":"7401","post_id":"7794","mon_id":"1159278","chapter_id":"1159327","question":"<p>Th\u1ef1c hi\u1ec7n phép tính <span class=\"math-tex\">$\\dfrac{3}{2}\\sqrt{6}+2\\sqrt{\\dfrac{2}{3}}-4\\sqrt{\\dfrac{3}{2}}$<\/span> ta có k\u1ebft qu\u1ea3:<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$2\\sqrt{6}$<\/span>","<strong>B.<\/strong> <span class=\"math-tex\">$\\sqrt{6}$<\/span>","<strong>C.<\/strong> <span class=\"math-tex\">$\\dfrac{\\sqrt{6}}{6}$<\/span>","<strong>D.<\/strong> <span class=\"math-tex\">$-\\dfrac{\\sqrt{6}}{6}$<\/span>"],"correct":"3","level":"2","hint":"","answer":"<p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>C.<\/strong> <span class=\"math-tex\">$\\dfrac{\\sqrt{6}}{6}$<\/span><\/span><\/p><p><span class=\"math-tex\">$\\dfrac{3}{2}\\sqrt{6}+2\\sqrt{\\dfrac{2}{3}}-4\\sqrt{\\dfrac{3}{2}}$<\/span><\/p><p><span class=\"math-tex\">$=\\dfrac{3}{2}\\sqrt{6}+\\dfrac{2}{3}\\sqrt{6}-2\\sqrt{6}$<\/span><\/p><p><span class=\"math-tex\">$=\\bigg(\\dfrac{3}{2}+\\dfrac{2}{3}-2\\bigg).\\sqrt{6}$<\/span><\/p><p><span class=\"math-tex\">$=\\dfrac{1}{6}\\sqrt{6}$<\/span><\/p><p><span style=\"color:#16a085;\"><span class=\"math-tex\">$=\\dfrac{\\sqrt{6}}{6}$<\/span><\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"127","test":"0","date":"2024-10-07 02:18:36","option_type":"math","len":0},{"id":"7403","post_id":"7794","mon_id":"1159278","chapter_id":"1159327","question":"<p>Rút g\u1ecdn bi\u1ec3u th\u1ee9c <span class=\"math-tex\">$A=\\sqrt{\\dfrac{3+\\sqrt{5}}{3-\\sqrt{5}}}+\\sqrt{\\dfrac{3-\\sqrt{5}}{3+\\sqrt{5}}}$<\/span> có k\u1ebft qu\u1ea3 là:<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$A=2\\sqrt{5}$<\/span>","<strong>B.<\/strong> <span class=\"math-tex\">$A=\\sqrt{5}$<\/span>","<strong>C.<\/strong> <span class=\"math-tex\">$A=3$<\/span>","<strong>D.<\/strong> <span class=\"math-tex\">$A=6$<\/span>"],"correct":"3","level":"2","hint":"","answer":"<p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>C.<\/strong> <span class=\"math-tex\">$A=3$<\/span><\/span><\/p><p><span class=\"math-tex\">$A=\\sqrt{\\dfrac{3+\\sqrt{5}}{3-\\sqrt{5}}}+\\sqrt{\\dfrac{3-\\sqrt{5}}{3+\\sqrt{5}}}$<\/span><\/p><p><span class=\"math-tex\">$=\\sqrt{\\dfrac{(3+\\sqrt{5})(3+\\sqrt{5})}{(3-\\sqrt{5})(3+\\sqrt{5})}}+\\sqrt{\\dfrac{(3-\\sqrt{5})(3-\\sqrt{5})}{(3+\\sqrt{5})(3-\\sqrt{5})}}$<\/span><\/p><p><span class=\"math-tex\">$=\\sqrt{\\dfrac{(3+\\sqrt{5})^2}{4}}+\\sqrt{\\dfrac{(3-\\sqrt{5})^2}{4}}$<\/span><\/p><p><span class=\"math-tex\">$=\\dfrac{3+\\sqrt{5}}{2}+\\dfrac{3-\\sqrt{5}}{2}$<\/span><\/p><p>= <strong><span style=\"color:#16a085;\">3<\/span><\/strong><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"127","test":"0","date":"2024-10-07 02:25:50","option_type":"math","len":0}]}