Luyện tập chung (sau bài 16, 17)

Home Lớp 9 Toán lớp 9 - Sách Kết nối tri thức Luyện tập chung (sau bài 16, 17)Bài tập trung bình

{"common":{"save":0,"post_id":"8035","level":2,"total":10,"point":10,"point_extra":0},"segment":[{"id":"8534","post_id":"8035","mon_id":"1159278","chapter_id":"1159329","question":"Trong h\u1ec7 t\u1ecda \u0111\u1ed9 Oxy cho \u0111i\u1ec3m A (2 ; 4) và \u0111\u01b0\u1eddng tròn (A ; 4). Ch\u1ecdn \u0111áp án \u0111úng.<\/p>","options":["A.<\/strong> \u0110\u01b0\u1eddng tròn (A ; 3) ti\u1ebfp xúc v\u1edbi tr\u1ee5c Ox.","B.<\/strong> \u0110\u01b0\u1eddng tròn (A ; 3) ti\u1ebfp xúc v\u1edbi tr\u1ee5c Oy.","C.<\/strong> \u0110\u01b0\u1eddng tròn (A ; 3) không c\u1eaft tr\u1ee5c Ox.","D.<\/strong> \u0110\u01b0\u1eddng tròn (A ; 3) không c\u1eaft tr\u1ee5c Oy."],"correct":"1","level":"2","hint":"","answer":"Ch\u1ecdn A.<\/strong> \u0110\u01b0\u1eddng tròn (A ; 3) ti\u1ebfp xúc v\u1edbi tr\u1ee5c Ox.<\/span><\/p>Kho\u1ea3ng cách t\u1eeb A \u0111\u1ebfn tr\u1ee5c Ox là d = AH = OK = 4. Kho\u1ea3ng cách t\u1eeb A \u0111\u1ebfn tr\u1ee5c Oy là d' = AK = OH = 2. Do \u0111ó \u0111\u01b0\u1eddng tròn (A ; 3) ti\u1ebfp xúc v\u1edbi tr\u1ee5c Ox vì d = R = 4. \u0110\u01b0\u1eddng tròn (A ; 3) c\u1eaft tr\u1ee5c Oy vì d' = 2 < 4 = R.<\/p><svg height=\"300\" width=\"310\"> <g> <title><\/title> <rect fill=\"#fff\" height=\"302\" id=\"canvas_background\" width=\"312\" x=\"-1\" y=\"-1\"><\/rect> <g display=\"none\" height=\"100%\" id=\"canvasGrid\" overflow=\"visible\" width=\"100%\" x=\"0\" y=\"0\"> <rect fill=\"url(#gridpattern)\" height=\"100%\" stroke-width=\"0\" width=\"100%\" x=\"0\" y=\"0\"><\/rect> <\/g> <\/g> <g> <title><\/title> <ellipse cx=\"125.5\" cy=\"157.49999\" fill=\"none\" id=\"svg_2\" rx=\"107.99999\" ry=\"108.49999\" stroke=\"#000\" stroke-width=\"1.5\"><\/ellipse> <line fill=\"none\" id=\"svg_4\" stroke=\"#000\" stroke-linecap=\"null\" stroke-linejoin=\"null\" stroke-opacity=\"null\" stroke-width=\"1.5\" x1=\"70.5\" x2=\"70.5\" y1=\"3\" y2=\"293\"><\/line> <line fill=\"none\" id=\"svg_6\" stroke=\"#000\" stroke-linecap=\"null\" stroke-linejoin=\"null\" stroke-opacity=\"null\" stroke-width=\"1.5\" x1=\"3.5\" x2=\"299.5\" y1=\"266\" y2=\"266\"><\/line> <line fill=\"none\" id=\"svg_7\" stroke=\"#000\" stroke-dasharray=\"5,5\" stroke-linecap=\"null\" stroke-linejoin=\"null\" stroke-opacity=\"null\" stroke-width=\"1.5\" x1=\"69.5\" x2=\"125.5\" y1=\"157\" y2=\"157\"><\/line> <line fill=\"none\" id=\"svg_8\" stroke=\"#000\" stroke-dasharray=\"5,5\" stroke-linecap=\"null\" stroke-linejoin=\"null\" stroke-opacity=\"null\" stroke-width=\"1.5\" transform=\"rotate(90 125.24999999999999,211.50000000000003) \" x1=\"72\" x2=\"178.5\" y1=\"211.5\" y2=\"211.5\"><\/line> <text fill=\"#000000\" fill-opacity=\"null\" font-family=\"Times New Roman, Times, serif\" font-size=\"24\" font-style=\"italic\" font-weight=\"bold\" id=\"svg_9\" stroke=\"#000\" stroke-opacity=\"null\" stroke-width=\"0\" text-anchor=\"start\" x=\"48\" xml:space=\"preserve\" y=\"16.25\">y<\/text> <text fill=\"#000000\" fill-opacity=\"null\" font-family=\"Times New Roman, Times, serif\" font-size=\"24\" font-style=\"italic\" font-weight=\"bold\" id=\"svg_10\" stroke=\"#000\" stroke-opacity=\"null\" stroke-width=\"0\" text-anchor=\"start\" x=\"286\" xml:space=\"preserve\" y=\"289.25\">x<\/text> <text fill=\"#000000\" fill-opacity=\"null\" font-family=\"Times New Roman, Times, serif\" font-size=\"24\" font-weight=\"bold\" id=\"svg_11\" stroke=\"#000\" stroke-opacity=\"null\" stroke-width=\"0\" text-anchor=\"start\" x=\"48\" xml:space=\"preserve\" y=\"285.25\">O<\/text> <text fill=\"#000000\" fill-opacity=\"null\" font-family=\"Times New Roman, Times, serif\" font-size=\"24\" font-weight=\"bold\" id=\"svg_12\" stroke=\"#000\" stroke-opacity=\"null\" stroke-width=\"0\" style=\"cursor: move;\" text-anchor=\"start\" x=\"72\" xml:space=\"preserve\" y=\"146.25\">K<\/text> <text fill=\"#000000\" fill-opacity=\"null\" font-family=\"Times New Roman, Times, serif\" font-size=\"24\" font-weight=\"bold\" id=\"svg_13\" stroke=\"#000\" stroke-opacity=\"null\" stroke-width=\"0\" text-anchor=\"start\" x=\"128\" xml:space=\"preserve\" y=\"158.25\">A<\/text> <text fill=\"#000000\" fill-opacity=\"null\" font-family=\"Times New Roman, Times, serif\" font-size=\"24\" font-weight=\"bold\" id=\"svg_14\" stroke=\"#000\" stroke-opacity=\"null\" stroke-width=\"0\" text-anchor=\"start\" x=\"125\" xml:space=\"preserve\" y=\"259.25\">H<\/text> <text fill=\"#000000\" fill-opacity=\"null\" font-family=\"Times New Roman, Times, serif\" font-size=\"24\" font-weight=\"bold\" id=\"svg_15\" stroke=\"#000\" stroke-opacity=\"null\" stroke-width=\"0\" text-anchor=\"start\" x=\"291\" xml:space=\"preserve\" y=\"273.25\">><\/text> <text fill=\"#000000\" fill-opacity=\"null\" font-family=\"Times New Roman, Times, serif\" font-size=\"24\" font-weight=\"bold\" id=\"svg_16\" stroke=\"#000\" stroke-opacity=\"null\" stroke-width=\"0\" text-anchor=\"start\" transform=\"rotate(-90 70.00000000000001,8.249999999999995) \" x=\"63\" xml:space=\"preserve\" y=\"16.25\">><\/text> <text fill=\"#000000\" fill-opacity=\"null\" font-family=\"Times New Roman, Times, serif\" font-size=\"24\" font-weight=\"bold\" id=\"svg_17\" stroke=\"#000\" stroke-opacity=\"null\" stroke-width=\"0\" text-anchor=\"start\" x=\"119.5\" xml:space=\"preserve\" y=\"286.25\">2<\/text> <text fill=\"#000000\" fill-opacity=\"null\" font-family=\"Times New Roman, Times, serif\" font-size=\"24\" font-weight=\"bold\" id=\"svg_18\" stroke=\"#000\" stroke-opacity=\"null\" stroke-width=\"0\" text-anchor=\"start\" x=\"54.5\" xml:space=\"preserve\" y=\"167.25\">4<\/text> <\/g> <\/svg><\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"127","test":"0","date":"2024-11-13 10:14:04","option_type":"txt","len":3},{"id":"8536","post_id":"8035","mon_id":"1159278","chapter_id":"1159329","question":"Cho \u0111\u01b0\u1eddng tròn tâm O bán kính 5 cm và m\u1ed9t \u0111i\u1ec3m A cách O là 13 cm. K\u1ebb ti\u1ebfp tuy\u1ebfn AB v\u1edbi \u0111\u01b0\u1eddng tròn trong \u0111ó B là ti\u1ebfp \u0111i\u1ec3m. \u0110\u1ed9 dài \u0111o\u1ea1n AB b\u1eb1ng:<\/p>","options":["A.<\/strong> 8 cm","B.<\/strong> 10 cm","C.<\/strong> 12 cm","D.<\/strong> 15 cm"],"correct":"3","level":"2","hint":"","answer":"Ch\u1ecdn C.<\/strong> 12 cm.<\/span><\/p>AB là ti\u1ebfp tuy\u1ebfn c\u1ee7a \u0111\u01b0\u1eddng tròn (O) v\u1edbi B là ti\u1ebfp \u0111i\u1ec3m nên $\\triangle$<\/span> ABO vuông t\u1ea1i B. Áp d\u1ee5ng \u0111\u1ecbnh lý Pythagore ta có: AB = $\\sqrt{OA^2-OB^2}$<\/span> = $\\sqrt{13^2-5^2}$<\/span> = 12 cm.<\/p><svg height=\"230\" width=\"340\"> <g><title><\/title><rect fill=\"#ffffff\" height=\"232\" id=\"canvas_background\" width=\"342\" x=\"-1\" y=\"-1\"><\/rect> <g display=\"none\" height=\"100%\" id=\"canvasGrid\" overflow=\"visible\" width=\"100%\" x=\"0\" y=\"0\"> <rect fill=\"url(#gridpattern)\" height=\"100%\" stroke-width=\"0\" width=\"100%\" x=\"0\" y=\"0\"><\/rect> <\/g> <\/g> <g><title><\/title><g id=\"svg_3\"> <ellipse cx=\"102\" cy=\"122.25\" fill=\"#fff\" id=\"svg_1\" rx=\"100\" ry=\"100\" stroke=\"#000\" stroke-width=\"1.5\"><\/ellipse> <ellipse cx=\"102\" cy=\"122.25\" fill=\"#000000\" id=\"svg_2\" rx=\"2\" ry=\"2\" stroke=\"#000\" stroke-width=\"1.5\"><\/ellipse> <\/g> <path d=\"m332.68802,124.01747l0,-102l-230.96642,102l230.96642,0z\" fill=\"none\" id=\"svg_4\" stroke=\"#000\" stroke-opacity=\"null\" stroke-width=\"1.5\" transform=\"rotate(-180 217.20480346679688,73.01747131347656) \"><\/path> <text fill=\"#000000\" font-family=\"Helvetica, Arial, sans-serif\" font-size=\"24\" id=\"svg_5\" stroke=\"#000\" stroke-opacity=\"null\" stroke-width=\"0\" text-anchor=\"start\" x=\"88.5\" xml:space=\"preserve\" y=\"144.25\">O<\/text> <text fill=\"#000000\" font-family=\"Helvetica, Arial, sans-serif\" font-size=\"24\" id=\"svg_6\" stroke=\"#000\" stroke-opacity=\"null\" stroke-width=\"0\" text-anchor=\"start\" x=\"95.5\" xml:space=\"preserve\" y=\"19.25\">B<\/text> <text fill=\"#000000\" font-family=\"Helvetica, Arial, sans-serif\" font-size=\"24\" id=\"svg_7\" stroke=\"#000\" stroke-opacity=\"null\" stroke-width=\"0\" text-anchor=\"start\" x=\"320.5\" xml:space=\"preserve\" y=\"45.25\">A<\/text> <rect fill=\"none\" height=\"15\" id=\"svg_8\" stroke=\"#000\" stroke-opacity=\"null\" stroke-width=\"1.5\" width=\"15\" x=\"101.5\" y=\"22.25\"><\/rect> <\/g> <\/svg><\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"127","test":"0","date":"2024-11-13 10:21:22","option_type":"txt","len":0},{"id":"8537","post_id":"8035","mon_id":"1159278","chapter_id":"1159329","question":"Cho hình thang vuông ABCD có $\\widehat{A}=\\widehat{B}=90^o$<\/span>, AD = 2 mc, BC = 6 cm, CD = 8 cm. \u0110\u01b0\u1eddng th\u1eb3ng AB ti\u1ebfp xúc v\u1edbi \u0111\u01b0\u1eddng tròn:<\/p>","options":["A.<\/strong> \u0110\u01b0\u1eddng kính DC","B.<\/strong> Bán kính DC","C.<\/strong> Bán kính BC","D.<\/strong> Bán kính AD"],"correct":"1","level":"2","hint":"","answer":"Ch\u1ecdn A.<\/strong> \u0110\u01b0\u1eddng kính DC<\/span><\/p>G\u1ecdi I, K l\u1ea7n l\u01b0\u1ee3t là trung \u0111i\u1ec3m c\u1ee7a CD và AB.<\/p>Ta có: IK là \u0111\u01b0\u1eddng trung bình c\u1ee7a hình thang ABCD suy ra $IK=\\dfrac{AD+BC}{2}=4$<\/span> (cm).<\/p>L\u1ea1i có: AD \/\/ IK, AD &perp; AB nên IK &perp; AB mà $IK=\\dfrac{CD}{2} (=4cm)$<\/span>.<\/p>Do \u0111ó AB 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