{"common":{"save":0,"post_id":"8783","level":2,"total":10,"point":10,"point_extra":0},"segment":[{"id":"11764","post_id":"8783","mon_id":"1159278","chapter_id":"1159334","question":"<p>Hình c\u1ea7u tâm O bán kính 0,4 mm thì có th\u1ec3 tích là:<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$\\dfrac{32\\pi}{375}\\;mm^3$<\/span>.","<strong>B.<\/strong> <span class=\"math-tex\">$\\dfrac{32\\pi}{325}\\;mm^3$<\/span>.","<strong>C.<\/strong> <span class=\"math-tex\">$\\dfrac{16\\pi}{375}\\;mm^3$<\/span>.","<strong>D.<\/strong> <span class=\"math-tex\">$\\dfrac{16\\pi}{325}\\;mm^3$<\/span>."],"correct":"1","level":"2","hint":"","answer":"<p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>A.<\/strong> <span class=\"math-tex\">$\\dfrac{32\\pi}{375}\\;mm^3$<\/span>.<\/span><\/p><p>Th\u1ec3 tích c\u1ee7a hình c\u1ea7u tâm O bán kính R = 0,4 mm là:<\/p><p><span class=\"math-tex\">$V=\\dfrac{4}{3}\\pi R^3=\\dfrac{4}{3}.\\pi.0,4^3=\\dfrac{32\\pi}{375}$<\/span> (mm³).<\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"127","test":"0","date":"2025-05-30 10:40:32","option_type":"math","len":0},{"id":"11765","post_id":"8783","mon_id":"1159278","chapter_id":"1159334","question":"<p>M\u1ed9t hình tr\u1ee5 có chi\u1ec1u cao b\u1eb1ng 5 m và di\u1ec7n tích xung quanh b\u1eb1ng <span class=\"math-tex\">$20\\pi \\;(m^2)$<\/span>. Tính th\u1ec3 tích c\u1ee7a hình tr\u1ee5.<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$18\\pi\\;m^3$<\/span>.","<strong>B.<\/strong> <span class=\"math-tex\">$20\\pi\\;m^3$<\/span>.","<strong>C.<\/strong> <span class=\"math-tex\">$10\\pi\\;m^3$<\/span>.","<strong>D.<\/strong> <span class=\"math-tex\">$12\\pi\\;m^3$<\/span>."],"correct":"2","level":"2","hint":"","answer":"<p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>B.<\/strong> <span class=\"math-tex\">$20\\pi\\;m^3$<\/span>.<\/span><\/p><p>G\u1ecdi R (R > 0, \u0111\u01a1n v\u1ecb m) là bán kính \u0111áy c\u1ee7a hình tr\u1ee5.<\/p><p>Vì di\u1ec7n tích xung quanh c\u1ee7a hình tr\u1ee5 b\u1eb1ng <span class=\"math-tex\">$20\\pi \\;(m^2)$<\/span> nên <span class=\"math-tex\">$2\\pi R.5=20\\pi$<\/span>. Suy ra R = 2 (m).<\/p><p>Th\u1ec3 tích c\u1ee7a hình tr\u1ee5 là <span class=\"math-tex\">$V=\\pi.2^2.5=20\\pi$<\/span> (m³).<\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"127","test":"0","date":"2025-05-30 10:46:33","option_type":"math","len":0},{"id":"11766","post_id":"8783","mon_id":"1159278","chapter_id":"1159334","question":"<p>M\u1ed9t hình c\u1ea7u có di\u1ec7n tích b\u1ec1 m\u1eb7t là <span class=\"math-tex\">$324\\pi\\;cm^2$<\/span> thì th\u1ec3 tích c\u1ee7a hình c\u1ea7u \u0111ó là:<\/p>","options":["<strong>A.<\/strong> <span class=\"math-tex\">$792\\pi\\;cm^3$<\/span>.","<strong>B.<\/strong> <span class=\"math-tex\">$108\\pi\\;cm^3$<\/span>.","<strong>C.<\/strong> <span class=\"math-tex\">$972\\pi\\;cm^3$<\/span>.","<strong>D.<\/strong> <span class=\"math-tex\">$927\\pi\\;cm^3$<\/span>."],"correct":"3","level":"2","hint":"","answer":"<p>Ch\u1ecdn <span style=\"color:#16a085;\"><strong>C.<\/strong> <span class=\"math-tex\">$972\\pi\\;cm^3$<\/span>.<\/span><\/p><p>G\u1ecdi R (R > 0, \u0111\u01a1n v\u1ecb cm) là bán kính c\u1ee7a hình c\u1ea7u.<\/p><p>Vì hình c\u1ea7u có di\u1ec7n tích b\u1ec1 m\u1eb7t là <span class=\"math-tex\">$324\\pi\\;cm^2$<\/span> nên <span class=\"math-tex\">$4\\pi R^2=324\\pi$<\/span>. Suy ra R² = 81 hay R = 9 (cm).<\/p><p>Th\u1ec3 tích c\u1ee7a hình c\u1ea7u \u0111ó là <span class=\"math-tex\">$V=\\dfrac{4}{3}\\pi R^3=\\dfrac{4}{3}\\pi.9^3=972\\pi(cm^3)$<\/span>.<\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"127","test":"0","date":"2025-05-30 10:51:24","option_type":"math","len":0}]}