{"segment":[{"time":24,"part":[{"title":"\u0110i\u1ec1n k\u1ebft qu\u1ea3 v\u00e0o \u00f4 tr\u1ed1ng ","title_trans":"","temp":"fill_the_blank","correct":[[["-6"]]],"list":[{"point":10,"width":40,"type_input":"","ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai8/lv3/img\/5.jpg' \/><\/center>Bi\u1ec3u th\u1ee9c $\\left( -4{{a}^{5}}{{b}^{2}}-\\dfrac{4}{9}{{a}^{4}}{{b}^{5}}+\\dfrac{2}{3}{{a}^{3}}{{b}^{6}} \\right): \\dfrac{2}{3}{{a}^{3}}{{b}^{2}} $ c\u00f3 h\u1ec7 s\u1ed1 c\u1ee7a $a^2$ l\u00e0 _input_","hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1:<\/b> R\u00fat g\u1ecdn bi\u1ec3u th\u1ee9c: Th\u1ef1c hi\u1ec7n chia \u0111a th\u1ee9c cho \u0111\u01a1n th\u1ee9c.<br\/> <b> B\u01b0\u1edbc 2:<\/b> T\u00ecm h\u1ec7 s\u1ed1 c\u1ee7a $a^2$. <br\/><span class='basic_green'>B\u00e0i gi\u1ea3i<\/span><br\/> $ \\left( -4{{a}^{5}}{{b}^{2}}-\\dfrac{4}{9}{{a}^{4}}{{b}^{5}}+\\dfrac{2}{3}{{a}^{3}}{{b}^{6}} \\right): \\dfrac{2}{3}{{a}^{3}}{{b}^{2}} $<br\/>$ =-4{{a}^{5}}{{b}^{2}}: \\dfrac{2}{3}{{a}^{3}}{{b}^{2}} -\\dfrac{4}{9}{{a}^{4}}{{b}^{5}}: \\dfrac{2}{3}{{a}^{3}}{{b}^{2}} +\\dfrac{2}{3}{{a}^{3}}{{b}^{6}}: \\dfrac{2}{3}{{a}^{3}}{{b}^{2}} $<br\/>$ =-6{{a}^{2}}-\\dfrac{2}{3}a{{b}^{3}}+{{b}^{4}} $. <br\/> H\u1ec7 s\u1ed1 c\u1ee7a $a^2$ l\u00e0 $-6$. <br\/> <span class='basic_pink'> Do \u0111\u00f3 ph\u1ea3i \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $-6$. <\/span><\/span> "}]}],"id_ques":761},{"time":24,"part":[{"title":"Ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"select":["A. $\\dfrac{5}{2}$","B. $\\dfrac{3}{2}$","C. $\\dfrac{1}{2}$"],"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai8/lv3/img\/4.jpg' \/><\/center>Bi\u1ec3u th\u1ee9c $\\left( 8{{x}^{3}}-4{{x}^{2}} \\right):4x-\\left( 4{{x}^{2}}-5x \\right):2x+{{\\left( 2x \\right)}^{2}}$ c\u00f3 h\u1ec7 s\u1ed1 t\u1ef1 do l\u00e0 ?","hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1:<\/b> R\u00fat g\u1ecdn bi\u1ec3u th\u1ee9c: Th\u1ef1c hi\u1ec7n chia \u0111a th\u1ee9c cho \u0111\u01a1n th\u1ee9c.<br\/> <b> B\u01b0\u1edbc 2:<\/b>T\u00ecm h\u1ec7 s\u1ed1 t\u1ef1 do. <br\/><span class='basic_green'>B\u00e0i gi\u1ea3i<\/span><br\/> $ \\left( 8{{x}^{3}}-4{{x}^{2}} \\right):4x-\\left( 4{{x}^{2}}-5x \\right):2x+{{\\left( 2x \\right)}^{2}} $<br\/>$ =2{{x}^{2}}-x-2x+\\dfrac{5}{2}+4{{x}^{2}} $<br\/>$ =6{{x}^{2}}-3x+\\dfrac{5}{2} $ <br\/> H\u1ec7 s\u1ed1 t\u1ef1 do l\u00e0 $\\dfrac{5}{2}$."}]}],"id_ques":762},{"time":24,"part":[{"title":"Ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"select":["A. $\\dfrac{5}{3}$","B. $\\dfrac{1}{3}$","C. $\\dfrac{4}{3}$"],"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai8/lv3/img\/2.jpg' \/><\/center>Bi\u1ebft $\\left( 8{{x}^{3}}-4{{x}^{2}} \\right):2{{x}^{2}}-\\left( 4{{x}^{2}}-3x \\right): x +2x=-x+5$, gi\u00e1 tr\u1ecb c\u1ee7a $x$ l\u00e0 ?","hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1:<\/b> Th\u1ef1c hi\u1ec7n chia \u0111a th\u1ee9c cho \u0111\u01a1n th\u1ee9c \u1edf v\u1ebf tr\u00e1i.<br\/> <b> B\u01b0\u1edbc 2:<\/b> R\u00fat g\u1ecdn r\u1ed3i t\u00ecm gi\u00e1 tr\u1ecb c\u1ee7a $x$. <br\/><span class='basic_green'>B\u00e0i gi\u1ea3i<\/span><br\/> $ \\left( 8{{x}^{3}}-4{{x}^{2}} \\right) : 2{{x}^{2}} - \\left( 4{{x}^{2}}-3x \\right) : x+2x =-x+5 \\\\ \\Leftrightarrow 4x-2-4x+3+2x =-x+5 \\\\ \\Leftrightarrow 2x+1 =-x+5 \\\\ \\Leftrightarrow 3x =4 \\\\ \\Leftrightarrow x =\\dfrac{4}{3}$"}]}],"id_ques":763},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t.<br\/> Kh\u1eb3ng \u0111\u1ecbnh d\u01b0\u1edbi \u0111\u00e2y \u0111\u00fang hay sai","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":10,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai8/lv3/img\/16.jpg' \/><\/center> \u0110a th\u1ee9c $A=(x^3y^3-9x^6y^5+12x^3y^3) : 3x^3y^3$ chia h\u1ebft cho \u0111\u01a1n th\u1ee9c $B=xy$ ","select":["\u0110\u00fang","Sai"],"hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn<\/span><br\/> <b> Quy t\u1eafc:<\/b> \u0110\u1ec3 $ax^my^n$ chia h\u1ebft cho $bx^py^q$ th\u00ec $\\left\\{ \\begin{align} & m\\ge p \\\\ & n\\ge q \\\\ \\end{align} \\right.$<br\/><b> B\u01b0\u1edbc 1: <\/b> R\u00fat g\u1ecdn \u0111a th\u1ee9c $A$: Chia \u0111a th\u1ee9c cho \u0111\u01a1n th\u1ee9c.<br\/> <b> B\u01b0\u1edbc 2:<\/b> X\u00e9t t\u1eebng h\u1ea1ng t\u1eed c\u1ee7a $A$ xem c\u00f3 chia h\u1ebft cho $B$ kh\u00f4ng.<br\/> <b> B\u01b0\u1edbc 3:<\/b> K\u1ebft lu\u1eadn $A$ c\u00f3 chia h\u1ebft cho $B$ kh\u00f4ng. <br\/> N\u1ebfu $a\\,\\vdots \\, m;b\\,\\vdots \\,m$ th\u00ec $(a+b)\\,\\vdots \\, m$. <br\/> N\u1ebfu $a\\,\\vdots \\, m;b\\,\\not\\vdots \\,m$ th\u00ec $(a+b)\\,\\not\\vdots \\, m$.<br\/><span class='basic_green'>Gi\u1ea3i<\/span><br\/><span class='basic_left'> $\\begin{aligned} A &=({{x}^{3}}{{y}^{3}}-9{{x}^{6}}{{y}^{5}}+12{{x}^{3}}{{y}^{3}}):3{{x}^{3}}{{y}^{3}} \\\\ & =\\dfrac{1}{3}-3{{x}^{3}}{{y}^{2}}+4 \\\\ & =-3{{x}^{3}}{{y}^{2}}+\\dfrac{13}{3} \\\\ & Do\\,\\,\\left\\{ \\begin{aligned} & -3{{x}^{3}}{{y}^{3}}\\,\\,\\vdots \\,\\,xy \\\\ & \\dfrac{13}{3}\\,\\,\\,\\not\\vdots \\,\\,xy \\\\ \\end{aligned} \\right.\\,\\,\\,\\\\&\\Rightarrow \\left( -3{{x}^{3}}{{y}^{2}}+\\dfrac{13}{3} \\right)\\,\\,\\,\\not\\vdots \\,\\,xy\\\\& \\Rightarrow A\\,\\,\\,\\not\\vdots \\,\\,\\,B \\\\ \\end{aligned}$ <span><br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 Sai.<\/span>","column":2}]}],"id_ques":764},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":10,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai8/lv3/img\/12.jpg' \/><\/center> T\u00ecm $n \\in \\mathbb{N}$ \u0111\u1ec3 ph\u00e9p chia sau l\u00e0 ph\u00e9p chia h\u1ebft.<br\/> $\\left( {{x}^{n-2}}{{y}^{7}}+{{x}^{5}}{{y}^{2n-3}} \\right):{{x}^{3}}{{y}^{n+2}}$ ","select":["A. $n=7$ ","B. $n=6$","C. $n=5$","D. $n=4$"],"hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn<\/span><br\/> Cho t\u1eebng h\u1ea1ng t\u1eed c\u1ee7a \u0111a th\u1ee9c chia h\u1ebft cho cho \u0111\u01a1n th\u1ee9c \u0111\u1ec3 t\u00ecm $n$. <br\/> <b> Quy t\u1eafc:<\/b> \u0110\u1ec3 $ax^my^n$ chia h\u1ebft cho $bx^py^q$ th\u00ec $\\left\\{ \\begin{align} & m\\ge p \\\\ & n\\ge q \\\\ \\end{align} \\right.$ <br\/> N\u1ebfu $a\\,\\vdots\\, m; b\\,\\vdots\\,m$ th\u00ec $(a+b)\\,\\vdots\\,m$<br\/> N\u1ebfu $a\\,\\vdots\\, m; b\\,\\not\\vdots\\,m$ th\u00ec $(a+b)\\,\\not\\vdots\\,m$ <br\/><span class='basic_green'>Gi\u1ea3i<\/span><br\/><span class='basic_left'>\u0110\u1ec3 $\\left( {{x}^{n-2}}{{y}^{7}}+{{x}^{5}}{{y}^{2n-3}} \\right):{{x}^{3}}{{y}^{n+2}}$ l\u00e0 ph\u00e9p chia h\u1ebft th\u00ec <br\/> $ \\left\\{ \\begin{aligned} & {{x}^{n-2}}{{y}^{7}}\\,\\,\\vdots \\,\\,{{x}^{3}}{{y}^{n+2}} \\\\ & {{x}^{5}}{{y}^{2n-3}}\\,\\,\\,\\vdots \\,\\,\\,{{x}^{3}}{{y}^{n+2}} \\\\ \\end{aligned} \\right.$$ \\Leftrightarrow \\left\\{ \\begin{aligned} & n-2\\ge 3 \\\\ & 7\\ge n+2 \\\\ & 2n-3\\ge n+2 \\\\ \\end{aligned} \\right. \\Leftrightarrow \\left\\{ \\begin{aligned} & n\\ge 5 \\\\ & n\\le 5 \\\\ & n\\ge 5 \\\\ \\end{aligned} \\right. \\Leftrightarrow n=5$ v\u1edbi $n \\in \\mathbb{N}$ <span><br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span>","column":2}]}],"id_ques":765},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":10,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai8/lv3/img\/12.jpg' \/><\/center> T\u00ecm $n \\in \\mathbb{N}$ \u0111\u1ec3 ph\u00e9p chia sau l\u00e0 ph\u00e9p chia h\u1ebft.<br\/> $(3x^{n-1}y^6-5x^{n+1}y^4):2x^3y^n$ ","select":["A. $n=3$ ","B. $n=6$","C. $n=5$","D. $n=4$"],"hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn<\/span><br\/> L\u1ea5y t\u1eebng h\u1ea1ng t\u1eed c\u1ee7a \u0111a th\u1ee9c chia cho \u0111\u01a1n th\u1ee9c \u0111\u1ec3 t\u00ecm $n$. <br\/> <b> Quy t\u1eafc:<\/b> \u0110\u1ec3 $ax^my^n$ chia h\u1ebft cho $bx^py^q$ th\u00ec $\\left\\{ \\begin{align} & m\\ge p \\\\ & n\\ge q \\\\ \\end{align} \\right.$ <br\/> N\u1ebfu $a\\,\\vdots\\, m; b\\,\\vdots\\,m$ th\u00ec $(a+b)\\,\\vdots\\,m$<br\/> N\u1ebfu $a\\,\\vdots\\, m; b\\,\\not\\vdots\\,m$ th\u00ec $(a+b)\\,\\not\\vdots\\,m$ <br\/><span class='basic_green'>Gi\u1ea3i<\/span><br\/><span class='basic_left'>\u0110\u1ec3 $(3x^{n-1}y^6-5x^{n+1}y^4):2x^3y^n$ l\u00e0 ph\u00e9p chia h\u1ebft th\u00ec <br\/> $ \\left\\{ \\begin{aligned} & 3x^{n-1}y^6\\,\\,\\vdots \\,2x^3y^n \\\\ & 5x^{n+1}y^4\\,\\,\\,\\vdots \\,\\,2x^3y^n\\, \\\\ \\end{aligned} \\right.\\Rightarrow \\left\\{ \\begin{aligned} & n-1\\ge 3 \\\\ & 6\\ge n \\\\ & n+1\\ge 3 \\\\ & 4\\ge n \\\\\\end{aligned} \\right.$$\\Rightarrow 4\\le n\\le 4 \\Rightarrow n=4$ v\u1edbi $n\\in \\mathbb{N}$ <span><br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span>","column":2}]}],"id_ques":766},{"time":24,"part":[{"title":"\u0110i\u1ec1n k\u1ebft qu\u1ea3 v\u00e0o \u00f4 tr\u1ed1ng ","title_trans":"","temp":"fill_the_blank","correct":[[["-6048"]]],"list":[{"point":10,"width":40,"type_input":"","ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai8/lv3/img\/11.jpg' \/><\/center> Gi\u00e1 tr\u1ecb c\u1ee7a bi\u1ec3u th\u1ee9c $\\left( {{a}^{2}}b-3a{{b}^{2}} \\right):\\dfrac{1}{2}ab$$+\\left( 6{{b}^{3}}-5a{{b}^{2}} \\right):{{b}^{2}}$ t\u1ea1i $a = b = 2016$ l\u00e0 _input_","hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> B\u01b0\u1edbc 1:<\/b> T\u00ecm k\u1ebft qu\u1ea3 c\u1ee7a ph\u00e9p chia \u0111\u00e3 cho: chia \u0111a th\u1ee9c cho \u0111\u01a1n th\u1ee9c.<br\/> <b> B\u01b0\u1edbc 2:<\/b> Thay $a = b = 2016$ v\u00e0o \u0111\u1ec3 t\u00ednh gi\u00e1 tr\u1ecb bi\u1ec3u th\u1ee9c. <br\/><span class='basic_green'>B\u00e0i gi\u1ea3i<\/span><br\/> $ \\left( {{a}^{2}}b-3a{{b}^{2}} \\right):\\dfrac{1}{2}ab+\\left( 6{{b}^{3}}-5a{{b}^{2}} \\right):{{b}^{2}} $<br\/>$ =2a-6b+6b-5a $<br\/>$ =-3a $ <br\/> Thay $a = b = 2016$ v\u00e0o ta \u0111\u01b0\u1ee3c: <br\/> $-3a=-3.2016=-6048$ <br\/> <span class='basic_pink'> Do \u0111\u00f3 s\u1ed1 ph\u1ea3i \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $-6048$. <\/span><\/span> "}]}],"id_ques":767},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":10,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai8/lv3/img\/8.jpg' \/><\/center> K\u1ebft qu\u1ea3 ph\u00e9p chia $\\left( 2016{{x}^{2016}}-2015{{x}^{2015}} \\right):{{x}^{2015}}$ l\u00e0: ","select":["A. $x^2-2015$ ","B. $2016x$ ","C. $x-2015$","D. $2016x-2015$"],"hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn<\/span><br\/> <b> Quy t\u1eafc chia \u0111a th\u1ee9c $A$ cho \u0111\u01a1n th\u1ee9c $B$<\/b>: Chia m\u1ed7i h\u1ea1ng t\u1eed c\u1ee7a $A$ cho $B$ r\u1ed3i c\u1ed9ng c\u00e1c k\u1ebft qu\u1ea3 v\u1edbi nhau.<br\/> <b> Quy t\u1eafc: Chia \u0111\u01a1n th\u1ee9c $A$ cho \u0111\u01a1n th\u1ee9c $B$<\/b> <br\/>+ Chia h\u1ec7 s\u1ed1 c\u1ee7a \u0111\u01a1n th\u1ee9c $A$ cho h\u1ec7 s\u1ed1 c\u1ee7a \u0111\u01a1n th\u1ee9c $B$.<br\/> + Chia t\u1eebng l\u0169y th\u1eeba c\u1ee7a bi\u1ebfn trong $A$ cho l\u0169y th\u1eeba c\u1ee7a c\u00f9ng bi\u1ebfn \u0111\u00f3 trong $B$. <br\/><span class='basic_green'>Gi\u1ea3i<\/span><br\/><span class='basic_left'>Ta c\u00f3 :<br\/> $\\begin{align} & \\left( 2016{{x}^{2016}}-2015{{x}^{2015}} \\right):{{x}^{2015}} \\\\ & =2016{{x}^{2016}}:{{x}^{2015}}-2015{{x}^{2015}}:{{x}^{2015}} \\\\ & =2016x-2015 \\\\ \\end{align}$ <span><br\/> <span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span>","column":2}]}],"id_ques":768},{"time":24,"part":[{"title":"Ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"select":["A. $6u^3 + 8v - 18uv $","B. $6u^3 + 8v - 8uv$","C. $6u^3 + 8v + 18uv$"],"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai8/lv3/img\/4.jpg' \/><\/center> K\u1ebft qu\u1ea3 ph\u00e9p chia <br\/> $\\left( 3{{u}^{5}}{{v}^{2}}+4{{u}^{2}}{{v}^{3}}-9{{u}^{3}}{{v}^{3}} \\right):\\dfrac{1}{2}{{u}^{2}}{{v}^{2}}$= ?","hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> Quy t\u1eafc chia \u0111a th\u1ee9c $A$ cho \u0111\u01a1n th\u1ee9c $B$<\/b>: Chia m\u1ed7i h\u1ea1ng t\u1eed c\u1ee7a $A$ cho $B$ r\u1ed3i c\u1ed9ng c\u00e1c k\u1ebft qu\u1ea3 v\u1edbi nhau.<br\/> <b> Quy t\u1eafc: Chia \u0111\u01a1n th\u1ee9c $A$ cho \u0111\u01a1n th\u1ee9c $B$<\/b> <br\/>+ Chia h\u1ec7 s\u1ed1 c\u1ee7a \u0111\u01a1n th\u1ee9c $A$ cho h\u1ec7 s\u1ed1 c\u1ee7a \u0111\u01a1n th\u1ee9c $B$.<br\/> + Chia t\u1eebng l\u0169y th\u1eeba c\u1ee7a bi\u1ebfn trong $A$ cho l\u0169y th\u1eeba c\u1ee7a c\u00f9ng bi\u1ebfn \u0111\u00f3 trong $B$. <br\/><span class='basic_green'>B\u00e0i gi\u1ea3i<\/span><br\/><b> $ \\left( 3{{u}^{5}}{{v}^{2}}+4{{u}^{2}}{{v}^{3}}-9{{u}^{3}}{{v}^{3}} \\right):\\dfrac{1}{2}{{u}^{2}}{{v}^{2}}$<br\/>$ =3{{u}^{5}}{{v}^{2}}:\\dfrac{1}{2}{{u}^{2}}{{v}^{2}}+4{{u}^{2}}{{v}^{3}}:\\dfrac{1}{2}{{u}^{2}}{{v}^{2}}-9{{u}^{3}}{{v}^{3}}:\\dfrac{1}{2}{{u}^{2}}{{v}^{2}} $<br\/>$ =6{{u}^{3}}+8v-18uv $<\/span> "}]}],"id_ques":769},{"time":24,"part":[{"title":"Ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"select":["A. $x^3y^3-4x^2y^2z^4$","B. $2x^3y^3-4x^2y^2z^4$","C. $-2x^3y^3-4x^2y^2z^4$"],"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai8/lv3/img\/2.jpg' \/><\/center>K\u1ebft qu\u1ea3 ph\u00e9p chia <br\/> $\\left( 6{{x}^{4}}{{y}^{5}}{{z}^{2}}+12{{x}^{3}}{{y}^{4}}{{z}^{6}} \\right):\\left( -3x{{y}^{2}}{{z}^{2}} \\right)$ =?","hint":"","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<\/span><br\/> <b> Quy t\u1eafc chia \u0111a th\u1ee9c $A$ cho \u0111\u01a1n th\u1ee9c $B$<\/b>: Chia m\u1ed7i h\u1ea1ng t\u1eed c\u1ee7a $A$ cho $B$ r\u1ed3i c\u1ed9ng c\u00e1c k\u1ebft qu\u1ea3 v\u1edbi nhau.<br\/> <b> Quy t\u1eafc: Chia \u0111\u01a1n th\u1ee9c $A$ cho \u0111\u01a1n th\u1ee9c $B$<\/b> <br\/>+ Chia h\u1ec7 s\u1ed1 c\u1ee7a \u0111\u01a1n th\u1ee9c $A$ cho h\u1ec7 s\u1ed1 c\u1ee7a \u0111\u01a1n th\u1ee9c $B$.<br\/> + Chia t\u1eebng l\u0169y th\u1eeba c\u1ee7a bi\u1ebfn trong $A$ cho l\u0169y th\u1eeba c\u1ee7a c\u00f9ng bi\u1ebfn \u0111\u00f3 trong $B$. <br\/><span class='basic_green'>B\u00e0i gi\u1ea3i<\/span><br\/><b> $ \\left( 6{{x}^{4}}{{y}^{5}}{{z}^{2}}+12{{x}^{3}}{{y}^{4}}{{z}^{6}} \\right):\\left( -3x{{y}^{2}}{{z}^{2}} \\right) $<br\/>$ =6{{x}^{4}}{{y}^{5}}{{z}^{2}}:\\left( -3x{{y}^{2}}{{z}^{2}} \\right)+12{{x}^{3}}{{y}^{4}}{{z}^{6}}:\\left( -3x{{y}^{2}}{{z}^{2}} \\right) $<br\/>$ =-2{{x}^{3}}{{y}^{3}}-4{{x}^{2}}{{y}^{2}}{{z}^{4}} $<\/span> "}]}],"id_ques":770}],"lesson":{"save":0,"level":3}}