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{"segment":[{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"\u0110\u1ec1 chung cho ba c\u00e2u","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"<span class='basic_left'>V\u1edbi $x \\ge 0$ v\u00e0 $x \\ne 9$. Cho bi\u1ec3u th\u1ee9c: <br\/>$M= \\left( \\dfrac{1}{\\sqrt{x}+3}+\\dfrac{\\sqrt{x}+9}{x-9} \\right).\\dfrac{\\sqrt{x}}{2}$<br\/><b> C\u00e2u 1: <\/b> R\u00fat g\u1ecdn $M$ \u0111\u01b0\u1ee3c k\u1ebft qu\u1ea3 l\u00e0:<\/span> ","select":["A. $\\dfrac{\\sqrt{x}}{2(\\sqrt{x}+3)}$ ","B. $\\dfrac{\\sqrt{x}}{2(\\sqrt{x}-3)}$","C. $\\dfrac{\\sqrt{x}}{\\sqrt{x}+3}$","D. $\\dfrac{\\sqrt{x}}{\\sqrt{x}-3}$"],"hint":"Quy \u0111\u1ed3ng c\u00e1c ph\u00e2n th\u1ee9c trong ngo\u1eb7c v\u00e0 r\u00fat g\u1ecdn","explain":"<span class='basic_left'>V\u1edbi $x \\ge 0$ v\u00e0 $x \\ne 9$. Ta c\u00f3:<br\/>$\\begin{align} M&= \\left( \\dfrac{1}{\\sqrt{x}+3}+\\dfrac{\\sqrt{x}+9}{x-9} \\right).\\dfrac{\\sqrt{x}}{2} \\\\ & =\\left[ \\dfrac{\\sqrt{x}-3+\\sqrt{x}+9}{\\left( \\sqrt{x}-3 \\right)\\left( \\sqrt{x}+3 \\right)} \\right].\\dfrac{\\sqrt{x}}{2} \\\\ & =\\dfrac{2\\sqrt{x}+6}{\\left( \\sqrt{x}-3 \\right)\\left( \\sqrt{x}+3 \\right)}.\\dfrac{\\sqrt{x}}{2} \\\\ & =\\dfrac{2\\left( \\sqrt{x}+3 \\right)}{\\left( \\sqrt{x}-3 \\right)\\left( \\sqrt{x}+3 \\right)}.\\dfrac{\\sqrt{x}}{2} \\\\ & =\\dfrac{\\sqrt{x}}{\\sqrt{x}-3} \\\\ \\end{align}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 D<\/span>","column":2}]}],"id_ques":711},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng ","title_trans":"\u0110\u1ec1 chung cho ba c\u00e2u","temp":"fill_the_blank","correct":[[["-2"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"<span class='basic_left'>V\u1edbi $x \\ge 0$ v\u00e0 $x \\ne 9$. Cho bi\u1ec3u th\u1ee9c: <br\/>$\\, M= \\left( \\dfrac{1}{\\sqrt{x}+3}+\\dfrac{\\sqrt{x}+9}{x-9} \\right).\\dfrac{\\sqrt{x}}{2}$<br\/><b> C\u00e2u 2: <\/b> V\u1edbi $x= 4$ th\u00ec $M=$_input_<\/span>","hint":"Thay $x= 4$ v\u00e0o bi\u1ec3u th\u1ee9c $M$","explain":"<span class='basic_left'>Theo c\u00e2u 1, v\u1edbi $x \\ge 0$ v\u00e0 $x \\ne 9$. Ta c\u00f3:<br\/> $M=\\dfrac{\\sqrt{x}}{\\sqrt{x}-3}$<br\/>Thay $ x=4$ v\u00e0o bi\u1ec3u th\u1ee9c $M$ ta c\u00f3:<br\/> $M=\\dfrac{\\sqrt{4}}{\\sqrt{4}-3}=\\dfrac{2}{2-3}=-2$ <br\/>V\u1eady $x=4$ th\u00ec $M= -2$ <br\/> <span class='basic_pink'>V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $-2$<\/span><\/span>"}]}],"id_ques":712},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng ","title_trans":"","temp":"fill_the_blank_random","correct":[[["0"],["4"],["16"],["36"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"<span class='basic_left'>V\u1edbi $x\\ge 0$ v\u00e0 $x \\ne 9$. Cho bi\u1ec3u th\u1ee9c: <br\/>$M= \\left( \\dfrac{1}{\\sqrt{x}+3}+\\dfrac{\\sqrt{x}+9}{x-9} \\right).\\dfrac{\\sqrt{x}}{2}$<br\/><b> C\u00e2u 3: <\/b> T\u00ecm $x\\in \\mathbb Z $ \u0111\u1ec3 $M \\in \\mathbb Z$<br\/>\u0110\u00e1p \u00e1n: $x\\in$ {_input_;_input_;_input_;_input_} <br\/> $\\,\\,\\,$(C\u00e1c gi\u00e1 tr\u1ecb c\u1ee7a $x$ vi\u1ebft theo th\u1ee9 t\u1ef1 t\u0103ng d\u1ea7n)<\/span>","hint":"Bi\u1ebfn \u0111\u1ed5i bi\u1ec3u th\u1ee9c v\u1ec1 d\u1ea1ng: $m+\\dfrac {n}{f(x)}$ v\u1edbi $m,n \\in \\mathbb Z$","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<br\/><\/span>B\u01b0\u1edbc 1: T\u00ecm \u0111i\u1ec1u ki\u1ec7n x\u00e1c \u0111\u1ecbnh c\u1ee7a bi\u1ec3u th\u1ee9c.<br\/>B\u01b0\u1edbc 2: Bi\u1ebfn \u0111\u1ed5i bi\u1ec3u th\u1ee9c v\u1ec1 d\u1ea1ng: $m+\\dfrac {n}{f(x)}$ v\u1edbi $m,n \\in \\mathbb Z$<br\/>B\u01b0\u1edbc 3: T\u00ecm $x$ th\u1ecfa m\u00e3n $f(x)\\in \u01af(n)$<br\/>B\u01b0\u1edbc 4: T\u00ecm $x$ v\u00e0 so s\u00e1nh v\u1edbi \u0111i\u1ec1u ki\u1ec7n v\u00e0 k\u1ebft lu\u1eadn <br\/><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/><span class='basic_left'> Theo c\u00e2u 1, v\u1edbi $x \\ge 0$ v\u00e0 $x \\ne 9$. Ta c\u00f3:<br\/> $M=\\dfrac{\\sqrt{x}}{\\sqrt{x}-3}$<br\/>$M=\\dfrac{\\sqrt{x}}{\\sqrt{x}-3}=1+\\dfrac{3}{\\sqrt{x}-3}$ <br\/>$M\\in \\mathbb Z\\Leftrightarrow 1+\\dfrac{3}{\\sqrt{x}-3}\\in \\mathbb Z\\,$$\\Leftrightarrow \\dfrac{3}{\\sqrt{x}-3}\\in \\mathbb Z$ <br\/>$\\Leftrightarrow \\sqrt{x}-3$ thu\u1ed9c $\u01af(3)=\\{\\pm 1;\\pm 3 \\}$<br\/>Ta c\u00f3 b\u1ea3ng sau:<br\/><table> <tr> <th>$\\sqrt{x}-3$<\/th> <th>$-3$<\/th> <th>$-1$<\/th> <th>$1$<\/th> <th>$3$<\/th> <\/tr> <tr> <td>$\\sqrt{x}$<\/td> <td>$0$<\/td> <td>$2$<\/td> <td>$4$<\/td> <td>$6$<\/td> <\/tr> <tr> <td>$x$<\/td> <td>$0$<\/td> <td>$4$<\/td> <td>$16$<\/td> <td>$36$<\/td> <\/tr><\/table><br\/>K\u1ebft h\u1ee3p v\u1edbi \u0111i\u1ec1u ki\u1ec7n $x \\ge 0$ v\u00e0 $x \\ne 9$, suy ra: $x\\in\\{0,4,16,36\\}$<br\/> <span class='basic_pink'>V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $0;4;16;36$<\/span><\/span><\/span>"}]}],"id_ques":713},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"R\u00fat g\u1ecdn bi\u1ec3u th\u1ee9c $2{{y}^{2}}\\sqrt{\\dfrac{{{x}^{4}}}{4{{y}^{2}}}}$ v\u1edbi $y < 0$ \u0111\u01b0\u1ee3c k\u1ebft qu\u1ea3 l\u00e0: ","select":["A. $\u2013 xy^2$ ","B. $\\dfrac{{{y}^{2}}{{x}^{2}}}{\\left| y \\right|}$","C. $-x^2y$","D. $\\sqrt{{{y}^{2}}{{x}^{4}}}$"],"hint":"\u00c1p d\u1ee5ng v\u1edbi $A$ l\u00e0 m\u1ed9t bi\u1ec3u th\u1ee9c, ta c\u00f3 $\\sqrt{A^2}=|A|=\\left\\{ \\begin{align} & A\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\text{n\u1ebfu}\\,\\,{A}\\ge {0} \\\\ & -A\\,\\,\\,\\,\\text{n\u1ebfu}\\,\\,{A}<{0} \\\\\\end{align} \\right.$ ","explain":"<span class='basic_left'>Ta c\u00f3:<br\/>$2{{y}^{2}}\\sqrt{\\dfrac{{{x}^{4}}}{4{{y}^{2}}}}=2{{y}^{2}}\\sqrt{{{\\left( \\dfrac{{{x}^{2}}}{2y} \\right)}^{2}}}\\,$$=2{{y}^{2}}.\\left| \\dfrac{{{x}^{2}}}{2y} \\right|=2{{y}^{2}}.\\left( -\\dfrac{{{x}^{2}}}{2y} \\right)\\,$$=-{{x}^{2}}y$ (V\u00ec $y < 0$ n\u00ean $|y|=-y$)<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C<\/span>","column":2}]}],"id_ques":714},{"time":24,"part":[{"title":"Ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"select":["A. $\\sqrt{5}$","B. $2\\sqrt{5}$","C. $3\\sqrt{5}$","D. $4\\sqrt{5}$"],"ques":"R\u00fat g\u1ecdn bi\u1ec3u th\u1ee9c: <br\/>$\\sqrt{{{\\left( \\sqrt{6}+\\sqrt{5} \\right)}^{2}}}-\\sqrt{{{\\left( \\sqrt{6}-\\sqrt{5} \\right)}^{2}}} = ?$","hint":"\u00c1p d\u1ee5ng h\u1eb1ng \u0111\u1eb3ng th\u1ee9c $\\sqrt {A^2}=|A|$","explain":"<span class='basic_left'>Ta c\u00f3:<br\/>$\\begin{align} & \\,\\,\\,\\sqrt{{{\\left( \\sqrt{6}+\\sqrt{5} \\right)}^{2}}}-\\sqrt{{{\\left( \\sqrt{6}-\\sqrt{5} \\right)}^{2}}} \\\\ & =\\left| \\sqrt{6}+\\sqrt{5} \\right|-\\left| \\sqrt{6}-\\sqrt{5} \\right| \\\\ & =\\sqrt{6}+\\sqrt{5}-\\left( \\sqrt{6}-\\sqrt{5} \\right)\\,\\,(V\u00ec\\,\\sqrt{6}>\\sqrt{5}) \\\\ & =\\sqrt{6}+\\sqrt{5}-\\sqrt{6}+\\sqrt{5} \\\\ & =2\\sqrt{5} \\\\ \\end{align}$ <br\/><span class='basic_pink'> V\u1eady \u0111\u00e1p \u00e1n c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $2\\sqrt{5}$<\/span><br\/><i>Ghi nh\u1edb:<\/i> V\u1edbi $A$ l\u00e0 m\u1ed9t bi\u1ec3u th\u1ee9c, ta c\u00f3 $\\sqrt{A^2}=|A|=\\left\\{ \\begin{align} & A\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\text{n\u1ebfu}\\,\\,{A}\\ge {0} \\\\ & -A\\,\\,\\,\\,\\text{n\u1ebfu}\\,\\,{A}<{0} \\\\\\end{align} \\right.$<\/span> "}]}],"id_ques":715},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng ","title_trans":"","temp":"fill_the_blank","correct":[[["-6"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"Th\u1ef1c hi\u1ec7n ph\u00e9p t\u00ednh: <br\/>$\\,\\dfrac{4}{1+\\sqrt{3}}-\\dfrac{2}{2-\\sqrt{3}} =$_input_","hint":"Tr\u1ee5c c\u0103n th\u1ee9c \u1edf m\u1eabu","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<br\/><\/span>B\u01b0\u1edbc 1: Tr\u1ee5c c\u0103n th\u1ee9c \u1edf m\u1eabu<br\/>V\u1edbi c\u00e1c bi\u1ec3u th\u1ee9c $A, B, C$ m\u00e0 $A\\ge0$ v\u00e0 $A\\ne {{B}^{2}}$ ta c\u00f3: $\\,\\,\\dfrac{C}{\\sqrt{A}\\pm B}=\\dfrac{C\\left( \\sqrt{A}\\mp B \\right)}{A-{{B}^{2}}}$ <br\/>B\u01b0\u1edbc 2: C\u1ed9ng tr\u1eeb c\u00e1c c\u0103n th\u1ee9c \u0111\u1ed3ng d\u1ea1ng<br\/><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/>Ta c\u00f3:<br\/>$\\begin{align} & \\,\\,\\,\\,\\dfrac{4}{1+\\sqrt{3}}-\\dfrac{2}{2-\\sqrt{3}} \\\\ & =\\dfrac{4(\\sqrt{3}-1)}{\\sqrt{{{3}^{2}}}-1}-\\dfrac{2(2+\\sqrt{3})}{4-\\sqrt{{{3}^{2}}}} \\\\ & =\\dfrac{4(\\sqrt{3}-1)}{2}-\\dfrac{2(2+\\sqrt{3})}{1} \\\\ & =2\\sqrt{3}-2-4-2\\sqrt{3} \\\\ & =-6 \\\\\\end{align}$ <br\/> <span class='basic_pink'>V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $-6$<\/span> <\/span><\/span>"}]}],"id_ques":716},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng ","title_trans":"","temp":"fill_the_blank","correct":[[["5"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai7/lv1/img\/4.jpg' \/><\/center>T\u00ednh: $\\,\\,\\,\\dfrac{\\sqrt{275}}{\\sqrt{11}}=$_input_","hint":"\u00c1p d\u1ee5ng v\u1edbi $a \\ge 0$ v\u00e0 $b> 0$ ta c\u00f3 $\\dfrac{\\sqrt{a}}{\\sqrt{b}}=\\sqrt{\\dfrac{a}{b}}$","explain":"<span class='basic_left'>Ta c\u00f3:<br\/>$\\dfrac{\\sqrt{275}}{\\sqrt{11}}$ = $\\sqrt{\\dfrac{275}{11}}=\\sqrt{25}=5$ <br\/> <span class='basic_pink'>V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $5$<\/span><\/span>"}]}],"id_ques":717},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng ","title_trans":"","temp":"fill_the_blank","correct":[[["1"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"T\u00ednh gi\u00e1 tr\u1ecb bi\u1ec3u th\u1ee9c:<br\/>$C=\\sqrt[3]{\\sqrt{5}+2}.\\sqrt[3]{\\sqrt{5}-2}$ <br\/> <b> \u0110\u00e1p \u00e1n: <\/b> $C=\\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{} $","hint":"\u00c1p d\u1ee5ng: $\\sqrt[3]{a}.\\sqrt[3]{b}=\\sqrt[3]{ab}$","explain":"<span class='basic_left'>Ta c\u00f3:<br\/>$C=\\sqrt[3]{\\sqrt{5}+2}.\\sqrt[3]{\\sqrt{5}-2}\\,$<br\/>$=\\sqrt[3]{\\left( \\sqrt{5}+2 \\right)\\left( \\sqrt{5}-2 \\right)}\\,$<br\/>$=\\sqrt[3]{5-4}$<br\/>$=1$ <br\/> <span class='basic_pink'>V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $1$<\/span><\/span>"}]}],"id_ques":718},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng ","title_trans":"","temp":"fill_the_blank","correct":[[["61"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai7/lv1/img\/9.jpg' \/><\/center><br\/>Gi\u1ea3i ph\u01b0\u01a1ng tr\u00ecnh $\\sqrt[3]{2x+3}=5$<br\/>T\u1eadp nghi\u1ec7m c\u1ee7a ph\u01b0\u01a1ng tr\u00ecnh l\u00e0 $S= ${_input_}","hint":"L\u1eadp ph\u01b0\u01a1ng hai v\u1ebf","explain":"<span class='basic_left'>Ta c\u00f3:<br\/>$\\begin{align}&\\sqrt[3]{2x+3}\\,\\,=5\\\\&\\Leftrightarrow 2x+3=125\\\\&\\Leftrightarrow2x=122 \\\\&\\Leftrightarrow x\\,\\,\\,=61\\\\\\end{align}$<br\/>T\u1eadp nghi\u1ec7m c\u1ee7a ph\u01b0\u01a1ng tr\u00ecnh l\u00e0 $S=\\{61\\}$ <br\/> <span class='basic_pink'>V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $61$<\/span><\/span>"}]}],"id_ques":719},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng ","title_trans":"","temp":"fill_the_blank_random","correct":[[["-1"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"T\u00ednh gi\u00e1 tr\u1ecb bi\u1ec3u th\u1ee9c:<br\/>$A =2x-\\sqrt{{{x}^{2}}+x+\\dfrac{1}{4}}$ t\u1ea1i $x=-\\dfrac{1}{2}$<br\/>\u0110\u00e1p s\u1ed1: $A=\\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{} $","hint":"\u0110\u01b0a bi\u1ec3u th\u1ee9c trong c\u0103n v\u1ec1 d\u1ea1ng $(A+B)^2$","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<br\/><\/span>B\u01b0\u1edbc 1: \u0110\u01b0a bi\u1ec3u th\u1ee9c ${x}^{2}+x+\\dfrac{1}{4}$ v\u1ec1 d\u1ea1ng $(a + b)^2$<br\/>B\u01b0\u1edbc 2: \u00c1p d\u1ee5ng $\\sqrt {A^2}=|A|$ \u0111\u1ec3 khai c\u0103n<br\/>B\u01b0\u1edbc 3: Thay $x$ v\u00e0o bi\u1ec3u th\u1ee9c $A$<br\/><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/>$\\begin{align} A & =2x-\\sqrt{{{x}^{2}}+x+\\dfrac{1}{4}} \\\\ & =2x-\\sqrt{{{\\left( x+\\dfrac{1}{2} \\right)}^{2}}} \\\\ & =2x-\\left| x+\\dfrac{1}{2} \\right| \\\\ \\end{align}$ <br\/>Thay $x=-\\dfrac{1}{2}$ v\u00e0o bi\u1ec3u th\u1ee9c $A$ ta c\u00f3:<br\/>$A=2.\\left( -\\dfrac{1}{2} \\right)-\\left| -\\dfrac{1}{2}+\\dfrac{1}{2} \\right|=-1$ <br\/> <span class='basic_pink'>V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $-1$<\/span><\/span><\/span>"}]}],"id_ques":720},{"time":24,"part":[{"title":"Kh\u1eb3ng \u0111\u1ecbnh sau \u0111\u00fang hay sai","title_trans":"","temp":"true_false","correct":[["f","t","t"]],"list":[{"point":5,"image":"https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai7/lv1/img\/1.png","col_name":["","\u0110\u00fang","Sai"],"arr_ques":["C\u0103n b\u1eadc hai c\u1ee7a $16$ l\u00e0 $4$ ","V\u1edbi hai s\u1ed1 $a$ v\u00e0 $b$ kh\u00f4ng \u00e2m, n\u1ebfu $a < b$ th\u00ec $\\sqrt{a}<\\sqrt{b}$","$\\sqrt{x+1}$ x\u00e1c \u0111\u1ecbnh khi $x \\ge - 1$"],"hint":"D\u1ef1a v\u00e0o \u0111\u1ecbnh ngh\u0129a v\u00e0 t\u00ednh ch\u1ea5t c\u1ee7a c\u0103n b\u1eadc hai","explain":["Sai ,v\u00ec $16$ c\u00f3 hai c\u0103n b\u1eadc hai l\u00e0 $4$ v\u00e0 $-4$","<br\/>\u0110\u00fang, v\u00ec v\u1edbi hai s\u1ed1 $a$ v\u00e0 $b$ kh\u00f4ng \u00e2m, n\u1ebfu a $< b$ th\u00ec $\\sqrt{a}<\\sqrt{b}$","<br\/>\u0110\u00fang, v\u00ec \u0111i\u1ec1u ki\u1ec7n: $x+1 \\ge \\Leftrightarrow x \\ge -1$"]}]}],"id_ques":721},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"T\u1eadp nghi\u1ec7m c\u1ee7a ph\u01b0\u01a1ng tr\u00ecnh $\\sqrt{\\dfrac{x}{9}}-\\sqrt{4x}=-5$ l\u00e0: ","select":["A. $S=\\{9\\}$","B. $S=\\{\\sqrt{3}\\}$","C. $S=\\{3\\}$","D. $S=\\left\\{\\dfrac{9}{7}\\right\\}$"],"hint":"\u00c1p d\u1ee5ng: Quy t\u1eafc \u0111\u01b0a th\u1eeba s\u1ed1 ra ngo\u00e0i d\u1ea5u c\u0103n ","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<br\/><\/span>B\u01b0\u1edbc 1: T\u00ecm \u0111i\u1ec1u ki\u1ec7n ph\u01b0\u01a1ng tr\u00ecnh c\u00f3 ngh\u0129a<br\/>B\u01b0\u1edbc 2: Bi\u1ebfn \u0111\u1ed5i ph\u01b0\u01a1ng tr\u00ecnh v\u1ec1 d\u1ea1ng $\\sqrt{A}=B\\Leftrightarrow A=B^2$ v\u00e0 gi\u1ea3i ph\u01b0\u01a1ng tr\u00ecnh.<br\/><span class='basic_green'>B\u00e0i gi\u1ea3i:<br\/><\/span>\u0110i\u1ec1u ki\u1ec7n: $x\\ge 0$<br\/>Ta c\u00f3:<br\/>$\\begin{align} & \\,\\,\\,\\sqrt{\\dfrac{x}{9}}-\\sqrt{4x}=\\,\\,-5 \\\\ & \\Leftrightarrow \\dfrac{\\sqrt{x}}{3}-2\\sqrt{x}=-5 \\\\ & \\Leftrightarrow -5\\sqrt{x}\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,\\,=-15 \\\\ & \\Leftrightarrow \\sqrt{x}=3 \\\\ & \\Leftrightarrow x\\,\\,\\,\\,\\,=9 \\\\ \\end{align}$ <br\/>V\u1eady ph\u01b0\u01a1ng tr\u00ecnh c\u00f3 t\u1eadp nghi\u1ec7m $S=\\{9\\}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A<\/span><\/span>","column":2}]}],"id_ques":722},{"time":24,"part":[{"title":"Ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"select":["A. $2\\sqrt{x}$","B. $\\sqrt{x}$","C. $-\\sqrt{x}$"],"ques":"<span class='basic_left'>Cho bi\u1ec3u th\u1ee9c $P =\\left( \\dfrac{\\sqrt{x}}{\\sqrt{x}-4}+\\dfrac{\\sqrt{x}}{\\sqrt{x}+4} \\right):\\dfrac{2\\sqrt{x}}{x-16}$ (v\u1edbi $x>0$ v\u00e0 $x\\ne 16$)<br\/><b>C\u00e2u 1: <\/b>R\u00fat g\u1ecdn $P$<br\/>\u0110\u00e1p s\u1ed1:$P=$?<\/span>","hint":"R\u00fat g\u1ecdn bi\u1ec3u th\u1ee9c trong ngo\u1eb7c tr\u01b0\u1edbc: M\u1eabu th\u1ee9c chung $(\\sqrt{x}+4 )(\\sqrt{x}-4)$ ","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<br\/><\/span>B\u01b0\u1edbc 1: T\u00ecm \u0111i\u1ec1u ki\u1ec7n x\u00e1c \u0111\u1ecbnh c\u1ee7a $P$<br\/> B\u01b0\u1edbc 2: Ph\u00e2n t\u00edch m\u1eabu th\u1ee9c th\u00e0nh nh\u00e2n t\u1eed, quy \u0111\u1ed3ng v\u00e0 r\u00fat g\u1ecdn $P$ <br\/><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/>V\u1edbi $x>0$ v\u00e0 $x\\ne 16$ ta c\u00f3:<br\/>$\\left( \\dfrac{\\sqrt{x}}{\\sqrt{x}-4}+\\dfrac{\\sqrt{x}}{\\sqrt{x}+4} \\right):\\dfrac{2\\sqrt{x}}{x-16}$<br\/>$= \\left[ \\dfrac{\\sqrt{x}(\\sqrt{x}+4)}{(\\sqrt{x}-4)\\left( \\sqrt{x}+4 \\right)}+\\dfrac{\\sqrt{x}\\left( \\sqrt{x}-4 \\right)}{(\\sqrt{x}+4)\\left( \\sqrt{x}-4 \\right)} \\right]\\,$$:\\dfrac{2\\sqrt{x}}{x-16}$<br\/>$=\\left[ \\dfrac{\\sqrt{x}(\\sqrt{x}+4)+\\sqrt{x}\\left( \\sqrt{x}-4 \\right)}{(\\sqrt{x}-4)\\left( \\sqrt{x+4} \\right)} \\right]\\,$$:\\dfrac{2\\sqrt{x}}{x-16}$<br\/>$=\\dfrac{x+4\\sqrt{x}+x-4\\sqrt{x}}{x-16}.\\dfrac{x-16}{2\\sqrt{x}}$<br\/>$= \\dfrac{2x}{2\\sqrt{x}}=\\sqrt{x}$<\/span><\/span>"}]}],"id_ques":723},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng ","title_trans":"\u0110\u1ec1 chung cho hai c\u00e2u","temp":"fill_the_blank","correct":[[["4"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"<span class='basic_left'>Cho bi\u1ec3u th\u1ee9c $P = \\left( \\dfrac{\\sqrt{x}}{\\sqrt{x}-4}+\\dfrac{\\sqrt{x}}{\\sqrt{x}+4} \\right):\\dfrac{2\\sqrt{x}}{x-16}$ (v\u1edbi $x>0$ v\u00e0 $x \\ne 16$)<br\/><b> C\u00e2u 2: <\/b> V\u1edbi $P=2$ th\u00ec $x=$_input_<\/span>","hint":"Gi\u1ea3i ph\u01b0\u01a1ng tr\u00ecnh $P=2$","explain":"<span class='basic_left'>Theo c\u00e2u 1, v\u1edbi $x>0$ v\u00e0 $x \\ne 16$, ta c\u00f3: $P=\\sqrt{x}$ <br\/>Ta c\u00f3:<br\/>$P = 2 \\Leftrightarrow \\sqrt{x}=2\\Leftrightarrow x=4$ (th\u1ecfa m\u00e3n) <br\/> <span class='basic_pink'>V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $4$<\/span><\/span>"}]}],"id_ques":724},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"K\u1ebft qu\u1ea3 ph\u00e9p t\u00ednh $\\dfrac{2+\\sqrt{2}}{\\sqrt{2}+1}:\\dfrac{3-\\sqrt{3}}{\\sqrt{3}-1}$ l\u00e0: ","select":["A. $\\dfrac{\\sqrt{6}}{3}$ ","B. $\\dfrac{-3}{\\sqrt{6}}$","C. $\\dfrac{-\\sqrt{6}}{3}$","D. $\\dfrac{-\\sqrt{6}}{6}$ "],"hint":"Ph\u00e2n t\u00edch t\u1eed th\u1ee9c th\u00e0nh nh\u00e2n t\u1eed r\u1ed3i r\u00fat g\u1ecdn.","explain":"<span class='basic_left'>Ta c\u00f3:<br\/>$\\begin{align}&\\,\\,\\,\\,\\,\\dfrac{2+\\sqrt{2}}{\\sqrt{2}+1}:\\dfrac{3-\\sqrt{3}}{\\sqrt{3}-1}\\\\&=\\dfrac{\\sqrt{2}\\left( \\sqrt{2}+1 \\right)}{\\sqrt{2}+1}.\\dfrac{\\sqrt{3}-1}{\\sqrt{3}\\left( \\sqrt{3}-1 \\right)}\\\\&=\\dfrac{\\sqrt{2}}{\\sqrt{3}}\\\\ &=\\dfrac{\\sqrt{6}}{3}\\\\ \\end{align}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A<\/span>","column":2}]}],"id_ques":725},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"T\u00ecm $x$ \u0111\u1ec3 bi\u1ec3u th\u1ee9c $\\sqrt{\\dfrac{4}{-7+x}}$ c\u00f3 ngh\u0129a: ","select":["A. $x\\le 7$ ","B. $x\\ge 7$","C. $x > 7$","D. $x< 7$"],"hint":"$\\sqrt{\\dfrac{1}{A}}$ c\u00f3 ngh\u0129a $\\Leftrightarrow A > 0$ ","explain":"<span class='basic_left'>Ta c\u00f3:<br\/>\u0110i\u1ec1u ki\u1ec7n: $-7+x > 0 \\Leftrightarrow x > 7$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C<\/span>","column":2}]}],"id_ques":726},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang nh\u1ea5t","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"V\u1edbi $x\\ge 0$. K\u1ebft qu\u1ea3 ph\u00e2n t\u00edch $6-\\sqrt{x}+36-x$ th\u00e0nh nh\u00e2n t\u1eed l\u00e0: ","select":["A. $\\left( \\sqrt{x} -6\\right)\\left( 4+\\sqrt{x} \\right)$ ","B. $\\left( 6-\\sqrt{x} \\right)\\left( 4+\\sqrt{x} \\right)$","C. $\\left( \\sqrt{x}-6 \\right)\\left( 7+\\sqrt{x} \\right)$","D. $\\left( 6-\\sqrt{x} \\right)\\left( 7+\\sqrt{x} \\right)$"],"explain":"<span class='basic_left'>Ta c\u00f3:<br\/>$\\begin{align} & \\,\\,\\,\\,\\,6-\\sqrt{x}+36-x\\\\ & =\\left( 6-\\sqrt{x} \\right)+\\left( 6-\\sqrt{x} \\right)\\left( 6+\\sqrt{x} \\right) \\\\ & =\\left( 6-\\sqrt{x} \\right)\\left( 7+\\sqrt{x} \\right) \\\\\\end{align}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 D<\/span>","column":2}]}],"id_ques":727},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng ","title_trans":"","temp":"fill_the_blank_random","correct":[[["2","-1"],["-1","2"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"Gi\u1ea3i ph\u01b0\u01a1ng tr\u00ecnh: $\\sqrt{{{\\left( 2x-1 \\right)}^{2}}}=3$<br\/>T\u1eadp nghi\u1ec7m c\u1ee7a ph\u01b0\u01a1ng tr\u00ecnh l\u00e0 $S=${_input_;_input_}","hint":"\u0110\u01b0a th\u1eeba s\u1ed1 ra ngo\u00e0i d\u1ea5u c\u0103n \u1edf v\u1ebf tr\u00e1i c\u1ee7a ph\u01b0\u01a1ng tr\u00ecnh.","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<br\/><\/span>\u00c1p d\u1ee5ng h\u1eb1ng \u0111\u1eb3ng th\u1ee9c: $\\sqrt {A^2}=|A|$<br\/> Gi\u1ea3i ph\u01b0\u01a1ng tr\u00ecnh $|A| = 0$<br\/><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/>Ta c\u00f3:<br\/>$\\begin{align} & \\sqrt{{{\\left( 2x-1 \\right)}^{2}}}=3 \\\\ & \\Leftrightarrow \\left| 2x-1 \\right|=3 \\\\ & \\Leftrightarrow \\left[ \\begin{matrix} 2x-1=3 \\\\ 2x-1=-3 \\\\\\end{matrix} \\right. \\\\ & \\Leftrightarrow \\left[ \\begin{matrix} 2x=4 \\\\ 2x=-2 \\\\\\end{matrix} \\right. \\\\ & \\Leftrightarrow \\left[ \\begin{matrix} x=2 \\\\ x=-1 \\\\\\end{matrix} \\right. \\\\ \\end{align}$<br\/>T\u1eadp nghi\u1ec7m c\u1ee7a ph\u01b0\u01a1ng tr\u00ecnh l\u00e0 l\u00e0 $S=\\left\\{ 2;-1 \\right\\}$ <br\/> <span class='basic_pink'>V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $2; -1$<\/span><\/span><\/span>"}]}],"id_ques":728},{"time":24,"part":[{"title":"Ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"select":["A. $15\\sqrt{2}$","B. $12\\sqrt{2}$","C. $10\\sqrt{2}$"],"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai7/lv1/img\/2.jpg' \/><\/center> R\u00fat g\u1ecdn bi\u1ec3u th\u1ee9c sau:<br\/>$3\\sqrt{5}-\\sqrt{45}+3\\sqrt{18}+\\sqrt{72}$=?","hint":"\u00c1p d\u1ee5ng quy t\u1eafc \u0111\u01b0a th\u1eeba s\u1ed1 ra ngo\u00e0i d\u1ea5u c\u0103n ","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<br\/><\/span>B\u01b0\u1edbc 1: \u00c1p d\u1ee5ng quy t\u1eafc \u0111\u01b0a th\u1eeba s\u1ed1 ra ngo\u00e0i d\u1ea5u c\u0103n <br\/>V\u1edbi $B\\ge 0$ ta c\u00f3 $\\sqrt{{{A}^{2}}B}=\\left| A \\right|\\sqrt{B}\\,$$=\\left\\{ \\begin{align} & \\begin{matrix} \\,\\,\\,A\\sqrt{B} & \\text {n\u1ebfu}\\,\\,\\, A\\ge0 \\\\\\end{matrix} \\\\ & \\begin{matrix} -A\\sqrt{B} & \\text {n\u1ebfu} \\,\\,\\,A < 0 \\\\\\end{matrix} \\\\ \\end{align} \\right.$<br\/> B\u01b0\u1edbc 2: C\u1ed9ng tr\u1eeb c\u00e1c c\u0103n th\u1ee9c \u0111\u1ed3ng d\u1ea1ng <br\/><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/>Ta c\u00f3:<br\/>$\\begin{align} & \\,\\,\\,\\,\\,\\,3\\sqrt{5}-\\sqrt{45}+3\\sqrt{18}+\\sqrt{72} \\\\ & =3\\sqrt{5}-\\sqrt{9.5}+3\\sqrt{9.2}+\\sqrt{36.2} \\\\ & =3\\sqrt{5}-3\\sqrt{5}+9\\sqrt{2}+6\\sqrt{2} \\\\ & =15\\sqrt{2} \\\\ \\end{align}$<\/span><\/span>"}]}],"id_ques":729},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng ","title_trans":"","temp":"fill_the_blank_random","correct":[[["-1"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai7/lv1/img\/1.png' \/><\/center>T\u00ednh : $\\,\\,\\,\\sqrt[3]{-0,5}.\\sqrt[3]{1,25}.\\sqrt[3]{\\dfrac{16}{10}}$=_input_","hint":"\u00c1p d\u1ee5ng $\\sqrt[3]{a}.\\sqrt[3]{b}=\\sqrt[3]{ab}$ ","explain":"<span class='basic_left'>Ta c\u00f3:<br\/>$\\sqrt[3]{-0,5}.\\sqrt[3]{1,25}.\\sqrt[3]{\\dfrac{16}{10}}=\\sqrt[3]{-0,5.1,25.\\dfrac{16}{10}}=\\sqrt[3]{\\dfrac{-5}{10}.\\dfrac{125}{100}.\\dfrac{16}{10}}=\\sqrt[3]{-1}=-1$ <br\/> <span class='basic_pink'>V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n v\u00e0o \u00f4 tr\u1ed1ng l\u00e0 $-1$<\/span><\/span>"}]}],"id_ques":730}],"lesson":{"save":0,"level":1}}

Điểm của bạn.

Câu hỏi này theo dạng chọn đáp án đúng, sau khi đọc xong câu hỏi, bạn bấm vào một trong số các đáp án mà chương trình đưa ra bên dưới, sau đó bấm vào nút gửi để kiểm tra đáp án và sẵn sàng chuyển sang câu hỏi kế tiếp

Trả lời đúng trong khoảng thời gian quy định bạn sẽ được + số điểm như sau:
Trong khoảng 1 phút đầu tiên + 5 điểm
Trong khoảng 1 phút -> 2 phút + 4 điểm
Trong khoảng 2 phút -> 3 phút + 3 điểm
Trong khoảng 3 phút -> 4 phút + 2 điểm
Trong khoảng 4 phút -> 5 phút + 1 điểm

Quá 5 phút: không được cộng điểm

Tổng thời gian làm mỗi câu (không giới hạn)

Điểm của bạn.

Bấm vào đây nếu phát hiện có lỗi hoặc muốn gửi góp ý