{"segment":[{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"\u0110\u1ec1 chung cho b\u1ed1n c\u00e2u","temp":"fill_the_blank","correct":[[["1"],["2"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"Cho hai \u0111\u01b0\u1eddng th\u1eb3ng $(d):\\, y= \\dfrac{1}{2}x + \\dfrac{3}{2}$ v\u00e0 $(d'):\\, y= - x+3$<br\/><b> C\u00e2u 1: <\/b> $(d)$ c\u1eaft $(d')$ t\u1ea1i $C$. <br\/> T\u1ecda \u0111\u1ed9 \u0111i\u1ec3m $C$ l\u00e0 (_input_;_input_)","explain":" Do $(d) \\cap (d')=C$ n\u00ean ho\u00e0nh \u0111\u1ed9 giao \u0111i\u1ec3m $C$ l\u00e0 nghi\u1ec7m c\u1ee7a ph\u01b0\u01a1ng tr\u00ecnh: <br\/>$\\dfrac{1}{2}x + \\dfrac{3}{2}= -x+3 \\\\ \\Leftrightarrow x+3=-2x+6 \\\\ \\Leftrightarrow 3x=3 \\\\ \\Leftrightarrow x=1\\\\$ <br\/> Thay $x=1$ v\u00e0o $y=-x+3$ \u0111\u01b0\u1ee3c: $y= -1+3=2$<br\/>Suy ra t\u1ecda \u0111\u1ed9 \u0111i\u1ec3m $C$ l\u00e0 $(1; 2)$<br\/><span class='basic_pink'>V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0 $1$ v\u00e0 $2$.<\/span>"}]}],"id_ques":151},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"\u0110\u1ec1 chung cho b\u1ed1n c\u00e2u","temp":"fill_the_blank","correct":[[["6"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"Cho hai \u0111\u01b0\u1eddng th\u1eb3ng $(d):\\, y= \\dfrac{1}{2}x + \\dfrac{3}{2}$ v\u00e0 $(d'):\\, y= - x+3$ <br\/><b> C\u00e2u 2: <\/b> $(d) \\cap Ox = A$; $(d')\\cap Ox =B$. <br\/> Di\u1ec7n t\u00edch tam gi\u00e1c $ACB$ l\u00e0 _input_ (\u0111\u01a1n v\u1ecb di\u1ec7n t\u00edch)","explain":" <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai12/lv1/img\/D924_D5.png' \/><\/center><br\/><span class='basic_left'>Theo c\u00e2u 1, ta c\u00f3 $(d) \\cap (d')=C(1; 2)$. <br\/>$(d)\\cap Ox = A \\Rightarrow A \\left( -3; 0 \\right)\\\\ (d') \\cap Ox = B \\Rightarrow B (3; 0)\\\\ \\Rightarrow AB= 6$ <br\/>H\u1ea1 $CH \\bot Ox$ t\u1ea1i $H \\Rightarrow CH = 2$ <br\/>Di\u1ec7n t\u00edch tam gi\u00e1c $ACB$ l\u00e0: $\\dfrac{AB.CH}{2}\\,$$=\\dfrac{6.2}{2}=6$ (\u0111\u01a1n v\u1ecb di\u1ec7n t\u00edch).<br\/><span class='basic_pink'>V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0 $6$.<\/span>"}]}],"id_ques":152},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"\u0110\u1ec1 chung cho b\u1ed1n c\u00e2u","temp":"fill_the_blank","correct":[[["135"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai12/lv1/img\/D924_D5.png' \/><\/center><br\/> Cho hai \u0111\u01b0\u1eddng th\u1eb3ng $(d)$: $y= \\dfrac{1}{2}x + \\dfrac{3}{2}$ v\u00e0 $(d')$: $y= - x+3$<br\/><b> C\u00e2u 3:<\/b> T\u00ednh g\u00f3c t\u1ea1o b\u1edfi \u0111\u01b0\u1eddng th\u1eb3ng $(d')$ v\u1edbi tr\u1ee5c $Ox$. <br\/>\u0110\u00e1p s\u1ed1: $\\FormInput[40][bl_elm_true basic_elm basic_blank basic_blank_part]{}^o$ ","explain":" <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai12/lv1/img\/D924_D5.png' \/><\/center><br\/> <span class='basic_left'>Theo h\u00ecnh v\u1ebd, ta c\u00f3: $BH = 2$.<br\/>X\u00e9t $\\Delta CHB$ c\u00f3: $tg\\, \\widehat{B_{1}}=\\dfrac{CH}{HB}=1\\,$$\\,\\Rightarrow \\widehat{{{B}_{1}}}={{45}^{o}}$<br\/>$\\widehat{B}_{2}=180^o-\\widehat{B_{1}}=135^o$<br\/> G\u00f3c t\u1ea1o b\u1edfi \u0111\u01b0\u1eddng th\u1eb3ng $(d')$ v\u1edbi tr\u1ee5c $Ox $ b\u1eb1ng $135^o$<br\/><span class='basic_pink'>V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0 $135$.<\/span> <\/span>"}]}],"id_ques":153},{"time":24,"part":[{"title":"H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"\u0110\u1ec1 chung cho b\u1ed1n c\u00e2u","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"Cho hai \u0111\u01b0\u1eddng th\u1eb3ng $(d)$: $y= \\dfrac{1}{2}x + \\dfrac{3}{2}$ v\u00e0 $(d')$: $y= - x+3$<br\/><b> C\u00e2u 4:<\/b> T\u00ednh g\u00f3c t\u1ea1o b\u1edfi \u0111\u01b0\u1eddng th\u1eb3ng $(d)$ v\u1edbi tr\u1ee5c $Ox$. ","select":["A. ${26}^{o}33'$","B. ${26}^{o}56'$","C. ${28}^{o}33'$ ","D. $ {28}^{o}56'$"],"explain":" <span class='basic_left'> <center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai12/lv1/img\/D924_D5.png' \/><\/center><br\/>Theo h\u00ecnh v\u1ebd, ta c\u00f3: $AH = 4$<br\/>X\u00e9t $\\Delta CHA$ c\u00f3: $ tg\\, \\widehat{A_{1}}=\\dfrac{CH}{HA}=\\dfrac{2}{4}=\\dfrac{1}{2}\\\\ \\Rightarrow \\widehat{{{A}_{1}}}\\approx {{26}^{o}33'}$<br\/>G\u00f3c t\u1ea1o b\u1edfi \u0111\u01b0\u1eddng th\u1eb3ng $(d)$ v\u1edbi tr\u1ee5c $Ox$ b\u1eb1ng ${{26}^{o}33'}$ <br\/><span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span>","column":4}]}],"id_ques":154},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00fang hay sai","title_trans":"","temp":"true_false","correct":[["f","f","t"]],"list":[{"point":5,"image":"https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai12/lv1/img\/2.png","col_name":["Cho \u0111\u01b0\u1eddng th\u1eb3ng $(d): \\,y=\\sqrt{5}x-5$","\u0110\u00fang","Sai"],"arr_ques":["$(d)$ \u0111i qua \u0111i\u1ec3m $M (1; 0)$ ","$(d)$ song song $(d'): y=-\\sqrt{5}x$","$(d)$ c\u1eaft tr\u1ee5c tung t\u1ea1i \u0111i\u1ec3m c\u00f3 tung \u0111\u1ed9 b\u1eb1ng $-5$"],"explain":["1 - Sai, v\u00ec $0 \\ne \\sqrt{5}-5 \\Rightarrow M(1; 0)\\notin (d)$","<br\/>2 - Sai, v\u00ec $\\sqrt{5}\\ne -\\sqrt{5}\\Rightarrow (d)$ c\u1eaft $(d')$","<br\/>3 - \u0110\u00fang, v\u00ec $(d) \\cap Oy =N(0; -5 )$ "]}]}],"id_ques":155},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["4"],["-7"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"V\u1edbi gi\u00e1 tr\u1ecb n\u00e0o c\u1ee7a $a, b$ th\u00ec \u0111\u01b0\u1eddng th\u1eb3ng $y=ax+ b$ \u0111i qua \u0111i\u1ec3m $A (1; -3)$ v\u00e0 song song v\u1edbi \u0111\u01b0\u1eddng th\u1eb3ng $y= 4x -1$.<br\/><b> \u0110\u00e1p s\u1ed1: <\/b> $a =$ _input_; $b=$ _input_","explain":" <span class='basic_left'> Do $y= ax + b$ song song v\u1edbi \u0111\u01b0\u1eddng th\u1eb3ng $y= 4x - 1\\Rightarrow a = 4 ; b \\ne -1$<br\/> M\u00e0 $A (1; -3)\\in y=ax+ b$<br\/>$\\,\\Rightarrow a.1+b=-3 \\\\ \\Leftrightarrow 4 + b = -3 \\\\ \\Leftrightarrow b= -7$<br\/><span class='basic_pink'>V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0 $4$ v\u00e0 $-7$<\/span>"}]}],"id_ques":156},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["2"],["3"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"Cho \u0111\u01b0\u1eddng th\u1eb3ng $(d_{1}):\\,\\,y=2x-1$ v\u00e0 $\\,(d_{2}):\\,\\,y=-x+5$<br\/>$\\,d_{1} \\cap d_{2}= A.\\,$ T\u1ecda \u0111\u1ed9 \u0111i\u1ec3m $A$ l\u00e0 (_input_ ; _input_)","explain":"<span class='basic_left'>Do $(d_{1})$ c\u1eaft $ (d_{2})$ t\u1ea1i $A$ n\u00ean ho\u00e0nh \u0111\u1ed9 giao \u0111i\u1ec3m $A$ l\u00e0 nghi\u1ec7m c\u1ee7a ph\u01b0\u01a1ng tr\u00ecnh: <br\/>$2x - 1 =-x + 5 $$\\,\\Leftrightarrow x =2\\Rightarrow y= 3$<br\/>$\\Rightarrow A (2;3)$<br\/><span class='basic_pink'>V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0 $2$ v\u00e0 $3$.<\/span><\/span>"}]}],"id_ques":157},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["3"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"T\u00ecm $m$ \u0111\u1ec3 \u0111\u01b0\u1eddng th\u1eb3ng $y= -3x + m -1$ v\u00e0 $y= 2x - m + 5$ c\u1eaft nhau t\u1ea1i m\u1ed9t \u0111i\u1ec3m tr\u00ean tr\u1ee5c tung. <br\/><b> \u0110\u00e1p s\u1ed1: <\/b> $m=$ _input_","hint":"Hai \u0111\u01b0\u1eddng th\u1eb3ng c\u1eaft nhau t\u1ea1i m\u1ed9t \u0111i\u1ec3m tr\u00ean tr\u1ee5c tung khi ch\u00fang c\u00f3 c\u00f9ng tung \u0111\u1ed9 g\u1ed1c v\u00e0 h\u1ec7 s\u1ed1 g\u00f3c kh\u00e1c nhau v\u00e0 kh\u00e1c $0$.","explain":" Theo b\u00e0i \u0111\u01b0\u1eddng th\u1eb3ng $y= -3x + m -1$ v\u00e0 \u0111\u01b0\u1eddng th\u1eb3ng $y= 2x - m + 5$ c\u1eaft nhau t\u1ea1i m\u1ed9t \u0111i\u1ec3m tr\u00ean tr\u1ee5c tung<br\/> n\u00ean tung \u0111\u1ed9 g\u1ed1c c\u1ee7a hai \u0111\u01b0\u1eddng th\u1eb3ng \u0111\u00f3 ph\u1ea3i b\u1eb1ng nhau.<br\/>$\\Leftrightarrow m -1 = -m + 5 \\\\ \\Leftrightarrow m\\,\\,\\,\\,\\,\\,\\,\\, \\,= 3$<br\/><span class='basic_pink'>V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0 $3$.<\/span>"}]}],"id_ques":158},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["4"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai12/lv1/img\/10.jpg' \/><\/center><br\/>\u0110\u01b0\u1eddng th\u1eb3ng $y=ax+ 2a -1$ \u0111i qua \u0111i\u1ec3m $M (-1; 3)$ c\u00f3 h\u1ec7 s\u1ed1 g\u00f3c l\u00e0 _input_ ","hint":"\u0110\u01b0\u1eddng th\u1eb3ng $y=ax+ b$ c\u00f3 h\u1ec7 s\u1ed1 g\u00f3c l\u00e0 $a$.","explain":"<span class='basic_left'> Do $M(-1; 3)$ thu\u1ed9c \u0111\u01b0\u1eddng th\u1eb3ng $y=ax + 2a -1$ n\u00ean ta thay t\u1ecda \u0111\u1ed9 \u0111i\u1ec3m $M$ v\u00e0o \u0111\u01b0\u1eddng th\u1eb3ng \u0111\u00f3: <br\/> $ 3=a.(-1)+2a - 1\\\\ \\Leftrightarrow a =4$ <br\/>Suy ra h\u1ec7 s\u1ed1 g\u00f3c c\u1ee7a \u0111\u01b0\u1eddng th\u1eb3ng l\u00e0 $4$<br\/><span class='basic_pink'>V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0 $4$.<\/span> <\/span>"}]}],"id_ques":159},{"time":24,"part":[{"title":"Ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"select":["A. $\\sqrt{10}$","B. $2\\sqrt{10}$","C. $3\\sqrt{10}$"],"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai12/lv1/img\/4.jpg' \/><\/center>Cho $O(0; 0)$ v\u00e0 $B(-3; 1)$. \u0110\u1ed9 d\u00e0i \u0111o\u1ea1n $OB$ l\u00e0 ?","hint":"X\u00e1c \u0111\u1ecbnh \u0111i\u1ec3m $B$ tr\u00ean h\u1ec7 tr\u1ee5c t\u1ecda \u0111\u1ed9 r\u1ed3i d\u00f9ng \u0111\u1ecbnh l\u00ed Pytago \u0111\u1ec3 t\u00ednh $OB$.","explain":"<span class='basic_left'> <b>C\u00e1ch 1:<\/b>Ta c\u00f3 h\u00ecnh v\u1ebd: <br\/><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai12/lv1/img\/D924_D1.png' \/><\/center> <br\/>H\u1ea1 $BH \\bot Ox$. <br\/>Theo h\u00ecnh v\u1ebd, ta c\u00f3 $OH= 3; BH = 1$<br\/>X\u00e9t $\\Delta OHB$ c\u00f3: <br\/> $OB^2=OH^2+HB^2$ (\u0111\u1ecbnh l\u00ed Py - ta - go) <br\/> $\\Rightarrow OB^2=3^2+1^2=10$ <br\/> $ \\Rightarrow OB= \\sqrt{10}$ <br\/><b> C\u00e1ch 2: <\/b>\u0110\u1ed9 d\u00e0i \u0111o\u1ea1n th\u1eb3ng $OB$ l\u00e0:<br\/>$\\begin{align}OB & =\\sqrt{{{\\left( {{x}_{B}}-{{x}_{O}} \\right)}^{2}}+{{\\left( {{y}_{B}}-{{y}_{O}} \\right)}^{2}}} \\\\ & =\\sqrt{{{\\left( -3-0\\right)}^{2}}+{{\\left( 1-0 \\right)}^{2}}} \\\\ & =\\sqrt{{{3}^{2}}+{{1}^{2}}} \\\\ & =\\sqrt{10} \\\\ \\end{align}$<br\/><b>L\u01b0u \u00fd:<\/b> C\u00f4ng th\u1ee9c t\u00ednh \u0111\u1ed9 d\u00e0i AB l\u00e0:<br\/>$AB=\\sqrt{(x_{B}-x_{A})^2+(y_{B}-y_{A})^2} $ <\/span> "}]}],"id_ques":160},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["-2"],["8"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"Cho hai \u0111\u01b0\u1eddng th\u1eb3ng $y=(m+1)x + 5$ v\u00e0 $y=-x+ n - 3$. Hai \u0111\u01b0\u1eddng th\u1eb3ng tr\u00f9ng nhau khi $m=$ _input_ ; $n =$ _input_ ","hint":"Cho hai \u0111\u01b0\u1eddng th\u1eb3ng $y= ax + b\\, (d)$ v\u00e0 $y= a'x + b'\\, (d')$, ($\\,a\\ne 0 ;\\,a'\\ne 0\\,$)<br\/>$(d) \\equiv (d') \\,\\Leftrightarrow a= a'; \\, b= b'$","explain":" <span class='basic_left'> Hai \u0111\u01b0\u1eddng th\u1eb3ng \u0111\u00e3 cho tr\u00f9ng nhau <br\/>$\\Leftrightarrow \\left\\{ \\begin{aligned} & m+1=-1 \\\\ & 5=n-3 \\\\ \\end{aligned} \\right.\\Leftrightarrow \\left\\{ \\begin{aligned} & m=-2 \\\\ & n=8 \\\\ \\end{aligned} \\right.$ <br\/><span class='basic_pink'>V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0 $-2$ v\u00e0 $8$.<\/span>"}]}],"id_ques":161},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank_random","correct":[[["-1"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"Cho hai \u0111\u01b0\u1eddng th\u1eb3ng $y=(m+2)x - 3$ v\u00e0 $y=-x+1$. Hai \u0111\u01b0\u1eddng th\u1eb3ng vu\u00f4ng g\u00f3c v\u1edbi nhau khi $m=$ _input_","hint":"Hai \u0111\u01b0\u1eddng th\u1eb3ng $y= ax + b$ v\u00e0 $y= a'x + b'$, $(a,a'\\ne 0)$ vu\u00f4ng g\u00f3c v\u1edbi nhau $\\Leftrightarrow a. a'=-1$","explain":" $y=(m+2)x - 3$ c\u00f3 h\u1ec7 s\u1ed1 $a= m + 2$.<br\/> $\\,y=-x+1$ c\u00f3 h\u1ec7 s\u1ed1 $a'=-1$.<br\/>\u0110\u1ec3 hai \u0111\u01b0\u1eddng th\u1eb3ng vu\u00f4ng g\u00f3c v\u1edbi nhau th\u00ec<br\/>$ (m+2).(-1)=-1 \\Leftrightarrow m =- 1$<br\/><span class='basic_pink'>V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0 $-1$.<\/span>"}]}],"id_ques":162},{"time":24,"part":[{"title":"H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"Cho h\u00e0m s\u1ed1 $y=(m+5)x - 1$ v\u00e0 $y=(3-m)x$. V\u1edbi gi\u00e1 tr\u1ecb n\u00e0o c\u1ee7a $m$ th\u00ec \u0111\u1ed3 th\u1ecb c\u1ee7a hai h\u00e0m s\u1ed1 l\u00e0 hai \u0111\u01b0\u1eddng th\u1eb3ng c\u1eaft nhau?","select":["A. $m \\ne -1$","B. $m \\ne 1$","C. $m \\ne 4$ ","D. $ m \\ne -4$"],"explain":"\u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y=(m+5)x-1$ c\u1eaft \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y=(3-m)x$<br\/>$\\Leftrightarrow m +5 \\ne 3-m\\\\ \\Leftrightarrow \\,\\,\\,\\,\\,\\,\\,\\,\\,m\\ne-1$ <br\/><span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span>","column":4}]}],"id_ques":163},{"time":24,"part":[{"title":"H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"Cho h\u00e0m s\u1ed1 $y=(m-2)x+3$ v\u00e0 $y=(2m+3)x-1$. V\u1edbi gi\u00e1 tr\u1ecb n\u00e0o c\u1ee7a $m$ th\u00ec \u0111\u1ed3 th\u1ecb c\u1ee7a hai h\u00e0m s\u1ed1 l\u00e0 hai \u0111\u01b0\u1eddng th\u1eb3ng song song v\u1edbi nhau?","select":["A. $m = -1$","B. $m= 1$","C. $m =5$ ","D. $m =- 5$"],"explain":" \u0110\u1ec3 \u0111\u01b0\u1eddng th\u1eb3ng $y=(m-2)x+3$ song song v\u1edbi \u0111\u01b0\u1eddng th\u1eb3ng $y=(2m+3)x-1$<br\/>$\\Leftrightarrow m -2=2m+3\\\\ \\Leftrightarrow \\,\\,\\,\\,\\,\\,\\,\\,\\,m=-5$ <br\/><span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span>","column":4}]}],"id_ques":164},{"time":24,"part":[{"title":"H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai12/lv1/img\/9.jpg' \/><\/center><br\/>T\u00ecm $m$ \u0111\u1ec3 h\u00e0m s\u1ed1 $y=(m+ 3)x + 2$ ngh\u1ecbch bi\u1ebfn tr\u00ean $\\mathbb{R}$","select":["A. $ m > -3$","B. $ m < -3$","C. $ m = -3$ "],"hint":"Tr\u00ean t\u1eadp s\u1ed1 th\u1ef1c $\\mathbb{R}$, h\u00e0m s\u1ed1 $y= ax + b$ \u0111\u1ed3ng bi\u1ebfn khi $a > 0$ v\u00e0 ngh\u1ecbch bi\u1ebfn khi $a < 0$. ","explain":"H\u00e0m s\u1ed1 $y=(m +3)x+ 2$ ngh\u1ecbch bi\u1ebfn bi\u1ebfn tr\u00ean $\\mathbb{R}$ $\\Leftrightarrow m + 3 < 0 \\Leftrightarrow m <-3$ <br\/><span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span>","column":3}]}],"id_ques":165},{"time":24,"part":[{"title":"H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai12/lv1/img\/1.png' \/><\/center><br\/>T\u00ecm $m$ \u0111\u1ec3 h\u00e0m s\u1ed1 $y=(m-7)x + 5$ \u0111\u1ed3ng bi\u1ebfn tr\u00ean $\\mathbb{R}$.","select":["A. $ m > 7$","B. $ m < 7$","C. $ m = 7$ ","D. $m > 5$"],"hint":"Tr\u00ean t\u1eadp s\u1ed1 th\u1ef1c $\\mathbb{R}$, h\u00e0m s\u1ed1 $y= ax + b $ \u0111\u1ed3ng bi\u1ebfn khi $a > 0$ v\u00e0 ngh\u1ecbch bi\u1ebfn khi $a < 0$. ","explain":"H\u00e0m s\u1ed1 $y=(m - 7)x+ 5$ \u0111\u1ed3ng bi\u1ebfn tr\u00ean $\\mathbb{R}\\Leftrightarrow m - 7 > 0 \\Leftrightarrow m > 7$ <br\/><span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span>","column":4}]}],"id_ques":166},{"time":24,"part":[{"title":"H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"Trong c\u00e1c h\u00e0m s\u1ed1 sau, h\u00e0m s\u1ed1 n\u00e0o l\u00e0 h\u00e0m b\u1eadc nh\u1ea5t? ","select":["A. $y=3x^2+2x$","B. $y=\\dfrac{x}{2}-1$","C. $y=\\sqrt{x}+3$ "],"hint":"H\u00e0m s\u1ed1 b\u1eadc nh\u1ea5t h\u00e0m s\u1ed1 \u0111\u01b0\u1ee3c cho b\u1edfi c\u00f4ng th\u1ee9c $y=ax+ b$, trong \u0111\u00f3 $a, b$ l\u00e0 c\u00e1c s\u1ed1 cho tr\u01b0\u1edbc v\u00e0 $a\\ne 0$","explain":"H\u00e0m s\u1ed1 $y=\\dfrac{x}{2}-1$ l\u00e0 h\u00e0m s\u1ed1 b\u1eadc nh\u1ea5t.<br\/><span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span>","column":3}]}],"id_ques":167},{"time":24,"part":[{"title":"H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"Cho \u0111\u01b0\u1eddng th\u1eb3ng $(d): \\,y= 2x - 6$, $(d)$ c\u1eaft tr\u1ee5c ho\u00e0nh t\u1ea1i \u0111i\u1ec3m $M$ c\u00f3 t\u1ecda \u0111\u1ed9 l\u00e0: ","select":["A. $(6; 0)$","B. $(-6; 0)$","C. $(3; 0)$ ","D. $(-3; 0)$"],"hint":"","explain":"Ta c\u00f3: $(d)\\cap Ox=M$. <br\/> Ho\u00e0nh \u0111\u1ed9 \u0111i\u1ec3m $M$ l\u00e0 nghi\u1ec7m c\u1ee7a ph\u01b0\u01a1ng tr\u00ecnh:<br\/> $2x -6 = 0 \\Leftrightarrow x= 3\\Rightarrow M (3;0)$ <br\/><span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span>","column":4}]}],"id_ques":168},{"time":24,"part":[{"title":"H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"Cho \u0111\u01b0\u1eddng th\u1eb3ng $(d):\\, y= 3x + 1$, $(d)$ c\u1eaft tr\u1ee5c tung t\u1ea1i \u0111i\u1ec3m $N$ c\u00f3 t\u1ecda \u0111\u1ed9 l\u00e0: ","select":["A. $\\left(0; \\dfrac{1}{3} \\right )$","B. $\\left( 0; -\\dfrac{1}{3} \\right )$","C. $\\left( 0; -1 \\right )$ ","D. $\\left( 0; 1 \\right )$"],"hint":"\u0110\u1ed3 th\u1ecb $y=ax+ b\\, \\,(a\\ne 0)$ l\u00e0 \u0111\u01b0\u1eddng th\u1eb3ng c\u1eaft tr\u1ee5c tung t\u1ea1i \u0111i\u1ec3m c\u00f3 t\u1ecda \u0111\u1ed9 $(0; b).$","explain":"\u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y=3x+ 1$ c\u1eaft tr\u1ee5c tung t\u1ea1i \u0111i\u1ec3m c\u00f3 t\u1ecda \u0111\u1ed9 $(0; 1)$<br\/><span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span>","column":2}]}],"id_ques":169},{"time":24,"part":[{"title":"H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"\u0110i\u1ec3m thu\u1ed9c \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y= x + 3$ l\u00e0: ","select":["A. $M(-1; 2)$","B. $ N(0;2)$","C. $P(-2; 3)$ ","D. $Q(1; 5)$"],"hint":"Thay l\u1ea7n l\u01b0\u1ee3t t\u1ecda \u0111\u1ed9 c\u00e1c \u0111i\u1ec3m v\u00e0o h\u00e0m s\u1ed1 $y= x + 3$","explain":"<span class='basic_left'>X\u00e9t \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $(d)$: $y=x+3$. <br\/>+ Thay t\u1ecda \u0111\u1ed9 \u0111i\u1ec3m $M(-1;2)$ v\u00e0o h\u00e0m s\u1ed1, ta c\u00f3: $2=-1+3$ (\u0111\u00fang). Suy ra $M(-1; 2) \\in (d)$.<br\/> + Thay t\u1ecda \u0111\u1ed9 \u0111i\u1ec3m $N(0;2)$ v\u00e0o h\u00e0m s\u1ed1, ta c\u00f3: $2=0+3$ (v\u00f4 l\u00ed). Suy ra $N$ kh\u00f4ng thu\u1ed9c $(d)$<br\/>+ Thay t\u1ecda \u0111\u1ed9 \u0111i\u1ec3m $P(-2;3)$ v\u00e0o h\u00e0m s\u1ed1, ta c\u00f3: $3=-2+3$ (v\u00f4 l\u00ed). Suy ra $P$ kh\u00f4ng thu\u1ed9c $(d)$<br\/>+ Thay t\u1ecda \u0111\u1ed9 \u0111i\u1ec3m $Q(1;5)$ v\u00e0o h\u00e0m s\u1ed1, ta c\u00f3: $5=1+3$ (v\u00f4 l\u00ed). Suy ra $Q$ kh\u00f4ng thu\u1ed9c $(d)$<br\/><span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 A.<\/span>","column":4}]}],"id_ques":170}],"lesson":{"save":0,"level":1}}