{"segment":[{"time":24,"part":[{"title":"H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"Ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng vu\u00f4ng g\u00f3c v\u1edbi \u0111\u01b0\u1eddng th\u1eb3ng $(d):\\,\\,y= 2x + 1$ v\u00e0 \u0111i qua \u0111i\u1ec3m $B (1; 3)$ c\u00f3 d\u1ea1ng: ","select":["A. $y= 0,5x + 2,5$","B. $y=0,5x + 3,5$","C. $y= -0,5x +2,5$","D. $y= -0,5x + 3,5$ "],"explain":"<span class='basic_left'> Ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng c\u1ea7n t\u00ecm c\u00f3 d\u1ea1ng: $(d'):\\,\\,y=ax + b$<br\/>V\u00ec $(d') \\bot (d)$$\\, \\, \\Rightarrow a.2= -1 \\Leftrightarrow a= -0,5$ <br\/>M\u00e0 $B (1; 3)\\in (d') \\Rightarrow 1.a + b= 3 \\,$$\\Rightarrow -0,5+ b= 3 \\Leftrightarrow b= 3,5$<br\/>Ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng $(d')$ c\u00f3 d\u1ea1ng $\\, y = -0,5x+ 3,5$ <br\/><span class='basic_pink'>\u0110\u00e1p \u00e1n l\u00e0 D.<\/span><\/span>","column":2}]}],"id_ques":121},{"time":24,"part":[{"title":"H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"Ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng song song v\u1edbi \u0111\u01b0\u1eddng th\u1eb3ng $y= 3x - 2$ v\u00e0 \u0111i qua \u0111i\u1ec3m $A (-1; 4)$ c\u00f3 d\u1ea1ng: ","select":["A. $y= 3x +1$","B. $y= 3x - 1$","C. $y= 3x + 7$ ","D. $y= 3x - 7$ "],"explain":"<span class='basic_left'> $(d):\\,\\,y=ax + b$<br\/>$(d) \/\/ y= 3x - 2 \\, \\, \\Rightarrow a= 3$ <br\/>M\u00e0 $A (-1; 4) \\,\\in (d) \\Rightarrow a.(-1) + b= 4\\,$$ \\Rightarrow -3 + b= 4 \\Leftrightarrow b= 7$<br\/>Ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng $(d)$ c\u00f3 d\u1ea1ng $ y = 3x + 7$ <br\/><span class='basic_pink'>\u0110\u00e1p \u00e1n l\u00e0 C.<\/span><\/span>","column":2}]}],"id_ques":122},{"time":24,"part":[{"title":"V\u1ebd \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y = -x+1$","title_trans":"\u0110\u1ec1 chung cho hai c\u00e2u","temp":"coordinates","correct":[["0,1","0.5,0.5","1,0","1.5,-0.5","2.5,-1.5","3,-2","3.5,-2.5","4,-3","4.5,-3.5","-0.5,1.5","-1,2","-1.5,2.5","-2,3","-2.5,3.5","-3,4","-3.5,4.5"]],"list":[{"point":5,"toa_do":[["1","0","A"]],"is_click":1,"name_toado_click":"B","draw_line":1,"ques":"Cho s\u1eb5n \u0111i\u1ec3m $A (1; 0)$. H\u00e3y click th\u00eam m\u1ed9t \u0111i\u1ec3m thu\u1ed9c \u0111\u1ed3 th\u1ecb \u0111\u1ec3 v\u1ebd \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1.<br\/>_inputduongthang_ <br\/> ","hint":"X\u00e1c \u0111\u1ecbnh giao \u0111i\u1ec3m c\u1ee7a \u0111\u1ed3 th\u1ecb v\u1edbi tr\u1ee5c t\u1ecda $Oy$","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn:<br\/><\/span>+ Cho $x = 0 \\Rightarrow y= b \\Rightarrow B(0;b)$<br\/>+ \u0110\u01b0\u1eddng th\u1eb1ng qua $A;B$ ta \u0111\u01b0\u1ee3c \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y= ax + b$.<br\/><span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/>Cho $x= 0 \\Rightarrow y=1\\Rightarrow B (0;1)$<br\/> \u0110\u01b0\u1eddng th\u1eb3ng \u0111i qua $A;B$ l\u00e0 \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y=-x+1$.<br\/><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai11/lv2/img\/D923_TB2.png' \/><\/center>"}]}],"id_ques":123},{"time":24,"part":[{"title":"H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"\u0110\u1ec1 chung cho hai c\u00e2u","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"G\u00f3c t\u1ea1o b\u1edfi \u0111\u01b0\u1eddng th\u1eb3ng $y=-x+1$ v\u1edbi tr\u1ee5c $Ox$ l\u00e0: ","select":["A. $30^0$","B. $60^0$","C. $120^0$ ","D. $135^0$ "],"hint":"","explain":"<span class='basic_left'> Theo c\u00e2u tr\u00ean, ta c\u00f3 \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $y=-x+1$<br\/><center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai11/lv2/img\/D923_TB2.png' \/><\/center><br\/>G\u1ecdi $\\alpha$ l\u00e0 g\u00f3c h\u1ee3p b\u1edfi \u0111\u01b0\u1eddng th\u1eb3ng $y=-x+1$ v\u1edbi tia $Ox$, ta c\u00f3: $\\alpha=\\widehat{BAx}$ <br\/>X\u00e9t $\\Delta OAB$ c\u00f3: $tg\\, \\widehat{OAB}=\\dfrac{OB}{OA}=\\dfrac{1}{1}=1$<br\/>$\\widehat{OAB}=45^o\\Rightarrow \\alpha ={{180}^{o}}-{{45}^{o}}=135^o$ <br\/><span class='basic_pink'>\u0110\u00e1p \u00e1n l\u00e0 D.<\/span>","column":2}]}],"id_ques":124},{"time":24,"part":[{"title":"H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"Cho \u0111\u01b0\u1eddng th\u1eb3ng $\\,(d):\\,y=\\sqrt{3}x+1$. \u0110\u01b0\u1eddng th\u1eb3ng $(d)$ t\u1ea1o v\u1edbi tia $Ox$ m\u1ed9t g\u00f3c l\u00e0: ","select":["A. $30^0$","B. $45^0$","C. $60^0$ ","D. $120^0$ "],"hint":"\u0110\u01b0\u1eddng th\u1eb3ng $y=ax + b \\,\\,(a > 0)$ t\u1ea1o v\u1edbi tia $Ox$ m\u1ed9t g\u00f3c $\\alpha\\,$ th\u00ec $a= tg\\,\\alpha$ ","explain":" G\u1ecdi $\\alpha$ l\u00e0 g\u00f3c h\u1ee3p b\u1edfi \u0111\u01b0\u1eddng th\u1eb3ng $(d)$ v\u1edbi tia $Ox$.<br\/>$\\Rightarrow tg \\,\\alpha=\\sqrt{3} \\Rightarrow \\alpha = 60^o$.<br\/><span class='basic_pink'>\u0110\u00e1p \u00e1n l\u00e0 C.<\/span>","column":2}]}],"id_ques":125},{"time":24,"part":[{"title":"H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"Vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng $(d)$ \u0111i qua g\u1ed1c t\u1ecda \u0111\u1ed9 v\u00e0 $(d)$ h\u1ee3p v\u1edbi tia $Ox$ m\u1ed9t g\u00f3c $45$ \u0111\u1ed9. ","select":["A. $y=\\sqrt{2}x$","B. $y=-\\sqrt{2}x$","C. $y= x $ ","D. $y= -x $ "],"hint":"\u0110\u01b0\u1eddng th\u1eb3ng $y=ax + b\\,\\, (a > 0)$ t\u1ea1o v\u1edbi tia $Ox$ m\u1ed9t g\u00f3c $\\alpha$ th\u00ec $a= tg\\alpha$ ","explain":"<span class='basic_left'>\u0110\u01b0\u1eddng th\u1eb3ng $(d)$ \u0111i qua g\u1ed1c t\u1ecda \u0111\u1ed9 c\u00f3 d\u1ea1ng $y= ax$. <br\/>G\u1ecdi $\\alpha$ l\u00e0 g\u00f3c h\u1ee3p b\u1edfi \u0111\u01b0\u1eddng th\u1eb3ng $(d)$ v\u1edbi tia $Ox$.<br\/>$\\Rightarrow a= tg\\, \\alpha= tg\\, 45^o =1\\Rightarrow a= 1$<br\/>V\u1eady ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng $(d)$ c\u1ea7n t\u00ecm l\u00e0 $y= x$. <br\/><span class='basic_pink'>\u0110\u00e1p \u00e1n l\u00e0 C.<\/span>","column":2}]}],"id_ques":126},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["3"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai11/lv2/img\/10.jpg' \/><\/center>X\u00e1c \u0111\u1ecbnh gi\u00e1 tr\u1ecb c\u1ee7a $m$ \u0111\u1ec3 hai \u0111\u01b0\u1eddng th\u1eb3ng $(d):\\,\\,y=-5x+m+1$ v\u00e0 $(d'):\\,\\, y= 4x+7-m $ c\u1eaft nhau t\u1ea1i m\u1ed9t \u0111i\u1ec3m tr\u00ean tr\u1ee5c tung.<br\/><b> \u0110\u00e1p s\u1ed1: <\/b> $m =$ _input_","hint":"\u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $(d)$ v\u00e0 $(d')$ c\u1eaft nhau t\u1ea1i m\u1ed9t \u0111i\u1ec3m tr\u00ean tr\u1ee5c tung khi ch\u00fang c\u00f3 c\u00f9ng tung \u0111\u1ed9 g\u1ed1c.","explain":"<span class='basic_left'> \u0110\u1ed3 th\u1ecb h\u00e0m s\u1ed1 $(d)$ v\u00e0 $(d')$ c\u1eaft nhau t\u1ea1i m\u1ed9t \u0111i\u1ec3m tr\u00ean tr\u1ee5c tung khi ch\u00fang c\u00f3 c\u00f9ng tung \u0111\u1ed9 g\u1ed1c.<br\/>$\\Rightarrow m + 1 = 7 - m \\Leftrightarrow 2m= 6\\,$$ \\Leftrightarrow m= 3$ <br\/><span class='basic_pink'>Do \u0111\u00f3 s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0 $3$.<\/span><\/span>"}]}],"id_ques":127},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["2","-2"],["-2","2"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai11/lv2/img\/2.jpg' \/><\/center>X\u00e1c \u0111\u1ecbnh gi\u00e1 tr\u1ecb c\u1ee7a $m$ \u0111\u1ec3 hai \u0111\u01b0\u1eddng th\u1eb3ng $(d):\\,\\,y=mx-4\\,$ v\u00e0 $(d'): y= x - m $ c\u1eaft nhau t\u1ea1i m\u1ed9t \u0111i\u1ec3m thu\u1ed9c tr\u1ee5c ho\u00e0nh<br\/><br\/><b> \u0110\u00e1p s\u1ed1: <\/b> $m \\in$ {_input_;_input_}","hint":"$(d)$ c\u1eaft $(d')=I(a; 0)$","explain":"<span class='basic_left'>Gi\u1ea3 s\u1eed $(d)$ c\u1eaft $(d')$ t\u1ea1i \u0111i\u1ec3m $I$ tr\u00ean tr\u1ee5c ho\u00e0nh c\u00f3 t\u1ecda \u0111\u1ed9 l\u00e0 $(a;0)$. <br\/>\u0110i\u1ec1u ki\u1ec7n: $(d)\\cap (d')\\Leftrightarrow m\\ne 1$<br\/> V\u00ec $I(a; 0) \\,\\in (d) \\Rightarrow a.m - 4=0 \\,\\,(1)$<br\/> V\u00ec $I(a; 0) \\,\\in (d') \\Rightarrow a - m=0\\Leftrightarrow a= m \\,\\,(2)$<br\/>Thay (2) v\u00e0o (1) ta \u0111\u01b0\u1ee3c $m^2-4=0 \\Leftrightarrow m= \\pm 2$. <br\/><span class='basic_pink'>Do \u0111\u00f3 s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0 $2$ v\u00e0 $-2$.<\/span><\/span"}]}],"id_ques":128},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"\u0110\u1ec1 chung cho hai c\u00e2u","temp":"fill_the_blank","correct":[[["1"],["3"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai11/lv2/img\/1.png' \/><\/center><br\/><span class='basic_left'>Cho h\u00e0m s\u1ed1 $y = (m-2)x+n\\,\\, (1)$<br\/><b>C\u00e2u 1: <\/b> T\u00ecm $m$ v\u00e0 $n$ \u0111\u1ec3 \u0111\u1ed3 th\u1ecb h\u00e0m s\u1ed1 c\u1eaft $Ox$ t\u1ea1i $A, Oy$ t\u1ea1i $B$ sao cho $x_{A}=y_{B}=3$<br\/><b> \u0110\u00e1p s\u1ed1: <\/b> $m=$ _input_; $n=$ _input_<\/span>","explain":"<span class='basic_left'> \u0110\u01b0\u1eddng th\u1eb3ng (1) c\u1eaft $Ox$ t\u1ea1i $A$ sao cho $x_{A}=3\\Rightarrow A(3; 0)$<br\/>\u0110\u01b0\u1eddng th\u1eb3ng (1) c\u1eaft $Oy$ t\u1ea1i $B$ sao cho $y_{B}=3\\Rightarrow B(0; 3)$<br\/>Thay t\u1ecda \u0111\u1ed9 $A$ v\u00e0 $B$ v\u00e0o (1) ta \u0111\u01b0\u1ee3c: <br\/>$\\left\\{ \\begin{aligned} & \\left( m-2 \\right).3+n=0 \\\\ & \\left( m-2 \\right).0+n=3 \\\\ \\end{aligned} \\right.\\Leftrightarrow \\left\\{ \\begin{aligned} & 3m+n-6=0 \\\\ & n=3 \\\\ \\end{aligned} \\right.\\Leftrightarrow \\left\\{ \\begin{aligned} & m=1 \\\\ & n=3 \\\\ \\end{aligned} \\right.$<br\/>V\u1eady $ m= 1; n=3$ ta \u0111\u01b0\u1ee3c h\u00e0m s\u1ed1 $y = -x +3$ <br\/><span class='basic_pink'>Do \u0111\u00f3 s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0 $1$ v\u00e0 $3$.<\/span>"}]}],"id_ques":129},{"time":24,"part":[{"title":"H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"\u0110\u1ec1 chung cho hai c\u00e2u","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"ques":"<span class='basic_left'>Cho h\u00e0m s\u1ed1 $y = (m-2)x+n\\,\\, (1)$<br\/><b>C\u00e2u 2: <\/b> Vi\u1ebft ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng cao $OH$ c\u1ee7a tam gi\u00e1c $OAB$.<\/span>","select":["A. $y=x$ ","B. $y=-x$","C. $y=2x$ ","D. $y=-2x$"],"hint":"\u0110\u01b0\u1eddng cao $OH$ l\u00e0 \u0111\u01b0\u1eddng th\u1eb3ng \u0111i qua g\u1ed1c t\u1ecda \u0111\u1ed9 $O$ v\u00e0 vu\u00f4ng g\u00f3c v\u1edbi \u0111\u01b0\u1eddng th\u1eb3ng $(1)$","explain":"<span class='basic_left'>Theo c\u00e2u 1 tr\u00ean, ta c\u00f3 ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng th\u1eb3ng $AB$ l\u00e0: $y= -x + 3$<br\/>Ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng cao $OH$ \u0111i qua $O(0; 0)$ c\u00f3 d\u1ea1ng $\\,y= ax$<br\/>$\\,OH \\bot AB\\,$$\\Rightarrow a.(-1)=-1\\Rightarrow a= 1$ <br\/>V\u1eady ph\u01b0\u01a1ng tr\u00ecnh \u0111\u01b0\u1eddng cao $OH$ l\u00e0: $y= x$ <br\/><span class='basic_pink'>\u0110\u00e1p \u00e1n l\u00e0 A.<\/span>","column":4}]}],"id_ques":130},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["5"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"Cho ba \u0111\u01b0\u1eddng th\u1eb3ng <br\/>$(d_{1}):\\,y= 5x-1$; $\\,\\,\\,\\,$$(d_{2}):\\,y= x +3$; $\\,\\,\\,\\,$$(d_{3}):\\,y =(m-1)x$.<br\/>Ba \u0111\u01b0\u1eddng th\u1eb3ng \u0111\u1ed3ng quy khi $m =$ _input_","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn<\/span><br\/>B\u01b0\u1edbc 1: T\u00ecm giao \u0111i\u1ec3m c\u1ee7a hai \u0111\u01b0\u1eddng th\u1eb3ng $d_{1}\\,$ v\u00e0 $\\,d_{2}$<br\/>B\u01b0\u1edbc 2: Thay t\u1ecda \u0111\u1ed9 \u0111i\u1ec3m v\u1eeba t\u00ecm \u0111\u01b0\u1ee3c v\u00e0o $\\,d_{3}$ \u0111\u1ec3 t\u00ednh ra $m$.<br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/>G\u1ecdi $d_{1} \\cap d_{2}=A$ <br\/> Ho\u00e0nh \u0111\u1ed9 giao \u0111i\u1ec3m $A$ l\u00e0 nghi\u1ec7m c\u1ee7a ph\u01b0\u01a1ng tr\u00ecnh:<br\/>$5x-1= x + 3 \\Leftrightarrow x= 1 \\Rightarrow y=4 $$\\,\\,\\,\\,\\,$$\\Rightarrow A(1;4)$ <br\/>V\u00ec $d_{1};\\,d_{2};\\,d_{3}\\,$ \u0111\u1ed3ng quy $\\,\\Rightarrow A(1, 4 ) \\in (d_{3}) $$\\,\\Leftrightarrow (m-1).1=4 \\Leftrightarrow m = 5$ <br\/><span class='basic_pink'>V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0 $5$.<\/span>"}]}],"id_ques":131},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"\u0110\u1ec1 chung cho ba c\u00e2u ","temp":"fill_the_blank","correct":[[["3"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"<span class='basic_left'>Cho hai \u0111\u01b0\u1eddng th\u1eb3ng $(d_{1}):\\,y= m(x+2)$; $\\,\\,\\,\\,$$(d_{2}):\\,y= (2m-3)x+2$<br\/><b> C\u00e2u 1: <\/b> V\u1edbi gi\u00e1 tr\u1ecb n\u00e0o c\u1ee7a $m$ th\u00ec $\\, d_{1}\/\/d_{2}$.<br\/><b> \u0110\u00e1p s\u1ed1 : <\/b> $m=$_input_<\/span>","hint":"Cho hai \u0111\u01b0\u1eddng th\u1eb3ng $y= ax + b\\, (d)$ v\u00e0 $y= a'x + b' \\,(d')$, ($\\,a\\ne 0 ;\\,a'\\ne 0\\,$)<br\/>$(d) \/\/ (d') \\,\\Leftrightarrow a= a'; b\\ne b'$","explain":" Ta c\u00f3: $(d_{1}):\\,\\,y=mx + 2m\\,\\,$ song song v\u1edbi $\\,(d_{2}):\\,\\,y=(2m-3)x+2$<br\/>$\\left\\{ \\begin{aligned} & m=2m-3 \\\\ & 2m\\ne 2 \\\\ \\end{aligned} \\right.$$\\,\\Leftrightarrow \\left\\{ \\begin{aligned} & m=3 \\\\ & m\\ne 1 \\\\ \\end{aligned} \\right.\\,$$\\Leftrightarrow m=3$<br\/><span class='basic_pink'>V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0 $3$.<\/span>"}]}],"id_ques":132},{"time":24,"part":[{"title":"H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"\u0110\u1ec1 chung cho ba c\u00e2u","temp":"multiple_choice","correct":[[4]],"list":[{"point":5,"ques":"<span class='basic_left'>Cho hai \u0111\u01b0\u1eddng th\u1eb3ng $(d_{1}):\\,y= m(x+2)$; $\\,\\,\\,\\,$$(d_{2}):\\,y= (2m-3)x+2$<br\/><b> C\u00e2u 2: <\/b> V\u1edbi gi\u00e1 tr\u1ecb n\u00e0o c\u1ee7a $m$ th\u00ec $\\, d_{1}\\,$ tr\u00f9ng v\u1edbi $\\,d_{2}$.","select":["A. $m = 3$ ","B. $m= 1$","C. $m=3$ ho\u1eb7c $m=1$ ","D. Kh\u00f4ng c\u00f3 gi\u00e1 tr\u1ecb n\u00e0o c\u1ee7a $m$ th\u1ecfa m\u00e3n."],"explain":" Ta c\u00f3: $(d_{1}):\\,y= mx+2m$ tr\u00f9ng v\u1edbi $(d_{2}):\\,y= (2m-3)x+2$ <br\/> $\\Leftrightarrow \\left\\{ \\begin{aligned} & m=2m-3 \\\\ & 2m=2 \\\\ \\end{aligned} \\right.\\,$$\\Leftrightarrow \\left\\{ \\begin{aligned} & m=3 \\\\ & m=1 \\\\ \\end{aligned} \\right.$ $\\,\\,\\,\\,$(Kh\u00f4ng th\u1ecfa m\u00e3n)<br\/>$\\Rightarrow$ Kh\u00f4ng c\u00f3 gi\u00e1 tr\u1ecb n\u00e0o c\u1ee7a $m$ \u0111\u1ec3 hai \u0111\u01b0\u1eddng th\u1eb3ng n\u00e0y tr\u00f9ng nhau.<br\/><span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 D.<\/span>","column":2}]}],"id_ques":133},{"time":24,"part":[{"title":"Ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":5,"select":["A. $\\left[\\begin{aligned} & m=1 \\\\ & m=\\dfrac{1}{2} \\end{aligned} \\right.$","B. $\\left[\\begin{aligned} & m=1 \\\\ & m=\\dfrac{1}{3} \\end{aligned} \\right.$","C. $\\left[\\begin{aligned} & m=1 \\\\ & m=\\dfrac{3}{2} \\end{aligned} \\right.$"],"ques":"<span class='basic_left'>Cho hai \u0111\u01b0\u1eddng th\u1eb3ng $(d_{1}):\\,y= m(x+2)$; $\\,\\,\\,\\,$$(d_{2}):\\,y= (2m-3)x+2$<br\/>V\u1edbi gi\u00e1 tr\u1ecb n\u00e0o c\u1ee7a $m$ th\u00ec $\\, d_{1}\\bot d_{2}$.<br\/><b> \u0110\u00e1p s\u1ed1 : <\/b> $m$=?<\/span>","explain":" <span class='basic_left'>Ta c\u00f3 $(d_{1}):\\,\\,y=mx + 2m\\,\\,$ vu\u00f4ng g\u00f3c v\u1edbi $\\,(d_{2}):\\,\\,y=(2m-3)x+2$<br\/>$\\begin{aligned} &\\Leftrightarrow m.(2m-3)=-1\\\\& \\Leftrightarrow 2m^2-3m+1=0\\\\&\\Leftrightarrow 2m^2-2m-m+1=0 \\\\&\\Leftrightarrow 2m(m-1)-(m-1)=0 \\\\&\\Leftrightarrow (m-1)(2m-1)=0\\\\&\\Leftrightarrow \\left[ \\begin{aligned} & m=1 \\\\ & m=\\dfrac{1}{2} \\\\ \\end{aligned} \\right.\\\\ \\end{aligned}$ <br\/><\/span>"}]}],"id_ques":134},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["0"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"Cho ba \u0111\u01b0\u1eddng th\u1eb3ng <br\/>$(d_{1}):\\,y= x$; $\\,\\,\\,\\,$$(d_{2}):\\,y= -x +2$; $\\,\\,\\,\\,$$(d_{3}):\\,y =mx+1$.<br\/>Ba \u0111\u01b0\u1eddng th\u1eb3ng \u0111\u1ed3ng quy khi $m =$ _input_","explain":"<span class='basic_left'><span class='basic_green'>H\u01b0\u1edbng d\u1eabn<\/span><br\/>B\u01b0\u1edbc 1: T\u00ecm giao \u0111i\u1ec3m c\u1ee7a hai \u0111\u01b0\u1eddng th\u1eb3ng $d_{1}\\,$ v\u00e0 $\\,d_{2}$<br\/>B\u01b0\u1edbc 2: Thay t\u1ecda \u0111\u1ed9 \u0111i\u1ec3m v\u1eeba t\u00ecm \u0111\u01b0\u1ee3c v\u00e0o $\\,d_{3}$ \u0111\u1ec3 t\u00ednh ra $m$.<br\/> <span class='basic_green'>B\u00e0i gi\u1ea3i:<\/span><br\/>G\u1ecdi $d_{1} \\cap d_{2}=A\\,$ <br\/> Ho\u00e0nh \u0111\u1ed9 giao \u0111i\u1ec3m $A$ l\u00e0 nghi\u1ec7m c\u1ee7a ph\u01b0\u01a1ng tr\u00ecnh:<br\/>$x= -x + 2 \\Leftrightarrow x= 1 \\Rightarrow y=1 $$\\,\\,\\,\\,\\,$$\\Rightarrow A(1;1)$ <br\/>V\u00ec $d_{1};\\,d_{2};\\,d_{3}\\,$ \u0111\u1ed3ng quy $\\,\\Rightarrow A(1, 1 ) \\in (d_{3}) $$\\,\\Leftrightarrow m.1+1=1 \\Leftrightarrow m = 0 $ <br\/><span class='basic_pink'>V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0 $0$.<\/span>"}]}],"id_ques":135},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["6"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai11/lv2/img\/9.jpg' \/><\/center><br\/>\u0110\u01b0\u1eddng th\u1eb3ng $\\,y= ax + 2a - 3$ \u0111i qua \u0111i\u1ec3m $M (-1; 3)$ c\u00f3 h\u1ec7 s\u1ed1 g\u00f3c b\u1eb1ng _input_","hint":"","explain":" \u0110\u01b0\u1eddng th\u1eb3ng $\\,y= ax + 2a - 3$ \u0111i qua \u0111i\u1ec3m $M (-1; 3)$ n\u00ean thay t\u1ecda \u0111\u1ed9 \u0111i\u1ec3m $M$ v\u00e0o \u0111\u01b0\u1eddng th\u1eb3ng \u0111\u00f3, ta \u0111\u01b0\u1ee3c: <br\/>$ a.(-1)+2a - 3= 3$$\\, \\Leftrightarrow a = 6$<br\/>$\\Rightarrow$ H\u1ec7 s\u1ed1 g\u00f3c b\u1eb1ng $6$. <br\/><span class='basic_pink'>V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0 $6$.<\/span>"}]}],"id_ques":136},{"time":24,"part":[{"title":"\u0110i\u1ec1n s\u1ed1 th\u00edch h\u1ee3p v\u00e0o \u00f4 tr\u1ed1ng","title_trans":"","temp":"fill_the_blank","correct":[[["-7"]]],"list":[{"point":5,"width":40,"content":"","type_input":"","type_check":"","ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai11/lv2/img\/2.jpg' \/><\/center>Cho \u0111\u01b0\u1eddng th\u1eb3ng $\\,(d):\\, \\,y = (m+ 5)x - 2$<br\/>\u0110\u01b0\u1eddng th\u1eb1ng $(d)$ vu\u00f4ng g\u00f3c v\u1edbi \u0111\u01b0\u1eddng th\u1eb1ng $(d'): \\,\\,x - 2y = 3$ khi $m=$_input_ ","hint":"Cho hai \u0111\u01b0\u1eddng th\u1eb3ng $y= ax + b\\, (d)$ v\u00e0 $y= a'x + b'\\, (d')$, ($\\,a\\ne 0 ;\\,a'\\ne 0\\,$)<br\/>$(d) \\,\\bot (d') \\,\\Leftrightarrow a.a'=-1$","explain":" <span class='basic_left'> Ta c\u00f3 $x - 2y =3\\Leftrightarrow y= \\dfrac{x}{2}-\\dfrac{3}{2}$<br\/> \u0110\u1ec3 $(d)\\bot (d')$ th\u00ec: <br\/>$\\begin {align} (m+5).\\dfrac{1}{2}=-1\\\\ \\Leftrightarrow m+ 5= -2 \\\\ \\Leftrightarrow m = - 7\\\\ \\end {align}$ <br\/><span class='basic_pink'>V\u1eady s\u1ed1 c\u1ea7n \u0111i\u1ec1n l\u00e0 $-7$.<\/span> <\/span>"}]}],"id_ques":137},{"time":24,"part":[{"title":"H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"<center><img src='https://www.luyenthi123.com/file/luyenthi123/lop9/toan/daiso/bai11/lv2/img\/9.jpg' \/><\/center>Hai \u0111\u01b0\u1eddng th\u1eb3ng $y= - kx - m + 2$ ($\\,k \\ne 0$) v\u00e0 $\\,y =\\dfrac{k-2}{2}x-\\dfrac{m+1}{2}$ $\\, (k \\ne 2)$ tr\u00f9ng nhau khi: ","select":["A. $k= \\dfrac{2}{3}$ ","B. $k= \\dfrac{2}{3}, m= 5$","C. $k= 2, m =5$","D. $k= 2; m = 1$ "],"hint":"Cho hai \u0111\u01b0\u1eddng th\u1eb3ng $y= ax + b\\, (d)$ v\u00e0 $y= a'x + b'\\, (d')$, ($\\,a\\ne 0 ;\\,a'\\ne 0\\,$)<br\/>$(d) \\,\\equiv (d') \\,\\Leftrightarrow a = a'; b = b'$","explain":"<span class='basic_left'> Hai \u0111\u01b0\u1eddng th\u1eb3ng $y= - kx - m + 2$ v\u00e0 $\\,y =\\dfrac{k-2}{2}x-\\dfrac{m+1}{2}$ tr\u00f9ng nhau khi v\u00e0 ch\u1ec9 khi: <br\/>$\\left\\{ \\begin{aligned} & -k=\\dfrac{k-2}{2} \\\\ & -m+2=-\\dfrac{m+1}{2} \\\\\\end{aligned} \\right.$$\\,\\Leftrightarrow \\left\\{ \\begin{aligned} & -2k=k-2 \\\\ & -2m+4=-m-1 \\\\ \\end{aligned} \\right.$$\\,\\Leftrightarrow \\left\\{ \\begin{aligned} & k=\\dfrac{2}{3} \\\\ & m=5 \\\\ \\end{aligned} \\right.$<br\/><span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span>","column":2}]}],"id_ques":138},{"time":24,"part":[{"title":"H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":5,"ques":"Hai \u0111\u01b0\u1eddng th\u1eb3ng $y=(m-3)x + 3\\, (m \\,\\ne \\, 3)$ v\u00e0 $y= (1 - 2m)x + 1 \\,\\left( m \\,\\ne\\, \\dfrac{1}{2}\\right)$ c\u1eaft nhau khi: ","select":["A. $m = \\dfrac{4}{3}$ ","B. $m \\ne \\dfrac{4}{3}, m\\ne 3, m \\ne \\dfrac{1}{2}$","C. $m \\ne \\dfrac{4}{3}$ ","D. $m = \\dfrac{1}{2}$ "],"hint":"Cho hai \u0111\u01b0\u1eddng th\u1eb3ng $y= ax + b\\, (d)$ v\u00e0 $y= a'x + b'\\, (d')$, ($\\,a\\ne 0 ;\\,a'\\ne 0\\,$)<br\/>$(d) \\cap (d') \\,\\Leftrightarrow a \\ne a'$","explain":"<span class='basic_left'>Hai \u0111\u01b0\u1eddng th\u1eb3ng $y=(m-3)x + 3\\, (m \\,\\ne \\, 3)$ v\u00e0 $y= (1 - 2m)x + 1 \\,\\left(m \\,\\ne\\, \\dfrac{1}{2}\\right)$ c\u1eaft nhau khi v\u00e0 ch\u1ec9 khi: <br\/>$ m - 3 \\ne 1 - 2m \\Leftrightarrow 3m \\ne 4$$\\,\\Leftrightarrow m \\ne \\dfrac{4}{3}$<br\/>K\u1ebft h\u1ee3p v\u1edbi \u0111i\u1ec1u ki\u1ec7n $\\Rightarrow m \\ne \\dfrac{4}{3}, m\\ne 3, m \\ne \\dfrac{1}{2}$<br\/><span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 B.<\/span>","column":2}]}],"id_ques":139},{"time":24,"part":[{"title":"H\u00e3y ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":5,"ques":"Hai \u0111\u01b0\u1eddng th\u1eb3ng $y=kx + m - 2 \\,(k \\,\\ne \\, 0) $ v\u00e0 $y= (2-k)x + 4 - m \\,(k \\,\\ne\\, 2)$ song song v\u1edbi nhau khi: ","select":["A. $k \\ne 1; \\, m = 3$ ","B. $k \\ne 1; \\,m\\ne3$","C. $k = 1; \\,m\\ne 3$ ","D. $k = 1; \\,m = 3$ "],"hint":"Cho hai \u0111\u01b0\u1eddng th\u1eb3ng $y= ax + b\\, (d)$ v\u00e0 $y= a'x + b'\\, (d')$, ($\\,a\\ne 0 ;\\,a'\\ne 0\\,$)<br\/> $(d) \/\/ (d') \\,\\Leftrightarrow a= a'; b\\ne b'$","explain":"<span class='basic_left'> Hai \u0111\u01b0\u1eddng th\u1eb3ng $y=kx + m - 2 \\,(k \\,\\ne \\, 0) $ v\u00e0 $y= (2-k)x + 4 - m \\,(k \\,\\ne\\, 2)$ song song v\u1edbi nhau khi v\u00e0 ch\u1ec9 khi: <br\/>$ \\left\\{ \\begin{aligned} & k=2-k \\\\ & m-2\\ne 4-m \\\\ \\end{aligned} \\right.\\,$$\\Leftrightarrow \\left\\{ \\begin{aligned} & k=1 \\,\\,\\text{(th\u1ecfa m\u00e3n)}\\\\ & m\\ne 3 \\\\ \\end{aligned} \\right.$ <br\/><span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n l\u00e0 C.<\/span>","column":2}]}],"id_ques":140}],"lesson":{"save":0,"level":2}}