Chú ý: Để đảm bảo quyền lợi và bảo vệ tài khoản của mình
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{"common":{"save":0,"post_id":"6412","level":2,"total":10,"point":10,"point_extra":0},"segment":[{"id":"6559","mon_id":"1158790","chapter_id":"1158864","post_id":"6412","question":"<p>M\u1ed9t \u0111\u1ed9ng c\u01a1 có công su\u1ea5t tiêu th\u1ee5 b\u1eb1ng 5 kW kéo m\u1ed9t v\u1eadt có tr\u1ecdng l\u01b0\u1ee3ng 12 kN lên cao 30 m theo ph\u01b0\u01a1ng th\u1eb3ng \u0111\u1ee9ng trong th\u1eddi gian 90 s v\u1edbi v\u1eadn t\u1ed1c không \u0111\u1ed5i. Hi\u1ec7u su\u1ea5t c\u1ee7a \u0111\u1ed9ng c\u01a1 b\u1eb1ng<\/p>","options":["<strong>A. <\/strong>100%.","<strong>B. <\/strong>80%.","<strong>C.<\/strong> 60%.","<strong>D. <\/strong>40%."],"correct":"2","level":"2","hint":"<p>S\u1eed d\u1ee5ng công th\u1ee9c: <span class=\"math-tex\">$H= \\frac{A_ci}{A_tp}.100$<\/span>%<\/p>","answer":"<p>L\u1eddi gi\u1ea3i<br \/>Công có ích \u0111\u1ec3 nâng v\u1eadt lên là:<br \/> <span class=\"math-tex\">$A_ci= P.h= 12000.30= 360000(J)$<\/span><br \/>Công toàn ph\u1ea7n do \u0111\u1ed9ng c\u01a1 sinh ra là:<br \/> <span class=\"math-tex\">$A_tp= P.t= 5000.90= 450000(J)$<\/span><br \/>Hi\u1ec7u su\u1ea5t c\u1ee7a \u0111\u1ed9ng c\u01a1 b\u1eb1ng:<br \/> <span class=\"math-tex\">$H= \\frac{A_ci}{A_tp}.100 = \\frac{360000}{450000}.100= 80$<\/span>%<br \/>\u0110áp án \u0111úng: <span style=\"color:#16a085;\"><strong>B. 80%.<\/strong><\/span><\/p>","type":"choose","extra_type":"classic","user_id":"149","test":"0","date":"2023-04-04 08:43:10","option_type":"txt","len":0},{"id":"6560","mon_id":"1158790","chapter_id":"1158864","post_id":"6412","question":"<p>M\u1ed9t máy b\u01a1m n\u01b0\u1edbc có công su\u1ea5t 1,5 kW, hi\u1ec7u su\u1ea5t 70%. L\u1ea5y g = 10 m\/<span class=\"math-tex\">$s^2$<\/span>. Bi\u1ebft kh\u1ed1i l\u01b0\u1ee3ng riêng c\u1ee7a n\u01b0\u1edbc là D = <span class=\"math-tex\">$10^3$<\/span> (kg\/<span class=\"math-tex\">$m^3$<\/span>). Dùng máy này \u0111\u1ec3 b\u01a1m n\u01b0\u1edbc lên \u0111\u1ed9 cao 10 m, sau n\u1eeda gi\u1edd máy \u0111ã b\u01a1m lên b\u1ec3 m\u1ed9t l\u01b0\u1ee3ng n\u01b0\u1edbc b\u1eb1ng<\/p>","options":["<strong>A.<\/strong> 18,9 <span class=\"math-tex\">$m^3$<\/span>.","<strong>B.<\/strong> 15,8 <span class=\"math-tex\">$m^3$<\/span>.","<strong>C. <\/strong>94,5 <span class=\"math-tex\">$m^3$<\/span>.","<strong>D.<\/strong> 24,2 <span class=\"math-tex\">$m^3$<\/span>."],"correct":"1","level":"2","hint":"<p>S\u1eed d\u1ee5ng công th\u1ee9c: <span class=\"math-tex\">$H= \\frac{A_ci}{A_tp}.100$<\/span>%, <span class=\"math-tex\">$A_tp= P.t$<\/span>, <span class=\"math-tex\">$A_tp= F.s.cos\\alpha$<\/span><\/p>","answer":"<p>L\u1eddi gi\u1ea3i<br \/>Công toàn ph\u1ea7n c\u1ee7a máy b\u01a1m là:<br \/> <span class=\"math-tex\">$A_tp= P.t$<\/span><br \/>Ta có: <span class=\"math-tex\">$H= \\frac{A_ci}{A_tp} \\Phi A_ci= A_tp. H= P.t.H$<\/span><br \/>M\u1eb7t khác: <span class=\"math-tex\">$A_ci= mgh= DVgh$<\/span><br \/> <span class=\"math-tex\">$\\Phi P.t.H= DVgh \\Phi V= \\frac{P.t.H}{Dgh}$<\/span><br \/>L\u01b0\u1ee3ng n\u01b0\u1edbc mà máy b\u01a1m lên \u0111\u01b0\u1ee3c sau n\u1eeda gi\u1edd là:<br \/> <span class=\"math-tex\">$V= \\frac{P.t.H}{Dgh}= \\frac{1,5.10^3. 0,5.3600.0,7}{10^3.10.10}=18,9(m^3)$<\/span><br \/>\u0110áp án \u0111úng: <span style=\"color:#16a085;\"><strong>A. 18,9 <span class=\"math-tex\">$m^3$<\/span>.<\/strong><\/span><\/p>","type":"choose","extra_type":"classic","user_id":"149","test":"0","date":"2023-04-04 09:03:02","option_type":"math","len":0},{"id":"6561","mon_id":"1158790","chapter_id":"1158864","post_id":"6412","question":"<p>Mô\u0323t \u0111ô\u0323ng c\u01a1 \u0111iê\u0323n c\u01a1\u0303 nho\u0309 \u0111\u01b0\u01a1\u0323c s\u01b0\u0309 du\u0323ng \u0111ê\u0309 nâng mô\u0323t vâ\u0323t co\u0301 tro\u0323ng l\u01b0\u01a1\u0323ng 3,0 N lên cao 80 cm trong 6,0 s. Hiê\u0323u suâ\u0301t cu\u0309a \u0111ô\u0323ng c\u01a1 la\u0300 20%. Công suâ\u0301t \u0111iê\u0323n câ\u0301p cho \u0111ô\u0323ng c\u01a1 b\u0103\u0300ng<\/p>","options":["<strong>A.<\/strong> 0,080 W.","<strong>B.<\/strong> 2,0 W.","<strong>C. <\/strong>0,80 W.","<strong>D.<\/strong> 200 W."],"correct":"2","level":"2","hint":"<p>S\u1eed d\u1ee5ng công th\u1ee9c: <span class=\"math-tex\">$H= \\frac{A_ci}{A_tp}.100$<\/span>%, <span class=\"math-tex\">$A_tp= P.t$<\/span>, <span class=\"math-tex\">$A_tp= F.s.cos\\alpha$<\/span><\/p>","answer":"<p>L\u1eddi gi\u1ea3i<br \/>Công có ích \u0111\u1ec3 nâng v\u1eadt lên là:<br \/> <span class=\"math-tex\">$A_ci= P.h= 3.0,8= 2,4(J)$<\/span><br \/>Công toàn ph\u1ea7n do \u0111\u1ed9ng c\u01a1 sinh ra b\u1eb1ng:<br \/> <span class=\"math-tex\">$A_tp= P.t$<\/span><br \/>Mà hi\u1ec7u su\u1ea5t c\u1ee7a \u0111\u1ed9ng c\u01a1:<br \/> <span class=\"svgedit\"><svg height=\"300\" width=\"400\" xmlns:xlink=\"http:\/\/www.w3.org\/1999\/xlink\"> <g><title><\/title><rect fill=\"#fff\" height=\"302\" id=\"canvas_background\" 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y=\"13\"><\/image> <\/g> <\/svg><\/span><br \/>\u0110áp án \u0111úng: <span style=\"color:#16a085;\"><strong>B. 2 W.<\/strong><\/span><\/p>","type":"choose","extra_type":"classic","user_id":"149","test":"0","date":"2023-04-04 09:04:59","option_type":"txt","len":1}]}