Bài 3: Thực hành tính sai số trong phép đo. Ghi kết quả đo

Home Lớp 10 Vật lý 10 - Sách kết nối tri thức Bài 3: Thực hành tính sai số trong phép đo. Ghi kết quả đoBài tập trung bình

{"common":{"save":0,"post_id":"6286","level":2,"total":10,"point":10,"point_extra":0},"segment":[{"id":"5646","mon_id":"1158790","chapter_id":"1158791","post_id":"6286","question":"\u0110âu là cách vi\u1ebft \u0111úng k\u1ebft qu\u1ea3 \u0111o khi có sai s\u1ed1?<\/p>","options":["A. $A=\\bar{A} -\\triangle{A}$<\/span>","B. $A=\\bar{A} +\\triangle{A}$<\/span>","C. $\\bar{A} -\\triangle{A}\\leq A\\leq \\bar{A}+\\triangle{A}$<\/span> ","D. $\\bar{A} -\\triangle{A}< A< \\bar{A}+\\triangle{A}$<\/span>"],"correct":"3","level":"2","hint":"Cách vi\u1ebft k\u1ebft qu\u1ea3 \u0111o:  $\\bar{A} -\\triangle{A}\\leq A\\leq \\bar{A}+\\triangle{A}$<\/span><\/p>","answer":"Ch\u1ecdn C. Cách vi\u1ebft k\u1ebft qu\u1ea3 \u0111o:  $\\bar{A} -\\triangle{A}\\leq A\\leq \\bar{A}+\\triangle{A}$<\/span><\/strong><\/span><\/p>","type":"choose","extra_type":"classic","user_id":"147","test":"0","date":"2022-09-28 13:47:27","option_type":"math","len":0},{"id":"5647","mon_id":"1158790","chapter_id":"1158791","post_id":"6286","question":"Bi\u1ebft giá tr\u1ecb trung bình và sai s\u1ed1 tuy\u1ec7t \u0111\u1ed1i c\u1ee7a \u0111\u1ea1i l\u01b0\u1ee3ng A l\u1ea7n l\u01b0\u1ee3t là $\\bar A$<\/span>  và $\\triangle A$<\/span> . Công th\u1ee9c tính sai s\u1ed1 t\u1ec9 \u0111\u1ed1i c\u1ee7a \u0111\u1ea1i l\u01b0\u1ee3ng A là<\/p>","options":["A. $\\delta A=\\bar{A} +\\triangle A$<\/span>","B. $\\delta A=\\frac{\\triangle A}{\\bar{A}}.100$<\/span>%","C. $\u200b\u200b\u200b\u200b\u200b\u200b\\delta A=\\frac{\\bar A}{\\triangle A +A }.100$<\/span>%","D. $\u200b\u200b\u200b\u200b\u200b\u200b\\delta A=\\frac{\\bar A}{\\triangle A -A }.100$<\/span>%"],"correct":"2","level":"2","hint":"Sai s\u1ed1 t\u1ec9 \u0111\u1ed1i c\u1ee7a phép \u0111o là t\u1ec9 s\u1ed1 gi\u1eefa sai s\u1ed1 tuy\u1ec7t \u0111\u1ed1i và giá tr\u1ecb trung bình c\u1ee7a \u0111\u1ea1i l\u01b0\u1ee3ng c\u1ea7n \u0111o.<\/p>","answer":"Ch\u1ecdn B. B. $\\delta A=\\frac{\\triangle A}{\\bar{A}}.100$<\/span>%<\/strong><\/span><\/p>","type":"choose","extra_type":"classic","user_id":"147","test":"0","date":"2022-09-29 04:19:43","option_type":"math","len":0},{"id":"5648","mon_id":"1158790","chapter_id":"1158791","post_id":"6286","question":"Th\u1eddi gian chuy\u1ec3n \u0111\u1ed9ng c\u1ee7a m\u1ed9t v\u1eadt \u0111o \u0111\u01b0\u1ee3c là 5,21646871 (s). Cách vi\u1ebft nào d\u01b0\u1edbi \u0111ây \u0111úng v\u1edbi quy t\u1eafc làm tròn s\u1ed1?<\/p>","options":["A. t = 5,217 (s) ","B. t = 5,216 (s) ","C. t = 5,2164 (s)","D. t = 5,21646 (s)"],"correct":"2","level":"2","hint":"Quy t\u1eafc làm tròn s\u1ed1: + N\u1ebfu ch\u1eef s\u1ed1 \u1edf hàng b\u1ecf \u0111i nh\u1ecf h\u01a1n 5 thì ch\u1eef s\u1ed1 bên trái v\u1eabn gi\u1eef nguyên. + N\u1ebfu ch\u1eef s\u1ed1 \u1edf hàng b\u1ecf \u0111i l\u1edbn h\u01a1n 5 thì ch\u1eef s\u1ed1 bên trái t\u0103ng thêm m\u1ed9t \u0111\u01a1n v\u1ecb.<\/p>","answer":"Ch\u1ecdn B. Ch\u1ec9 có \u0111áp án B là \u0111úng vì hàng b\u1ecf \u0111i là hàng th\u1eadp phân th\u1ee9 4 tr\u1edf v\u1ec1 sau có giá tr\u1ecb b\u1eb1ng 4 (nh\u1ecf h\u01a1n 5) nên ch\u1eef s\u1ed1 bên trái s\u1ed1 th\u1eadp phân th\u1ee9 4 v\u1eabn \u0111\u01b0\u1ee3c gi\u1eef nguyên.<\/strong><\/span><\/p>","type":"choose","extra_type":"classic","user_id":"147","test":"0","date":"2022-09-29 04:21:29","option_type":"txt","len":2}]}