{"segment":[{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":10,"ques":"Ph\u01b0\u01a1ng tr\u00ecnh ch\u1eef c\u1ee7a ph\u1ea3n \u1ee9ng h\u00f3a h\u1ecdc gi\u1eefa kh\u00ed Nit\u01a1 v\u00e0 kh\u00ed hi\u0111ro t\u1ea1o ra amoniac nh\u01b0 sau: Kh\u00ed nit\u01a1 + Kh\u00ed hi\u0111ro $\\to $ amoniac. S\u01a1 \u0111\u1ed3 c\u1ee7a ph\u1ea3n \u1ee9ng l\u00e0 ","select":["A. ${{H}_{2}}+N{{H}_{3}}--->{{N}_{2}}$ ","B. ${{H}_{2}}+{{N}_{2}}--->N{{H}_{3}}$ ","C. $3{{H}_{2}}+{{N}_{2}}\\to 2N{{H}_{3}}$ ","D. $3{{H}_{2}}+{{N}_{2}}--->2N{{H}_{3}}$ "],"hint":"","explain":"<span class='basic_left'>S\u01a1 \u0111\u1ed3 c\u1ee7a ph\u1ea3n \u1ee9ng g\u1ed3m c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc c\u1ee7a c\u00e1c ch\u1ea5t tham gia ph\u1ea3n \u1ee9ng v\u00e0 s\u1ea3n ph\u1ea9m<br\/>D\u1ea1ng s\u01a1 \u0111\u1ed3 c\u1ee7a ph\u1ea3n \u1ee9ng l\u00e0 $A+B--->B+D$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2050},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":10,"ques":"Cho s\u01a1 \u0111\u1ed3 c\u1ee7a ph\u1ea3n \u1ee9ng sau: $Al+HCl--->AlC{{l}_{3}}+{{H}_{2}}$. Ph\u01b0\u01a1ng tr\u00ecnh h\u00f3a h\u1ecdc c\u1ee7a ph\u1ea3n \u1ee9ng l\u00e0 ","select":["A. $Al+HCl\\to AlC{{l}_{3}}+{{H}_{2}}$ ","B. $2Al+6HCl\\to 2AlC{{l}_{3}}+3{{H}_{2}}$ ","C. $2Al+6HCl\\to 2AlC{{l}_{3}}+{{H}_{2}}$ ","D. $Al+6HCl\\to 2AlC{{l}_{3}}+3{{H}_{2}}$ "],"hint":"","explain":"<span class='basic_left'>- Ta ch\u1ec9 vi\u1ec7c th\u00eam h\u1ec7 s\u1ed1 2 v\u00e0o tr\u01b0\u1edbc $AlC{{l}_{3}}$ \u0111\u1ec3 cho s\u1ed1 nguy\u00ean t\u1eed $Cl$ ch\u1eb5n. Khi \u0111\u00f3, v\u1ebf ph\u1ea3i c\u00f3 6 nguy\u00ean t\u1eed $Cl$ trong 2$AlC{{l}_{3}}$ n\u00ean v\u1ebf tr\u00e1i th\u00eam h\u1ec7 s\u1ed1 6 tr\u01b0\u1edbc $HCl$<br\/>$Al+6HCl--->2AlC{{l}_{3}}+{{H}_{2}}$<br\/>- V\u1ebf ph\u1ea3i c\u00f3 2 nguy\u00ean t\u1eed $Al$ trong 2$AlC{{l}_{3}}$, v\u1ebf tr\u00e1i ta th\u00eam h\u1ec7 s\u1ed1 2 tr\u01b0\u1edbc $Al$<br\/>$2Al+6HCl--->2AlC{{l}_{3}}+{{H}_{2}}$<br\/>V\u1ebf tr\u00e1i c\u00f3 6 nguy\u00ean t\u1eed $H$ trong $6HCl$, n\u00ean v\u1ebf ph\u1ea3i ta th\u00eam h\u1ec7 s\u1ed1 3 tr\u01b0\u1edbc ${{H}_{2}}$<br\/>$2Al+6HCl\\to 2AlC{{l}_{3}}+3{{H}_{2}}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2051},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":10,"ques":"Cho ph\u01b0\u01a1ng tr\u00ecnh ph\u1ea3n \u1ee9ng sau: $MgC{{l}_{2}}+2KOH\\to Mg{{(OH)}_{2}}+2KCl$. \u00dd ngh\u0129a c\u1ee7a ph\u01b0\u01a1ng tr\u00ecnh h\u00f3a h\u1ecdc n\u00e0o sau \u0111\u00e2y \u0111\u00fang: ","select":["A. C\u1ee9 1 ph\u00e2n t\u1eed $MgC{{l}_{2}}$ ph\u1ea3n \u1ee9ng t\u1ea1o ra 2 ph\u00e2n t\u1eed $KCl$ ","B. C\u1ee9 1 ph\u00e2n t\u1eed $MgC{{l}_{2}}$ t\u00e1c d\u1ee5ng v\u1edbi 2 ph\u00e2n t\u1eed $KOH$ ","C. C\u1ee9 1 ph\u00e2n t\u1eed $MgC{{l}_{2}}$ ph\u1ea3n \u1ee9ng t\u1ea1o ra 1 ph\u00e2n t\u1eed $Mg{{(OH)}_{2}}$ ","D. T\u1ea5t c\u1ea3 c\u00e1c \u0111\u00e1p \u00e1n tr\u00ean \u0111\u1ec1u \u0111\u00fang "],"hint":"","explain":"<span class='basic_left'>Ph\u01b0\u01a1ng tr\u00ecnh h\u00f3a h\u1ecdc cho bi\u1ebft t\u1ef7 l\u1ec7 v\u1ec1 s\u1ed1 nguy\u00ean t\u1eed, s\u1ed1 ph\u00e2n t\u1eed gi\u1eefa c\u00e1c ch\u1ea5t c\u0169ng nh\u01b0 t\u1eebng c\u1eb7p ch\u1ea5t trong ph\u00e2n t\u1eed<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 D.<\/span><\/span> ","column":1}]}],"id_ques":2052},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":10,"ques":"Cho s\u01a1 \u0111\u1ed3 ph\u1ea3n \u1ee9ng h\u00f3a h\u1ecdc sau: $KCl{{O}_{3}}--->KCl+{{O}_{2}}$. T\u1ef7 l\u1ec7 v\u1ec1 s\u1ed1 nguy\u00ean t\u1eed, s\u1ed1 ph\u00e2n t\u1eed gi\u1eefa c\u00e1c ch\u1ea5t trong ph\u1ea3n \u1ee9ng l\u00e0 ","select":["A. S\u1ed1 ph\u00e2n t\u1eed $KCl{{O}_{3}}$ : s\u1ed1 ph\u00e2n t\u1eed $KCl$ : s\u1ed1 ph\u00e2n t\u1eed ${{O}_{2}}$ = 2 : 2 : 3 ","B. S\u1ed1 ph\u00e2n t\u1eed $KCl{{O}_{3}}$ : s\u1ed1 ph\u00e2n t\u1eed $KCl$ : s\u1ed1 ph\u00e2n t\u1eed ${{O}_{2}}$ = 1 : 1 : 3 ","C. S\u1ed1 ph\u00e2n t\u1eed $KCl{{O}_{3}}$ : s\u1ed1 ph\u00e2n t\u1eed $KCl$ : s\u1ed1 ph\u00e2n t\u1eed ${{O}_{2}}$ = 2 : 1 : 3 ","D. S\u1ed1 ph\u00e2n t\u1eed $KCl{{O}_{3}}$ : s\u1ed1 ph\u00e2n t\u1eed $KCl$ : s\u1ed1 ph\u00e2n t\u1eed ${{O}_{2}}$ = 2 : 2 : 1 "],"hint":"","explain":"<span class='basic_left'>B\u01b0\u1edbc 1: L\u00e0m ch\u1eb5n s\u1ed1 nguy\u00ean t\u1eed oxi \u1edf b\u00ean tr\u00e1i<br\/>$2KCl{{O}_{3}}--->KCl+{{O}_{2}}$<br\/>B\u01b0\u1edbc 2: B\u1eaft \u0111\u1ea7u c\u00e2n b\u1eb1ng t\u1eeb nguy\u00ean t\u1eed O, b\u1ed9i chung nh\u1ecf nh\u1ea5t c\u1ee7a 6 v\u00e0 2 l\u00e0 6.<br\/> V\u1eady h\u1ec7 s\u1ed1 c\u1ee7a ${{O}_{2}}$ l\u00e0 3<br\/>$2KCl{{O}_{3}}--->KCl+3{{O}_{2}}$<br\/>B\u01b0\u1edbc 3: C\u00e2n b\u1eb1ng s\u1ed1 nguy\u00ean t\u1eed c\u00f2n l\u1ea1i l\u00e0 $K$ v\u00e0 $Cl$<br\/>$2KCl{{O}_{3}}--->2KCl+3{{O}_{2}}$<br\/>Ph\u01b0\u01a1ng tr\u00ecnh h\u00f3a h\u1ecdc ho\u00e0n ch\u1ec9nh l\u00e0 <br\/>$2KCl{{O}_{3}}\\to 2KCl+3{{O}_{2}}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A.<\/span><\/span> ","column":1}]}],"id_ques":2053},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":10,"ques":"Cho s\u01a1 \u0111\u1ed3 ph\u1ea3n \u1ee9ng kh\u00f4ng \u0111\u1ea7y \u0111\u1ee7 nh\u01b0 sau: $Cu{{(OH)}_{2}}+{{H}_{2}}S{{O}_{4}}--->?+{{H}_{2}}O$. C\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc th\u00edch h\u1ee3p \u0111\u1eb7t v\u00e0o ch\u1ed7 c\u00f3 d\u1ea5u $?$ l\u00e0 ","select":["A. $FeS{{O}_{4}}$ ","B. $CuC{{l}_{2}}$ ","C. $CuS{{O}_{4}}$ ","D. $C{{u}_{2}}{{(S{{O}_{4}})}_{3}}$ "],"hint":"","explain":"<span class='basic_left'>Trong ph\u00e2n t\u1eed $Cu{{(OH)}_{2}}$ c\u00f3 $Cu$ h\u00f3a tr\u1ecb $II$ v\u00e0 nh\u00f3m $OH$ h\u00f3a tr\u1ecb $I$<br\/>Trong ph\u00e2n t\u1eed ${{H}_{2}}S{{O}_{4}}$ c\u00f3 $H$ h\u00f3a tr\u1ecb $I$ v\u00e0 nh\u00f3m $S{{O}_{4}}$ h\u00f3a tr\u1ecb $II$ <br\/>S\u1ea3n ph\u1ea9m ph\u1ea3n \u1ee9ng m\u1edbi c\u00f3 ph\u00e2n t\u1eed n\u01b0\u1edbc ${{H}_{2}}O$<br\/>Theo l\u00fd thuy\u1ebft \u0111\u00e3 h\u1ecdc: Trong ph\u1ea3n \u1ee9ng h\u00f3a h\u1ecdc ch\u1ec9 c\u00f3 li\u00ean k\u1ebft gi\u1eefa c\u00e1c nguy\u00ean t\u1eed thay \u0111\u1ed5i l\u00e0m cho ph\u00e2n t\u1eed n\u00e0y bi\u1ebfn \u0111\u1ed5i th\u00e0nh ph\u00e2n t\u1eed kh\u00e1c<br\/>v\u1eady s\u1ea3n ph\u1ea9m \u1edf \u0111\u00e2y c\u00f2n thi\u1ebfu s\u1ef1 li\u00ean k\u1ebft c\u1ee7a $Cu$ v\u1edbi nh\u00f3m $S{{O}_{4}}$<br\/><span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":2054},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":10,"ques":"Cho s\u01a1 \u0111\u1ed3 ph\u1ea3n \u1ee9ng h\u00f3a h\u1ecdc sau: $F{{e}_{2}}{{O}_{3}}+{{H}_{2}}S{{O}_{4}}--->F{{e}_{2}}{{(S{{O}_{4}})}_{3}}+{{H}_{2}}O$. Ph\u01b0\u01a1ng tr\u00ecnh h\u00f3a h\u1ecdc c\u1ee7a ph\u1ea3n \u1ee9ng l\u00e0 ","select":["A. $3F{{e}_{2}}{{O}_{3}}+3{{H}_{2}}S{{O}_{4}}\\to F{{e}_{2}}{{(S{{O}_{4}})}_{3}}+3{{H}_{2}}O$ ","B. $F{{e}_{2}}{{O}_{3}}+3{{H}_{2}}S{{O}_{4}}\\to F{{e}_{2}}{{(S{{O}_{4}})}_{3}}+3{{H}_{2}}O$ ","C. $F{{e}_{2}}{{O}_{3}}+3{{H}_{2}}S{{O}_{4}}\\to 2F{{e}_{2}}{{(S{{O}_{4}})}_{3}}+3{{H}_{2}}O$ ","D. $3F{{e}_{2}}{{O}_{3}}+3{{H}_{2}}S{{O}_{4}}\\to 4F{{e}_{2}}{{(S{{O}_{4}})}_{3}}+3{{H}_{2}}O$ "],"hint":"","explain":"<span class='basic_left'>Nh\u1eadn x\u00e9t: S\u1ed1 nguy\u00ean t\u1eed $Fe$ v\u00e0 $H$ \u1edf hai v\u1ec1 \u0111\u00e3 b\u1eb1ng nhau ch\u1ec9 c\u00f2n nguy\u00ean t\u1eed Oxi v\u00e0 nh\u00f3m $S{{O}_{4}}$<br\/>Ta th\u1ea5y v\u1ec1 tr\u00e1i c\u00f3 3 nguy\u00ean t\u1eed $O$ v\u00e0 1 nh\u00f3m $S{{O}_{4}}$ c\u00f2n v\u1ebf ph\u1ea3i th\u00ec ng\u01b0\u1ee3c l\u1ea1i<br\/>V\u1eady ta ch\u1ec9 c\u1ea7n th\u00eam 3 v\u00e0o ${{H}_{2}}S{{O}_{4}}$ \u1edf v\u1ec1 tr\u00e1i v\u00e0 th\u00eam 3 v\u00e0o ${{H}_{2}}O$ \u1edf v\u1ec1 ph\u1ea3i <br\/>Suy ra $F{{e}_{2}}{{O}_{3}}+3{{H}_{2}}S{{O}_{4}}\\to F{{e}_{2}}{{(S{{O}_{4}})}_{3}}+3{{H}_{2}}O$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 B.<\/span><\/span> ","column":1}]}],"id_ques":2055},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":10,"ques":"Cho ph\u01b0\u01a1ng tr\u00ecnh ph\u1ea3n \u1ee9ng sau: $Mg+xHCl\\to MgC{{l}_{2}}+{{H}_{2}}$. H\u1ec7 s\u1ed1 x c\u1ee7a ph\u01b0\u01a1ng tr\u00ecnh l\u00e0 ","select":["A. $x=3$ ","B. $x=4$ ","C. $x=5$ ","D. $x=2$ "],"hint":"","explain":"<span class='basic_left'>Ta th\u1ea5y s\u1ed1 nguy\u00ean t\u1eed $Mg$ \u1edf c\u1ea3 hai v\u1ec1 \u0111\u1ec1u b\u1eb1ng nhau<br\/>S\u1ed1 nguy\u00ean t\u1eed $H$ v\u00e0 $Cl$ \u1edf v\u1ec1 tr\u00e1i c\u00f3 t\u1ef7 l\u1ec7 1:1 c\u00f2n \u1edf v\u1ec1 ph\u1ea3i l\u00e0 2:2<br\/>V\u1eady ch\u1ec9 c\u1ea7n th\u00eam 2 v\u00e0o ph\u00e2n t\u1eed $HCl$ th\u00ec s\u1ed1 nguy\u00ean t\u1eed \u1edf 2 v\u1ebf \u0111\u1ec1u c\u00e2n b\u1eb1ng nhau<br\/>$Mg+2HCl\\to MgC{{l}_{2}}+{{H}_{2}}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":2056},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":10,"ques":"Kim lo\u1ea1i nh\u00f4m $Al$ t\u00e1c d\u1ee5ng v\u1edbi axit sunfuric ${{H}_{2}}S{{O}_{4}}$ t\u1ea1o ra ch\u1ea5t nh\u00f4m sunfat $A{{l}_{2}}{{(S{{O}_{4}})}_{3}}$ v\u00e0 kh\u00ed hi\u0111ro ${{H}_{2}}$. S\u01a1 \u0111\u1ed3 c\u1ee7a ph\u1ea3n \u1ee9ng l\u00e0 ","select":["A. $2Al+{{H}_{2}}S{{O}_{4}}\\to A{{l}_{2}}{{(S{{O}_{4}})}_{3}}+{{H}_{2}}$ ","B. $Al+{{H}_{2}}S{{O}_{4}}--->A{{l}_{2}}{{(S{{O}_{4}})}_{3}}$ ","C. $Al+{{H}_{2}}S{{O}_{4}}--->A{{l}_{2}}{{(S{{O}_{4}})}_{3}}+{{H}_{2}}$ ","D. $2Al+{{H}_{2}}S{{O}_{4}}\\to A{{l}_{2}}{{(S{{O}_{4}})}_{3}}+3{{H}_{2}}$ "],"hint":"","explain":"<span class='basic_left'>S\u01a1 \u0111\u1ed3 c\u1ee7a ph\u1ea3n \u1ee9ng g\u1ed3m c\u00f4ng th\u1ee9c h\u00f3a h\u1ecdc c\u1ee7a c\u00e1c ch\u1ea5t tham gia ph\u1ea3n \u1ee9ng v\u00e0 s\u1ea3n ph\u1ea9m<br\/>D\u1ea1ng s\u01a1 \u0111\u1ed3 c\u1ee7a ph\u1ea3n \u1ee9ng l\u00e0 $A+B--->B+D$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C.<\/span><\/span> ","column":1}]}],"id_ques":2057},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":10,"ques":"Cho s\u01a1 \u0111\u1ed3 ph\u1ea3n \u1ee9ng sau: $Fe{{(N{{O}_{3}})}_{3}}+KOH--->Fe{{(OH)}_{3}}+KN{{O}_{3}}$. Ph\u01b0\u01a1ng tr\u00ecnh h\u00f3a h\u1ecdc c\u1ee7a ph\u1ea3n \u1ee9ng tr\u00ean l\u00e0 ","select":["A. $Fe{{(N{{O}_{3}})}_{3}}+3KOH\\to Fe{{(OH)}_{3}}+3KN{{O}_{3}}$ ","B. $Fe{{(N{{O}_{3}})}_{3}}+KOH\\to Fe{{(OH)}_{3}}+KN{{O}_{3}}$ ","C. $3Fe{{(N{{O}_{3}})}_{3}}+KOH\\to 3Fe{{(OH)}_{3}}+KN{{O}_{3}}$ ","D. $Fe{{(N{{O}_{3}})}_{3}}+KOH\\to 3Fe{{(OH)}_{3}}+3KN{{O}_{3}}$ "],"hint":"","explain":"<span class='basic_left'>B\u01b0\u1edbc 1: C\u00e2n b\u1eb1ng nh\u00f3m $OH$ \u1edf hai v\u1ec1 c\u1ee7a ph\u01b0\u01a1ng tr\u00ecnh b\u1eb1ng c\u00e1ch th\u00eam h\u1ec7 s\u1ed1 3 tr\u01b0\u1edbc ph\u00e2n t\u1eed $KOH$<br\/>B\u01b0\u1edbc 2: C\u00e2n b\u1eb1ng nh\u00f3m $N{{O}_{3}}$ \u1edf hai c\u1ee7a ph\u01b0\u01a1ng tr\u00ecnh b\u1eb1ng c\u00e1ch th\u00eam h\u1ec7 s\u1ed1 3 tr\u01b0\u1edbc ph\u00e2n t\u1eed $KN{{O}_{3}}$<br\/>Suy ra ph\u01b0\u01a1ng tr\u00ecnh h\u00f3a h\u1ecdc l\u00e0 $Fe{{(N{{O}_{3}})}_{3}}+3KOH\\to Fe{{(OH)}_{3}}+3KN{{O}_{3}}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A.<\/span><\/span> ","column":1}]}],"id_ques":2058},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":10,"ques":"Cho Ph\u01b0\u01a1ng tr\u00ecnh h\u00f3a h\u1ecdc sau: $2Al+3{{H}_{2}}S{{O}_{4}}\\to A{{l}_{2}}{{(S{{O}_{4}})}_{3}}+3{{H}_{2}}$. N\u1ebfu c\u00f3 ${{6,02.10}^{22}}$ nguy\u00ean t\u1eed $Al$ s\u1ebd t\u00e1c d\u1ee5ng \u0111\u01b0\u1ee3c v\u1edbi bao nhi\u00eau ph\u00e2n t\u1eed ${{H}_{2}}S{{O}_{4}}$ ? ","select":["A. ${{9,03.10}^{23}}$ ","B. ${{9,03.10}^{22}}$ ","C. ${{18,06.10}^{22}}$ ","D. ${{3,01.10}^{22}}$ "],"hint":"","explain":"<span class='basic_left'>Theo ph\u01b0\u01a1ng tr\u00ecnh c\u1ee9 2 nguy\u00ean t\u1eed $Al$ t\u00e1c d\u1ee5ng v\u1edbi 3 ph\u00e2n t\u1eed ${{H}_{2}}S{{O}_{4}}$<br\/>V\u1eady c\u00f3 ${{6,02.10}^{22}}$ nguy\u00ean t\u1eed $Al$ s\u1ebd t\u00e1c d\u1ee5ng v\u1edbi x ph\u00e2n t\u1eed ${{H}_{2}}S{{O}_{4}}$<br\/>$\\to x={{6,02.10}^{22}}.\\dfrac{3}{2}={{9,03.10}^{22}}$<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":2059}],"lesson":{"save":0,"level":2}}