{"segment":[{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":10,"ques":"Trong c\u00e1c d\u00e3y ch\u1ea5t sau, d\u00e3y ch\u1ea5t n\u00e0o ch\u1ec9 thu\u1ed9c \u0111\u01a1n ch\u1ea5t ","select":["A. $Cu{{(OH)}_{2}},BaO,NaN{{O}_{3}},HCl$ ","B. ${{H}_{2}}S{{O}_{4}},C{{H}_{4}},CuO,N{{a}_{2}}O$ ","C. ${{H}_{2}},S,C,Na$ ","D. ${{C}_{2}}{{H}_{2}},C,{{H}_{2}}O,{{O}_{2}}$ "],"hint":"","explain":"<span class='basic_left'>\u0110\u01a1n ch\u1ea5t l\u00e0 nh\u1eefng ch\u1ea5t t\u1ea1o n\u00ean t\u1eeb m\u1ed9t nguy\u00ean t\u1ed1 h\u00f3a h\u1ecdc <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C.<\/span><\/span> ","column":1}]}],"id_ques":1970},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":10,"ques":"\u0110\u1ec3 tr\u1edf th\u00e0nh ph\u00e2n t\u1eed c\u1ee7a h\u1ee3p ch\u1ea5t th\u00ec t\u1ed1i thi\u1ec3u c\u1ea7n ph\u1ea3i c\u00f3 bao nhi\u00eau nguy\u00ean t\u1eed li\u00ean k\u1ebft v\u1edbi nhau: ","select":["A. 4 nguy\u00ean t\u1eed ","B. 2 nguy\u00ean t\u1eed ","C. 3 nguy\u00ean t\u1eed ","D. 1 nguy\u00ean t\u1eed "],"hint":"","explain":"<span class='basic_left'>H\u1ee3p ch\u1ea5t l\u00e0 nh\u1eefng ch\u1ea5t t\u1ea1o n\u00ean t\u1eeb hai nguy\u00ean t\u1ed1 h\u00f3a h\u1ecdc tr\u1edf n\u00ean <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 B.<\/span><\/span> ","column":1}]}],"id_ques":1971},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":10,"ques":"D\u00e3y ch\u1ea5t n\u00e0o sau \u0111\u00e2y \u0111\u1ec1u l\u00e0 h\u1ee3p ch\u1ea5t v\u00f4 c\u01a1 ","select":["A. $Ba{{(OH)}_{2}},FeO,NaN{{O}_{3}},NaCl$ ","B. ${{H}_{2}}S{{O}_{4}},KN{{O}_{3}},C{{H}_{4}},CaO$ ","C. ${{C}_{6}}{{H}_{12}}{{O}_{6}},{{C}_{2}}{{H}_{6}},CaO,{{C}_{2}}{{H}_{2}}$ ","D. ${{C}_{12}}{{H}_{22}}{{O}_{11}},{{C}_{3}}{{H}_{6}},CuO,HCl$ "],"hint":"","explain":"<span class='basic_left'>H\u1ee3p ch\u1ea5t v\u00f4 c\u01a1 l\u00e0 nh\u1eefng h\u1ee3p ch\u1ea5t h\u00f3a h\u1ecdc kh\u00f4ng c\u00f3 m\u1eb7t nguy\u00ean t\u1eed cacbon, ngo\u1ea1i tr\u1eeb kh\u00ed CO, kh\u00ed $C{{O}_{2}}$, acid ${{H}_{2}}C{{O}_{3}}$ v\u00e0 c\u00e1c mu\u1ed1i cacbonat, hidrocacbonat <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A.<\/span><\/span> ","column":1}]}],"id_ques":1972},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":10,"ques":"D\u00e3y ch\u1ea5t n\u00e0o sau \u0111\u00e2y \u0111\u1ec1u l\u00e0 \u0111\u01a1n ch\u1ea5t kim lo\u1ea1i ","select":["A. $K, {{O}_{2}}, Na, {{H}_{2}}$ ","B. $Cu, Fe, Al, S$ ","C. ${{N}_{2}}, P, Ca, Cr$ ","D. $Ag, Au, Cu, Zn$"],"hint":"","explain":"<span class='basic_left'>\u0110\u01a1n ch\u1ea5t kim lo\u1ea1i: c\u1ea5u t\u1ea1o t\u1eeb nguy\u00ean t\u1eed, d\u1eabn \u0111i\u1ec7n, d\u1eabn nhi\u1ec7t t\u1ed1t, c\u00f3 \u00e1nh kim, d\u1ec5 u\u1ed1n...ch\u00fang \u0111\u01b0\u1ee3c s\u1eafp x\u1ebfp kh\u00edt nhau v\u00e0 theo m\u1ed9t tr\u1eadt t\u1ef1 x\u00e1c \u0111\u1ecbnh <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 D.<\/span><\/span> ","column":2}]}],"id_ques":1973},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":10,"ques":"H\u1ee3p ch\u1ea5t c\u1ee7a kim lo\u1ea1i $M$ v\u1edbi nh\u00f3m $PO_{4}^{3-}$ c\u00f3 c\u00f4ng th\u1ee9c l\u00e0 ${{M}_{3}}{{(P{{O}_{4}})}_{2}}$ c\u00f3 ph\u00e2n t\u1eed kh\u1ed1i b\u1eb1ng 262. Kim lo\u1ea1i $M$ l\u00e0 ","select":["A. $Mg$ ","B. $Ca$ ","C. $Ba$ ","D. $Cu$ "],"hint":"","explain":"<span class='basic_left'>Ta c\u00f3:<br\/> $\\begin{aligned} & {{M}_{{{M}_{3}}{{(P{{O}_{4}})}_{2}}}}=262 \\\\ & \\Rightarrow 3M+2(31+4.16)=262 \\\\ & \\Rightarrow M=\\dfrac{262-2.(31+4.16)}{3}=24 \\\\\\end{aligned}$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":1974},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[2]],"list":[{"point":10,"ques":"Nguy\u00ean t\u1eed Z n\u1eb7ng h\u01a1n nguy\u00ean t\u1eed Natri l\u00e0 17 \u0111vc. K\u00fd hi\u1ec7u h\u00f3a h\u1ecdc c\u1ee7a nguy\u00ean t\u1eed Z l\u00e0 ","select":["A. $K$ ","B. $Ca$ ","C. $Mg$ ","D. $Zn$ "],"hint":"","explain":"<span class='basic_left'>Ta c\u00f3: ${{M}_{Z}}={{M}_{Na}}+17\\Rightarrow {{M}_{Z}}=23+17=40$ \u0111vc<br\/>Tra b\u1ea3ng tu\u1ea7n ho\u00e0n c\u00e1c nguy\u00ean t\u1ed1 h\u00f3a h\u1ecdc, nguy\u00ean t\u1eed Z l\u00e0 Canxi ( Ca )<br\/><br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 B.<\/span><\/span> ","column":2}]}],"id_ques":1975},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":10,"ques":"Ph\u00e2n t\u1eed n\u01b0\u1edbc c\u00f3 c\u00f4ng th\u1ee9c l\u00e0 ${{H}_{2}}O$. Ph\u1ea7n tr\u0103m v\u1ec1 kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a nguy\u00ean t\u1ed1 Hidro trong h\u1ee3p ch\u1ea5t l\u00e0 ","select":["A. $20\\%$","B. $33,33\\%$ ","C. $11,11\\%$ ","D. $22,22\\%$ "],"hint":"","explain":"<span class='basic_left'>Ta c\u00f3: $\\%{{m}_{H}}=\\dfrac{{{m}_{H}}}{{{m}_{{{H}_{2}}O}}}.100\\%=\\dfrac{2.1}{2.1+16}.100=11,11\\%$ <br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C .<\/span><\/span> ","column":2}]}],"id_ques":1976},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","tit{le_trans":"","temp":"multiple_choice","correct":[[3]],"list":[{"point":10,"ques":"Ph\u00e2n t\u1eed c\u1ee7a m\u1ed9t ch\u1ea5t g\u1ed3m nguy\u00ean t\u1eed nguy\u00ean t\u1ed1 Y li\u00ean k\u1ebft v\u1edbi 2 nguy\u00ean t\u1eed Oxi. Nguy\u00ean t\u1ed1 Oxi chi\u1ebfm 50% v\u1ec1 kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a h\u1ee3p ch\u1ea5t. K\u00fd hi\u1ec7u h\u00f3a h\u1ecdc c\u1ee7a nguy\u00ean t\u1ed1 Y l\u00e0 ","select":["A. N ","B. P ","C. S ","D. C "],"hint":"","explain":"<span class='basic_left'>G\u1ecdi h\u1ee3p ch\u1ea5t ${{YO}_{2}}$ l\u00e0 A<br\/>Ta c\u00f3: $%O=\\dfrac{{{M}_{O}}}{{{M}_{A}}}.100%\\Rightarrow {{M}_{A}}=\\dfrac{2.16}{50}.100\\Rightarrow {{M}_{A}}=64$<br\/>$\\Rightarrow {{M}_{Y}}=64-32=32$<br\/>V\u1eady Y l\u00e0 nguy\u00ean t\u1ed1 l\u01b0u hu\u1ef3nh ( S )<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 C.<\/span><\/span> ","column":2}]}],"id_ques":1977},{"time":24,"part":[{"title":"L\u1ef1a ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[4]],"list":[{"point":10,"ques":"Ph\u00e2n t\u1eed kh\u1ed1i c\u1ee7a $CuS{{O}_{4}}$ ","select":["A. 120 \u0111vc ","B. 130 \u0111vc ","C. 150 \u0111vc ","D. 160 \u0111vc "],"hint":"","explain":"<span class='basic_left'>Ph\u00e2n t\u1eed kh\u1ed1i l\u00e0 kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a m\u1ed9t ph\u00e2n t\u1eed t\u00ednh b\u1eb1ng \u0111\u01a1n v\u1ecb cacbon <br\/>Ta c\u00f3: ${{M}_{CuS{{O}_{4}}}}=64+32+12.4=160$ \u0111vc<br\/><span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 D .<\/span><\/span> ","column":2}]}],"id_ques":1978},{"time":24,"part":[{"title":"ch\u1ecdn \u0111\u00e1p \u00e1n \u0111\u00fang","title_trans":"","temp":"multiple_choice","correct":[[1]],"list":[{"point":10,"ques":"Hai nguy\u00ean t\u1eed A li\u00ean k\u1ebft v\u1edbi 3 nguy\u00ean t\u1eed oxi t\u1ea1o ph\u00e2n t\u1eed c\u00f3 ph\u00e2n t\u1eed kh\u1ed1i b\u1eb1ng 160. A l\u00e0 nguy\u00ean t\u1ed1 n\u00e0o?","select":["A. Fe ","B. Cu ","C. Cr ","D. Zn "],"hint":"","explain":"<span class='basic_left'>Ta c\u00f3: $2{{M}_{A}}+3{{M}_{O}}=160\\Rightarrow {{M}_{A}}=\\dfrac{160-3.16}{2}=56$ <br\/>Tra b\u1ea3ng tu\u1ea7n ho\u00e0n c\u00e1c nguy\u00ean t\u1ed1 h\u00f3a h\u1ecdc, nguy\u00ean t\u1ed1 A l\u00e0 s\u1eaft ( Fe )<br\/> <span class='basic_pink'>V\u1eady \u0111\u00e1p \u00e1n \u0111\u00fang l\u00e0 A.<\/span><\/span> ","column":2}]}],"id_ques":1979}],"lesson":{"save":0,"level":2}}