Alkene - trung bình

Home Lớp 9 Khoa học tự nhiên 9 - sách kết nối tri thức Bài 24: AlkeneBài tập trung bình

{"common":{"save":0,"post_id":"7881","level":2,"total":10,"point":10,"point_extra":0},"segment":[{"id":"8184","post_id":"7881","mon_id":"1159533","chapter_id":"1159554","question":"Ch\u1ea5t làm m\u1ea5t màu dung d\u1ecbch n\u01b0\u1edbc bromine là:<\/p>","options":["A.<\/strong> CH$_{3}$<\/span> – CH$_{3}$<\/span>","B. <\/strong>CH$_{3}$<\/span> – OH","C. <\/strong>CH$_{3}$<\/span> – Cl","D. <\/strong>CH$_{2}$<\/span> = CH$_{2}$<\/span>"],"correct":"4","level":"2","hint":"- Bromine trong n\u01b0\u1edbc<\/strong> (Br\u2082) có màu nâu \u0111\u1ecf và \u0111\u01b0\u1ee3c s\u1eed d\u1ee5ng \u0111\u1ec3 ki\u1ec3m tra s\u1ef1 có m\u1eb7t c\u1ee7a liên k\u1ebft \u0111ôi ho\u1eb7c ba<\/strong> trong các h\u1ee3p ch\u1ea5t h\u1eefu c\u01a1.<\/p>- Ch\u1ea5t làm m\u1ea5t màu dung d\u1ecbch n\u01b0\u1edbc bromine th\u01b0\u1eddng s\u1ebd tham gia ph\u1ea3n \u1ee9ng c\u1ed9ng v\u1edbi bromine<\/strong>, d\u1eabn \u0111\u1ebfn bi\u1ebfn m\u1ea5t màu nâu \u0111\u1ecf<\/strong>.<\/p>","answer":"\u0110áp án \u0111úng: D. CH$_{2}$<\/span> = CH$_{2}$<\/span><\/strong><\/span><\/p>\u0110ây là alkene<\/strong> (ethylene), có liên k\u1ebft \u0111ôi<\/strong> và s\u1ebd ph\u1ea3n \u1ee9ng v\u1edbi bromine<\/strong> thông qua ph\u1ea3n \u1ee9ng c\u1ed9ng, làm m\u1ea5t màu dung d\u1ecbch bromine.<\/p>","type":"choose","extra_type":"shape1","time":"0","user_id":"127","test":"0","date":"2024-10-30 08:48:10","option_type":"math","len":0},{"id":"8185","post_id":"7881","mon_id":"1159533","chapter_id":"1159554","question":"Trong nhóm các hydrocarbon sau, nhóm hydrocarbon nào có ph\u1ea3n \u1ee9ng \u0111\u1eb7c tr\u01b0ng là ph\u1ea3n \u1ee9ng c\u1ed9ng?<\/p>","options":["A.<\/strong> C$_{2}$<\/span>H$_{4}$<\/span>, CH$_{4}$<\/span>","B. <\/strong>C$_{2}$<\/span>H$_{4}$<\/span>, C$_{6}$<\/span>H$_{6}$<\/span>","C. <\/strong>C$_{2}$<\/span>H$_{4}$<\/span>, C$_{3}$<\/span>H$_{6}$<\/span>","D. <\/strong>C$_{2}$<\/span>H$_{2}$<\/span>, C$_{6}$<\/span>H$_{6}$<\/span>"],"correct":"3","level":"2","hint":"- Các ch\u1ea5t c\u1ea7n có các liên k\u1ebft \u0111ôi<\/strong> ho\u1eb7c liên k\u1ebft ba<\/strong> trong phân t\u1eed.<\/p>- Xem xét các h\u1ee3p ch\u1ea5t thu\u1ed9c alkene<\/strong>, alkyne<\/strong> có kh\u1ea3 n\u0103ng tham gia ph\u1ea3n \u1ee9ng c\u1ed9ng d\u1ec5 dàng.<\/p>","answer":"\u0110áp án \u0111úng: C. C$_{2}$<\/span>H$_{4}$<\/span>, C$_{3}$<\/span>H$_{6}$<\/span><\/strong><\/span><\/p>- Ph\u1ea3n \u1ee9ng c\u1ed9ng<\/strong> là \u0111\u1eb7c tr\u01b0ng c\u1ee7a các hydrocarbon có liên k\u1ebft \u0111ôi ho\u1eb7c ba<\/strong> (nh\u01b0 alkene<\/strong> và alkyne<\/strong>).<\/p>- C\u2082H\u2084<\/strong> và C\u2083H\u2086<\/strong> là các alkene<\/strong> (ch\u1ee9a liên k\u1ebft \u0111ôi), nên d\u1ec5 dàng tham gia ph\u1ea3n \u1ee9ng c\u1ed9ng.<\/p>","type":"choose","extra_type":"cloud","time":"0","user_id":"127","test":"0","date":"2024-10-30 10:04:11","option_type":"math","len":0},{"id":"8186","post_id":"7881","mon_id":"1159533","chapter_id":"1159554","question":"\u0110\u1ed1t cháy ch\u1ea5t nào sau \u0111ây cho s\u1ed1 mol CO$_{2}$<\/span> b\u1eb1ng s\u1ed1 mol H$_{2}$<\/span>O?<\/p>","options":["A. <\/strong>CH$_{4}$<\/span>","B.<\/strong> C$_{2}$<\/span>H$_{4}$<\/span>","C. <\/strong>C$_{2}$<\/span>H$_{2}$<\/span>","D.<\/strong> C$_{6}$<\/span>H$_{6}$<\/span>"],"correct":"2","level":"2","hint":"- Vi\u1ebft ph\u01b0\u01a1ng trình \u0111\u1ed1t cháy<\/strong> c\u1ee7a t\u1eebng ch\u1ea5t.<\/p>- Tìm t\u1ef7 l\u1ec7 mol gi\u1eefa CO\u2082 và H\u2082O<\/strong> trong m\u1ed7i ph\u1ea3n \u1ee9ng.<\/p>- Ch\u1ea5t nào khi \u0111\u1ed1t cháy cho s\u1ed1 mol CO\u2082 b\u1eb1ng s\u1ed1 mol H\u2082O<\/strong> là \u0111áp án \u0111úng.<\/p>","answer":"\u0110áp án \u0111úng: B. C$_{2}$<\/span>H$_{4}$<\/span><\/strong><\/span><\/p>\u0110\u1ed1t cháy C\u2082H\u2084:<\/strong> C$_{2}$<\/span>H$_{4}$<\/span> + 3O$_{2}$<\/span> → 2CO$_{2}$<\/span> + 2H$_{2}$<\/span>O<\/p>=> T\u1ef7 l\u1ec7: 2 mol CO\u2082 : 2 mol H\u2082O → B\u1eb1ng nhau<\/strong>.<\/p>","type":"choose","extra_type":"shape2","time":"0","user_id":"127","test":"0","date":"2024-10-30 10:08:03","option_type":"math","len":0}]}