Điện trở. Định luật Ohm

Home Lớp 9 Khoa học tự nhiên 9 - sách kết nối tri thức Bài 11: Điện trở. Định luật OhmBài tập cơ bản

{"common":{"save":0,"post_id":"8240","level":1,"total":10,"point":10,"point_extra":0},"segment":[{"id":"9341","post_id":"8240","mon_id":"1159533","chapter_id":"1159663","question":"\u0110i\u1ec7n tr\u1edf là gì?<\/p>","options":["A. L\u01b0\u1ee3ng \u0111i\u1ec7n tích truy\u1ec1n qua m\u1ea1ch trong m\u1ed9t giây.","B. \u0110\u1ea1i l\u01b0\u1ee3ng \u0111\u1eb7c tr\u01b0ng cho kh\u1ea3 n\u0103ng c\u1ea3n tr\u1edf dòng \u0111i\u1ec7n c\u1ee7a v\u1eadt li\u1ec7u.","C. N\u0103ng l\u01b0\u1ee3ng tiêu th\u1ee5 c\u1ee7a dòng \u0111i\u1ec7n trong m\u1ed9t m\u1ea1ch.","D. Công su\u1ea5t c\u1ee7a dòng \u0111i\u1ec7n trong m\u1ed9t m\u1ea1ch."],"correct":"2","level":"1","hint":"","answer":"\u0110áp án: B. \u0110\u1ea1i l\u01b0\u1ee3ng \u0111\u1eb7c tr\u01b0ng cho kh\u1ea3 n\u0103ng c\u1ea3n tr\u1edf dòng \u0111i\u1ec7n c\u1ee7a v\u1eadt li\u1ec7u. Gi\u1ea3i thích: \u0110i\u1ec7n tr\u1edf là \u0111\u1ea1i l\u01b0\u1ee3ng \u0111\u1eb7c tr\u01b0ng cho kh\u1ea3 n\u0103ng c\u1ea3n tr\u1edf dòng \u0111i\u1ec7n c\u1ee7a m\u1ed9t v\u1eadt d\u1eabn.  <\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"125","test":"0","date":"2024-12-25 23:40:43","option_type":"txt","len":3},{"id":"9344","post_id":"8240","mon_id":"1159533","chapter_id":"1159663","question":"\u0110\u01a1n v\u1ecb \u0111o \u0111i\u1ec7n tr\u1edf là gì?<\/p>","options":["A. Vôn (V)","B. Ampe (A)","C. Ôm (Ω)","D. Watt (W)"],"correct":"3","level":"1","hint":"","answer":"\u0110áp án: C. Ôm (Ω). Gi\u1ea3i thích: \u0110i\u1ec7n tr\u1edf \u0111\u01b0\u1ee3c \u0111o b\u1eb1ng \u0111\u01a1n v\u1ecb Ôm, ký hi\u1ec7u là Ω.  <\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"125","test":"0","date":"2024-12-25 23:43:56","option_type":"txt","len":2},{"id":"9354","post_id":"8240","mon_id":"1159533","chapter_id":"1159663","question":"\u0110\u1ecbnh lu\u1eadt Ohm \u0111\u01b0\u1ee3c phát bi\u1ec3u nh\u01b0 th\u1ebf nào?<\/p>","options":["A. \u0110i\u1ec7n tr\u1edf t\u1ec9 l\u1ec7 thu\u1eadn v\u1edbi hi\u1ec7u \u0111i\u1ec7n th\u1ebf và dòng \u0111i\u1ec7n.","B. Dòng \u0111i\u1ec7n ch\u1ea1y qua m\u1ed9t \u0111o\u1ea1n m\u1ea1ch t\u1ec9 l\u1ec7 thu\u1eadn v\u1edbi hi\u1ec7u \u0111i\u1ec7n th\u1ebf \u0111\u1eb7t vào hai \u0111\u1ea7u \u0111o\u1ea1n m\u1ea1ch và t\u1ec9 l\u1ec7 ngh\u1ecbch v\u1edbi \u0111i\u1ec7n tr\u1edf.","C. Hi\u1ec7u \u0111i\u1ec7n th\u1ebf \u0111\u1eb7t vào hai \u0111\u1ea7u \u0111o\u1ea1n m\u1ea1ch t\u1ec9 l\u1ec7 ngh\u1ecbch v\u1edbi dòng \u0111i\u1ec7n và \u0111i\u1ec7n tr\u1edf.","D. Dòng \u0111i\u1ec7n không ph\u1ee5 thu\u1ed9c vào hi\u1ec7u \u0111i\u1ec7n th\u1ebf và \u0111i\u1ec7n tr\u1edf."],"correct":"2","level":"1","hint":"","answer":"\u0110áp án: B. Dòng \u0111i\u1ec7n ch\u1ea1y qua m\u1ed9t \u0111o\u1ea1n m\u1ea1ch t\u1ec9 l\u1ec7 thu\u1eadn v\u1edbi hi\u1ec7u \u0111i\u1ec7n th\u1ebf \u0111\u1eb7t vào hai \u0111\u1ea7u \u0111o\u1ea1n m\u1ea1ch và t\u1ec9 l\u1ec7 ngh\u1ecbch v\u1edbi \u0111i\u1ec7n tr\u1edf.<\/p>Gi\u1ea3i thích:<\/p>\u0110\u1ecbnh lu\u1eadt Ohm: $I = { U \\over R}$<\/span><\/p>trong \u0111ó:<\/p>- $I$<\/span>: C\u01b0\u1eddng \u0111\u1ed9 dòng \u0111i\u1ec7n (A)<\/p>- $U$<\/span>: Hi\u1ec7u \u0111i\u1ec7n th\u1ebf (V)<\/p>- $R$<\/span>: \u0110i\u1ec7n tr\u1edf (Ω)<\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"125","test":"0","date":"2024-12-26 11:40:04","option_type":"txt","len":3}]}