Lăng kính (nâng cao)

Home Lớp 9 Khoa học tự nhiên 9 - sách kết nối tri thức Bài 7: Lăng kínhBài tập nâng cao

{"common":{"save":0,"post_id":"8188","level":3,"total":10,"point":10,"point_extra":0},"segment":[{"id":"9266","post_id":"8188","mon_id":"1159533","chapter_id":"1159595","question":"M\u1ed9t l\u0103ng kính th\u1ee7y tin có chi\u1ebft su\u1ea5t n = 1,5 và góc chi\u1ebft quang A = 30°. Tia sáng chi\u1ebfu t\u1edbi l\u0103ng kính v\u1edbi góc t\u1edbi $i_1 = 40^o$<\/span>. Góc khúc x\u1ea1 $r_1$<\/span> t\u1ea1i m\u1eb7t \u0111\u1ea7u tiên \u0111\u01b0\u1ee3c tính b\u1eb1ng công th\u1ee9c:<\/p>","options":["A. $r_1 = arcsin\\ ({sin\\ i_1 \\over n})$<\/span>","B. $r_1 = n.sin\\ i_1$<\/span>","C. $r_1 = {sin\\ i_1 \\over n}$<\/span>","D. $r_1\n\u200b\n =n+sin\\ i_1\n\u200b\n$<\/span>"],"correct":"1","level":"3","hint":"Áp d\u1ee5ng công th\u1ee9c \u0111\u1ecbnh lu\u1eadt khúc x\u1ea1<\/p>","answer":"\u0110áp án: A.  $r_1 = arcsin\\ ({sin\\ i_1 \\over n})$<\/span><\/p>Gi\u1ea3i thích:<\/p>S\u1eed d\u1ee5ng \u0111\u1ecbnh lu\u1eadt khúc x\u1ea1 ánh sáng: $n = {sin\\ i_1 \\over sin\\ r_1}$<\/span>. Suy ra  $r_1 = arcsin\\ ({sin\\ i_1 \\over n})$<\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"125","test":"0","date":"2024-12-23 10:51:29","option_type":"math","len":0},{"id":"9267","post_id":"8188","mon_id":"1159533","chapter_id":"1159595","question":"M\u1ed9t l\u0103ng kính có góc chi\u1ebft quang A = 40°. Tia sáng chi\u1ebfu t\u1edbi l\u0103ng kính theo ph\u01b0\u01a1ng vuông góc v\u1edbi m\u1eb7t bên \u0111\u1ea7u tiên. Góc l\u1ec7ch c\u1ee7a tia sáng sau khi ra kh\u1ecfi l\u0103ng kính ph\u1ee5 thu\u1ed9c vào:<\/p>","options":["A. Chi\u1ebft su\u1ea5t c\u1ee7a l\u0103ng kính và góc chi\u1ebft quang.","B. Chi\u1ebft su\u1ea5t c\u1ee7a môi tr\u01b0\u1eddng ngoài.","C. Góc t\u1edbi t\u1ea1i m\u1eb7t ra c\u1ee7a l\u0103ng kính.","D. Góc ph\u1ea3n x\u1ea1 t\u1ea1i m\u1eb7t vào c\u1ee7a l\u0103ng kính."],"correct":"1","level":"3","hint":"","answer":"\u0110áp án: A. Chi\u1ebft su\u1ea5t c\u1ee7a l\u0103ng kính và góc chi\u1ebft quang. Gi\u1ea3i thích: Góc l\u1ec7ch c\u1ee7a tia sáng qua l\u0103ng kính ph\u1ee5 thu\u1ed9c ch\u1ee7 y\u1ebfu vào góc chi\u1ebft quang và chi\u1ebft su\u1ea5t c\u1ee7a l\u0103ng kính, theo công th\u1ee9c góc l\u1ec7ch: $D = i_1 + i_2 - A$<\/span><\/p>  <\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"125","test":"0","date":"2024-12-23 10:54:13","option_type":"txt","len":3},{"id":"9268","post_id":"8188","mon_id":"1159533","chapter_id":"1159595","question":"M\u1ed9t l\u0103ng kính có góc chi\u1ebft quang A = 30°, chi\u1ebft su\u1ea5t c\u1ee7a l\u0103ng kính n = 1,5. Ánh sáng chi\u1ebfu vào l\u0103ng kính v\u1edbi góc t\u1edbi $i_1 = 45^o$<\/span>. Tính góc khúc x\u1ea1 $r_1\\n$<\/span> t\u1ea1i m\u1eb7t \u0111\u1ea7u tiên.<\/p>","options":["A. 20°","B. 25°","C. 28°","D. 30°"],"correct":"3","level":"3","hint":"","answer":"\u0110áp án: C. 28°<\/p>Gi\u1ea3i thích:<\/p>S\u1eed d\u1ee5ng \u0111\u1ecbnh lu\u1eadt khúc x\u1ea1 ánh sáng:<\/p>$n= {sin\\ i_1 \\over sin\\ r_1}$<\/span> $=> sin\\ r_1 = {sin\\ i_1 \\over n}$<\/span> $ = {sin\\ 45^o\\over 1,5} = 0,471$<\/span><\/p>T\u1eeb \u0111ó: $r_1 = arcsin (0,471) = 28^o$<\/span><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"125","test":"0","date":"2024-12-23 11:34:32","option_type":"txt","len":0}]}