Polymer - nâng cao

Home Lớp 9 Khoa học tự nhiên 9 - sách kết nối tri thức Bài 32: PolymerBài tập nâng cao

{"common":{"save":0,"post_id":"8132","level":3,"total":10,"point":10,"point_extra":0},"segment":[{"id":"8997","post_id":"8132","mon_id":"1159533","chapter_id":"1159587","question":"Phân t\u1eed kh\u1ed1i trung bình c\u1ee7a poly (vinylchloride) (PVC) là 75000. S\u1ed1 m\u1eaft xích có trong phân t\u1eed là?<\/p>","options":["A. <\/strong>2100","B. <\/strong>1200","C. <\/strong>1000","D.<\/strong> 1500"],"correct":"2","level":"3","hint":"\u0110\u1ec3 tính s\u1ed1 m\u1eaft xích trong phân t\u1eed PVC, b\u1ea1n c\u1ea7n bi\u1ebft phân t\u1eed kh\u1ed1i c\u1ee7a m\u1ed9t m\u1eaft xích (monomer) và sau \u0111ó chia phân t\u1eed kh\u1ed1i trung bình c\u1ee7a polymer cho phân t\u1eed kh\u1ed1i c\u1ee7a m\u1ed9t m\u1eaft xích.<\/p>","answer":"\u0110áp án \u0111úng: B. 1200<\/strong><\/span><\/p>Poli (vinyl clorua) là [-CH2<\/sub>-CH(Cl)]n<\/sub> ⇒ n = 75000 ÷ 62,5 = 1200<\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"127","test":"0","date":"2024-12-03 23:23:37","option_type":"txt","len":0},{"id":"8998","post_id":"8132","mon_id":"1159533","chapter_id":"1159587","question":"M\u1ed9t polime (Y) có c\u1ea5u t\u1ea1o m\u1ea1ch nh\u01b0 sau:… –CH$_{2}$<\/span>–CH$_{2}$<\/span>–CH$_{2}$<\/span>–CH$_{2}$<\/span>–CH$_{2}$<\/span>–CH$_{2}$<\/span>– …<\/p>Công th\u1ee9c 1 m\u1eaft xích c\u1ee7a polymer (Y) là:<\/p>","options":["A. <\/strong>–CH$_{2}$<\/span>–CH$_{2}$<\/span>–CH$_{2}$<\/span>–","B. <\/strong>–CH$_{2}$<\/span>–","C.<\/strong> –CH$_{2}$<\/span>–CH$_{2}$<\/span>–CH$_{2}$<\/span>–CH$_{2}$<\/span>–","D. <\/strong>–CH$_{2}$<\/span>–CH$_{2}$<\/span>–"],"correct":"4","level":"3","hint":"Hãy chú ý \u0111\u1ebfn c\u1ea5u trúc m\u1ea1ch c\u1ee7a polymer (Y). C\u1ea5u trúc m\u1ea1ch này có ch\u1ee9a m\u1ed9t chu\u1ed7i các nhóm –CH$_{2}$<\/span>– và \u0111\u01b0\u1ee3c l\u1eb7p l\u1ea1i liên ti\u1ebfp trong polymer. Công th\u1ee9c 1 m\u1eaft xích c\u1ee7a polymer chính là ph\u1ea7n \u0111\u01a1n gi\u1ea3n nh\u1ea5t c\u1ee7a chu\u1ed7i này, có th\u1ec3 coi là \u0111\u01a1n v\u1ecb c\u1ea5u trúc c\u01a1 b\u1ea3n mà polymer t\u1ea1o thành.<\/p>","answer":"\u0110áp án \u0111úng: D. –CH$_{2}$<\/span>–CH$_{2}$<\/span>–<\/span><\/strong><\/p>D\u1ef1a vào c\u1ea5u trúc m\u1ea1ch c\u1ee7a polymer (Y), m\u1ed7i m\u1eaft xích polymer \u0111\u01b0\u1ee3c t\u1ea1o thành t\u1eeb hai nguyên t\u1eed carbon (CH2) liên k\u1ebft v\u1edbi nhau (–CH$_{2}$<\/span>–CH$_{2}$<\/span>–)<\/strong>. Vì v\u1eady, công th\u1ee9c 1 m\u1eaft xích c\u1ee7a polymer này chính là –CH$_{2}$<\/span>–CH$_{2}$<\/span>–<\/strong>.<\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"127","test":"0","date":"2024-12-03 23:24:07","option_type":"math","len":0},{"id":"8999","post_id":"8132","mon_id":"1159533","chapter_id":"1159587","question":"Trùng h\u1ee3p m t\u1ea5n ethylene thu \u0111\u01b0\u1ee3c 1 t\u1ea5n polyethylene (PE) v\u1edbi hi\u1ec7u su\u1ea5t ph\u1ea3n \u1ee9ng b\u1eb1ng 80%. Giá tr\u1ecb c\u1ee7a m là:<\/p>","options":["A. <\/strong>0,80","B. <\/strong>1,25","C. <\/strong>1,80","D.<\/strong> 2,00"],"correct":"2","level":"3","hint":"Hi\u1ec7u su\u1ea5t ph\u1ea3n \u1ee9ng \u0111\u01b0\u1ee3c tính b\u1eb1ng t\u1ef7 l\u1ec7 gi\u1eefa kh\u1ed1i l\u01b0\u1ee3ng ch\u1ea5t s\u1ea3n ph\u1ea9m th\u1ef1c t\u1ebf thu \u0111\u01b0\u1ee3c và kh\u1ed1i l\u01b0\u1ee3ng ch\u1ea5t s\u1ea3n ph\u1ea9m lý thuy\u1ebft có th\u1ec3 thu \u0111\u01b0\u1ee3c. \u0110\u1ec3 tính giá tr\u1ecb mmm, b\u1ea1n c\u1ea7n áp d\u1ee5ng các kh\u1ed1i l\u01b0\u1ee3ng mol c\u1ee7a ethylene (C\u2082H\u2084) và polyethylene (C\u2082H\u2084)n.<\/p>","answer":"\u0110áp án \u0111úng: B. 1,25<\/span><\/strong><\/p>PTHH: <\/strong>nC$_{2}$<\/span>H$_{4}$<\/span> → (C$_{2}$<\/span>H$_{4}$<\/span>)$_{n}$<\/span><\/p>$m = {1.100 \\over 80}$<\/span> = 1,25 t\u1ea5n.<\/p>","type":"choose","extra_type":"shape2","time":"0","user_id":"127","test":"0","date":"2024-12-03 23:24:59","option_type":"txt","len":0}]}