{"common":{"save":0,"post_id":"7854","level":2,"total":10,"point":10,"point_extra":0},"segment":[{"id":"7964","post_id":"7854","mon_id":"1159533","chapter_id":"1159546","question":"<p>Carbon vô \u0111\u1ecbnh hình \u0111\u01b0\u1ee3c \u0111i\u1ec1u ch\u1ebf t\u1eeb than g\u1ed7 hay gáo d\u1eeba có tên là than ho\u1ea1t tính. Tính ch\u1ea5t nào c\u1ee7a than ho\u1ea1t tính giúp con ng\u01b0\u1eddi ch\u1ebf t\u1ea1o các thi\u1ebft b\u1ecb phòng \u0111\u1ed9c, l\u1ecdc n\u01b0\u1edbc?<\/p>","options":["<strong>A. <\/strong>Than ho\u1ea1t tính d\u1ec5 cháy","<strong>B.<\/strong> Than ho\u1ea1t tính có c\u1ea5u trúc l\u1edbp","<strong>C. <\/strong>Than ho\u1ea1t tính có kh\u1ea3 n\u0103ng h\u1ea5p ph\u1ee5 cao","<strong>D. <\/strong>Than ho\u1ea1t tính có kh\u1ea3 n\u0103ng hòa tan t\u1ed1t trong nhi\u1ec1u dung môi"],"correct":"3","level":"2","hint":"<p>D\u1ef1a vào tính ch\u1ea5t giúp than ho\u1ea1t tính gi\u1eef l\u1ea1i các ch\u1ea5t \u0111\u1ed9c ho\u1eb7c t\u1ea1p ch\u1ea5t, làm cho nó hi\u1ec7u qu\u1ea3 trong vi\u1ec7c l\u1ecdc và b\u1ea3o v\u1ec7.<\/p>","answer":"<p>\u0110áp án \u0111úng: <span style=\"color:#16a085;\"><strong>C. Than ho\u1ea1t tính có kh\u1ea3 n\u0103ng h\u1ea5p ph\u1ee5 cao<\/strong><\/span><\/p><p>Than ho\u1ea1t tính có b\u1ec1 m\u1eb7t l\u1edbn và nhi\u1ec1u l\u1ed7 x\u1ed1p, giúp <strong>h\u1ea5p ph\u1ee5<\/strong> các phân t\u1eed khí, ch\u1ea5t \u0111\u1ed9c, và t\u1ea1p ch\u1ea5t, nên \u0111\u01b0\u1ee3c dùng trong <strong>thi\u1ebft b\u1ecb phòng \u0111\u1ed9c<\/strong> và <strong>l\u1ecdc n\u01b0\u1edbc<\/strong>.<\/p>","type":"choose","extra_type":"cloud","time":"0","user_id":"127","test":"0","date":"2024-10-18 16:12:43","option_type":"txt","len":0},{"id":"7965","post_id":"7854","mon_id":"1159533","chapter_id":"1159546","question":"<p>Kim c\u01b0\u01a1ng \u0111\u01b0\u1ee3c s\u1eed d\u1ee5ng làm m\u0169i khoan, dao c\u1eaft th\u1ee7y tinh và b\u1ed9t mài vì kim c\u01b0\u01a1ng là ch\u1ea5t có \u0111\u1ed9 c\u1ee9ng r\u1ea5t l\u1edbn. Tính ch\u1ea5t trên m\u1ed9t ph\u1ea7n là do tinh th\u1ec3 kim c\u01b0\u01a1ng thu\u1ed9c lo\u1ea1i tinh th\u1ec3<\/p>","options":["<strong>A. <\/strong>nguyên t\u1eed \u0111i\u1ec3n hình","<strong>B.<\/strong> kim lo\u1ea1i \u0111i\u1ec3n hình","<strong>C.<\/strong> ion \u0111i\u1ec3n hình","<strong>D. <\/strong>phân t\u1eed \u0111i\u1ec3n hình"],"correct":"1","level":"2","hint":"<p>D\u1ef1a vào lo\u1ea1i liên k\u1ebft trong tinh th\u1ec3 kim c\u01b0\u01a1ng, n\u01a1i các nguyên t\u1eed carbon \u0111\u01b0\u1ee3c liên k\u1ebft ch\u1eb7t ch\u1ebd v\u1edbi nhau theo m\u1ed9t m\u1ea1ng ba chi\u1ec1u r\u1ea5t b\u1ec1n v\u1eefng.<\/p>","answer":"<p>\u0110áp án \u0111úng: <span style=\"color:#16a085;\"><strong>A. nguyên t\u1eed \u0111i\u1ec3n hình<\/strong><\/span><\/p><p>Kim c\u01b0\u01a1ng thu\u1ed9c lo\u1ea1i <strong>tinh th\u1ec3 nguyên t\u1eed \u0111i\u1ec3n hình<\/strong>, v\u1edbi m\u1ed7i nguyên t\u1eed carbon liên k\u1ebft c\u1ed9ng hóa tr\u1ecb v\u1edbi b\u1ed1n nguyên t\u1eed carbon khác, t\u1ea1o thành c\u1ea5u trúc ba chi\u1ec1u c\u1ef1c k\u1ef3 ch\u1eafc ch\u1eafn, làm cho kim c\u01b0\u01a1ng có \u0111\u1ed9 c\u1ee9ng r\u1ea5t cao.<\/p>","type":"choose","extra_type":"cloud","time":"0","user_id":"127","test":"0","date":"2024-10-18 16:14:20","option_type":"txt","len":0},{"id":"7966","post_id":"7854","mon_id":"1159533","chapter_id":"1159546","question":"<p>\u0110\u1ed1t cháy carbon b\u1edfi O<span class=\"math-tex\">$_{2}$<\/span>, n\u1ebfu d\u01b0 th\u1eeba oxi thì sau ph\u1ea3n \u1ee9ng thu \u0111\u01b0\u1ee3c khí nào?<\/p>","options":["<strong>A.<\/strong> CO<span class=\"math-tex\">$_{2}$<\/span>","<strong>B. <\/strong>O<span class=\"math-tex\">$_{2}$<\/span>","<strong>C. <\/strong>C và CO d\u01b0","<strong>D. <\/strong>CO<span class=\"math-tex\">$_{2}$<\/span> và O<span class=\"math-tex\">$_{2}$<\/span> d\u01b0"],"correct":"4","level":"2","hint":"<p>- D\u1ef1a vào ph\u1ea3n \u1ee9ng \u0111\u1ed1t cháy hoàn toàn carbon khi có \u0111\u1ee7 ho\u1eb7c d\u01b0 th\u1eeba oxygen.<\/p><p>- Ph\u1ea3n \u1ee9ng này t\u1ea1o ra s\u1ea3n ph\u1ea9m khí có liên quan tr\u1ef1c ti\u1ebfp \u0111\u1ebfn s\u1ef1 cháy hoàn toàn.<\/p>","answer":"<p>\u0110áp án \u0111úng: <span style=\"color:#16a085;\"><strong>D. CO<span class=\"math-tex\">$_{2}$<\/span> và O<span class=\"math-tex\">$_{2}$<\/span> d\u01b0<\/strong><\/span><\/p><p>\u0110\u1ed1t cháy cacbon b\u1edfi O<span class=\"math-tex\">$_{2}$<\/span>, n\u1ebfu d\u01b0 th\u1eeba oxi thì sau ph\u1ea3n \u1ee9ng thu \u0111\u01b0\u1ee3c h\u1ed7n h\u1ee3p khí là CO<span class=\"math-tex\">$_{2}$<\/span> và O<span class=\"math-tex\">$_{2}$<\/span> d\u01b0.<\/p>","type":"choose","extra_type":"shape1","time":"0","user_id":"127","test":"0","date":"2024-10-18 16:18:06","option_type":"math","len":0}]}