Muối - trung bình

Home Lớp 8 Khoa học tự nhiên 8 - sách Kết nối tri thức Bài 11: MuốiBài tập trung bình

{"common":{"save":0,"post_id":"8578","level":2,"total":10,"point":10,"point_extra":0},"segment":[{"id":"7999","post_id":"8578","mon_id":"1159539","chapter_id":"1159543","question":"\u0110\u1ec3 có \u0111\u01b0\u1ee3c dung d\u1ecbch NaCl 32%, thì kh\u1ed1i l\u01b0\u1ee3ng NaCl c\u1ea7n l\u1ea5y hoà tan vào 200 gam n\u01b0\u1edbc là:       <\/p>","options":["A. 90g.","B. 94,12 g.","C. 100g.","D. 141,18 g."],"correct":"2","level":"2","hint":"Áp d\u1ee5ng công th\u1ee9c tính n\u1ed3ng \u0111\u1ed9 %.<\/p>","answer":"\u0110áp án \u0111úng: B. 94,12 g.<\/strong><\/p>G\u1ecdi kh\u1ed1i l\u01b0\u1ee3ng NaCl c\u1ea7n dùng là m (gam)<\/p>=> mdung d\u1ecbch = mNaCl + mH2O = m + 200<\/p>C% = mct \/ mdd.100% => m \/ (m+200).100% = 32% => m = 94,12 g<\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"139","test":"0","date":"2025-03-04 22:12:13","option_type":"txt","len":1},{"id":"8000","post_id":"8578","mon_id":"1159539","chapter_id":"1159543","question":"Xác \u0111\u1ecbnh kh\u1ed1i l\u01b0\u1ee3ng Ba(OH)\u2082 có trong dung d\u1ecbch, sau \u0111ó tính s\u1ed1 mol Ba(OH)\u2082. Vi\u1ebft ph\u01b0\u01a1ng trình ph\u1ea3n \u1ee9ng v\u1edbi K\u2082CO\u2083 và tìm s\u1ed1 mol BaCO\u2083 t\u1ea1o thành. Cu\u1ed1i cùng, tính kh\u1ed1i l\u01b0\u1ee3ng BaCO\u2083.<\/p>","options":["A. 4,89 gam","B. 5,91 gam","C. 6,19 gam","D. 5,45 gam"],"correct":"2","level":"2","hint":"- Xác \u0111\u1ecbnh s\u1ed1 mol Ba(OH)2\u200b trong dung d\u1ecbch ban \u0111\u1ea7u.<\/p>- Vi\u1ebft ph\u01b0\u01a1ng trình ph\u1ea3n \u1ee9ng gi\u1eefa Ba(OH)2 và K2\u200bCO3\u200b.<\/p>- Xác \u0111\u1ecbnh s\u1ed1 mol BaCO3 t\u1ea1o thành và tính kh\u1ed1i l\u01b0\u1ee3ng c\u1ee7a nó.<\/p>","answer":"\u0110áp án \u0111úng: B. 5,91 gam<\/strong><\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"139","test":"0","date":"2025-03-04 22:15:41","option_type":"txt","len":1},{"id":"8001","post_id":"8578","mon_id":"1159539","chapter_id":"1159543","question":"Cho dung d\u1ecbch NaOH vào \u1ed1ng nghi\u1ec7m \u0111\u1ef1ng dung d\u1ecbch FeCl3, ta quan sát \u0111\u01b0\u1ee3c hi\u1ec7n t\u01b0\u1ee3ng là:<\/p>","options":["A. Có khí thoát ra","B. Xu\u1ea5t hi\u1ec7n k\u1ebft t\u1ee7a màu tr\u1eafng","C. Xu\u1ea5t hi\u1ec7n k\u1ebft t\u1ee7a xanh lam","D. Xu\u1ea5t hi\u1ec7n k\u1ebft t\u1ee7a màu \u0111\u1ecf nâu"],"correct":"4","level":"2","hint":"Ph\u1ea3n \u1ee9ng gi\u1eefa NaOH và FeCl\u2083 t\u1ea1o ra hi\u0111roxit c\u1ee7a s\u1eaft. Hãy nh\u1edb màu s\u1eafc \u0111\u1eb7c tr\u01b0ng c\u1ee7a Fe(OH)\u2083.<\/p>","answer":"\u0110áp án \u0111úng: D. Xu\u1ea5t hi\u1ec7n k\u1ebft t\u1ee7a màu \u0111\u1ecf nâu<\/strong><\/p>Khi cho NaOH vào dung d\u1ecbch FeCl\u2083, x\u1ea3y ra ph\u1ea3n \u1ee9ng: FeCl3 + 3NaOH → Fe(OH)3↓ + 3NaCl<\/p>Fe(OH)\u2083 là m\u1ed9t hi\u0111roxit không tan, có màu \u0111\u1ecf nâu \u0111\u1eb7c tr\u01b0ng.<\/p>","type":"choose","extra_type":"classic","time":"0","user_id":"139","test":"0","date":"2025-03-04 22:17:07","option_type":"txt","len":2}]}