Ôn thi tốt nghiệp THPT môn Hoá học - Lớp 12 - Đề tham khảo tốt nghiệp THPT môn Hoá học năm 2025 của Vĩnh Phúc (lần 1)

{"save":1,"level":1,"time":"50","total":40,"point":5,"segment":[{"id":"5326","test_id":"534","question":"<p>C\u1ea5u tr&uacute;c m\u1ea1ch v&ograve;ng c\u1ee7a carbohydrate n&agrave;o sau \u0111&acirc;y kh&ocirc;ng c&oacute; nh&oacute;m <span class=\"math-tex\">$-OH$<\/span> hemiacetal ho\u1eb7c hemiketal?<\/p>","options":["<strong>A.<\/strong>&nbsp;Saccharose.","<strong>B.<\/strong>&nbsp;Fructose.","<strong>C.<\/strong>&nbsp;Glucose.","<strong>D.<\/strong>&nbsp;Maltose."],"correct":"1","answer":"<p>Ch\u1ecdn&nbsp;<span style=\"color:#16a085;\"><strong>A.<\/strong>&nbsp;Saccharose.<\/span><\/p><p>C\u1ea5u tr&uacute;c m\u1ea1ch v&ograve;ng c\u1ee7a Saccharose kh&ocirc;ng c&oacute; nh&oacute;m <span class=\"math-tex\">$-OH$<\/span> hemiacetal ho\u1eb7c hemiketal.<\/p><p>D\u1ea1ng&nbsp;v&ograve;ng c\u1ee7a glucose v&agrave; maltose c&oacute; nh&oacute;m&nbsp;<span class=\"math-tex\">$-OH$<\/span>&nbsp;hemiacetal. D\u1ea1ng v&ograve;ng c\u1ee7a fructose c&oacute; nh&oacute;m&nbsp;<span class=\"math-tex\">$-OH$<\/span>&nbsp;hemiketal.<\/p>","type":"choose","user_id":"131","test":"1","date":"2025-06-12 10:29:10"},{"id":"5330","test_id":"534","question":"<p>Polypropylene l&agrave; ch\u1ea5t d\u1ebbo r\u1ea5t b\u1ec1n v&agrave; d\u1ebbo, c&oacute; kh\u1ea3 n\u0103ng ch\u1ecbu l\u1ef1c t\u1ed1t. N&oacute; th\u01b0\u1eddng \u0111\u01b0\u1ee3c s\u1eed d\u1ee5ng \u0111\u1ec3 l&agrave;m h\u1ed9p \u0111\u1ef1ng th\u1ee9c \u0103n,&nbsp;chai l\u1ecd, v&agrave; nhi\u1ec1u s\u1ea3n ph\u1ea9m kh&aacute;c c\u1ea7n \u0111\u1ed9 b\u1ec1n cao&hellip;. Polypropylene \u0111\u01b0\u1ee3c t\u1ed5ng h\u1ee3p t\u1eeb monomer n&agrave;o sau \u0111&acirc;y?<\/p>","options":["<strong>A.<\/strong>&nbsp;<span class=\"math-tex\">$CH_2=CH(CH_3)COOCH_3$<\/span>","<strong>B.<\/strong>&nbsp;<span class=\"math-tex\">$CH_2=CH_2$<\/span>","<strong>C.<\/strong>&nbsp;<span class=\"math-tex\">$CH_2=CHCN$<\/span>","<strong>D.<\/strong>&nbsp;<span class=\"math-tex\">$CH_3CH=CH_2$<\/span>"],"correct":"4","answer":"<p>Ch\u1ecdn&nbsp;<span style=\"color:#16a085;\"><strong>D.<\/strong>&nbsp;<span class=\"math-tex\">$CH_3CH=CH_2$<\/span>.<\/span><\/p><p>Polypropylene \u0111\u01b0\u1ee3c t\u1ed5ng h\u1ee3p t\u1eeb&nbsp;<span class=\"math-tex\">$CH_3CH=CH_2$<\/span>&nbsp;b\u1eb1ng ph\u1ea3n \u1ee9ng tr&ugrave;ng h\u1ee3p<\/p><p><span class=\"math-tex\">$nCH_3CH=CH_2\\xrightarrow{t^0,p,xt}[-CH(CH_3)-CH_2-]_n$<\/span><\/p>","type":"choose","user_id":"131","test":"1","date":"2025-06-12 10:36:26"}]}