Ôn thi tốt nghiệp THPT môn Hoá học - Lớp 12 - Đề tham khảo tốt nghiệp THPT môn Hóa học năm 2025 của Quảng Bình (lần 1)

{"save":1,"level":1,"time":"50","total":40,"point":5,"segment":[{"id":"5689","test_id":"541","question":"<p>Trong th\u1ef1c t\u1ebf, s\u1eed d\u1ee5ng c&aacute;ch n&agrave;o sau \u0111&acirc;y \u0111\u1ec3 b\u1ea3o v\u1ec7 kim lo\u1ea1i s\u1eaft kh\u1ecfi b\u1ecb \u0103n m&ograve;n?<\/p>","options":["<strong>A.<\/strong> G\u1eafn \u0111\u1ed3ng v\u1edbi kim lo\u1ea1i s\u1eaft.","<strong>B.<\/strong> Ng&acirc;m s\u1eaft trong dung d\u1ecbch acid.","<strong>C.<\/strong> Ph\u1ee7 m\u1ed9t l\u1edbp s\u01a1n l&ecirc;n b\u1ec1 m\u1eb7t s\u1eaft.","<strong>D.<\/strong> \u0110\u1ec3 trong kh&ocirc;ng kh&iacute; \u1ea9m."],"correct":"3","answer":"<p>Ch\u1ecdn&nbsp;<span style=\"color:#16a085;\"><strong>C.<\/strong> Ph\u1ee7 m\u1ed9t l\u1edbp s\u01a1n l&ecirc;n b\u1ec1 m\u1eb7t s\u1eaft.<\/span><\/p><p>Trong th\u1ef1c t\u1ebf, ng\u01b0\u1eddi ta ph\u1ee7 m\u1ed9t l\u1edbp s\u01a1n l&ecirc;n b\u1ec1 m\u1eb7t s\u1eaft, s\u01a1n s\u1ebd ng\u0103n c&aacute;ch s\u1eaft v\u1edbi m&ocirc;i tr\u01b0\u1eddng b&ecirc;n ngo&agrave;i nh\u1edd \u0111&oacute; b\u1ea3o v\u1ec7 kim lo\u1ea1i s\u1eaft kh\u1ecfi b\u1ecb \u0103n m&ograve;n.<\/p>","type":"choose","user_id":"131","test":"1","date":"2025-06-15 10:19:06"},{"id":"5690","test_id":"541","question":"<p>Tro th\u1ef1c v\u1eadt \u0111\u01b0\u1ee3c s\u1eed d\u1ee5ng nh\u01b0 m\u1ed9t lo\u1ea1i ph&acirc;n b&oacute;n cung c\u1ea5p nguy&ecirc;n t\u1ed1 potassium cho c&acirc;y tr\u1ed3ng do ch\u1ee9a mu\u1ed1i potassium carbonate. C&ocirc;ng th\u1ee9c c\u1ee7a potassium carbonate l&agrave;<\/p>","options":["<strong>A.<\/strong>&nbsp;<span class=\"math-tex\">$KCl$<\/span>","<strong>B.<\/strong>&nbsp;<span class=\"math-tex\">$KOH$<\/span>","<strong>C.<\/strong>&nbsp;<span class=\"math-tex\">$KHCO_3$<\/span>","<strong>D.<\/strong>&nbsp;<span class=\"math-tex\">$K_2CO_3$<\/span>"],"correct":"4","answer":"<p>Ch\u1ecdn&nbsp;<span style=\"color:#16a085;\"><strong>D.<\/strong>&nbsp;<span class=\"math-tex\">$K_2CO_3$<\/span>.<\/span><\/p><p>C&ocirc;ng th\u1ee9c c\u1ee7a potassium carbonate l&agrave; K<sub>2<\/sub>CO<sub>3<\/sub>.<\/p>","type":"choose","user_id":"131","test":"1","date":"2025-06-15 10:20:29"}]}